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How to compress a folder and send via email in android

Everyone: I am trying to send a folder (there are many files inside this folder) via email in Android Development.
First, I tried send the whole folder directly by using a click event and intent event.
My first attempt code shows the following:
My first part of code is onclicklistener event:
listView.setOnMenuItemClickListener(new SwipeMenuListView.OnMenuItemClickListener() {
#Override
public boolean onMenuItemClick(int position, SwipeMenu menu,int index) {
switch (index) {
case 0:
sendEmail(list.get(position).getName());
break;
case 1:
list.remove(position);
adapter.notifyDataSetChanged();
}
return false;
}
});
My second code to send Email is as follows:
public void sendEmail(String data_path){
Intent email = new Intent(Intent.ACTION_SEND);
File file_location = new File(SDCard, data_path);
email.setType("vnd.android.cursor.dir/email");
email.putExtra(Intent.EXTRA_EMAIL, new String[]{"example#gmail.com"}); //set up email
email.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file_location)); //add attachment
email.putExtra(Intent.EXTRA_SUBJECT, "Subject");
startActivity(Intent.createChooser(email, "pick an Email provider"));
}
When I run this code, it works fine to jump into email sender, but without any folder implement, the email implement is empty.
I am wondering if it is impossible to send a folder directly via email.
Now I am trying to another way to solve this: I am planning to compress folder(.zip) first and then send the zip file to email in just one click event, But I can not find any solutions showing how to compress the folder and send zip file in just one click event, What I mean is that I want a solution which:
Clicks the file that needs to be sent (click event has finished)
After it triggers the click event, the app will compress the clicked file to a zip file.
The zip file will automatically add as mail implements that waits to be sent
I was trapped there for many days and still failed to find any answers, I also search on StackOverflow, but most questions are about how to compress a file or send file by email. I am looking for a way to compress a folder and send a zip file in one click event.
If you have any ideas, I would quite appreciate them!

Here is a workaround to transform your folder into zip.
First, grant permissions:
<uses-permission android:name="android.permission.WRITE_INTERNAL_STORAGE" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
And then use this to transform your folder:
/*
*
* Zips a file at a location and places the resulting zip file at the toLocation
* Example: zipFileAtPath("downloads/myfolder", "downloads/myFolder.zip");
*/
public boolean zipFileAtPath(String sourcePath, String toLocation) {
final int BUFFER = 2048;
File sourceFile = new File(sourcePath);
try {
BufferedInputStream origin = null;
FileOutputStream dest = new FileOutputStream(toLocation);
ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(
dest));
if (sourceFile.isDirectory()) {
zipSubFolder(out, sourceFile, sourceFile.getParent().length());
} else {
byte data[] = new byte[BUFFER];
FileInputStream fi = new FileInputStream(sourcePath);
origin = new BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(getLastPathComponent(sourcePath));
out.putNextEntry(entry);
int count;
while ((count = origin.read(data, 0, BUFFER)) != -1) {
out.write(data, 0, count);
}
}
out.close();
} catch (Exception e) {
e.printStackTrace();
return false;
}
Here is another example:
private static void zipFolder(String inputFolderPath, String outZipPath) {
try {
FileOutputStream fos = new FileOutputStream(outZipPath);
ZipOutputStream zos = new ZipOutputStream(fos);
File srcFile = new File(inputFolderPath);
File[] files = srcFile.listFiles();
Log.d("", "Zip directory: " + srcFile.getName());
for (int i = 0; i < files.length; i++) {
Log.d("", "Adding file: " + files[i].getName());
byte[] buffer = new byte[1024];
FileInputStream fis = new FileInputStream(files[i]);
zos.putNextEntry(new ZipEntry(files[i].getName()));
int length;
while ((length = fis.read(buffer)) > 0) {
zos.write(buffer, 0, length);
}
zos.closeEntry();
fis.close();
}
zos.close();
} catch (IOException ioe) {
Log.e("", ioe.getMessage());
}
}
Also you can use this library to zip a folder or file.
Import the .jar into your project and then you can do this to transform what you need:
try {
File input = new File("path/to/your/input/fileOrFolder");
String destinationPath = Environment.getExternalStorageDirectory().getAbsolutePath() + File.separator + "zippedItem.zip";
ZipParameters parameters = new ZipParameters();
parameters.setCompressionMethod(Zip4jConstants.COMP_STORE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
File output = new File(destinationPath);
ZipFile zipFile = new ZipFile(output);
// .addFolder or .addFile depending on your input
if (sourceFile.isDirectory())
zipFile.addFolder(input, parameters);
else
zipFile.addFile(input, parameters);
// Your input file/directory has been zipped at this point and you
// can access it as a normal file using the following line of code
File zippedFile = zipFile.getFile();
} catch (ZipException e) {
Log.e(TAG, Log.getStackTraceString(e));
}
This should do the trick.

How to create a .zip file from two .doc file?

I want to write a unit test to test creating .zip file from two .doc files. BU I take an error: Error creating zip file: java.io.FileNotFoundException: D:\file1.txt (The system cannot find the file specified)
My code is here:
#Test
public void testIsZipped() {
String actualValue1 = "D:/file1.txt";
String actualValue2 = "D:/file2.txt";
String zipFile = "D:/file.zip";
String[] srcFiles = { actualValue1, actualValue2 };
try {
// create byte buffer
byte[] buffer = new byte[1024];
FileOutputStream fos = new FileOutputStream(zipFile);
zos = new ZipOutputStream(fos);
for (int i = 0; i < srcFiles.length; i++) {
File srcFile = new File(srcFiles[i]);
FileInputStream fis = new FileInputStream(srcFile);
// begin writing a new ZIP entry, positions the stream to the
// start of the entry data
zos.putNextEntry(new ZipEntry(srcFile.getName()));
int length;
while ((length = fis.read(buffer)) > 0) {
zos.write(buffer, 0, length);
}
zos.closeEntry();
// close the InputStream
fis.close();
}
// close the ZipOutputStream
zos.close();
}
catch (IOException ioe) {
System.out.println("Error creating zip file: " + ioe);
}
String result = zos.toString();
assertEquals("D:/file.zip", result);
}
Can I get name of zip file from zos to test, How to understand to pass the test? Can anybody help me to solve this error? Thank you.

First, are your files created in a previous test method? If yes consider that junit tests do not execute in the order you defined your test methods, have a look at this:
How to run test methods in specific order in JUnit4?
Second, you could add a debugging line:
File srcFile = new File(srcFiles[i]);
System.out.append(srcFile+ ": " + srcFile.exists() + " " + srcFile.canRead());
After you solve the exception you will run into this problem, the test will fail:
String result = zos.toString();
assertEquals("D:/file.zip", result);
zos.toString() will return something like: "java.util.zip.ZipOutputStream#1ae369b7" which will not be equal to "D:/file.zip".
String zipFile = "D:/file.zip";
ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(zipFile));
System.out.println(zos.toString());

I keep getting java.io.FileNotFoundException with my zip extractor

Could anybody help me with my java zip extractor as stated in the title I keep getting java.io.FileNotFoundException on the folders with files in them
public void UnZip() {
try {
byte[] data = new byte[1000];
int byteRead;
BufferedOutputStream bout = null;
ZipInputStream zin = new ZipInputStream(new BufferedInputStream(new FileInputStream(sourceFile)));
ZipEntry entry;
while ((entry = zin.getNextEntry()) != null) {
String filename = entry.getName();
File newfile = new File(Deobf2 + File.separator + filename);
System.out.println("file unzip : " + newfile.getAbsoluteFile());
new File(newfile.getParent()).mkdirs();
FileOutputStream fos = new FileOutputStream(newfile);
int len;
while ((len = zin.read(data)) > 0) {
fos.write(data, 0, len);
}
fos.close();
entry = zin.getNextEntry();
}
zin.closeEntry();
zin.close();
System.out.println("Done");
} catch (Exception e) {
e.printStackTrace();
}
}
error log
http://pastebin.com/crMKaa37
values
static String tempDir = System.getProperty("java.io.tmpdir");
public static File Deobf = new File(tempDir + "Deobf");
public static String Deobf2 = Deobf.toString();
entire code paste
http://pastebin.com/1vTfABR1

I have copy pasted same code and it is working fine. I think u dont have administrator permission on C drive. login As Administrator and run . it will work.
Access Denied Exception will come when u don have administrator level of permission on C drive.

The problem is Your doing
String Deobf2 = Deobf.toString();//this does not give the location of the file
use
file.getAbsolutePath();
in your case Deobf.getAbsolutePath();
instead. Check http://www.mkyong.com/java/how-to-get-the-filepath-of-a-file-in-java/
if you want to get the path only till the parent directory check this How to get absolute path of directory of a file?

Problem fixed changed some code
for anyone whos wants a copy of the working zip extraction code here you go http://pastebin.com/bXL8pUSg
The variable Deobf2 in the output of the zip

Java file upload - inputstream issue

I have to upload some files from jsp page, when i read the inputstream for the same.
I am checking for its authenticity that its a valid file or not, for that I am using jmimemagic and it takes input stream as argument and now when I am trying to upload it, its only uploading 1 byte of data?
I feel like there is some issue with inputstream any solution pls?
//For checking the file type
InputStream loIns = aoFileStream.getInputStreamToReadFile();
byte[] fileArray = IOUtils.toByteArray(loIns);
mimeType = Magic.getMagicMatch(fileArray, true).getMimeType();
if(!loAllowedFileTypesMimeList.contains(mimeType)){
return false;
}else{
String lsFileName = aoFileStream.getFileName();
String lsFileExt = lsFileName.substring(lsFileName.lastIndexOf(".") + 1);
if(loAllowedFileTypesList.contains(lsFileExt.toLowerCase())){
return true;
}
return false;
}
// For uploading the content
File loOutputFile = new File(asFilePathToUpload);
if(!loOutputFile.exists()){
FileOutputStream loOutput = new FileOutputStream(loOutputFile);
while (liEnd != -1) {
liEnd = inputStreamToReadFile.read();
loOutput.write(liEnd);
}
inputStreamToReadFile.close();
loOutput.close();
}

In
byte[] fileArray = IOUtils.toByteArray(loIns);
you've already exhausted your inputstream, so when you want to write it to a file, you should use the content of the fileArray, not your loIns:
FileUtils.writeByteArrayToFile(loOutput, fileArray);
FileUtils is provided by apache-commons

How to extract Lotus Notes database icon?

I have tried to extract Lotus Notes database icon by using DXL Exporter but it is not success. Result file is corrupt and can not be opened by image viewer.
How can I extract Lotus Notes database icon by using java?
private String extractDatabaseIcon() {
String tag = "";
String idfile = "";
String password = "";
String dbfile = "";
NotesThread.sinitThread();
Session s = NotesFactory.createSessionWithFullAccess();
s.createRegistration().switchToID(idfile, password);
Database d = s.getDatabase("", dbfile);
NoteCollection nc = d.createNoteCollection(false);
nc.setSelectIcon(true);
nc.buildCollection();
String noteId = nc.getFirstNoteID();
int counter = 0;
while (noteId != null) {
counter++;
try {
Document doc = d.getDocumentByID(noteId);
DxlExporter dxl = s.createDxlExporter();
String xml = dxl.exportDxl(doc);
xml = xml.substring(xml.indexOf("<note "));
org.jsoup.nodes.Document jdoc = Jsoup.parse(xml);
Element ele = jdoc.select("rawitemdata").first();
String raw = ele.text().trim();
String temp = System.getProperty("java.io.tmpdir") + UUID.randomUUID().toString() + "\\";
File file = new File(temp);
file.mkdir();
String filename = temp + UUID.randomUUID().toString().replaceAll("-", "") + ".gif";
byte[] buffer = decode(raw.getBytes());
FileOutputStream fos = new FileOutputStream(filename);
fos.write(buffer);
fos.close();
tag = filename;
} catch (Exception e) {
logger.error("", e);
}
if (counter >= nc.getCount()) {
noteId = null;
} else {
noteId = nc.getNextNoteID(noteId);
}
}
return tag;
}
private byte[] decode(byte[] b) throws Exception {
ByteArrayInputStream bais = new ByteArrayInputStream(b);
InputStream b64is = MimeUtility.decode(bais, "base64");
byte[] tmp = new byte[b.length];
int n = b64is.read(tmp);
byte[] res = new byte[n];
System.arraycopy(tmp, 0, res, 0, n);
return res;
}

It is not even a bitmap, it is an icon. The format you can find here:
http://www.daubnet.com/formats/ICO.html
I managed to do this, a long time ago, in LotusScript. My code was based on an earlier version of this page:
http://www2.tcl.tk/11202
For the icon itself, you only have to open one document:
NotesDocument doc = db.getDocumentByID("FFFF8010")
exporter = session.createDXLExporter
exporter.setConvertNotesBitmapsToGIF(false)
outputXML = exporter.export(doc)
and then parse the XML to find the rawitemdata from the IconBitmap item, as you did in your original code.

I'm not sure what the format is. As far as I know' it's a 16 color bitmap, but not in standard BMP file format. And it's definitely not GIF format, but you can tell the DXLExporter to convert it. The default is to leave it native, so you need to add this to your code before you export:
dxl.setConvertNotesBitmapsToGIF(true);