Java While(boolean) how this code work? - java

This is the code from lesson on Udemy. I don't understand how the boolean stop; work in this while loop. I don't see any changes of stop inside the loop.
Can some one explain me please how while loop work in this particular case.
package socket;
import java.io.*;
import java.net.*;
public class MultiUserService
{
public static void main(String [] args) //throws Exception
{
try
{
ServerSocket serverSocket = new ServerSocket(9090);
System.out.println("wainting for clients...");
boolean stop = false;
while(!stop)
{
Socket socket = serverSocket.accept();
PrintWriter out = new PrintWriter(socket.getOutputStream(), true);
out.println("Hello client!");
BufferedReader input = new BufferedReader(new InputStreamReader(socket.getInputStream()));
String clientInput = input.readLine();
System.out.println(clientInput);
input.close();
out.close();
socket.close();
}
serverSocket.close();
} catch (Exception e)
{
System.out.println(e.toString());
}
}
}

Indeed, there is no change of stop in the loop, which means the loop won't ever stop, unless an exception is thrown.
Since it is a server, listening for sockets, this is an expected behavior: the server keeps listening and serving clients.
Note that in production code, there should be a way to stop the server, which, depending on the approach, may or may not require actually stopping that loop (there are asynchronous ways available).

That's the point; once it starts, the loop won't stop unless something goes very wrong.

Related

How do i interrupt the loop of a socket

So my program has clients that are entering tasks and they can see each other tasks but i want the server to close when all the clients are shutdown by a command and i don't want to look for more clients after the last one closes.
What i have tried is counting the number of clients that entered and when there is none, the problem is that the server tries to accept new clients and does't check the condition can any one help me?
public static void main(String[] args) {
try {
ServerSocket serverSocket = new ServerSocket(4242);
while (acceptNewClients) {
Socket clientSocket = serverSocket.accept();
countClient++;
System.out.println(countClient);
ThreadedServer clientThread = new ThreadedServer(clientSocket);
new Thread(clientThread).start();
if (countClient == 0) {
flipAcceptNewClients();
}
}
}catch (IOException e) {
e.printStackTrace();
}
If you want to shut down the server, call System.exit(0); to do so.
interrupting the thread that is blocking on serverSocket.accept() may or may not work; depends on the OS and JVM, hence, that's not a great way to do this.

Stop a thread which has a while (true) [duplicate]

In my main thread I have a while(listening) loop which calls accept() on my ServerSocket object, then starts a new client thread and adds it to a Collection when a new client is accepted.
I also have an Admin thread which I want to use to issue commands, like 'exit', which will cause all the client threads to be shut down, shut itself down, and shut down the main thread, by turning listening to false.
However, the accept() call in the while(listening) loop blocks, and there doesn't seem to be any way to interrupt it, so the while condition cannot be checked again and the program cannot exit!
Is there a better way to do this? Or some way to interrupt the blocking method?
You can call close() from another thread, and the accept() call will throw a SocketException.
Set timeout on accept(), then the call will timeout the blocking after specified time:
http://docs.oracle.com/javase/7/docs/api/java/net/SocketOptions.html#SO_TIMEOUT
Set a timeout on blocking Socket operations:
ServerSocket.accept();
SocketInputStream.read();
DatagramSocket.receive();
The option must be set prior to entering a blocking operation to take effect. If the timeout expires and the operation would continue to block, java.io.InterruptedIOException is raised. The Socket is not closed in this case.
Is calling close() on the ServerSocket an option?
http://java.sun.com/j2se/6/docs/api/java/net/ServerSocket.html#close%28%29
Closes this socket. Any thread currently blocked in accept() will throw a SocketException.
You can just create "void" socket for break serversocket.accept()
Server side
private static final byte END_WAITING = 66;
private static final byte CONNECT_REQUEST = 1;
while (true) {
Socket clientSock = serverSocket.accept();
int code = clientSock.getInputStream().read();
if (code == END_WAITING
/*&& clientSock.getInetAddress().getHostAddress().equals(myIp)*/) {
// End waiting clients code detected
break;
} else if (code == CONNECT_REQUEST) { // other action
// ...
}
}
Method for break server cycle
void acceptClients() {
try {
Socket s = new Socket(myIp, PORT);
s.getOutputStream().write(END_WAITING);
s.getOutputStream().flush();
s.close();
} catch (IOException e) {
}
}
The reason ServerSocket.close() throws an exception
is because you have an outputstream or an inputstream
attached to that socket.
You can avoid this exception safely by first closing the input and output streams.
Then try closing the ServerSocket.
Here is an example:
void closeServer() throws IOException {
try {
if (outputstream != null)
outputstream.close();
if (inputstream != null)
inputstream.close();
} catch (IOException e1) {
e1.printStackTrace();
}
if (!serversock.isClosed())
serversock.close();
}
}
You can call this method to close any socket from anywhere without getting an exception.
Use serverSocket.setSoTimeout(timeoutInMillis).
OK, I got this working in a way that addresses the OP's question more directly.
Keep reading past the short answer for a Thread example of how I use this.
Short answer:
ServerSocket myServer;
Socket clientSocket;
try {
myServer = new ServerSocket(port)
myServer.setSoTimeout(2000);
//YOU MUST DO THIS ANYTIME TO ASSIGN new ServerSocket() to myServer‼!
clientSocket = myServer.accept();
//In this case, after 2 seconds the below interruption will be thrown
}
catch (java.io.InterruptedIOException e) {
/* This is where you handle the timeout. THIS WILL NOT stop
the running of your code unless you issue a break; so you
can do whatever you need to do here to handle whatever you
want to happen when the timeout occurs.
*/
}
Real world example:
In this example, I have a ServerSocket waiting for a connection inside a Thread. When I close the app, I want to shut down the thread (more specifically, the socket) in a clean manner before I let the app close, so I use the .setSoTimeout() on the ServerSocket then I use the interrupt that is thrown after the timeout to check and see if the parent is trying to shut down the thread. If so, then I set close the socket, then set a flag indicating that the thread is done, then I break out of the Threads loop which returns a null.
package MyServer;
import javafx.concurrent.Task;
import java.io.IOException;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import javafx.concurrent.Task;
import java.io.IOException;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
public class Server {
public Server (int port) {this.port = port;}
private boolean threadDone = false;
private boolean threadInterrupted = false;
private boolean threadRunning = false;
private ServerSocket myServer = null;
private Socket clientSocket = null;
private Thread serverThread = null;;
private int port;
private static final int SO_TIMEOUT = 5000; //5 seconds
public void startServer() {
if (!threadRunning) {
serverThread = new Thread(thisServerTask);
serverThread.setDaemon(true);
serverThread.start();
}
}
public void stopServer() {
if (threadRunning) {
threadInterrupted = true;
while (!threadDone) {
//We are just waiting for the timeout to exception happen
}
if (threadDone) {threadRunning = false;}
}
}
public boolean isRunning() {return threadRunning;}
private Task<Void> thisServerTask = new Task <Void>() {
#Override public Void call() throws InterruptedException {
threadRunning = true;
try {
myServer = new ServerSocket(port);
myServer.setSoTimeout(SO_TIMEOUT);
clientSocket = new Socket();
} catch (IOException e) {
e.printStackTrace();
}
while(true) {
try {
clientSocket = myServer.accept();
}
catch (java.io.InterruptedIOException e) {
if (threadInterrupted) {
try { clientSocket.close(); } //This is the clean exit I'm after.
catch (IOException e1) { e1.printStackTrace(); }
threadDone = true;
break;
}
} catch (SocketException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
};
}
Then, in my Controller class ... (I will only show relevant code, massage it into your own code as needed)
public class Controller {
Server server = null;
private static final int port = 10000;
private void stopTheServer() {
server.stopServer();
while (server.isRunning() {
//We just wait for the server service to stop.
}
}
#FXML private void initialize() {
Platform.runLater(()-> {
server = new Server(port);
server.startServer();
Stage stage = (Stage) serverStatusLabel.getScene().getWindow();
stage.setOnCloseRequest(event->stopTheServer());
});
}
}
I hope this helps someone down the road.
Another thing you can try which is cleaner, is to check a flag in the accept loop, and then when your admin thread wants to kill the thread blocking on the accept, set the flag (make it thread safe) and then make a client socket connection to the listening socket.
The accept will stop blocking and return the new socket.
You can work out some simple protocol thing telling the listening thread to exit the thread cleanly.
And then close the socket on the client side.
No exceptions, much cleaner.
You can simply pass the timeout limit (milli seconds) as a parameter while calling accept function.
eg serverSocket.accept(1000);
automatically close the request after 1 sec

Is there a timeout case that allows for code a block of code to be terminated after a specific amount of time? [duplicate]

In my main thread I have a while(listening) loop which calls accept() on my ServerSocket object, then starts a new client thread and adds it to a Collection when a new client is accepted.
I also have an Admin thread which I want to use to issue commands, like 'exit', which will cause all the client threads to be shut down, shut itself down, and shut down the main thread, by turning listening to false.
However, the accept() call in the while(listening) loop blocks, and there doesn't seem to be any way to interrupt it, so the while condition cannot be checked again and the program cannot exit!
Is there a better way to do this? Or some way to interrupt the blocking method?
You can call close() from another thread, and the accept() call will throw a SocketException.
Set timeout on accept(), then the call will timeout the blocking after specified time:
http://docs.oracle.com/javase/7/docs/api/java/net/SocketOptions.html#SO_TIMEOUT
Set a timeout on blocking Socket operations:
ServerSocket.accept();
SocketInputStream.read();
DatagramSocket.receive();
The option must be set prior to entering a blocking operation to take effect. If the timeout expires and the operation would continue to block, java.io.InterruptedIOException is raised. The Socket is not closed in this case.
Is calling close() on the ServerSocket an option?
http://java.sun.com/j2se/6/docs/api/java/net/ServerSocket.html#close%28%29
Closes this socket. Any thread currently blocked in accept() will throw a SocketException.
You can just create "void" socket for break serversocket.accept()
Server side
private static final byte END_WAITING = 66;
private static final byte CONNECT_REQUEST = 1;
while (true) {
Socket clientSock = serverSocket.accept();
int code = clientSock.getInputStream().read();
if (code == END_WAITING
/*&& clientSock.getInetAddress().getHostAddress().equals(myIp)*/) {
// End waiting clients code detected
break;
} else if (code == CONNECT_REQUEST) { // other action
// ...
}
}
Method for break server cycle
void acceptClients() {
try {
Socket s = new Socket(myIp, PORT);
s.getOutputStream().write(END_WAITING);
s.getOutputStream().flush();
s.close();
} catch (IOException e) {
}
}
The reason ServerSocket.close() throws an exception
is because you have an outputstream or an inputstream
attached to that socket.
You can avoid this exception safely by first closing the input and output streams.
Then try closing the ServerSocket.
Here is an example:
void closeServer() throws IOException {
try {
if (outputstream != null)
outputstream.close();
if (inputstream != null)
inputstream.close();
} catch (IOException e1) {
e1.printStackTrace();
}
if (!serversock.isClosed())
serversock.close();
}
}
You can call this method to close any socket from anywhere without getting an exception.
Use serverSocket.setSoTimeout(timeoutInMillis).
OK, I got this working in a way that addresses the OP's question more directly.
Keep reading past the short answer for a Thread example of how I use this.
Short answer:
ServerSocket myServer;
Socket clientSocket;
try {
myServer = new ServerSocket(port)
myServer.setSoTimeout(2000);
//YOU MUST DO THIS ANYTIME TO ASSIGN new ServerSocket() to myServer‼!
clientSocket = myServer.accept();
//In this case, after 2 seconds the below interruption will be thrown
}
catch (java.io.InterruptedIOException e) {
/* This is where you handle the timeout. THIS WILL NOT stop
the running of your code unless you issue a break; so you
can do whatever you need to do here to handle whatever you
want to happen when the timeout occurs.
*/
}
Real world example:
In this example, I have a ServerSocket waiting for a connection inside a Thread. When I close the app, I want to shut down the thread (more specifically, the socket) in a clean manner before I let the app close, so I use the .setSoTimeout() on the ServerSocket then I use the interrupt that is thrown after the timeout to check and see if the parent is trying to shut down the thread. If so, then I set close the socket, then set a flag indicating that the thread is done, then I break out of the Threads loop which returns a null.
package MyServer;
import javafx.concurrent.Task;
import java.io.IOException;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import javafx.concurrent.Task;
import java.io.IOException;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
public class Server {
public Server (int port) {this.port = port;}
private boolean threadDone = false;
private boolean threadInterrupted = false;
private boolean threadRunning = false;
private ServerSocket myServer = null;
private Socket clientSocket = null;
private Thread serverThread = null;;
private int port;
private static final int SO_TIMEOUT = 5000; //5 seconds
public void startServer() {
if (!threadRunning) {
serverThread = new Thread(thisServerTask);
serverThread.setDaemon(true);
serverThread.start();
}
}
public void stopServer() {
if (threadRunning) {
threadInterrupted = true;
while (!threadDone) {
//We are just waiting for the timeout to exception happen
}
if (threadDone) {threadRunning = false;}
}
}
public boolean isRunning() {return threadRunning;}
private Task<Void> thisServerTask = new Task <Void>() {
#Override public Void call() throws InterruptedException {
threadRunning = true;
try {
myServer = new ServerSocket(port);
myServer.setSoTimeout(SO_TIMEOUT);
clientSocket = new Socket();
} catch (IOException e) {
e.printStackTrace();
}
while(true) {
try {
clientSocket = myServer.accept();
}
catch (java.io.InterruptedIOException e) {
if (threadInterrupted) {
try { clientSocket.close(); } //This is the clean exit I'm after.
catch (IOException e1) { e1.printStackTrace(); }
threadDone = true;
break;
}
} catch (SocketException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
};
}
Then, in my Controller class ... (I will only show relevant code, massage it into your own code as needed)
public class Controller {
Server server = null;
private static final int port = 10000;
private void stopTheServer() {
server.stopServer();
while (server.isRunning() {
//We just wait for the server service to stop.
}
}
#FXML private void initialize() {
Platform.runLater(()-> {
server = new Server(port);
server.startServer();
Stage stage = (Stage) serverStatusLabel.getScene().getWindow();
stage.setOnCloseRequest(event->stopTheServer());
});
}
}
I hope this helps someone down the road.
Another thing you can try which is cleaner, is to check a flag in the accept loop, and then when your admin thread wants to kill the thread blocking on the accept, set the flag (make it thread safe) and then make a client socket connection to the listening socket.
The accept will stop blocking and return the new socket.
You can work out some simple protocol thing telling the listening thread to exit the thread cleanly.
And then close the socket on the client side.
No exceptions, much cleaner.
You can simply pass the timeout limit (milli seconds) as a parameter while calling accept function.
eg serverSocket.accept(1000);
automatically close the request after 1 sec

Strange behavior in a simple chat using Java

I started to study java last month, and now I'm trying to write a simple chat program but I encountered something strange, and I was curious for the reason behind it.
import java.io.*;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.Scanner;
public class Server {
public static void main(String[] args) throws IOException {
String text = "";
ServerSocket ss = new ServerSocket(21025);
while (true){
System.out.println("Waiting...");
Socket s1 = ss.accept();
System.out.println("Connection accepted from "+s1.getInetAddress());
PrintStream pout = new PrintStream(s1.getOutputStream());
pout.println("Connected to the server");
new Thread(new Ricevitore(s1)).start();
}
}
}
public class Ricevitore implements Runnable {
String text = "";
Socket skt;
public Ricevitore(Socket skt){
this.skt = skt;
}
#Override
public void run() {
while (!text.equalsIgnoreCase("end")) {
try {
InputStream in = skt.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(in));
text = br.readLine();
if (!text.equalsIgnoreCase("end"))
System.out.println(text);
}
catch (IOException e){}
}
}
}
public class Client {
public static void main(String[] args) throws IOException {
//Create a socket
try (Socket s = new Socket("127.0.0.1", 21025)) {
String text="";
while(!text.equalsIgnoreCase("end")) {
//Allows messages from server
InputStream in = s.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(in));
if (br.ready()) {
Scanner server = new Scanner(br);
String testoServer = br.readLine();
System.out.println(testoServer);
}
//Allows to send text to the server
OutputStream out = s.getOutputStream();
PrintStream pout = new PrintStream(out);
Scanner tastiera = new Scanner(System.in);
text = tastiera.nextLine();
pout.println(text);
}
}
}
}
This is the complete program for the moment, my question is this: Since I wanted to avoid printing the word "end" to close the program, I inserted
if (!text.equalsIgnoreCase("end"))
but after that the server does not display the message "connected to server" unless I first input something through the client.
If I comment out that if statement, both messages "Connection accepted" and "Connected to server" got printed at the same time as intended.
I don't know if my question is clear, and I'm rather interested in learning why something like this happens.
If there are other things which any of you think is wrong I'll be happy to here about them.
I have only a wild guess which looks probable though.
In your client you read the message from the server if br.ready() returns true. It may happen that this function returns false, and the client goes to waiting for user's input.
After you send a message from the client to the server, the client repeats the test and now gets the message from the server.
I cannot explain why removing if (!text.equalsIgnoreCase("end")) in server's code makes the issue go away. That line isn't even executed until you send a message from the client.
So I think it's just a coincidence. There are two processes involved, and the outcome depends on how fast code executes in either process.
I ran your example many times, and once I did not receive the greeting from the server even though the if above was in its place.
A general suggestion for your code: you don't need to create input/output streams as well as Scanner on each iteration, you should do it only once.
To end communication session, you can just close PrintStream in your client as soon as you receive end from user. Your server will get null from br.readLine(). At this point, you close br and complete run().

Java multiplayer server blocking io

I am currently developing a prototype for a game and I need a simple server to run it.
At this stage, I don't want to invest the time learning about all the different full-featured multiplayer game servers already there (smartfox, etc...)
I know how to develop a basic Server with Threads listening on Sockets but I have ran into a roadblock. Here's the run() function of the Thread
public void run() {
try {
out = new PrintWriter(mSocket1.getOutputStream(), true);
in = new BufferedReader( new InputStreamReader( mSocket1.getInputStream() ) );
String inputLine1 = null, outputLine;
out.println("hello");
out.flush();
while( (inputLine1 = in.readLine()) != null) {
outputLine = mGameControl.processInput(mPlayerNum, inputLine1);
out.println(outputLine);
out.flush();
if(outputLine.contentEquals("bye"))
break;
}
Terminate();
}
catch(IOException e) { e.printStackTrace(); }
}
Now my problem is that the thread is blocked waiting for input. I do have other similar Threads connected to other client which may result in information being dispatched to all clients...
How can I modify it so that a different Thread can interact with it and push info to the client?
Just write a synchronised public method which writes to your PrintWriter, and allow other threads to use it to send messages to your client. Call the same method from your read loop to avoid two threads writing at the same time.
Here's a tested example:
import java.io.*;
import java.net.ServerSocket;
import java.net.Socket;
public class SocketTest {
public static class Client implements Runnable {
private final BufferedReader in;
private final PrintWriter out;
public Client(Socket clientSocket) throws IOException {
out = new PrintWriter(clientSocket.getOutputStream(), true);
in = new BufferedReader( new InputStreamReader( clientSocket.getInputStream() ) );
}
public void run() {
send("Hello");
String inputLine1 = null, outputLine;
try {
while( (inputLine1 = in.readLine()) != null) {
outputLine = inputLine1.toLowerCase();
System.out.println(inputLine1);
send(outputLine);
if(outputLine.contentEquals("bye"))
break;
}
} catch (IOException e) {
e.printStackTrace();
}
}
public synchronized void send(String message) {
out.println(message);
out.flush();
}
}
public static void main(String[] args) throws IOException, InterruptedException {
ServerSocket s = new ServerSocket(5050);
Socket clientSocket = s.accept();
Client client = new Client(clientSocket);
Thread clientThread = new Thread(client);
clientThread.start();
int i = 1;
while (true) {
Thread.sleep(1000);
client.send("Tick " + (i++));
}
}
}
Use Netty to handle your connections and query treatments. Since I discovered that project, I never touched sockets directly anymore (except when writing C programs, etc.)
There are actually some examples to look at and the documentation is quite extensive. The project is very well alive since a couple of years already, and is not soon to die! There's a fairly large user base behind it.
If you only need to perform a non-blocking read on the socket, one of the simplests ways is to use available(). Call available and if there is data to read (bytes pending > 0), perform the read, any way, wait using Thread.sleep() and try to read again. This allow the thread to do while waiting for input data and cat react to external signals.
The use of selectors is encouraged when you need to perform high-performance non-blocking read using one thread and several sockets (java.nio.channels.Selector).

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