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Receiving payload request and displaying it on a webpage using spring

First of all I'm new to Spring and tried my best to get this working. So this is my question.
I have a spring MVC project which is supposed to receive a request payload (JSON request) and display the payload body on a webpage. Please see my project content and the controller class below
#Controller
public class CallbackPayloadController {
public CallbackPayloadController() {
System.out.println("In controller class!!!!");
}
#RequestMapping(value = "/requestreceiver", consumes = "application/json", method = RequestMethod.POST)
public void receivePayload(#RequestBody String payload) {
System.out.println("In the controller method....");
System.out.println("Payload is : " + payload);
}
}
Now if I do a POST to http://localhost:8080/PayloadReceiver/requestreceiver/ using POSTMAN it says HTTP STATUS 404. My Json content that I am posting is
{
"key":"123"
}
My web.xml is as follows
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>PayloadReceiver</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>requestreceiver</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>requestreceiver</servlet-name>
<url-pattern>/requestreceiver.jsp</url-pattern>
<url-pattern>/requestreceiver.html</url-pattern>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
</web-app>
Second question is if I successfully receive the payload, how do I display the payload content on a new webpage?

Try to add the return statement to your method like this:
#RequestMapping(value = "/requestreceiver",consumes="...",method = RequestMethod.POST)
public String receivePayload(...)
...
return "requestreceiver";

jaxrs - Unable to call the webservice : 404 Not Found Error

I have created a simple webservice but I am unable to call it. I get 404 Not found error.
package com.fms.mdw.rest;
#Path("/Search")
public class SearchWebService {
#POST
#Path("/searchData")
#Consumes(MediaType.APPLICATION_JSON)
#Produces("application/json")
public FMSResponseInfo getSearchData(SearchDTO searchDTO) {
System.out.println("Entered the getSearchData()");
FMSResponseInfo fmsResponseInfo = new FMSResponseInfo();
List<SearchDetailsDTO> searchDetailsDtoList = new ArrayList<>();
for (int i = 0; i < 5; i++) {
SearchDetailsDTO searchDetailsDto = new SearchDetailsDTO();
searchDetailsDto.setBarcode("barcode" + i);
searchDetailsDto.setDocNo("docNo" + i);
searchDetailsDto.setDocType("docType" + i);
searchDetailsDtoList.add(searchDetailsDto);
}
fmsResponseInfo.setStatus("200");
fmsResponseInfo.setMessage("Success");
fmsResponseInfo.setData(searchDetailsDtoList);
System.out.println("Leaving the getSearchData()");
return fmsResponseInfo;
}
}
SearchDTO has two fields searchType, searchText both of type string.So the json payload will be {"searchType":"", "searchText":""}
I have registered the webservice in the following manner in web.xml :
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>LatestFMS</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>LatestFMS Web Application</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.fms.mdw.rest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>LatestFMS Web Application</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
I am able to access the webpages, but I am unable to call the webservice. I am using RESTClient to send post request. The web server is apache tomcat 7 and jersey 2.16 .
The url I am hitting is http://localhost:8082/LatestFMS/rest/Search/searchData.
I am unable to resolve the issue, please help ! ! !

Rest Jersey does not consume POST Request Payload JSON object

This is my ajax code, here I send json object as Request payload.
$(document).ready(function() {
var firstName = $("#firstName").val();
var lastName = $("#lastName").val();
var address = $("#address").val();
$("#studentInsert").click(function() {
student.presonal_details = {
firstName: $("#firstName").val(),
lastName: $("#lastName").val(),
address: $("#address").val(),
}
$.ajax({
type: "post",
url: "http://localhost:8080/RestJersey/rest/jsonRequestReceiver/saveStudentDeta il",
contentType: "application/json; charset=utf-8",
data: JSON.stringify(student.presonal_details),
success: function(data) {
console.log(data);
}
});
});
});
Java Code:
I want to know how do I write REST service API code for receiving the json Object.
#POST
#Path("/saveStudentDetail")
#Consumes(MediaType.APPLICATION_JSON)
public void saveStudentDetail() {
}
This is my web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID"
version="3.0">
<display-name>RestJersey</display-name>
<welcome-file-list>
<!-- <welcome-file>index1.html</welcome-file> -->
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>jersey-servlet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>jersey-servlet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
And may POJO class:
package com.rest.test.to;
import javax.xml.bind.annotation.XmlRootElement;
#XmlRootElement
public class StudentDetailsTO {
private String firstName;
private String lastName;
private String address;
// getters and setters
}

Use below code
#POST
#Path("/saveStudentDetail")
#Consumes(MediaType.APPLICATION_JSON)
public void saveStudentDetail(StudentDetailsTO student){
String fname= student.getFirstName();
String lname= student.getLastName();
String address= student.getAddress();
}

Error when starting jax-rs server

I am getting the following error when trying to start my web service locally
SEVERE: The ResourceConfig instance does not contain any root resource classes.
com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes.
at com.sun.jersey.server.impl.application.RootResourceUriRules.<init>(RootResourceUriRules.java:99)
at com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1359)
at com.sun.jersey.server.impl.application.WebApplicationImpl.access$700(WebApplicationImpl.java:180)
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:799)
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:795)
at com.sun.jersey.spi.inject.Errors.processWithErrors(Errors.java:193)
at com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:795)
at com.sun.jersey.api.container.ContainerFactory.createContainer(ContainerFactory.java:172)
at com.sun.jersey.api.container.ContainerFactory.createContainer(ContainerFactory.java:264)
at com.sun.jersey.api.container.ContainerFactory.createContainer(ContainerFactory.java:246)
at com.sun.jersey.api.container.httpserver.HttpServerFactory.create(HttpServerFactory.java:117)
at com.sun.jersey.api.container.httpserver.HttpServerFactory.create(HttpServerFactory.java:92)
at com.swiped.main.ServerStart.main(ServerStart.java:14)
My classes look as follows;
public class ExposedFunctions {
private static Logger logger = Logger.getLogger(ExposedFunctions.class);
private DBFactoryController controller = new DBFactoryController();
public ExposedFunctions(){
if(controller!= null){
controller.buildCache();
}
}
#GET
#Path("/add/{username}/{password}/{email}/{firstname}/{lastname}")
#Produces(MediaType.TEXT_PLAIN)
public String register(#PathParam("username") String username, #PathParam("password") String password, #PathParam("email") String email, #PathParam("firstname") String firstname, #PathParam("lastname") String lastname) {
if(StringUtilities.stringEmptyOrNull(username, password, email, firstname, lastname)){
logger.error("String was null or empty when registering");
}
RegistrationStatus status = controller.register(username, password, email, firstname, lastname);
return status.getValue();
}
}
My web xml is as follows;
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>com.swiped.service</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.swiped.service</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
And I kick it all off with my main class which looks as follows;
#SuppressWarnings("restriction")
public static void main(String[] args){
try{
HttpServer server = HttpServerFactory.create(BASE_URI);
server.start();
System.out.println("Press Enter to stop the server. ");
System.in.read();
server.stop(0);
}catch(Exception e){
e.printStackTrace();
}
}
I have noticed that plenty of people have had a similar error however there is lots of varying advice given for individual circumstances making it hard for me to find a solution for this error. Does anyone see anything obviously wrong with my approach and if so please could you help me in resolving it?
Thanks for your time

Annotate ExposedFunctions with #Path, too.
#Path("/")
public class ExposedFunctions {
Edit: The class is the root resource while the methods are sub resources. You must have both.

REST WS with Interface

I'm trying to implement a REST WS. The following code works ok:
#Path("/MyRest")
#WebService
public class MyService {
#GET
#Produces(MediaType.APPLICATION_JSON)
#Path("/{id}")
public Response test(#PathParam("id") String id) {
String str = "{\"status\":\"ok\",\"id\":\"" + id + "\"}";
return Response.status(200).entity(str).build();
}
}
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>WSRest</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>
com.sun.jersey.spi.container.servlet.ServletContainer
</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>test</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
Now i'm trying to do it with an Interface. The interface would be like follows, I guess:
#Path("/MyRest")
#WebService
public interface IService {
#GET
#Produces(MediaType.APPLICATION_JSON)
#Path("/{id}")
public Response test(#PathParam("id") String id);
}
And now the WS implementation would be like this, right?:
public class MyService implements IService{
#Override
public Response test(#PathParam("id") String id) {
String str = "{\"status\":\"ok\",\"id\":\"" + id + "\"}";
return Response.status(200).entity(str).build();
}
}
I'm getting "HTTP Status 500 - Servlet.init() for servlet Jersey REST Service threw exception" when I try to "run" it again :/
Any ideas? Thanks in advance.
Full exception:
type Exception report
message Servlet.init() for servlet Jersey REST Service threw exception
description The server encountered an internal error that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: Servlet.init() for servlet Jersey REST Service threw exception
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1041)
org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:603)
org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2430)
org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2419)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
java.lang.Thread.run(Thread.java:722)
root cause
com.sun.jersey.spi.inject.Errors$ErrorMessagesException
com.sun.jersey.spi.inject.Errors.processErrorMessages(Errors.java:170)
com.sun.jersey.spi.inject.Errors.postProcess(Errors.java:136)
com.sun.jersey.spi.inject.Errors.processWithErrors(Errors.java:199)
com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:795)
com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:790)
com.sun.jersey.spi.container.servlet.ServletContainer.initiate(ServletContainer.java:491)
com.sun.jersey.spi.container.servlet.ServletContainer$InternalWebComponent.initiate(ServletContainer.java:321)
com.sun.jersey.spi.container.servlet.WebComponent.load(WebComponent.java:605)
com.sun.jersey.spi.container.servlet.WebComponent.init(WebComponent.java:207)
com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:376)
com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:559)
javax.servlet.GenericServlet.init(GenericServlet.java:160)
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1041)
org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:603)
org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2430)
org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2419)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
java.lang.Thread.run(Thread.java:722)

An example of a web method using an interface:
Web service implementation:
#Path("/WS")
#WebService
public class WebService implements IWebService {
#Override
#POST
#Consumes("application/json")
#Produces("application/json")
#Path("/Login")
public Response Login(JSONObject data) {
//stuff here
}
}
Interface:
public interface IWebService {
#POST
#Consumes("application/json")
#Produces("application/json")
#Path("/Login")
public Response Login(JSONObject data);
}