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Java can't compile in terminal because of external libraries

I'm on Ubuntu 22.04 trying to run my code in the terminal.
The program works without problems in VScode, also when running multiple instances.
The program is consisted of six class files.
The trouble occurs when I try and run it with terminal. When compiling the java file
with javac it shows errors at places where I use the external libraries.
If I compile it with VScode and run the class file in terminal, I get the following error java.lang.ClassNotFoundException
This is causing me problems since I'm also supposed to dockerize the program.

You can add the following code in your setting.json file "java.project.outputPath": "bin",
This will be the .class file generated by VS Code in the bin folder of the same directory when running the Java code.
You can use the java command after entering the file directory with the cd command.

This generally indicates that the class path with which you're compiling your program does not include the correct paths to your libraries. Assuming your libraries are jar files, your javac command should look something like this:
javac -cp libs/lib1.jar:libs/lib2.jar srcs/*.java
where libs/ is the relative path to your libraries and srcs/ is the relative path to your own java files.
And when you run the program, make sure your class path includes both the locations of your libraries and the location of your class files (which in this case would be the current directory):
java -cp .:libs/lib1.jar:libs/lib2.jar <MainClass>

Creation of a .bat file of a java application

I am a bit confused about the process to create a .bat file of a java application. I have exported the executable jar using IDE say Application.jar in C: directory. Then I have written two lines in a .txt file as stated below and saved it as .bat file in the same directory where i have my application.jar. But on double click of the .bat file, the application is not getting executed.
.BAT file code
javac Application.java
java -cp . Application
Note: I have also set the JRE and JDK path in my environment variables till bin path in My Computer properties. But it is not working. Can someone suggest me how can I fix this, because I want to execute my code by doubleclickng on a .bat file. It will be nice if someone can provide me every step I need to follow to accomplish this as I havent ever done this before.
Thanks ,

The first line in your batch file is attempting to compile your program !?
The second line is attempting to run the Application.class file.
What you want if you have produced an executable jar file is:
java -jar Application.jar
But you don't really need the batch file at all. If you double click on the jar file and it runs your program then you can just create a shortcut to it.

Your .bat is just fine. When you double click it might be executing and then closes. This is because your program might not have any UI and it isnt waiting for any input. To verify this take a command prompt and then execute your bat file via that.
In other case I assume that you have a java class called Application and you need to run this via a batch file. In that case if the class have a main method then you just need one line in .bat file
java -cp <the path to class file> Application
So you might be using a javac just to take advantage of class path as current directory. So when you say
javac Application.java
java -cp . Application
It compiles the class to current folder and set that as class path and then execute. This is absolutely file as long as the Application.java doesnt have any third party dependency. But in this case again you need not set -cp to . (current directory will be taken as classpath automatically unless otherwise specificed). So below will also work fine.
javac Application.java
java Application
I support Jurgen reply. If you have an executable jar file and a jre in path then double clicking it will run the application. The META-INF folder inside the jar will have a MANIFEST.MF file which uses a property called Main-Class: to specify the main executing class. And on double clicking this class gets executed. However its only useful if you have a UI. Else it'll also have no effect.
In all these context the Application.jar you mentioned is irrelevant. If that is a third party jar that you need to run the you should include that in -cp argument.

jar not reading input file directory recursively

I'm having trouble running the jar command in cygwin. The input-files parameter isn't treating the directory I'm passing it recursively when I'm referencing it with ".."s in my path.
For example, I'm running this in the same directory as the "src" directory. src/ contains my package structure of class and java files. This runs properly and creates a jar containing my source and class files.
jar cf jarname.jar src
However when I run this next command, I get an empty jar except for a manifest file.
jar cf jarname.jar localdir/../src
I need to run this from a script that needs to find this directory with a ".." directory so I need the 2nd command to work.
Anybody know why this isn't working or have a workaround? I tried using realpath but it complains that it can't find that path at all. I may be using it wrong though.

The Directory path in cygwin is different . To navigate to any drive for example to C drive we need to type in:
/cygdrive/c
A very easy work around i found useful is just to type cmd in the terminal . This allows you to use the actual path than the cygwin specific path .
try typing cmd and then running the command , it worked for me

java command line argument to make jar find files in two directories?

I have a jar file which I do not have the source code but want to use.
The jar file prompts for a file to read and generates an output file using a combinatin of the input file and a number of 'helper' files it uses for data. It works perfecty fine if run from its expected home directory, but I'm trying to write a script which will allow running the jar from anywhere.
The problem is that if I try running the jar file from anywhere other then its home directories it fails to find the support files it needs to properly generate its data.
If I run the file from its expected home directory I have to give the full address of the input file or it won't find it. I would prefer to be able to give just the relative path and Java know to look at whatever directory the person calling my script is in.
Is there a way I can have a bash script pass a command line argument to Java that would ensure that this jar looks at both of the relevant directories (directory of the helper files and the current dir of the person calling the script) when trying to resolve a relative file path? Something like the -classpath argument?

With the --classpath (or -cp) you can tell your Java program where it should take the dependency classes. So, probably if you do like in your files directory
$JAVA_HOME/bin/java -cp '.:/path/to/the/original/program' My.class myfile.txt
then it will wind the program, and find your files as well.
UPDATE
If it doesn't work, you can try to force the file loading some other way. The Javadoc says:
By default the classes in the java.io package always
resolve relative pathnames against the current user directory. This
directory is named by the system property user.dir, and
is typically the directory in which the Java virtual machine was
invoked.
So, you can try running the program from the original directory this way:
$JAVA_HOME/bin/java -Duser.dir=/path/to/the/files/directory My.class myfile.txt
UPDATE2:
As I wrote in a comment, you can try symlinks. Execute the following commands in the original directory:
ln -s /path/to/the/files/directory datafiles
$JAVA_HOME/bin/java My.class datafiles/myfile.txt

Sorry - ignore. I missed the first line of your question.
You could pass the two paths as an argument to the jar file - then append the path location at runtime. Many ways to do that, here is one:
java -DdirectoryA="/somewhere" -DdirectoryB="/elsewhere" -jar program.jar
and in your code
String pathA = System.getProperty("directoryA");

JVM Launcher cannot find main class

I am using NetBeans to build my executable JAR and haven't messed around with any Ant or project settings (using defaults).
When I go to Run >> Clean and Build Project, I see NetBeans building my JAR and putting it into my project's dist/ directory without a hitch.
When I double-click that JAR to run it, I get the following error message:
Could not find the main class: com.me.myorg.MainApp. Program will exit.
If I open up the JAR in WinRAR and extract the META-INF/MANIFEST.MF file, I see the following attribute defined:
Main-Class: com.me.myorg.MainApp
Obviously, com.me.myorg.MainApp is the "head" of my GUI (Swing) app.
Any ideas as to what is going on? How to troubleshoot? Thanks in advance.

Try in command prompt(Windows):
ftype jarfile="C:\PATH_TO\javaw.exe" -jar "%1" %
EDIT
Run the command prompt like this: Go to Start and in the Search box type CMD. Right click the Command Prompt icon and choose Run as Administrator.
http://www.howtogeek.com/howto/windows-vista/run-a-command-as-administrator-from-the-windows-vista-run-box/
Then run the command above.

Is there a new line after the main class declaration?
Main-Class: com.me.myorg.MainApp
# empty line here
The manifest file format requires each line to end with a line separator. If the line with main class is the last line in the file it is ignored.