Let's say I have following flat JSON structure:
{
"name": "name",
"validFrom": "2018-01-09",
"validTo": "2018-01-10",
}
and MyPojo class:
public class MyPojo {
private String name;
#JsonUnwrapped
private Validity validity;
}
and Validity class:
public class Validity {
private LocalDate validFrom;
private LocalDate validTo;
}
I created custom unwrapping serializer and it works fine.
I would like to deserialize JSON above into MyPojo class which includes Validity value object.
How should custom deserializer for Validity be implemented?
#JsonProperty does not work as I want to use 2 Json properties for Validity construction
I would recommend a constructor in this case, a lot simpler than a custom deserializer, something like:
#JsonCreator
public MyPojo(#JsonProperty("name") String name,
#JsonProperty("validFrom") String validFrom,
#JsonProperty("validTo") String validTo) {
this.name = name;
this.validity = new Validity(validFrom, validTo);
}
It's implied that LocalDate is parsed from String above but you may have Jackson parse them.
You may skip annotations above if you use Java 8 with parameter names module
That will require an extra annotation on validity, see open Jackson issue here
#JsonProperty(access = JsonProperty.Access.READ_ONLY)
#JsonUnwrapped
private Validity validity;
Related
I am new to Spring Boot and I am trying to figure out how to parse json data. I see a lot of tutorials on how to map json string object to an annotated Java class and using and object mapper, like this:
json:
{
"UUID": "xyz",
"name": "some name"
}
public class MyClass{
#JsonProperty
private UUID id;
#JsonProperty
private String name;
#JsonAnyGetter
public UUID getId() {
return this.id;
}
#JsonAnySetter
public void setId(UUID id) {
this.id = id;
}
#JsonAnyGetter
public String getName() {
return this.name;
}
#JsonAnySetter
public void setName(String name) {
this.name = name;
}
}
ObjectMapper objectMapper = new ObjectMapper();
MyClass customer = objectMapper.readValue(jsonString, MyClass.class);
The problem is that the system I am getting the json string from does not match the class naming conventions we use (and I cannot change either one). So, instead of having the example json string above, it might look like this:
{
"randomdstring-fieldId": "xyz",
"anotherrandomstring-name": "some name"
}
This use case only has two fields, but my use case has a larger payload. Is there a way to either map the field names from the json object to the field names in the Java class or is there a way to just parse the json string as a key value pair (so that I can just manually add the fields to my Java object)?
In Jackson with #JsonProperty you can customize the field name with it's annotation parameter value
Therefore, you just have to annotate the entity fields with the #JsonProperty annotation and provide a custom JSON property name, like this:
public class MyClass{
#JsonProperty("original_field_name_in_json")
private UUID id;
...
The #JsonProperty will do it for you:
#JsonProperty("name_in_json")
private Long value;
I am following this article https://quarkus.io/guides/rest-client to build a REST Client to parse the output from the restcountries.eu service.
Here the class holding the model:
public class Country {
public String name;
public String alpha2Code;
public String capital;
public List<Currency> currencies;
public static class Currency {
public String code;
public String name;
public String symbol;
}
}
Now, suppose I would like to add a custom fields such as timestamp, to record the instant when this object has been created. I imagine, I would go ahead and add another field like below:
public class Country {
public String name;
public String alpha2Code;
public String capital;
public List<Currency> currencies;
public Instant timestamp; //<--------- added attribute
[....]
My question is: how do I tell the client to populate that field? Normally, I would have done it in the constructor. However, I could not find docs that explain this part.
Thanks for your help
Simone
You can actually do this in the default constructor. Frameworks like JSONB or Jackson expect POJOs to have a default constructor. They will call it when they create an instance of Country.
Use the #JsonbTransient or #JsonIgnore annotations to mark that attribute of your POJO as ignorable in order to avoid the unmarshaller complaining about attributes that cannot be found in the response.
#Data
public class Country {
private String name;
private String alpha2Code;
private String capital;
private List<Currency> currencies;
#JsonbTransient // if you're using JSONB (default in Quarkus)
#JsonIgnore // if you're using Jackson
private Instant timestamp;
public Country() {
this.timestamp = Instant.now();
}
PS The #Data annotation is something you should consider using. Encapsulation is not a bad thing but creating getters/setters is tedious. But Project Lombok certainly helps here.
Now I have bean like this:
#Data
public class JsonSerialModel {
public JsonSerialModel(String name, Date birthday,List<String> names) {
this.birthday = birthday;
this.name = name;
this.names = names;
}
private String name;
#JsonSerialize(using = JsonCustomerSerialize.class)
private Date birthday;
#JsonSerialize(keyUsing = JsonCustomerContentSerialize.class)
private List<String> names;
}
by this I can custom field serialize
but I wanna use custom annotation like #Coustom(value="AES") so I can
get value AES and serialize my filed by AES or other value,
so how to implement this by using jackson
Finally I get answer from jackson source code test case
Implement ContextualSerializer interface then use BeanProperty
I am using Spring #RequestBody to map a JSON payload to a Java Object. Unfortunately this JSON payload does not use a set convention but rather has names that use both camelCase and snake_case.
To be clear my Controller looks like this:
#RequestMapping(value="/mobile/device", method = RequestMethod.PUT)
public ResponseEntity<Object> flagDevice (#RequestBody List<MobileDeviceData> deviceInfoList) {
... code here ...
}
with the MobileDeviceData Entity object having several setter methods like:
public void setDeviceName(String deviceName) {
this.deviceName = deviceName;
}
public void setFlagId(int flagId) {
this.flagId = flagId;
}
This works great and without any extra effort when the JSON objects name is camelCase. However for snake_case names I need to add the Annotation:
#JsonProperty("flag_id")
private int flagId;
in order for it to be picked up.
I know it's not a good idea to use the #JsonProperty if it can be avoided as you then will need to annotate every parameter. My question is, is there a more general way to enforce matching snake_case with the corresponding camelCase in the Entity object? And obviously to do it without screwing up the ones that are already camelCase.
As per the article here, there is a simple approach to deserialize the MobileDeviceData class. Here is the sample code as below:
#JsonDeserialize(using = UserDeserializer.class)
public class User {
private ObjectId id;
private String username;
private String password;
public User(ObjectId id, String username, String password) {
this.id = id;
this.username = username;
this.password = password;
}
public ObjectId getId() { return id; }
public String getUsername() { return username; }
public String getPassword() { return password; }
}
Assume User is the class we’re interested in writing the Deserializer for. Not much is notable here, except for the annotations that tell Jackson who knows how deserialize this class.
public class UserDeserializer extends JsonDeserializer {
#Override
public User deserialize(JsonParser jsonParser,
DeserializationContext deserializationContext) throws IOException {
ObjectCodec oc = jsonParser.getCodec();
JsonNode node = oc.readTree(jsonParser);
return new User(null,
node.get("username").getTextValue(),
node.get("password").getTextValue());
}
}
The deserializer is created by extending Jackson’s abstract JsonDeserializer class, and giving it the type we want to deserialize to. Difficult is figuring out that you can reference the JSON by field name with the JsonParser's ObjectCodec.
I hope it helps.
Please feel free to comment if needed!
Having been working on this a bit, I now realize doing anything like what was requested would be counterproductive.
When you receive (deserialize) a JSON Object, it is generally expected that you will deliver (serialize) with the same parameters. If an implementation extracted both camelCase and underscore parameters the same way, then it would not know how to deserialize correctly later on. By following a standard convention and then using #JsonProperty for all the exceptions, it remains possible to deserialize and later deliver the JSON object just as it was received.
I am developing using an ORM where I extend a base orm class to create tables.
For example:
public class Person extends DbItem {
#JsonIgnore
private String index;
private String firstName;
private String lastName;
}
Problem is that when I use ObjectMapper to serialize, it tries to serialize the members of the DbItem class. Is there any simple way to prevent this? For example with an annotation.
I had a look at a similar problem Jackson serialization: how to ignore superclass properties but I was hoping it could be done simpler, and I'm not sure if I could do it as I can't change the superclass since it is in an external library.
You can use a Mix-in or #JsonIgnoreProperties
For the purposes of these examples, the base ORM class and extension are assumed to be:
public class DbItem {
public String dbPropertyA;
public String dbPropertyB;
}
and
public class Person extends DbItem {
public String index;
public String firstName;
public String lastName;
}
respectively.
Using a Mix-in
A Mix-in is an abstraction of the de/serialization instructions that Jackson understands from an object itself. It is a way to customize de/serialization of 3rd party classes. In order to define a Mix-in, an abstract class must be created and registered with the ObjectMapper.
Example Mix-in Definition
public abstract class PersonMixIn {
#JsonIgnore public String dbPropertyA;
#JsonIgnore public String dbPropertyB;
#JsonIgnore public String index;
}
Registering the Mix-in
#Test
public void serializePersonWithMixIn() throws JsonProcessingException {
// set up test data including parent properties
Person person = makeFakePerson();
// register the mix in
ObjectMapper om = new ObjectMapper()
.addMixIn(Person.class, PersonMixIn.class);
// translate object to JSON string using Jackson
String json = om.writeValueAsString(person);
assertFalse(json.contains("dbPropertyA"));
assertFalse(json.contains("dbPropertyB"));
assertFalse(json.contains("index"));
System.out.println(json);
}
#JsonIgnoreProperties
If you want to avoid creating a class and configuring the ObjectMapper, the #JsonIgnoreProperties annotation can be utilized. Simply annotate the class you are serializing and list the properties to exclude.
Example Serializable Object
#JsonIgnoreProperties({"index", "dbPropertyA", "dbPropertyB"})
public class Person extends DbItem {
public String index;
public String firstName;
public String lastName;
}
See It In Action
#Test
public void serializePersonWithIgnorePropertiesAnnotation() throws JsonProcessingException {
// set up test data including parent properties
Person person = makeFakePerson();
ObjectMapper om = new ObjectMapper();
// translate object to JSON string using Jackson
String json = om.writeValueAsString(person);
assertFalse(json.contains("dbPropertyA"));
assertFalse(json.contains("dbPropertyB"));
assertFalse(json.contains("index"));
System.out.println(json);
}
You want to do custom field level serialization. This will be a bit more work to maintain your code base, but is by far the simplest solution. See Jackson JSON custom serialization for certain fields for implementation details.