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I tried the java language using netbeans 12 with jdk version 8, but it always got an error in the output [duplicate]

I am trying to use Console class to get input from user but a null object is returned when I call System.console(). Do I have to change anything before using System.console?
Console co=System.console();
System.out.println(co);
try{
String s=co.readLine();
}

Using Console to read input (usable only outside of an IDE):
System.out.print("Enter something:");
String input = System.console().readLine();
Another way (works everywhere):
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Test {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter String");
String s = br.readLine();
System.out.print("Enter Integer:");
try {
int i = Integer.parseInt(br.readLine());
} catch(NumberFormatException nfe) {
System.err.println("Invalid Format!");
}
}
}
System.console() returns null in an IDE.
So if you really need to use System.console(), read this solution from McDowell.

Scanner in = new Scanner(System.in);
int i = in.nextInt();
String s = in.next();

There are few ways to read input string from your console/keyboard. The following sample code shows how to read a string from the console/keyboard by using Java.
public class ConsoleReadingDemo {
public static void main(String[] args) {
// ====
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Please enter user name : ");
String username = null;
try {
username = reader.readLine();
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("You entered : " + username);
// ===== In Java 5, Java.util,Scanner is used for this purpose.
Scanner in = new Scanner(System.in);
System.out.print("Please enter user name : ");
username = in.nextLine();
System.out.println("You entered : " + username);
// ====== Java 6
Console console = System.console();
username = console.readLine("Please enter user name : ");
System.out.println("You entered : " + username);
}
}
The last part of code used java.io.Console class. you can not get Console instance from System.console() when running the demo code through Eclipse. Because eclipse runs your application as a background process and not as a top-level process with a system console.

It will depend on your environment. If you're running a Swing UI via javaw for example, then there isn't a console to display. If you're running within an IDE, it will very much depend on the specific IDE's handling of console IO.
From the command line, it should be fine though. Sample:
import java.io.Console;
public class Test {
public static void main(String[] args) throws Exception {
Console console = System.console();
if (console == null) {
System.out.println("Unable to fetch console");
return;
}
String line = console.readLine();
console.printf("I saw this line: %s", line);
}
}
Run this just with java:
> javac Test.java
> java Test
Foo <---- entered by the user
I saw this line: Foo <---- program output
Another option is to use System.in, which you may want to wrap in a BufferedReader to read lines, or use Scanner (again wrapping System.in).

Found some good answer here regarding reading from console, here another way use 'Scanner' to read from console:
import java.util.Scanner;
String data;
Scanner scanInput = new Scanner(System.in);
data= scanInput.nextLine();
scanInput.close();
System.out.println(data);

Try this. hope this will help.
String cls0;
String cls1;
Scanner in = new Scanner(System.in);
System.out.println("Enter a string");
cls0 = in.nextLine();
System.out.println("Enter a string");
cls1 = in.nextLine();

The following takes athspk's answer and makes it into one that loops continually until the user types "exit". I've also written a followup answer where I've taken this code and made it testable.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class LoopingConsoleInputExample {
public static final String EXIT_COMMAND = "exit";
public static void main(final String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter some text, or '" + EXIT_COMMAND + "' to quit");
while (true) {
System.out.print("> ");
String input = br.readLine();
System.out.println(input);
if (input.length() == EXIT_COMMAND.length() && input.toLowerCase().equals(EXIT_COMMAND)) {
System.out.println("Exiting.");
return;
}
System.out.println("...response goes here...");
}
}
}
Example output:
Enter some text, or 'exit' to quit
> one
one
...response goes here...
> two
two
...response goes here...
> three
three
...response goes here...
> exit
exit
Exiting.

I wrote the Text-IO library, which can deal with the problem of System.console() being null when running an application from within an IDE.
It introduces an abstraction layer similar to the one proposed by McDowell.
If System.console() returns null, the library switches to a Swing-based console.
In addition, Text-IO has a series of useful features:
supports reading values with various data types.
allows masking the input when reading sensitive data.
allows selecting a value from a list.
allows specifying constraints on the input values (format patterns, value ranges, length constraints etc.).
Usage example:
TextIO textIO = TextIoFactory.getTextIO();
String user = textIO.newStringInputReader()
.withDefaultValue("admin")
.read("Username");
String password = textIO.newStringInputReader()
.withMinLength(6)
.withInputMasking(true)
.read("Password");
int age = textIO.newIntInputReader()
.withMinVal(13)
.read("Age");
Month month = textIO.newEnumInputReader(Month.class)
.read("What month were you born in?");
textIO.getTextTerminal().println("User " + user + " is " + age + " years old, " +
"was born in " + month + " and has the password " + password + ".");
In this image you can see the above code running in a Swing-based console.

Use System.in
http://www.java-tips.org/java-se-tips/java.util/how-to-read-input-from-console.html

How can I print something in the same line as the user input?

I wrote this code:
import java.util.Scanner;
public static void main (String[] args){
Scanner scan = new Scanner (System.in);
String inp;
int m;
System.out.println ("Please enter some characters.");
inp = scan.nextLine();
m = inp.length();
System.out.println(" = " + m);
}
If I run that, I get something like this:
Please enter some characters.
12345
= 5
But how can I get the = 5 to be printed on the same line as the characters entered by the user, like below?
Please enter some characters.
12345 = 5

There is no function in standard Java that allows you to easily do this.
You will need to interact with the terminal using ANSI escape codes. This is not supported by all terminals.
You could also use a library that will do this for you, some examples in random order:
Charva
Lanterna
Java Curses Library

just write like this:
System.out.print(" = " + m);
println prints to a new line.
hope it works

System.out.print("Please enter some characters.");
inp = scan.nextLine();
m = inp.length();
System.out.println(" = " + m);
When you print the question, remove the ln part (System.out.print("Please enter....))
This will allow your input to be on the same line as the prompt.
Then you can print System.out.println( inp + " = " + m);
However you can't type something after the input as far as i know but you can echo it.

Creating mad-lib game in java and receiving NoSuchElementException method [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I'm trying to create a java program that recieves a .txt file and plays the game, then prints it all into a new file (named by the user). I've reached the point where all the words have been chosen but am getting a NoSuchElementException message after that. I have a pretty basic knowledge of java and absolutely no clue how to proceed. Anyone have suggestions?
import java.io.*;
import java.util.*;
public class MadLibs {
public static void main(String[] args) throws FileNotFoundException {
Scanner console = new Scanner(System.in);
intro();
//in order to create the output file first prompts user to decide
//whether they want to create a mad-lib, view their mad-lib or quit
//if 'c' is selected then while loop is exited
String action = "c";
String fileName = "fileName";
while (action.equals("c")) {
System.out.print("(C)reate mad-lib, (V)iew mad-lib, (Q)uit? ");
action = console.nextLine();
action = action.toLowerCase();
File file = new File(fileName);
System.out.print("Input file name: ");
while (!file.exists()) {
fileName = console.nextLine();
file = new File(fileName);
if (!file.exists()) {
System.out.print("File not found. Try again: ");
}
}
//asks for a file to read from for the mad-lib game
//and creates file (named by user) to input the information
System.out.print("Output file name: ");
String outputName = console.nextLine();
System.out.println();
File outputFile = new File(outputName);
PrintStream output = new PrintStream(outputFile);
Scanner tokens = new Scanner(file);
while (tokens.hasNext()) {
String token = tokens.next();
//calls the returned placeHolder
String placeHolder = placeHolder(console, tokens, token);
String newWord = madLib(console, token, placeHolder);
//copies each token and pastes into new output file
}
}
while (action.equals("v")) {
System.out.print("Input file name: ");
fileName = console.nextLine();
File outputFile = new File(fileName);
if (!outputFile.exists()) {
System.out.print("File not found. Try again: ");
fileName = console.nextLine();
} else {
PrintStream output = new PrintStream(outputFile);
output = System.out;
}
}
while (action.equals("q")) {
}
}
public static String madLib(Scanner console, String token, String
placeHolder) throws FileNotFoundException{
String word = placeHolder.replace("<", "").replace(">", ": ").replace("-",
" ");
String startsWith = String.valueOf(word.charAt(0));
if (startsWith.equalsIgnoreCase("a") || startsWith.equalsIgnoreCase("e")
||
startsWith.equalsIgnoreCase("i") || startsWith.equalsIgnoreCase("o")
||
startsWith.equalsIgnoreCase("u")) {
String article = "an ";
System.out.print("Please type " + article + word);
String newWord = console.next();
return newWord;
} else {
String article = "a ";
System.out.print("Please type " + article + word);
String newWord = console.next();
return newWord;
}
}
public static String placeHolder(Scanner console, Scanner tokens, String
token) throws FileNotFoundException {
while(!(token.startsWith("<") && token.endsWith(">"))) {
//not a placeholder!
//continue reading file
token = tokens.next();
}
//outside of this while loop = found a placeholder!!
String placeHolder = token;
//returns placeholder to main
return placeHolder;
}
//method prints out the introduction to the game
public static void intro() {
System.out.println("Welcome to the game of Mad Libs");
System.out.println("I will ask you to provide various words");
System.out.println("and phrases to fill in a story.");
System.out.println("The result will be written to an output file.");
System.out.println();
}
}
Also am currently using a file called simple.txt with the text:
I wannabe a <job> when I grow up.
Just like my dad.
Life is <adjective> like that!
This is the full error message:
Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Scanner.java:862)
at java.util.Scanner.next(Scanner.java:1371)
at MadLibs.placeHolder(MadLibs.java:96)
at MadLibs.main(MadLibs.java:46)

I ran your code and got a NoSuchElementException instead of a NoSuchFileException. To circumvent this exception you need to check if there are any more tokens while in the method placeHolder. Otherwise, after entering every placeholder you would still search for the next placeholder token although there is no next().
Change your code to:
while(tokens.hasNext() && !(token.startsWith("<") && token.endsWith(">"))) {
//not a placeholder!
//continue reading file
System.out.println(token);
token = tokens.next();
}

while loop error in Java

well im currently learning java my myself but from what i know i just cant seem to fix this problem
currently testing a script where if u dont type ur name exactly u must re-type it but this error appears i searched everywhere but most of the things i tried dont work
Please type in your name:
lucas
Welcome lucas
Confirm your name:
luca
Please type in your name:
Exception in thread "main" java.util.NoSuchElementException: No line found
at java.util.Scanner.nextLine(Unknown Source)
at input.main(input.java:9)
here is the code:
import java.util.Scanner;
public class input {
public static void main(String[] args) {
while (true) {
try (Scanner input = new Scanner(System.in)) {
System.out.println("Please type in your name: ");
String name = input.nextLine();
System.out.println("Welcome " + name);
if (name.equals("nico")) {
System.out.println("bitch");
break;
} else {
System.out.println("Confirm your name:");
String name1 = input.nextLine();
if (name1.equals("nico")) {
System.out.println("Hello " + name1 + "... bitch");
} else if (name1.equals(name)) {
System.out.println("Thank you");
break;
}
}
}
}
}
}

Move the try-with-resources to around your while loop. When execution leaves the try-with-resources, Java closes the resources. Here, that resource is the standard input, which cannot be re-opened.
try (Scanner input = new Scanner(System.in)) {
while (true) {
System.out.println("Please type in your name: ");
You actually don't really need the try-with-resources here. Don't close standard input/output/error.

Don't put the Scanner into your loop.
Loop while the scanner still has input.
Currently, you create new Scanner too often.

Is a scan line escaping?

I've been doing a small project for class, it runs perfectly without problems but when pitted against the class's auto testers it gives back 2 No line found errors. Asking the course's staff they say it's probably because I'm trying to scan a line when none exist, but I tried printing all my scans and didn't discover anything like that.
That's all the scans I have in my code:
Scanner sc = new Scanner(System.in);
String sentence;
int choice;
System.out.println("Please enter a sentence:");
sentence = sc.nextLine();
printMenu(); // calls a function to print the menu.
// gets the require action
System.out.println("Choose option to execute:");
choice = sc.nextInt();
sc.nextLine();
(I tried with and without the last sc.nextLine)
static void replaceStr(String str)
{
String oldWord, newWord;
Scanner in = new Scanner(System.in);
// get the strings
System.out.println("String to replace: ");
oldWord = in.nextLine();
System.out.println("New String: ");
newWord = in.nextLine();
// replace
str = str.replace(oldWord, newWord);
System.out.println("The result is: " + str);
in.close();
}
static void removeNextChars(String str)
{
Scanner in = new Scanner(System.in);
String remStr; // to store the string to replace
String tmpStr = ""; //the string we are going to change.
int i; // to store the location of indexStr
// gets the index
System.out.println("Enter a string: ");
remStr = in.nextLine();
i=str.indexOf(remStr);
in.close(); // bye bye
if (i < 0)
{
System.out.println("The result is: "+str);
return;
}
// Build the new string without the unwanted chars.
/* code that builds new string */
str = tmpStr;
System.out.println("The result is: "+str);
}
Any idea how a line can leak here?

Here is the problem. You are using in.close(); at multiple places(last statement in replaceStr method and around the middle in removeNextChars method). When you close the scnaner using close() method, it closes your InputStream (System.in) as well. That InputStream can't be reopened with-in your program.
public void close() throws IOException --> Closes this input stream and releases any system resources associated with this stream. The general contract of close is that it closes the input stream. A closed stream cannot perform input operations and **cannot be reopened.**
Any read attempts after the scanner close will result into exception NoSuchElementException.
Please close your scanner only once, when your program is done.
EDIT: Scanner Closing/usage:
In yout main function:
Scanner sc = new Scanner(System.in);
....
.....
replaceStr(Scanner sc, String str);
.....
....
removeNextChars(Scanner sc ,String str);
....
....
//In the end
sc.close();
static void replaceStr(Scanner in, String str){
//All the code without scanner instantiation and closing
...
}
static void removeNextChars(Scanner in, String str){
//All the code without scanner instantiation and closing
...
}
You should be all good.