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Where i Can find text file created by servlet in Eclipse

This may be a stupid question, but I have to ask because I couldn't find any proper solution.
I am new to Eclipse. I created a Dynamic Web project in Eclipse, In this, I write a simple code to create a text file, Only file name is specified Not the path that where to create, After successful execution, i could not find my text file in my project folder.
If path is specified in the code, I can find the text file in specified directory, My Question is where i can find my text file if i am not specify a path ?
And my code is
try {
FileWriter outFile = new FileWriter("user_details.txt", true);
PrintWriter out1 = new PrintWriter(outFile);
out1.append(request.getParameter("un"));
out1.println();
out1.append(request.getParameter("pw"));
out1.close();
outFile.close();
System.out.println("file created");
} catch(Exception e) {
System.out.println("error in writing a file"+e);
}
I edited my code with following lines,
String path = new File("user_details.txt").getAbsolutePath();
System.out.println(path);
The path that i got is below
D:\Android\eclipse_JE\eclipse\user_details.txt
Why i got it in the eclipse folder ?
Then,
How can i create a text file in my web app, if this is not the right way to create a textfile ?

The file is located in the actual working directory of your application server. Do a
System.out.println(new File("").getAbsolutPath());
and you'll find the location.
However this is not a good idea to write files in web application like this, because first you never know where it is and second you never know whether you write privilege on it.
You need to specify some filesystem root for your application by passing it as init-parameter and use it as parent for everything you need to do on the filesystem. Check this answer to a similar Question.
You could then create your file like this:
String fsroot = getServletContext().getInitParameter("fsroot")
File ud = new File(fsroot, "user_details.txt");
FileWriter outFile = new FileWriter(ud, true);

You may try the getAbsolutePath() method.
String newFile = new File("Demo.txt").getAbsolutePath();
It will show the location where the files will be created.

previous file deletion process

I am stuck up in a odd situation that is I am creating a file in a folder but I need to make sure that before the creation of a file if any file is there in the folder then it must be deleted only the current file which is process should be there.
since in my application every day a job runs which create the file in that folder so when ever presently job is running it should delete previous day file and no file should be there in afolder but the code that is shown below creates the file in that folder but the issue is that previous day file or if the job run multiple time on the same day also then those files are also thhere in the folder which should be deleted please advise how to achieve this..
File file = new File(FilePath + s); //path is c:\\abc folder & s is file name fgty.dat file
if (file.exists()) {
file.delete();
}
file.createNewFile();
Please advise

In your place I'd move the directory to a different name, say abc.OLD, recreate it and then create your file. If everything goes well, at the end you can remove the ols directory.
If different instances of your program could be running at the same time you need to implement some form of synchronization. A rather simplistic approach could be to check if the abc.OLD directory exists and abort execution if it does.

Without seeing more of your code, it sounds like you just need to empty the folder before opening a new file, since right now you're only deleting the file with the exact name that you're going to write. Use the list method of file objects.
File newFile = new File(FilePath + s);
for (File f : new File(FilePath).listFiles()) { // For each file in the directory, delete it.
f.delete();
}
newFile.createNewFile();
Note that this won't work if your folder contains other non-empty directories; you'll need a more robust solution. But the code above will at least delete all the files in the folder (barring Exceptions obviously) before creating the new file.
If, as you mentioned in the comments, you only want to delete *.dat files, it's as simple as putting a check in before you delete anything.
for (File f : new File(FilePath).listFiles()) { // For each file in the directory, delete it.
if (f.getName().endsWith(".dat")) { // Only delete .dat files
f.delete();
}
}

File file = new File(FilePath+"test.txt");
File folder = new File(FilePath);
File[] listOfFiles = folder.listFiles();
for(int i = 0; i < listOfFiles.length; i++) {
if (listOfFiles[i].isFile()) {
System.out.println("File " + listOfFiles[i].getName());
listOfFiles[i].delete();
}
}
try {
file.createNewFile();
} catch (IOException e) {
e.printStackTrace(); //To change body of catch statement use File | Settings | File Templates.
}

First I think you can have problems with the way you instanciate your Fileobject because if you don't have your path separator (\), you will try to create c:\abcfgty.dat instead of c:\abc\fgty.dat.
Use instead :
File file = new File(filePath, s);
Then you can delete the files ending by ".dat". As I understood, you don't need to delete sub directories. (Here is a link that tells you how. See also here)
for (File f : filePath.list()) { // For each file in the directory, delete it.
if(f.isFile() && file.getName().toLowerCase().endsWith(".dat");){
f.delete();
}
}
try {
file.createNewFile();
} catch (IOException ex) {
//Please do something here, at leat ex.printStackTrace()
}
Note that we can use a FileFilter to select the files to delete.
EDIT
As it was suggested in other answers, it might be preferable to move or rename the existing files instead of deleting them directly.

Create Directory along with file using file stream in java

I have a String like this "D:/Data/files/store/file.txt" now I want to check ,is directory is already exist or not, if not I want to create directory along with text file. I have tried mkdirs() but its creating directory like this data->files->store->file.txt. means its creates file.txt as folder, not a file. can any one kindly help me to do this. thanks in advance.

You need to run mkdirs() on parent directory, not the file itself
File file = new File("D:/Data/files/store/file.txt");
file.getParentFile().mkdirs();
try {
file.createNewFile();
} catch (IOException e) {
e.printStackTrace();
}

Here you go...
boolean b = (new File("D:/Data/files/store/file.txt").getParentFile()).mkdirs();

Java, create a file and a folder

I am creating files with Java in Windows. This works:
String newFile = "c:/"+Utilities.timeFormat();
...
some code that creates a folder
This does not work:
String newFile = "c:/newDirectory/"+Utilities.timeFormat();
...
some code that creates a folder

You have to use File.mkdir() or File.mkdirs() method to create a folder.
EDIT:
String path="c:/newDirectory";
File file=new File(path);
if(!file.exists())
file.mkdirs(); // or file.mkdir()
file=new File(path + "/" + Utilities.timeFormat());
if(file.createNewFile())
{
}

without knowing your actual code which is creating the directory:
use mkdirs() instead of mkdir()

Can you check that you have permissions to create a folder in c:/?
Can you show us the stacktrace too?

If "newDirectory" doesn't exist yet, you should use the method mkdirs() from the File class to create all the directories in between.

The fact that the directory doesn't exist is probably why it isn't working he first time through. As many have pointed out use mkdirs() will ensure if the file you want to write is in subfolders it will create them. Now here is what it might look like:
File file = new File( new File("c:/newDirectory"), Utilities.timeFormat() );
if( !file.getParentFile().exists() ) {
file.getParentFile().mkdirs();
}
OutputStream stream = new BufferedOutputStream( new FileOutputStream( file ) );
try {
// put your code here to write the file
} finally {
stream.close();
}
Notice I'm not using + to create a path. Instead I create a File object, and pass it the parent File and the name of the file. Also notice I'm not putting path separators in between the parent and filename. Using the File constructor takes care of a system independent way of creating paths.

zip a folder structure using java

I am trying to zip the following file structure on my machine,
parent/
parent/test1
parent/test1/image1.jpeg
parent/test2
The problem here is i cant zip the above file structure using java. I have google and found following code sample but it only zip the files only inside a given folder.
File inFolder=new File("out");
File outFolder=new File("Out.zip");
ZipOutputStream out = new ZipOutputStream(new
BufferedOutputStream(new FileOutputStream(outFolder)));
BufferedInputStream in = null;
byte[] data = new byte[1000];
String files[] = inFolder.list();
for (int i=0; i<files.length; i++)
{
in = new BufferedInputStream(new FileInputStream
(inFolder.getPath() + "/" + files[i]), 1000);
out.putNextEntry(new ZipEntry(files[i]));
int count;
while((count = in.read(data,0,1000)) != -1)
{
out.write(data, 0, count);
}
out.closeEntry();
}
out.flush();
out.close();
In the above code the out is a folder and we need to have some files..also folder cannot be empty if so it throws a exception java.util.zip.ZipException or cant contain any sub folders even files inside it (eg:out\newfolder\image.jpeg) if so it throws a java.io.FileNotFoundException: out\newfolder (Access is denied).
In my case im costructig the above file structure by quering the database sometime empty folders along the folder structure can be have.
Can some one please tell me a solution?
Thank You.

What is probably happening is that you're trying to treat every entry as a FileInputStream. However, for a directory, this is not true. Since the path is not to a file, when you try to read it, a FileNotFoundException is thrown. For directories, you still want to create the ZipEntry, but instead of trying to read in any data, just skip it and move on to the next path.

write two methods. The first one takes dirpath, makes a zip stream and calls another method which copies files to the zip stream and calls itself recursively for directories as below:
open an entry in the zip stream for the given directory
list files and dirs in the given directory, loop through them
if an entry is a file, open an entry, copy file content to the entry, close it
if an entry is a directory, call this method. Pass the zip stream
close the entry.
The first method closes the zip stream.