Getting data from php file in my Android java class using bufferreader - java

I am getting data from php file in android java class using
BufferedReader reader = new BufferedReader(new
InputStreamReader(con.getInputStream()));.
This code is in my php file is
echo "abc";
echo "xyz";
This is the code of my java file.
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line = null;
Complete_line = null;// Read Server Response
while ((line = reader.readLine()) != null) {
System.out.println(line);
break;
}
But when I read from Buffer reader it will read a whole one line, or it will print "line" string as "abcxyz". But I want them as two lines as they are two different lines in the PHP file.

try this,
BufferedReader reader = null;
StringBuffer response = new StringBuffer();
try {
reader = new BufferedReader(new InputStreamReader(in));
String line = "";
while ((line = reader.readLine()) != null) {
response.append(line+"\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}

In PHP, unless you seperate the 2 lines a a newline character \n, the two echos are the same. To seperate echos into different lines, you need to end the strings with \n, like this:
echo "abc\n";
echo "xyz\n";

Related

Trying to replace a symbol in a text file of 4000 lines, ends up with only 500 in Java

What i'm trying to do, is to replace a symbol in a file text which contains over 4000 lines but using the below code, after the program ends, it only remain 500 lines. Why is this file truncated? How to solve this?
This is my code:
ArrayList<String> arrayList = new ArrayList<>();
try (FileReader fileReader = new FileReader(file);
BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while ((line = bufferedReader.readLine()) != null) {
line = line.replace("þ", "t");
arrayList.add(line);
try (BufferedWriter bw = new BufferedWriter(new FileWriter(file))) {
for (String string : arrayList) {
bw.write(string + "\n");
}
} catch (Exception e) {System.err.println(e);}
}
} catch (Exception e) {e.printStackTrace();}
Thanks in advance!
new BufferedWriter(new FileWriter(file)) clear file.
You should open it only once. Also you reading and writing to the same file. You should use different files.
Like this
try (FileReader fileReader = new FileReader(inputFile);
BufferedReader bufferedReader = new BufferedReader(fileReader);
BufferedWriter bw = new BufferedWriter(new FileWriter(outputFile))) {
String line;
while ((line = bufferedReader.readLine()) != null) {
line = line.replace("þ", "t");
bw.write(line + "\n");
}
} catch (Exception e) {
e.printStackTrace();
}
You are writing to the same file while you are reading it. This won't work. Once you start writing, the file becomes empty (plus whatever you've written), so subsequent reads will report end-of-file. Your ~500 lines will be buffered input from the first read.
One solution is to do all the reading first, before opening the file again for writing:
Array<String> arrayList = new ArrayList<>();
try (BufferedReader bufferedReader = new BufferedReader(new FileReader(file))) {
while ((String line = bufferedReader.readLine()) != null) {
line = line.replace("þ", "t");
arrayList.add(line);
}
} catch (Exception e) {
e.printStackTrace();
}
try (BufferedWriter bw = new BufferedWriter(new FileWriter(file))) {
for (String string : arrayList) {
bw.write(string + "\n");
}
} catch (Exception e) {
System.err.println(e);
}
Here, first the program slurps the file into a List<String>, fixing the lines as it goes. Then it writes all the lines back out to the file.
There are circumstances in which this model is appropriate. For example, you might be building a non-linear data structure from the file content. Or you might need to see the last line before you can modify earlier lines (and be unable to re-open the data source from the start).
However I'd suggest a method that's more thrifty with memory. You don't need to keep all those lines in memory. You can read one line, fix it up, then forget about it. But to do this, you'll need to write to a second file.
String filein = "inputfile";
String fileout = filein + ".tmp";
try(
BufferedReader reader = new BufferedReader(new FileReader(filein));
Writer writer = new BufferedWriter(FileWriter(fileout))
) {
while ((String line = bufferedReader.readLine()) != null) {
writer.write(line.replace("þ", "t");
}
}
Files.move(Paths.get(fileout)),
Paths.get(filein),
CopyOption.REPLACE_EXISTING);
I have left out the necessary exception catching -- add back in as required.

How to read wsdl from a url using java

I'm new to java. I want to read wsdl from java. I have sample northwind service http://services.odata.org/Northwind/Northwind.svc/$metadata
I want to read output xml for the above URL. I tried in different ways, It didn't work.
URL oracle = new URL("http://services.odata.org/Northwind/Northwind.svc/$metadata");
BufferedReader in = new BufferedReader(
new InputStreamReader(oracle.openStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
in.close();
Method #2
private static void readHttp() {
Charset charset = Charset.forName("US-ASCII");
Path file = Paths.get("http://services.odata.org/Northwind/Northwind.svc/$metadata");
try (BufferedReader reader = Files.newBufferedReader(file, charset)) {
String line = null;
while ((line = reader.readLine()) != null) {
System.out.println(line);
}
} catch (IOException x) {
System.err.format("IOException: %s%n", x);
}
}
Can anyone suggest me how to proceed on this.
Thanks,
Use org.apache.commons.io.IOUtils
IOUtils.toString(new URL("http://services.odata.org/Northwind/Northwind.svc/"));

Unable to a read a large file using BufferedReader in Java

I am trying to read a file using BufferedReader, but when I tried to print, It is returning some weird characters.
Code of reading file is:
private static String readJsonFile(String fileName) throws IOException{
BufferedReader br = null;
try {
StringBuilder sb = new StringBuilder();
br = new BufferedReader(new FileReader(fileName));
String line = br.readLine();
while(line != null ){
sb.append(line);
System.out.println(line);
line=br.readLine();
}
return sb.toString();
} finally{
br.close();
}
}
This function is being called as :
String jsonString = null;
try {
jsonString = readJsonFile(fileName);
} catch (IOException e) {
e.printStackTrace();
}
But when I tried to print this in console using System.out.println(jsonString);, It is returning some fancy pictures.
Note: It is Working file when file size is small.
Is there any limit on size of file it can read ?
You're using the platform default encoding to read the file, which is probably encoded in UTF8. Check the actual encoding of the file, and specify the encoding:
BufferedReader r = new BufferedReader(new InputStreamReader(new FileInputStream("...", StandardCharsets.UTF_8));
Note that since you simply want to read everything from the file, you could simply use
String json = new String(Files.readAllBytes(...), StandardCharsets.UTF_8);

How to escape a line that starts with a special character while reading files in java

Suppose a file contains the following lines:
#Do
#not
#use
#these
#lines.
Use
these.
My aim is to read only those lines which does not start with #. How this can be optimally done in Java?
Let's assume that you want to accumulate the lines (of course you can do everything with each line).
String filePath = "somePath\\lines.txt";
// Lines accumulator.
ArrayList<String> filteredLines = new ArrayList<String>();
BufferedReader bufferedReader = null;
try {
bufferedReader = new BufferedReader(new FileReader(filePath));
String line;
while ((line = bufferedReader.readLine()) != null) {
// Line filtering. Please note that empty lines
// will match this criteria!
if (!line.startsWith("#")) {
filteredLines.add(line);
}
}
}
finally {
if (bufferedReader != null)
bufferedReader.close();
}
Using Java 7 try-with-resources statement:
String filePath = "somePath\\lines.txt";
ArrayList<String> filteredLines = new ArrayList<String>();
try (Reader reader = new FileReader(filePath);
BufferedReader bufferedReader = new BufferedReader(reader)) {
String line;
while ((line = bufferedReader.readLine()) != null) {
if (!line.startsWith("#"))
filteredLines.add(line);
}
}
Use the String.startsWith() method. in your case you would use
if(!myString.startsWith("#"))
{
//some code here
}
BufferedReader.readLine() return a String. you could check if that line starts with # using string.startsWith()
FileReader reader = new FileReader("file1.txt");
BufferedReader br = new BufferedReader(reader);
String line="";
while((line=br.readLine())!=null){
if(!line.startsWith("#")){
System.out.println(line);
}
}
}

Using PrintWriter in Java

I trying to run multiple command shells from Java. I am able to do that (and get the output in the console using PrintWriter). However, I want to be able to get the output of each command in a separate String. Is that possible?
Here is a part of the code :
File wd = new File("/bin");
Process proc = null;
BufferedReader in = new BufferedReader(new InputStreamReader(proc.getInputStream()));
PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(proc.getOutputStream())), true);
out.println("cd ..");
out.println("ls");
System.out.println("moving to /var directory");
out.println("cd /var/");
out.println("ls");
//get output of ls command in string variable
out.println("cd ..");
out.println("cd /etc/");
out.println("ls -a");
out.println("ps");
out.println("exit");
try {
String line;
while ((line = in.readLine()) != null) {
System.out.println(line);
}
proc.waitFor();
in.close();
out.close();
proc.destroy();
}
catch (Exception e) {
e.printStackTrace();
}
Have you tried putting a section like
StringBuilder builder = new StringBuilder();
String line = null;
while ((line = in.readLine()) != null) {
builder.append(line).append("\n");
}
String commandOutput = builder.toString();
after each command? Is that roughly what you are trying to achieve?

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