According to this blog post from December 2017, it is possible to change the name used to search for Spring Boot configuration files programmatically like this:
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.builder.SpringApplicationBuilder;
#SpringBootApplication
public class Application {
public static void main(String[] args) {
new SpringApplicationBuilder(Application.class)
.properties("spring.config.name:conf")
.build()
.run(args);
}
}
I have tried this using Spring Boot version 1.5.9-RELEASE, but this does not work. Setting spring.config.name as an argument does work:
mvn spring-boot:run -Dspring.config.name=conf
However, I do not have control over the arguments passed to my Spring Boot application when it is started so this is not an option.
Is it no longer possible to set spring.config.name programmatically, am I missing something, or is this a bug?
Doesn't directly answer the question, but I eventually discovered a workaround. Setting the spring.config.name by adding it to the arguments does work:
package com.ups.cep;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
#SpringBootApplication
public class Application {
public static void main(String[] args) {
List<String> arguments = new ArrayList<>(Arrays.asList(args));
arguments.add("-Dspring.config.name=conf");
SpringApplication.run(Application.class, arguments.toArray(new String[arguments.size()]));
}
}
Your example works for me (Spring Boot 2.4.3) so it could be bug at that time.
A similar SO answer also uses SpringApplicationBuilder.properties(String... defaultProperties) to define configuration name.
new SpringApplicationBuilder(Application.class)
.properties("spring.config.name:conf")
.build()
.run(args);
I checked both spring.config.name=conf and spring.config.name:conf and they work.
Related
I have a spring boot application I'm building, and at the start, I need to check some system files and prepare some database pools using the information the app finds there. Normally, I'd include this in the main method of the #SpringBootApplication annotated class, however, when I deploy my app as a WAR file to an external Tomcat server, that main class doesn't seem to run. I've checked around at what you're supposed to have in that main class, and my main application class now looks like this:
package com.companyname.projectname;
import com.companyname.projectname.database.DatabasePoolManager;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.builder.SpringApplicationBuilder;
import org.springframework.boot.web.servlet.support.SpringBootServletInitializer;
import org.springframework.context.ApplicationContext;
#SpringBootApplication
public class WebApplication extends SpringBootServletInitializer {
private static final Logger logger = LoggerFactory.getLogger(WebApplication.class);
public static void main(String[] args) {
ApplicationContext applicationContext = SpringApplication.run(WebApplication.class, args);
DatabasePoolManager dpm = applicationContext.getBean(DatabasePoolManager.class);
dpm.setUpPools();
logger.error("\n\nIS ANYBODY OUT THERE?\n\n");
}
#Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder builder) {
logger.error("\n\nIS ANYBODY OUT THERE? (But in the configure method)\n\n");
return builder.sources(WebApplication.class);
}
}
This is different than my original setup because of the extends and override of configure.
So far, this still runs fine with my Intellij IDE, but once moved and deployed to the tomcat server, none of the log messages appear. The app still works, but is clearly missing some setup that grants it's functionality (connections to databases). How would I go about running some setup code on the application start, when I deploy this app as a WAR file?
Thanks again to M. Deinum in the comments above, to run once on startup, I used this new class shown below:
package com.companyname.projectname;
import com.companyname.projectname.database.DatabasePoolManager;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.ApplicationArguments;
import org.springframework.boot.ApplicationRunner;
import org.springframework.context.ApplicationContext;
import org.springframework.stereotype.Component;
#Component
public class AppStartupRunner implements ApplicationRunner {
#Autowired
ApplicationContext applicationContext;
private static final Logger logger = LoggerFactory.getLogger(AppStartupRunner.class);
#Override
public void run(ApplicationArguments args) throws Exception {
DatabasePoolManager dpm = applicationContext.getBean(DatabasePoolManager.class);
dpm.setUpPools();
}
}
I have a new springboot application I am attempting to get started.
The error I receive is
org.springframework.context.ApplicationContextException: Unable to start reactive web server; nested exception is org.springframework.context.ApplicationContextException: Unable to start ReactiveWebApplicationContext due to missing ReactiveWebServerFactory bean.
at org.springframework.boot.web.reactive.context.ReactiveWebServerApplicationContext.onRefresh(ReactiveWebServerApplicationContext.java:76) ~[spring-boot-2.0.1.RELEASE.jar:2.0.1.RELEASE]
src/main/java/bubbleshadow/RootController.java
package bubbleshadow;
import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RestController;
import reactor.core.publisher.Mono;
#RestController
public class RootController {
public RootController() {
}
#GetMapping("/")
public Mono<HttpStatus> returnOk() {
return Mono.just(HttpStatus.OK);
}
}
src/test/java/test/bubbleshadow/RootControllerTest.java
package test.bubbleshadow;
import bubbleshadow.RootController;
import org.junit.jupiter.api.Test;
import org.junit.jupiter.api.extension.ExtendWith;
import org.springframework.beans.factory.annotation.Autowired;
// import org.springframework.boot.test.autoconfigure.web.reactive.WebFluxTest;
import org.springframework.boot.test.autoconfigure.web.reactive.AutoConfigureWebTestClient;
import org.springframework.test.web.reactive.server.WebTestClient;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit.jupiter.SpringExtension;
import org.springframework.boot.test.context.SpringBootTest.WebEnvironment;
#ExtendWith(SpringExtension.class)
#SpringBootTest(classes=RootController.class, webEnvironment = WebEnvironment.RANDOM_PORT)
#AutoConfigureWebTestClient
public class RootControllerTest {
#Autowired
WebTestClient webTestClient;
#Test
public void baseRouteShouldReturnStatusOK() {
webTestClient.head().uri("/").exchange().expectStatus().isOk();
}
}
Your configuration is not sufficient for reactive tests.
The reactive WebTestClient as well as ReactiveWebApplicationContext need reactive server in the application context. Add annotation #EnableAutoConfiguration to your RootControllerTest and let Spring's do it for you.
The autoconfiguration searches your class path and after find reactive classes and reactive context then create ReactiveWebServerFactory bean.
I assume you are using maven to get your dependencies.
I solved the problem by using:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-webflux</artifactId>
<version>2.0.3.RELEASE</version>
</dependency>
Instead of:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webflux</artifactId>
<version>5.0.7.RELEASE</version>
</dependency>
For me, the error was being caused by a missing #SpringBootApplication annotation on the Spring class containing the main() method entry point which actually starts the Boot application. Using the following resolved the error:
#SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
Likely a corrupt download. Try removing ~/.m2/repository.
You actually just need to change webEnvironment = WebEnvironment.RANDOM_PORT to webEnvironment = WebEnvironment.MOCK in your #SpringBootTest annotation.
#vdou's answer helped me to resolve my issue.
In addition to adding #EnableAutoConfiguration, I also had to manually add the spring application type:
spring:
main:
web-application-type: reactive
There is obviously something in my dependencies that is causing Spring not to be able to discover the type.
I hope this helps somebody...
If you are using Kotlin, check if in your Application class that contains the main method, doesnt have this:
runApplication<Application>{
webApplicationType = WebApplicationType.REACTIVE
}
Then change the "REACTIVE" to "SERVELET", will work like a charm.
If None of the above solutions work, try adding
#ContextConfiguration(loader = AnnotationConfigContextLoader.class)
It may help you
import org.springframework.test.context.support.AnnotationConfigContextLoader;
Yet another reason this can occur is if you're importing in a configuration class for your test that is not marked with #TestConfiguration annotation
How do I configure the use of a properties file using Java DSL and the Main object?
According to this page I should be able to call something like:
main.setPropertyPlaceholderLocations("example.properties");
However that simply doesn't work. It seems that option wasn't added until Camel 2.18 and I'm running 2.17.1.
What was the original way to set a properties file to use when letting the application run in a standalone form?
Some backstory:
I'm trying to convert from Spring to Java DSL. During that conversion I was attempting to have my Camel application run on its own. I know that is achieved using main.run();.
I had things "functioning" when using the CamelContext, but that cannot run on its own. So I know using the following will work in that case:
PropertiesComponent pc = new PropertiesComponent();
pc.setLocation("classpath:/myProperties.properties");
context.addComponent("properties", pc);
Is there some way I can tell the main to use that setup? Or is there something else needed?
You can use the following snippet:
PropertiesComponent pc = new PropertiesComponent();
pc.setLocation("classpath:/myProperties.properties");
main.getCamelContexts().get(0).addComponent("properties", pc);
Also, if you are using camel-spring, you could use org.apache.camel.spring.Main class, it should use the property placeholder from your application context.
Since you are mentioning you are in the process to move from Spring XML to Java Config here's a minimum application that is using properties and injecting it into a Camel route (it's really properties management in Spring injected into our Camel route bean):
my.properties:
something=hey!
Main class:
package camelspringjavaconfig;
import org.apache.camel.spring.javaconfig.CamelConfiguration;
import org.apache.camel.spring.javaconfig.Main;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.annotation.PropertySource;
#Configuration
#ComponentScan("camelspringjavaconfig")
#PropertySource("classpath:my.properties")
public class MyApplication extends CamelConfiguration {
public static void main(String... args) throws Exception {
Main main = new Main();
main.setConfigClass(MyApplication.class); // <-- passing to the Camel Main the class serving as our #Configuration context
main.run(); // <-- never teminates
}
}
MyRoute class:
package camelspringjavaconfig;
import org.apache.camel.builder.RouteBuilder;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.core.env.Environment;
import org.springframework.stereotype.Component;
#Component
public class MyRoute extends RouteBuilder {
#Autowired
Environment env; //<-- we are wiring the Spring Env
#Override
public void configure() throws Exception {
System.out.println(env.getProperty("something")); //<-- so that we can extract our property
from("file://target/inbox")
.to("file://target/outbox");
}
}
I am converting an existing Java application to Spring Boot.
I'm a Spring Boot newbie. I know Spring Boot has support for application.properties, which is great for new apps. But this is a legacy app and I need an interim solution for now - without completely redesigning it. This app needs to call some initializer with a property file on startup. There is prod.properties and another one for tests - test.properties.
the prod file needs to be loaded from a specific location on disk (/mydir/prod.properties), while test.properties comes from tests' classpath.
also, may legacy classes require this "property class" to be initialized on their creation (they reference it in their static initializers, oh geez...) - so this init needs to happen before Spring Components are loaded.
what would be the easiest solution?
I came up with this overly-verbose-boiler-plate solution. it works, but maybe there is an easier way?
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import javax.inject.Inject;
#SpringBootApplication
public class DemoApplication implements CommandLineRunner {
#Inject
private Initializer initializer;
public static void main(String[] args) {
SpringApplication.run(DemoApplication.class, args);
}
#Override
public void run(String... args) throws Exception {
initializer.init();
}
}
public interface Initializer {
void init();
}
#Component
public class ProdInitializer implements Initializer {
#Override
public void init() {
System.out.println("PROD init - will load properties file from /myfolder/ and call some init class with it");
}
}
// and this is from TESTS section:
import org.springframework.context.annotation.Primary;
import org.springframework.stereotype.Component;
#Primary
#Component
public class TestInitializer implements Initializer {
#Override
public void init() {
System.out.println("TEST init - will load properties file from classpath and call some init class with it");
}
}
I tried having just one initializer with an additional test/resources/application.properties file with just 1 value in it (legacy property file location) hoping that Spring Boot would load application.properties from PROD code, then load the only value present in test/resources/application.properties and override the corresponding value in main/resources/application.properties, but no luck - apparently, Spring Boot ignores main/resources/application.properties for tests if test/resources/application.properties is present. so I would have to duplicate all settings from main/resources/application.properties in test/resources/application.properties with just one property being different.
I have the following class:
package hello;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.SpringApplication;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.stereotype.Component;
#Component
#EnableAutoConfiguration
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
If I reference it in my main camel route, like so:
package com.example.integration;
import hello.*;
import org.apache.camel.ProducerTemplate;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class TestCamelSpring {
public static void main(String[] args) {
ApplicationContext context = new ClassPathXmlApplicationContext("camelspring.xml");
ProducerTemplate camelTemplate = context.getBean("camelTemplate", ProducerTemplate.class);
Application.main(args);
System.out.println("Message Sending started");
camelTemplate.sendBody("jms:queue:testQSource","Sample Message");
System.out.println("Message sent");
}
}
Do my annotations in Application.class still get accessed even though I only reference Application.main?
I ask because the #EnableAutoConfiguration is supposed to configure the application for Tomcat, but now that I am not running Application.class directly, the application is defaulting to jetty and then I get an error that WebSockets are only supported in Tomcat.
Has anyone had this issue before or know how to solve it?
Here is the stack trace. I can see from the console log that it never starts the Tomcat instance that it does when the whole class is accessed in the example. It seems to be continuing as if it is a jetty app rather than Tomcat. Please correct me if any of these assumptions are wrong:
Caused by: java.lang.IllegalStateException: Websockets are currently only supported in Tomcat (found class org.springframework.boot.context.embedded.jetty.JettyEmbeddedServletContainerFactory).
at org.springframework.boot.autoconfigure.websocket.WebSocketAutoConfiguration$1.customize(WebSocketAutoConfiguration.java:74)
at org.springframework.boot.context.embedded.EmbeddedServletContainerCustomizerBeanPostProcessor.postProcessBeforeInitialization(EmbeddedServletContainerCustomizerBeanPostProcessor.java:67)
at org.springframework.boot.context.embedded.EmbeddedServletContainerCustomizerBeanPostProcessor.postProcessBeforeInitialization(EmbeddedServletContainerCustomizerBeanPostProcessor.java:54)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyBeanPostProcessorsBeforeInitialization(AbstractAutowireCapableBeanFactory.java:407)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1545)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:539)
... 16 more
First of all, annotations cannot be "called".
Annotations are data, not code. In your case Spring Boot reads your annotations when you call SpringApplication.run(Application.class, args); and performs necessary configurations, therefore it doesn't matter how you call Application.main().
I guess your problem is caused by the fact that you have Jetty in the classpath, and it forces Spring Boot to use Jetty rather than Tomcat as embedded servlet container.
So, try to do the following:
Find out how Jetty appeared in your classpath
Use mvn dependency:tree -Dverbose if you use Maven
If you don't need Jetty in the classpath, exclude it from dependencies
Otherwise, you need to force Spring Boot to ignore presence of Jetty
Something like exclude = EmbeddedServletContainerAutoConfiguration.EmbeddedJetty.class in #EnableAutoConfiguration may help