I have been using Hibernate a lot but using Hibernate/JPA with UUID got me stumped a bit. I am using hibernate 5.2.12.Final.
I have an object called TimePeriod with this mapping:
#Entity(name = "time_period")
public class TimePeriod extends AbstractDomainObject {
#OneToMany(mappedBy = "timePeriod", cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private List<TimePeriodBlock> timePeriodBlocks = new ArrayList<>();
...
public void addTimePeriodBlock(TimePeriodBlock timePeriodBlock) {
timePeriodBlock.setTimePeriod(this);
this.timePeriodBlocks.add(timePeriodBlock);
}
...
With the following child relationship:
#Entity(name = "time_period_block")
public class TimePeriodBlock extends AbstractDomainObject {
...
#ManyToOne
#JoinColumn(name = "time_period_id", nullable = false)
private TimePeriod timePeriod;
...
They share this super class:
#MappedSuperclass
public abstract class AbstractDomainObject {
...
#Id
#GeneratedValue
#Column(name = "id", columnDefinition = "uuid", updatable = false)
private UUID id;
...
When I execute the following:
// pseudo code
TimePeriod t = new TimePeriod();
t.setName("test");
TimePeriodBlock b = new TimePeriodBlock();
t.addTimePeriodBlock(b);
em.persist(t);
I get the exception:
...
Caused by: org.hibernate.PropertyValueException: not-null property references a null or transient value : test.TimePeriodBlock.timePeriod
...
Some notes:
I strongly believe that this could be because Hibernate generates the UUID (and not the database) but, since I am not sure, I hope some fellow Developer might know how this could work.
I am using PostgreSQL 9.6 and the database can also generates UUIDv4 but requires compiling an extra extension so I opted for Hibernate to generate it.
When I enter some data in the database and retrieve the data it is fetched without any error.
Storing other objects without #ManyToOne relationships do store without any error and have a UUID that is generated by Hibernate.
Well after some debugging and using Luay Abdulreheem suggestion I found out that hibernate is working just fine; in this case my objects are send using a REST interface (using Jackson) and the reference to the parent was lost as the unmarshalling of the JSON is done using fields.
So nothing to see here, move along...
Related
I have a simple table (ActivityLog) and I want it to have a PK that is also a FK to another table (User).
It seems to be a common thing to have, and I tried to follow this wikibook
Primary Keys through OneToOne and ManyToOne Relationships. The example there involved a composite key. I need just a primitive key, so I ended up with:
#Entity
public class User {
#Id
private Long id;
// other stuff
}
#Entity
public class ActivityLog {
#Id
#OneToOne(optional = false)
#JoinColumn(name="user_id", referencedColumnName="id")
private User user;
// other stuff
}
Unfortunately i am getting:
Caused by: java.lang.IllegalArgumentException: This class [class com.example.ActivityLog] does not define an IdClass
at org.hibernate.metamodel.internal.AbstractIdentifiableType.getIdClassAttributes(AbstractIdentifiableType.java:183)
at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation$IdMetadata.<init>(JpaMetamodelEntityInformation.java:253)
I tried to annotate ActivityLog with:
#IdClass(Long.class)
(even though from what I understand it is applicable only for composite keys), yet I am getting the exact same error.
Is my case different than what's on the mentioned wikibook?
Is Spring at fault here? (As suggested in this question? (no accepted answers)).
This should help:
#Entity
public class ActivityLog {
#Id
#Column(name = "user_id")
private Long id;
#OneToOne(optional = false)
#JoinColumn(name="user_id", referencedColumnName="id")
private User user;
// other stuff
}
Btw. I would expect, that you need more logs per user, so you would probably need some additional (generated) id anyway ...
I have a strange situation in my SINGLE_TAB inheritance Hibernate config whereby the #DiscriminatorColumn seems to be ignored and the query is always defaulting back to the 'dtype' column. It's like the behaviour I would see when I had not included the annotation at all (the default column name being 'dtype').
Base entity:
#Entity
#Table(name = "post")
#Inheritance(strategy = InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(columnDefinition = "post_type", discriminatorType = DiscriminatorType.STRING)
public class Post {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
#Column(name = "title")
private String title;
#Column(name = "body")
private String body;
#NotNull
#Column(name = "post_type", insertable = false, updatable = false)
private String postType;
// other simple columns
// ommit getters/setters + hashcode etc
}
Subclass entity:
#Entity
#DiscriminatorValue(value = "EVENT")
public class Event extends Post {
// ommitted basic methods, no extra config
}
I also need access to the discriminator value itself within each object (the postType field). I still have the same behaviour even if I remove it so it doesn't seem to be the cause.
When I try to do a query on the subclass through a JPA repository:
public interface EventRepository extends JpaRepository<Event, Integer> {
List<Event> findAll();
}
Hibernate generates the query:
select post0_.id as id2_4_, post0_.bodyl as body_bod3_4_, post0_.title as title12_4_
from post post0_
where post0_.dtype='EVENT'
which of course generates an error as 'dtype' doesn't exist in the table.
The strange thing is that if I use #DiscriminatorFormula("post_type") on the Post entity instead, everything seems to work. It is however slower so I would prefer to use the #DiscriminatorColumn as it should fit my needs exactly.
I am using Hibernate 5.2.10-FINAL and Spring Data JPA 1.11.4 (or generally the latest of hopefully everything).
Any ideas on what could be causing this?
I'm think you have this problem because you specified wrong parameter of #DiscriminatorColumn anotation, you should use name instead of columnDefinition.
I've been bashing my head on my keyboard for two days trying to figure this out...
Some background: We have a data model set up with a Perl code base that runs straight native SQL statements to the database via ODBC. For certain reasons, we decided to rewrite the code in Java... I thought it would be a good idea to use Hibernate to define all of the mappings. We don't want to edit the data model.
For simplicity sake, I can express the problem with only part of our data model. We have the entities "Job","JobDatabase" and "JobTable".
Job has a PK of job_name. Database has a PK of job_name,name. Table has a PK of job_name,src_database_name,name. As you may expect, Job has a OneToMany relationship with JobDatabase, and Database has a OneToMany with JobTable.
For purposes of this test, I'm starting with empty tables and trying to create some sample data. I can insert a Job and a JobDatabase, but when I try to insert the JobTable, Hibernate throws an error. Or more accurately, that is where it complains. It doesn't start executing my code because it detects the mapping error. However, if I remove the association between JobDatabase and JobTable, it will insert all Job and JobDatabase records correctly with no errors.
Sample Classes (all fields have getters/setters... there are also many other fields):
#Entity
#Table(name="Job")
public class Job implements Serializable {
#Id
#Column(name="job_name",nullable = false)
private String jobName;
#OneToMany(cascade = CascadeType.ALL)
#JoinColumn(name = "job_name", referencedColumnName = "job_name")
private Set<JobDatabase> databases;
}
#Entity
#Table(name="JobDatabase")
public class JobDatabase implements Serializable {
#Id
#Column(name="job_name",nullable = false)
private String jobName;
#Id
#Column(name="name",nullable = false)
private String name;
#OneToMany(cascade = CascadeType.ALL)
#JoinColumns({
#JoinColumn(name = "job_name", referencedColumnName = "job_name"),
#JoinColumn(name = "name", referencedColumnName = "src_database_name")
})
private Set<JobTable> tables;
}
#Entity
#Table(name="JobTable")
public class JobTable implements Serializable{
#Id
#Column(name="job_name",nullable = false)
private String jobName;
#Id
#Column(name="src_database_name",nullable = false)
private String srcDatabaseName;
#Id
#Column(name="name",nullable = false)
private String name;
}
The error:
Exception in thread "main" org.hibernate.MappingException: Unable to find column with logical name: src_database_name in JobDatabase
I keep getting this error. I do not understand why it is looking for the referenced column in the entity "owning" the mapping. src_database_name does indeed only exist in JobTable - it is referred to as "name" in JobDatabase. JobTable also has a "name" field, but it refers to the name of the Table.
You need to have src_database_name column in your JobDatabase table. Or you can change src_database_name to other column name.
For composite key reference column must be present in your source table.
I'm trying to write a hibernate adapter for an old database schema. This schema does not have a dedicated id column, but uses about three other columns to join data.
On some tables, I need to use coalesce. This is what I came up with so far:
About the definition:
A car can have elements, assigned by the car's user or by the car's group of users.
If FORIGN_ELEMENT holds a user's name, definition will be 'u'
If FORIGN_ELEMENT holds a group's name, definition will be 'g'
This also means, one table (CAR_TO_ELEMENT) is misused to map cars to elements and cargroups to elements. I defined a superclass CarElement and subclasses CarUserElement and CarGroupElement.
state is either "active" or an uninteresting string
I set definitition and state elsewhere, we do not need to worry about this.
Use DEP_NR on the join table. If it's zero, use USR_DEP_NR. I did this with COALESCE(NULLIF()) successfully in native SQL and want to achieve the same in Hibernate with Pojos.
Okay, here we go with the code:
#Entity
#Table(name="CAR")
public class Car extends TableEntry implements Serializable {
#Id
#Column(name="DEP_NR")
private int depnr;
#Id
#Column(name="USER_NAME")
#Type(type="TrimmedString")
private String username;
#ManyToOne(fetch = FetchType.EAGER, targetEntity=CarGroup.class)
#JoinColumns(value={
#JoinColumn(name="GROUP_NAME"),
#JoinColumn(name="DEP_NR"),
#JoinColumn(name="state"),
})
private CarGroup group;
#OneToMany(fetch=FetchType.EAGER, targetEntity=CarUserElement.class, mappedBy="car")
private Set<CarUserElement> elements;
}
#Entity
#Table(name="CAR_GROUP")
public class CarGroup extends TableEntry implements Serializable {
#Id
#Column(name="DEP_NR")
private int depnr;
#Id
#Column(name="GROUP_NAME")
#Type(type="TrimmedString")
private String group;
#ManyToOne(fetch = FetchType.EAGER, targetEntity=Car.class)
#JoinColumns(value={
#JoinColumn(name="GROUP_NAME"),
#JoinColumn(name="DEP_NR"),
#JoinColumn(name="state"),
})
private Set<Car> cars;
#OneToMany(fetch=FetchType.EAGER, targetEntity=CarGroupElement.class, mappedBy="car")
private Set<CarGroupElement> elements;
}
#MappedSuperclass
public class CarElement extends TableEntry {
#Id
#ManyToOne(fetch = FetchType.EAGER, targetEntity=Element.class)
#JoinColumns(value={
#JoinColumn(name="ELEMENT_NAME"),
#JoinColumn(name="state"),
})
private Element element;
}
#Entity
#Table(name="CAR_TO_ELEMENT")
public class CarUserElement extends CarElement {
#Id
#Column(name="DEFINITION")
private char definition;
#Id
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumnsOrFormulas(value = {
#JoinColumnOrFormula(formula=#JoinFormula(value="COALESCE(NULLIF(DEP_NR, 0), USR_DEP_NR)", referencedColumnName="DEP_NR")),
#JoinColumnOrFormula(column=#JoinColumn(name="FORIGN_ELEMENT", referencedColumnName="USER_NAME")),
#JoinColumnOrFormula(column=#JoinColumn(name="STATE", referencedColumnName="STATE"))
})
private Car car;
}
#Entity
#Table(name="CAR_TO_ELEMENT")
public class CarGroupElement extends CarElement {
#Id
#Column(name="DEFINITION")
private char definition;
#Id
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumnsOrFormulas(value = {
#JoinColumnOrFormula(formula=#JoinFormula(value="COALESCE(NULLIF(DEP_NR, 0), USR_DEP_NR)", referencedColumnName="DEP_NR")),
#JoinColumnOrFormula(column=#JoinColumn(name="FORIGN_ELEMENT", referencedColumnName="GROUP_NAME")),
#JoinColumnOrFormula(column=#JoinColumn(name="STATE", referencedColumnName="STATE"))
})
private Car car;
}
I tried all available versions of hibernate (from 3.5.1 [first version with #JoinColumnsOrFormulas] up to 4.x.x), but I always get this error:
Exception in thread "main" java.lang.ClassCastException: org.hibernate.mapping.Formula cannot be cast to org.hibernate.mapping.Column
at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:351)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1338)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1597)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1355)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1788)
Other hibernate users seem to have the same problem: They can't get it working with any version, see this thread and other stackoverflow questions:
https://forum.hibernate.org/viewtopic.php?f=1&t=1010559
To be more complete, here's my TrimmedString Class:
https://forum.hibernate.org/viewtopic.php?p=2191674&sid=049b85950db50a8bd145f9dac49a5f6e#p2191674
Thanks in advance!
PS: It works with joining just these three colulmns with just one DEP-NR-Column (i.e. either DEP_NR OR USR_DEP_NR using just #JoinColumns). But I need this coalesce(nullif()).
I ran into a similar problem, and it seems that the issue is that you are using a #Formula inside an #Id. Hibernate wants Ids to be insertable, and Formulas are read-only.
In my case I was able to work around the problem by making the individual columns Id properties on their own, and making the joined object a separate property. I don't know if this would work in your case since you're using two different columns in your formula, but if so your code might look something like:
#Entity
#Table(name="CAR_TO_ELEMENT")
public class CarUserElement extends CarElement {
#Id
#Column(name="DEFINITION")
private char definition;
#Id
#Column(name="DEP_NR")
private Integer depNr;
#Id
#Column(name="USR_DEP_NR")
private Integer usrDepNr;
#Id
#Column(name="FORIGN_ELEMENT")
private String userName;
#Id
#Column(name="STATE")
private String state;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumnsOrFormulas(value = {
#JoinColumnOrFormula(formula=#JoinFormula(value="COALESCE(NULLIF(DEP_NR, 0), USR_DEP_NR)", referencedColumnName="DEP_NR")),
#JoinColumnOrFormula(column=#JoinColumn(name="FORIGN_ELEMENT", referencedColumnName="USER_NAME", insertable = false, updatable = false)),
#JoinColumnOrFormula(column=#JoinColumn(name="STATE", referencedColumnName="STATE", insertable = false, updatable = false))
})
private Car car;
}
Join formulas are very fragile in Hibernate for the time being; I always had a difficult time to get them work properly.
The workaround that helped me often was to create database views which exposed the proper columns (including foreign keys that don't exist in the original tables). Then I mapped the entities to the views using classing Hibernate/JPA mappings.
Sometimes there are redundant joins in the generated SQL when using such entities, but the database optimizes such queries in most cases so that the execution plan is optimal anyway.
Another approach could be using #Subselects, which are some kind of Hibernate views, but I expect them to be less performant than the classic database views.
I ran into the cast exception as well and I'm on Hibernate 5.x.
Until Hibernate dedicates time to fix the issue, I found that while this guy's approach may not be cleanest (he even eludes to that fact!), it works.
You just need to add the #Column mappings (and get/set methods) to your association table objects that are returning null and manually set the values when you populate the relation data. Simple but effective!
I have the following set of classes
#Embeddable
public class SharedClass {
...
private String legacyField;
...
}
#Entity
public class LongStandingEntity {
...
private SharedClass sharedClass;
...
}
Where legacyfield stores some obsolete data in older objects but is not collected for new ones. However I do need to able to continue to access the old data.
I'm creating a new entity that also makes use of SharedClass
#Entity
public class NewEntity {
...
private SharedClass sharedClass;
...
}
It doesn't need legacyField and I'd like to avoid having to add a column in the database for it whilst keeping the mapping working for LongStandingEntity.
Is this possible with JPA annotations?
I don't recall a particular annotation that can help you with that. Still I'd rather take a design approach with this situation. If you have field that belongs only to a certain class separate them in another embedabble class that's associated only with the older data.
Seems like a cleaner approach to me, just to keep entities clearly differenciated.
One workaround I have found is to override the association with the parameters insertable=false and updatable=false.
#Entity
public class NewEntity {
...
#Embedded
#AssociationOverride(name = "legacyField", joinColumns = #JoinColumn(insertable = false, updatable = false))
private SharedClass sharedClass;
...
}
I fixed the problem as following
#Entity
public class NewEntity {
...
#AttributeOverrides({
#AttributeOverride(name = "legacyField", column = #Column(insertable = false, updatable = false))
})
#Embedded
private SharedClass sharedClass;
...
}
UPDATE
but when reading entity I get the
ERROR: column new_entity_.legacyField does not exist at character 1504
so the problem is NOT fixed