How does java continue after an exception? - java

I've exams on Monday and was therefore doing some preparations. Now I made an exercise to see how exceptions are handled in java.
I've got the following code to analyse:
public class ExceptionsExercise {
private int x;
private class E1 extends Exception {
E1() {
super("exception E1");
}
}
private class E2 extends Exception {
E2() {
super("exception E2");
}
}
private class E3 extends Exception {
E3() {
super("exception E3");
}
}
public void run() throws E1, E3 {
try {
doA();
System.out.print("3 ");
} catch (E2 e) {
System.out.print("4 ");
} finally {
System.out.print("5 ");
}
System.out.print("6 ");
}
public void doA() throws E1, E2, E3 {
if (x == 1) {
throw new E1();
} else if (x == 2) {
throw new E2();
} else {
doB();
System.out.print("7 ");
}
}
public void doB() throws E3 {
if (x == 3) {
System.out.print("8 ");
throw new E3();
} else {
System.out.print("9 ");
}
}
public static void main(String[] args) {
Main thisInstance = new Main();
for (int i = 0; i < 4; i++) {
thisInstance.x = i;
System.out.println("");
System.out.print("x = " + i + " ");
try {
thisInstance.run();
} catch (E1 e) {
System.out.println("0");
} catch (E3 e) {
}
System.out.println("2 ");
}
}
}
The question now is what the output is. But with that I had some issues. For example, when an execption is catched in a method, does the method continue normal? Like in the method run() after catching exception e2.
The opposite situation is when a method doesn't catch an exception. Is then just the finally-block executed and then the method breaks. So that in in run() the System.out.print("6 "); is not executed?
Thank you very much

So first of all you can run your code to see the results.
when an execption is catched in a method, does the method continue normal?
Yes. I mean it will be continued farther. For example if doA() throws exception then run() method doesn't print '3'. (but it will prints '5'always because of finally
Is then just the finally-block executed and then the method breaks. So that in in run() the System.out.print("6 "); is not executed?
Finally block executes always after try block. Was exception or not.

Related

Pause in Java + end method

I wanted to say for a school project in Greenfoot, that if a rover encounters a system error, it should output this and then wait a short time and then terminate the current method. However, the pause is marked with the following error code: unreported exception java. lang. InterupptedException; must be cought or declared to be thrown, as I am very new to Java I have no idea what to change. Besides, he should then end the method, but with the current command the whole scenario is ended.
"
public Rover (String pname, char pfrequenz, int penergie)
{
energie = penergie;
name = pname;
temp = 15 ;
distance = 0;
systemcheck = true;
frequenz = pfrequenz ;
}
public void check()
{
if (markeVorhanden())
{
energie = energie + 100;
}
if (energie == 0){
systemcheck = false;
}
if (systemcheck = false){
nachricht("System Failure");
java.util.concurrent.TimeUnit.SECONDS.sleep(2);
System.exit(0);
}
if (distance > 100){
nachricht("Congrats you have passed 100");
}
anzeige.anzeigen("Akku: "+energie+ " %");
}
Try this
import java.io.*;
public class Yourclass{
public void Rover (String pname, char pfrequenz, int penergie)
{
Integer energie = penergie;
String name = pname;
Integer temp = 15 ;
Integer distance = 0;
boolean systemcheck = true;
char frequenz = pfrequenz ;
}
public void check() throws IOException
{
if (markeVorhanden())
{
energie = energie + 100;
}
if (energie == 0){
systemcheck = false;
}
if (systemcheck = false){
nachricht("System Failure");
throw new IOException("sorry device error");
}
if (distance > 100){
nachricht("Congrats you have passed 100");
}
anzeige.anzeigen("Akku: "+energie+ " %");
}
public static void main(String []args) throws InterruptedException
{
Yourclass demo= new Yourclass();
System.out.println("Hello World");
try{
demo.check();
}
catch(Exception e)
{
Thread.sleep(2000);
System.out.println("function stopped");
}
}
}
You will have to read up on exception handling in Java. The sleep method may get interrupted and may thus raise an InterruptedException. You can either forward this exception or ignore it.
To forward the exception, declare the function a
public void check() throws InterruptedException
but then callers of this function will have to deal with that potential exception. Since interrupted does not look a severe problem here (the sleep is just a bit shorter than the two seconds), it may be fine to ignore the exception:
try { java.util.concurrent.TimeUnit.SECONDS.sleep(2); }
catch (InterruptedException ignored) {}
In order to just return from the current method use return instead of System.exit()

Multiple Exceptions In java

There are 3 different types of outputs , randomly . Can someone explain why the outputs are these?
Out1 => "m1_1
m1_3
m1_4
m2_1
m2_3
m3_1
m3_3" Case Exception3.
Out2=>"m1_1
m2_2
m2_3
m3_1
m3_3" Case Exception2.
Out3=>"m1_1
m3_2
m3_3" Case Exception1.
Classes:
class Exception1 extends Exception {
}
class Exception2 extends Exception {
}
class Exception3 extends Exception {
}
public class C {
public void method1() throws Exception1, Exception2 {
try {
System.out.println(Math.random()+"\n");
System.out.println("m1_1");
//some code here that will randomly throw Exception1,2,or3
if (Math.random() <= 0.3) {
throw new Exception1();
}
if (Math.random() < 0.6) {
throw new Exception2();
}
if (Math.random() < 0.9) {
throw new Exception3();
}
System.out.println("m1_2");
} catch (Exception3 e3) {
System.out.println("m1_3");
}
System.out.println("m1_4");
}
public void method2() throws Exception1 {
try {
method1();
System.out.println("m2_1");
} catch (Exception2 e2) {
System.out.println("m2_2");
}
System.out.println("m2_3");
}
public void method3() {
try {
method2();
System.out.println("m3_1");
} catch (Exception1 e1) {
System.out.println("m3_2");
}
System.out.println("m3_3");
}
}
class Tester {
public static void main(String[] a) {
C c = new C();
c.method3();
}
}
Your two problems are that you have multiple calls of Math.random, and multiple ifs that fit one condition.
You would need to get 1 number from Math.random() and use that e.g:
double rand = Math.random();
Then, you would need to switch the overlapping ifs to else ifs, since if rand was 0.1 it would fit all 3 if conditions.
So in the end method1 should look something like this:
public void method1() throws Exception1, Exception2 {
try {
double rand = Math.random();
System.out.println(rand+"\n");
System.out.println("m1_1");
//some code here that will randomly throw Exception1,2,or3
if (rand <= 0.3) {
throw new Exception1();
}
else if (rand < 0.6) {
throw new Exception2();
}
else if (rand < 0.9) {
throw new Exception3();
}
System.out.println("m1_2");
} catch (Exception3 e3) {
System.out.println("m1_3");
}
System.out.println("m1_4");
}

Compilation error:Exception is never thrown in body of corresponding try statement

In my quest to learn Java better, I have been trying to understand exception handling. I cannot understand why the following code fails to compile.
The compiler message is:
TestExceptionHandling.java:12: error: exception StupidException is never thrown in body of corresponding try statement
catch (StupidException stupidEx) {
^
In the try block, method exTest.doExTest() is called. In this method I catch an InterruptedException and in its catch block I throw a new StupidException.
So why does the compiler say it's not thrown? What am I missing? Can any expert help me see my mistake please?
public class TestExceptionHandling {
public static void main(String argv[]) {
String output = "";
try {
output = "\nCalling method doExTest:\n";
exTest.doExTest();
}
catch (StupidException stupidEx) {
System.out.println("\nJust caught a StupidException:\n " + stupidEx.toString());
}
System.out.println(output);
}
}
class exTest {
static long mainThreadId;
protected static void doExTest() { //throws StupidException
mainThreadId = Thread.currentThread().getId();
Thread t = new Thread(){
public void run(){
System.out.println("Now in run method, going to waste time counting etc. then interrupt main thread.");
// Keep the cpu busy for a while, so other thread gets going...
for (int i = 0; i < Integer.MAX_VALUE; i++) {
int iBoxed = (int)new Integer(String.valueOf(i));
String s = new String("This is a string" + String.valueOf(iBoxed));
}
// find thread to interrupt...
Thread[] threads = new Thread[0];
Thread.enumerate(threads);
for (Thread h: threads) {
if (h.getId() == mainThreadId) {
h.interrupt();
}
}
}
};
t.start();
try {
Thread.sleep(5000);
}
catch (InterruptedException e){
System.out.println("\nAn InterruptedException " + e.toString() + " has occurred. Exiting...");
throw new StupidException("Got an InterruptedException ", e); // ("Got an InterruptedException. Mutated to StupidException and throwing from doExTest to caller...", e);
}
}
}
class StupidException extends Exception {
public StupidException(String message, Throwable t) {
super(message + " " + t.toString());
}
public String toString() {
return "Stupid Exception: " + super.toString();
}
}
Methods need to explicitly declare that they throw exceptions (with the exception of runtime exceptions, which are a bit different). Try declaring your doExTest method as
protected static void doExTest() throws StupidException {
...
}

unreported exception NegativeNumber; must be caught or declared to be thrown

I have two files:
NewtonRaphson
public class NewtonRaphson {
public double squareRoot ( double input ) throws NegativeNumber{
if (input < 0.0 ) { throw new NegativeNumber("not allowed to input a negative number");}
else if (input == 0.0) { return 0.0; }
else{
double current = 10.0;
for (int i = 0; i < 10; ++i) {
current = current - (current*current - input)/(2*current);
}
return current;
}
}
public static void main(String[] args){
NewtonRaphson nr = new NewtonRaphson();
System.out.println(nr.squareRoot(2.0));
}
}
and NegativeNumber
public class NegativeNumber extends Exception {
public NegativeNumber(String msg){
super(msg);
}
}
When I compile the first one I get:
NewtonRaphson.java:17: unreported exception NegativeNumber; must be caught or declared to be thrown
System.out.println(nr.squareRoot(2.0));
^
1 error
Could someone help me why?
You're throwing NegativeNumber, but never catching it. What kind of baseball is this?
Add a try-catch to your main method.
public static void main(String[] args){
NewtonRaphson nr = new NewtonRaphson();
try {
System.out.println(nr.squareRoot(2.0));
} catch (NegativeNumber e) {
System.out.println("Be more positive!");
}
}
Or if you never want to catch it (this is not advised):
public static void main(String[] args) throws NegativeNumber {
NewtonRaphson nr = new NewtonRaphson();
System.out.println(nr.squareRoot(2.0));
}
public static void main(String[] args){
try{
NewtonRaphson nr = new NewtonRaphson();
System.out.println(nr.squareRoot(2.0));
}
catch(NegativeNumber e)
{
System.out.println("Exception happend!");
}
}

How do you implement a re-try-catch?

Try-catch is meant to help in the exception handling. This means somehow that it will help our system to be more robust: try to recover from an unexpected event.
We suspect something might happen when executing and instruction (sending a message), so it gets enclosed in the try. If that something nearly unexpected happens, we can do something: we write the catch. I don't think we called to just log the exception. I thing the catch block is meant to give us the opportunity of recovering from the error.
Now, let's say we recover from the error because we could fix what was wrong. It could be super nice to do a re-try:
try{ some_instruction(); }
catch (NearlyUnexpectedException e){
fix_the_problem();
retry;
}
This would quickly fall in the eternal loop, but let's say that the fix_the_problem returns true, then we retry. Given that there is no such thing in Java, how would YOU solve this problem? What would be your best design code for solving this?
This is like a philosophical question, given that I already know what I'm asking for is not directly supported by Java.
You need to enclose your try-catch inside a while loop like this: -
int count = 0;
int maxTries = 3;
while(true) {
try {
// Some Code
// break out of loop, or return, on success
} catch (SomeException e) {
// handle exception
if (++count == maxTries) throw e;
}
}
I have taken count and maxTries to avoid running into an infinite loop, in case the exception keeps on occurring in your try block.
Obligatory "enterprisy" solution:
public abstract class Operation {
abstract public void doIt();
public void handleException(Exception cause) {
//default impl: do nothing, log the exception, etc.
}
}
public class OperationHelper {
public static void doWithRetry(int maxAttempts, Operation operation) {
for (int count = 0; count < maxAttempts; count++) {
try {
operation.doIt();
count = maxAttempts; //don't retry
} catch (Exception e) {
operation.handleException(e);
}
}
}
}
And to call:
OperationHelper.doWithRetry(5, new Operation() {
#Override public void doIt() {
//do some stuff
}
#Override public void handleException(Exception cause) {
//recover from the Exception
}
});
As usual, the best design depends on the particular circumstances. Usually though, I write something like:
for (int retries = 0;; retries++) {
try {
return doSomething();
} catch (SomeException e) {
if (retries < 6) {
continue;
} else {
throw e;
}
}
}
You can use AOP and Java annotations from jcabi-aspects (I'm a developer):
#RetryOnFailure(attempts = 3, delay = 5)
public String load(URL url) {
return url.openConnection().getContent();
}
You could also use #Loggable and #LogException annotations.
Although try/catch into while is well-known and good strategy I want to suggest you recursive call:
void retry(int i, int limit) {
try {
} catch (SomeException e) {
// handle exception
if (i >= limit) {
throw e; // variant: wrap the exception, e.g. throw new RuntimeException(e);
}
retry(i++, limit);
}
}
Spring AOP and annotation based solution:
Usage (#RetryOperation is our custom annotation for the job):
#RetryOperation(retryCount = 1, waitSeconds = 10)
boolean someMethod() throws Exception {
}
We'll need two things to accomplish this: 1. an annotation interface, and 2. a spring aspect. Here's one way to implement these:
The Annotation Interface:
import java.lang.annotation.*;
#Target(ElementType.METHOD)
#Retention(RetentionPolicy.RUNTIME)
public #interface RetryOperation {
int retryCount();
int waitSeconds();
}
The Spring Aspect:
import org.aspectj.lang.ProceedingJoinPoint;
import org.aspectj.lang.annotation.Around;
import org.aspectj.lang.annotation.Aspect;
import org.aspectj.lang.reflect.MethodSignature;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Component;
import java.lang.reflect.Method;
#Aspect #Component
public class RetryAspect {
private static final Logger LOGGER = LoggerFactory.getLogger(RetryAspect.class);
#Around(value = "#annotation(RetryOperation)")
public Object retryOperation(ProceedingJoinPoint joinPoint) throws Throwable {
Object response = null;
Method method = ((MethodSignature) joinPoint.getSignature()).getMethod();
RetryOperation annotation = method.getAnnotation(RetryOperation.class);
int retryCount = annotation.retryCount();
int waitSeconds = annotation.waitSeconds();
boolean successful = false;
do {
try {
response = joinPoint.proceed();
successful = true;
} catch (Exception ex) {
LOGGER.info("Operation failed, retries remaining: {}", retryCount);
retryCount--;
if (retryCount < 0) {
throw ex;
}
if (waitSeconds > 0) {
LOGGER.info("Waiting for {} second(s) before next retry", waitSeconds);
Thread.sleep(waitSeconds * 1000l);
}
}
} while (!successful);
return response;
}
}
Most of these answers are essentially the same. Mine is also, but this is the form I like
boolean completed = false;
Throwable lastException = null;
for (int tryCount=0; tryCount < config.MAX_SOME_OPERATION_RETRIES; tryCount++)
{
try {
completed = some_operation();
break;
}
catch (UnlikelyException e) {
lastException = e;
fix_the_problem();
}
}
if (!completed) {
reportError(lastException);
}
Use a while loop with local status flag. Initialize the flag as false and set it to true when operation is successful e.g. below:
boolean success = false;
while(!success){
try{
some_instruction();
success = true;
} catch (NearlyUnexpectedException e){
fix_the_problem();
}
}
This will keep retrying until its successful.
If you want to retry only certain number of times then use a counter as well:
boolean success = false;
int count = 0, MAX_TRIES = 10;
while(!success && count++ < MAX_TRIES){
try{
some_instruction();
success = true;
} catch (NearlyUnexpectedException e){
fix_the_problem();
}
}
if(!success){
//It wasn't successful after 10 retries
}
This will try max 10 times if not successful until then an will exit if its successful before hand.
This is an old question but a solution is still relevant. Here is my generic solution in Java 8 without using any third party library:
public interface RetryConsumer<T> {
T evaluate() throws Throwable;
}
public interface RetryPredicate<T> {
boolean shouldRetry(T t);
}
public class RetryOperation<T> {
private RetryConsumer<T> retryConsumer;
private int noOfRetry;
private int delayInterval;
private TimeUnit timeUnit;
private RetryPredicate<T> retryPredicate;
private List<Class<? extends Throwable>> exceptionList;
public static class OperationBuilder<T> {
private RetryConsumer<T> iRetryConsumer;
private int iNoOfRetry;
private int iDelayInterval;
private TimeUnit iTimeUnit;
private RetryPredicate<T> iRetryPredicate;
private Class<? extends Throwable>[] exceptionClasses;
private OperationBuilder() {
}
public OperationBuilder<T> retryConsumer(final RetryConsumer<T> retryConsumer) {
this.iRetryConsumer = retryConsumer;
return this;
}
public OperationBuilder<T> noOfRetry(final int noOfRetry) {
this.iNoOfRetry = noOfRetry;
return this;
}
public OperationBuilder<T> delayInterval(final int delayInterval, final TimeUnit timeUnit) {
this.iDelayInterval = delayInterval;
this.iTimeUnit = timeUnit;
return this;
}
public OperationBuilder<T> retryPredicate(final RetryPredicate<T> retryPredicate) {
this.iRetryPredicate = retryPredicate;
return this;
}
#SafeVarargs
public final OperationBuilder<T> retryOn(final Class<? extends Throwable>... exceptionClasses) {
this.exceptionClasses = exceptionClasses;
return this;
}
public RetryOperation<T> build() {
if (Objects.isNull(iRetryConsumer)) {
throw new RuntimeException("'#retryConsumer:RetryConsumer<T>' not set");
}
List<Class<? extends Throwable>> exceptionList = new ArrayList<>();
if (Objects.nonNull(exceptionClasses) && exceptionClasses.length > 0) {
exceptionList = Arrays.asList(exceptionClasses);
}
iNoOfRetry = iNoOfRetry == 0 ? 1 : 0;
iTimeUnit = Objects.isNull(iTimeUnit) ? TimeUnit.MILLISECONDS : iTimeUnit;
return new RetryOperation<>(iRetryConsumer, iNoOfRetry, iDelayInterval, iTimeUnit, iRetryPredicate, exceptionList);
}
}
public static <T> OperationBuilder<T> newBuilder() {
return new OperationBuilder<>();
}
private RetryOperation(RetryConsumer<T> retryConsumer, int noOfRetry, int delayInterval, TimeUnit timeUnit,
RetryPredicate<T> retryPredicate, List<Class<? extends Throwable>> exceptionList) {
this.retryConsumer = retryConsumer;
this.noOfRetry = noOfRetry;
this.delayInterval = delayInterval;
this.timeUnit = timeUnit;
this.retryPredicate = retryPredicate;
this.exceptionList = exceptionList;
}
public T retry() throws Throwable {
T result = null;
int retries = 0;
while (retries < noOfRetry) {
try {
result = retryConsumer.evaluate();
if (Objects.nonNull(retryPredicate)) {
boolean shouldItRetry = retryPredicate.shouldRetry(result);
if (shouldItRetry) {
retries = increaseRetryCountAndSleep(retries);
} else {
return result;
}
} else {
// no retry condition defined, no exception thrown. This is the desired result.
return result;
}
} catch (Throwable e) {
retries = handleException(retries, e);
}
}
return result;
}
private int handleException(int retries, Throwable e) throws Throwable {
if (exceptionList.contains(e.getClass()) || (exceptionList.isEmpty())) {
// exception is excepted, continue retry.
retries = increaseRetryCountAndSleep(retries);
if (retries == noOfRetry) {
// evaluation is throwing exception, no more retry left. Throw it.
throw e;
}
} else {
// unexpected exception, no retry required. Throw it.
throw e;
}
return retries;
}
private int increaseRetryCountAndSleep(int retries) {
retries++;
if (retries < noOfRetry && delayInterval > 0) {
try {
timeUnit.sleep(delayInterval);
} catch (InterruptedException ignore) {
Thread.currentThread().interrupt();
}
}
return retries;
}
}
Let's have a test case like:
#Test
public void withPredicateAndException() {
AtomicInteger integer = new AtomicInteger();
try {
Integer result = RetryOperation.<Integer>newBuilder()
.retryConsumer(() -> {
int i = integer.incrementAndGet();
if (i % 2 == 1) {
throw new NumberFormatException("Very odd exception");
} else {
return i;
}
})
.noOfRetry(10)
.delayInterval(10, TimeUnit.MILLISECONDS)
.retryPredicate(value -> value <= 6)
.retryOn(NumberFormatException.class, EOFException.class)
.build()
.retry();
Assert.assertEquals(8, result.intValue());
} catch (Throwable throwable) {
Assert.fail();
}
}
A simple way to solve the issue would be to wrap the try/catch in a while loop and maintain a count. This way you could prevent an infinite loop by checking a count against some other variable while maintaining a log of your failures. It isn't the most exquisite solution, but it would work.
In case it's useful, a couple more options to consider, all thrown together (stopfile instead of retries, sleep, continue larger loop) all possibly helpful.
bigLoop:
while(!stopFileExists()) {
try {
// do work
break;
}
catch (ExpectedExceptionType e) {
// could sleep in here, too.
// another option would be to "restart" some bigger loop, like
continue bigLoop;
}
// ... more work
}
If not all exceptions warrant a retry, only some. And if at least one try has to be made, Here is an alternative utility method:
void runWithRetry(Runnable runnable, Class<Exception> exClass, int maxRetries) {
Exception err = null;
do {
maxRetries--;
try {
runnable.run();
err = null;
} catch (Exception e) {
if(exClass.isAssignableFrom(e.getClass())){
err = e;
}else {
throw e;
}
}
} while (err != null && maxRetries > 0);
if (err != null) {
throw err;
}
}
Usage:
runWithRetry(() -> {
// do something
}, TimeoutException.class, 5)
All a Try-Catch does is allow your program to fail gracefully. In a catch statement, you generally try to log the error, and maybe roll back changes if you need to.
bool finished = false;
while(finished == false)
{
try
{
//your code here
finished = true
}
catch(exception ex)
{
log.error("there was an error, ex");
}
}
Use a do-while to design re-try block.
boolean successful = false;
int maxTries = 3;
do{
try {
something();
success = true;
} catch(Me ifUCan) {
maxTries--;
}
} while (!successful || maxTries > 0)
Here a reusable and more generic approach for Java 8+ that does not require external libraries:
public interface IUnreliable<T extends Exception>
{
void tryRun ( ) throws T;
}
public static <T extends Exception> void retry (int retryCount, IUnreliable<T> runnable) throws T {
for (int retries = 0;; retries++) {
try {
runnable.tryRun();
return;
} catch (Exception e) {
if (retries < retryCount) {
continue;
} else {
throw e;
}
}
}
}
Usage:
#Test
public void demo() throws IOException {
retry(3, () -> {
new File("/tmp/test.txt").createNewFile();
});
}
You can use https://github.com/bnsd55/RetryCatch
Example:
RetryCatch retryCatchSyncRunnable = new RetryCatch();
retryCatchSyncRunnable
// For infinite retry times, just remove this row
.retryCount(3)
// For retrying on all exceptions, just remove this row
.retryOn(ArithmeticException.class, IndexOutOfBoundsException.class)
.onSuccess(() -> System.out.println("Success, There is no result because this is a runnable."))
.onRetry((retryCount, e) -> System.out.println("Retry count: " + retryCount + ", Exception message: " + e.getMessage()))
.onFailure(e -> System.out.println("Failure: Exception message: " + e.getMessage()))
.run(new ExampleRunnable());
Instead of new ExampleRunnable() you can pass your own anonymous function.
Simplifying #ach's previous solution into one file and using functional interfaces.
public class OperationHelper {
public static void doWithRetry(int maxAttempts, Runnable operation, Consumer<Exception> handle) {
for (int count = 0; count < maxAttempts; count++) {
try {
operation.run();
count = maxAttempts; //don't retry
} catch (Exception e) {
handle.accept(e);
}
}
}
}
simple
int MAX = 3;
int count = 0;
while (true) {
try {
...
break;
} catch (Exception e) {
if (count++ < MAX) {
continue;
}
...
break;
}
}
https://onlinegdb.com/a-7RsL1Gh
public void doSomething() throws Exception{
final int MAX_TRIES = 10;
int count = 0;
while(count++ < MAX_TRIES){
try{
System.out.println("trying");
causeIssue(count); // throws error/exception till count 2
System.out.println("trying successful");
break; // break on success
} catch (Exception e){
System.out.println("caught, logging Exception:" + count);
} catch (Error e){
System.out.println("caught, logging Error:" + count);
}
}
}
Output:
trying
caught, logging Error:1
trying
caught, logging Error:2
trying
trying successful
I know there are already many similar answers here, and mine is not much different, but I will post it anyway because it deals with a specific case/issue.
When dealing with the facebook Graph API in PHP you sometimes get an error, but immediately re-trying the same thing will give a positive result (for various magical Internet reasons that are beyond the scope of this question). In this case there is no need to fix any error, but to simply try again because there was some kind of "facebook error".
This code is used immediately after creating a facebook session:
//try more than once because sometimes "facebook error"
$attempt = 3;
while($attempt-- > 0)
{
// To validate the session:
try
{
$facebook_session->validate();
$attempt = 0;
}
catch (Facebook\FacebookRequestException $ex)
{
// Session not valid, Graph API returned an exception with the reason.
if($attempt <= 0){ echo $ex->getMessage(); }
}
catch (\Exception $ex)
{
// Graph API returned info, but it may mismatch the current app or have expired.
if($attempt <= 0){ echo $ex->getMessage(); }
}
}
Also, by having the for loop count down to zero ($attempt--) it makes it pretty easy to change the number of attempts in the future.
following is my solution with very simple approach!
while (true) {
try {
/// Statement what may cause an error;
break;
} catch (Exception e) {
}
}
Im not sure if this is the "Professional" way to do it and i'm not entirely sure if it works for everything.
boolean gotError = false;
do {
try {
// Code You're Trying
} catch ( FileNotFoundException ex ) {
// Exception
gotError = true;
}
} while ( gotError = true );
https://github.com/tusharmndr/retry-function-wrapper/tree/master/src/main/java/io
int MAX_RETRY = 3;
RetryUtil.<Boolean>retry(MAX_RETRY,() -> {
//Function to retry
return true;
});
The issue with the remaining solutions is that, the correspondent function tries continuously without a time interval in-between, thus over flooding the stack.
Why not just trying only every second and ad eternum?
Here a solution using setTimeout and a recursive function:
(function(){
try{
Run(); //tries for the 1st time, but Run() as function is not yet defined
}
catch(e){
(function retry(){
setTimeout(function(){
try{
console.log("trying...");
Run();
console.log("success!");
}
catch(e){
retry(); //calls recursively
}
}, 1000); //tries every second
}());
}
})();
//after 5 seconds, defines Run as a global function
var Run;
setTimeout(function(){
Run = function(){};
}, 5000);
Replace the function Run() by the function or code that you'd like to retry every second.
Give it a try using springs #Retryable annotation , the below method will retry for 3 attempts when RuntimeException occurs
#Retryable(maxAttempts=3,value= {RuntimeException.class},backoff = #Backoff(delay = 500))
public void checkSpringRetry(String str) {
if(StringUtils.equalsIgnoreCase(str, "R")) {
LOGGER.info("Inside retry.....!!");
throw new RuntimeException();
}
}
Below snippet execute some code snippet. If you got any error while executing the code snippet, sleep for M milliseconds and retry. Reference link.
public void retryAndExecuteErrorProneCode(int noOfTimesToRetry, CodeSnippet codeSnippet, int sleepTimeInMillis)
throws InterruptedException {
int currentExecutionCount = 0;
boolean codeExecuted = false;
while (currentExecutionCount < noOfTimesToRetry) {
try {
codeSnippet.errorProneCode();
System.out.println("Code executed successfully!!!!");
codeExecuted = true;
break;
} catch (Exception e) {
// Retry after 100 milliseconds
TimeUnit.MILLISECONDS.sleep(sleepTimeInMillis);
System.out.println(e.getMessage());
} finally {
currentExecutionCount++;
}
}
if (!codeExecuted)
throw new RuntimeException("Can't execute the code within given retries : " + noOfTimesToRetry);
}
Here is my solution similar to some others can wrap a function, but allows you to get the functions return value, if it suceeds.
/**
* Wraps a function with retry logic allowing exceptions to be caught and retires made.
*
* #param function the function to retry
* #param maxRetries maximum number of retires before failing
* #param delay time to wait between each retry
* #param allowedExceptionTypes exception types where if caught a retry will be performed
* #param <V> return type of the function
* #return the value returned by the function if successful
* #throws Exception Either an unexpected exception from the function or a {#link RuntimeException} if maxRetries is exceeded
*/
#SafeVarargs
public static <V> V runWithRetriesAndDelay(Callable<V> function, int maxRetries, Duration delay, Class<? extends Exception>... allowedExceptionTypes) throws Exception {
final Set<Class<? extends Exception>> exceptions = new HashSet<>(Arrays.asList(allowedExceptionTypes));
for(int i = 1; i <= maxRetries; i++) {
try {
return function.call();
} catch (Exception e) {
if(exceptions.contains(e.getClass())){
// An exception of an expected type
System.out.println("Attempt [" + i + "/" + maxRetries + "] Caught exception [" + e.getClass() + "]");
// Pause for the delay time
Thread.sleep(delay.toMillis());
}else {
// An unexpected exception type
throw e;
}
}
}
throw new RuntimeException(maxRetries + " retries exceeded");
}
This Solution allows you to configure a reusable functionality for retrying based on certain exception without using any external libraries
// Create a Function that suits your need .
#FunctionalInterface
public interface ThrowableBiFunction<U,T,R> {
R apply(U u ,T t) throws Exception;
}
//Here's the crux of the solution
public interface ExceptionRetryable<T, U, R> {
int getRetries();
List<Class<? extends Exception>> getRetryableExceptions();
default R execute(ThrowableBiFunction<T, U, R> function, T t, U u) throws Exception {
int numberOfRetries = getRetries();
return execute(function, t, u, numberOfRetries);
}
default R execute(ThrowableBiFunction<T, U, R> function, T t, U u, int retryCount) throws Exception {
try {
log.info(" Attempting to execute ExceptionRetryable#execute ,Number of remaining retries {} ",retryCount);
return function.apply(t, u);
} catch (Exception e) {
log.info(" error occurred in ExceptionRetryable#execute",e);
if (retryCount == 0)
throw e;
for (Class exp : getRetryableExceptions()) {
if (e.getClass() == exp) {
return execute(function, t, u, retryCount - 1);
}
}
throw e;
}
}
}
// create an implementation for exception retryable
public class TestRetryable implements ExceptionRetryable<String, String, List<String>> {
#Override
public int getRetries() {
return 10;
}
#Override
public List<Class<? extends Exception>> getRetryableExceptions() {
return Arrays.asList(new Exception1().getClass(), new Exception2().getClass());
;
}
}
// Finally create a ThrowableBiFunction that encapsulates that piece of code that needs to be retried on exception and an instance of ExceptionRetryable
TestRetryable retryable = new TestRetryable();
ThrowableBiFunction<Integer,Long, String> testRetrablefcn = { i, l ->
// your code goes here
};
Integer i = 0;
Long l = 1l;
String output = testRetrablefcn.execute(testRetrablefcn,i,l);
Production ready code:
#FunctionalInterface
public interface Operation {
void doCall() throws IOException;
default void handleException(Exception e) {
//Your custom default implementation
}
public class OperationHelper {
public static void doWithRetry(int maxAttempts, Operation operation) {
for (int count = 0; count <= maxAttempts; count++) {
try {
operation.doCall();
return;
} catch (Exception e) {
if (count == maxAttempts) {
e.printStackTrace();
return;
} else {
operation.handleException(e);
}
}
}
}
}
Usage with default implementation in code:
OperationHelper.doWithRetry(10,
() -> //do your job );
Usage when custom exception handle is needed:
OperationHelper.doWithRetry(10, new Operation() {
#Override public void doIt() {
//do some stuff
}
#Override public void handleException(Exception cause) {
//recover from the Exception
}
});

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