We Keep Coding

Linked list, count even and uneven positions, unsing recursion

I want to create two methods, "private int sumEven (Node node){}" for suming up even positions in a linked list and "sumOdd (Node node) {}" for suming up odd positions. I want to use recursion.
This is how far i've come, but i dont know what should I do next.
Does any one have a tipp or a hint for me, what should i do next?
public class RecursiveListTest {
static Node head;
static boolean found = false;
static int counter = 0;
public static void main(String[] args) {
RecursiveListTest list = new RecursiveListTest();
list.addNumber(3);
list.addNumber(5);
list.addNumber(2);
list.addNumber(7);
list.addNumber(5);
list.addNumber(1);
list.addNumber(4);
list.printList();
int sumEven = list.sumEven(head);
int sumOdd = list.sumOdd(head);
System.out.println();
System.out.println("Sum of even Positions: " + sumEven);
System.out.println();
System.out.println("Sum of odd Positions: " + sumOdd);
System.out.println();
}
// Node
private class Node {
Node next;
int value;
Node(int value, Node next) {
this.value = value;
this.next = next;
}
}
private int sumEven(Node n) {
int sumEven = 0;
int sumOdd = 0;
counter = counter + 1;
if (counter % 2 == 0) {
sumEven = sumEven + n.value;
if (n.next.next != null) {
sumEven = sumEven + sumEven(n.next.next);
}
}
else if (counter % 2 == 1) {
if (n.next != null) {
sumEven = sumEven + sumEven(n.next);
}
}
return sumEven;
}
private int sumOdd(Node n) {
return 0;
}
private void addNumber(int number) {
Node curr = head;
Node prev = null;
if (head == null) {
head = new Node(number, null);
} else {
while (curr != null) {
prev = curr;
curr = curr.next;
}
Node newNode = new Node(number, null);
prev.next = newNode;
}
}
private void printList() {
Node curr = head;
Node prev = null;
while (curr != null) {
System.out.print(curr.value + " ");
prev = curr;
curr = curr.next;
}
}
}

You should consider using variables private static int evenSum, oddSum and your methods could be:
private int sumEven() {
evenSum = 0;
sumEvenHelper(head);
return evenSum;
}
private int sumOdd() {
oddSum = 0;
sumEvenHelper(head);
return oddSum;
}
private void sumEvenHelper(Node n) {
if(n != null) {
evenSum += n.value;
sumOddHelper(n.next);
}
}
private void sumOddHelper(Node n) {
if(n != null) {
oddSum += n.value;
sumEvenHelper(n.next);
}
}
My code assumes head is list element 0. Otherwise you will call sumOddHelper(head) inside the sumEven and sumOdd methods.

Adding Number Represented by Linked List

I'm stuck on this problem:
You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in reverse order, such that the 1’s digit is at the head of the list. Write a function that adds the two numbers and returns the sum as a linked list.
EXAMPLE
Input: (3 -> 1 -> 5), (5 -> 9 -> 2)
Output: 8 -> 0 -> 8
The problem is that my result is 8 8 while the result should be 8 0 8.
I printed out the sum and it is 8 10 8 so it should work.
Any ideas?
Here is my code:
public Node addNumbers(Node number1, Node number2) {
if(number1 == null && number2 == null)
return null;
Node sumOf = null;
int sum = 0;
int carry = 0;
while(number1 != null && number2 != null) {
sum = number1.data + number2.data + carry;
System.out.println(sum);
// update carry for next operation
if(sum > 9)
carry = 1;
else
carry = 0;
if(sum > 9) {
if(sumOf == null) {
sumOf = new Node(sum % 10);
} else {
sumOf.next = new Node(sum % 10);
}
} else {
if(sumOf == null) {
sumOf = new Node(sum);
} else {
sumOf.next = new Node(sum);
}
}
number1 = number1.next;
number2 = number2.next;
}
return sumOf;
}
public void toString(Node node) {
System.out.println();
while (node != null) {
System.out.print(node.data + " ");
node = node.next;
}
}
public static void main(String[] args) {
AddTwoNumbers add = new AddTwoNumbers();
number1 = new Node(3);
number1.next = new Node(1);
number1.next.next = new Node(5);
number2 = new Node(5);
number2.next = new Node(9);
number2.next.next = new Node(2);
System.out.println("numbers: ");
add.toString(number1);
add.toString(number2);
System.out.println();
System.out.println("after adding: ");
add.toString(add.addNumbers(number1, number2));
}
}

You only ever set sumOf (if it is null) and sumOf.next (if sumOf is not null). Your resulting list therefore never has more than two elements. You need to track the current tail of your list and append there, instead of always appending to sumOf.
Additionally, you need to handle the cases where one input number has more digits than the other, and where you have non-zero carry after exhausting all the input digits. You do not presently handle either.

Here is the solution, do note that i carry forward when the sum of two integers is greater than 9 else i continue with the sum of next integers from both the list.
class Node {
private Object data;
private Node next;
public Object getData() { return data; }
public void setData(Object data) { this.data = data; }
public Node getNext() { return next; }
public void setNext(Node next) { this.next = next; }
public Node(final Object data, final Node next) {
this.data = data;
this.next = next;
}
#Override
public String toString() { return "Node:[Data=" + data + "]"; }
}
class SinglyLinkedList {
Node start;
public SinglyLinkedList() { start = null; }
public void addFront(final Object data) {
// create a reference to the start node with new data
Node node = new Node(data, start);
// assign our start to a new node
start = node;
}
public void addRear(final Object data) {
Node node = new Node(data, null);
Node current = start;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(node);
} else {
addFront(data);
}
}
public void deleteNode(final Object data) {
Node previous = start;
if (previous == null) {
return;
}
Node current = previous.getNext();
if (previous != null && previous.getData().equals(data)) {
start = previous.getNext();
previous = current;
current = previous.getNext();
return;
}
while (current != null) {
if (current.getData().equals(data)) {
previous.setNext(current.getNext());
current = previous.getNext();
} else {
previous = previous.getNext();
current = previous.getNext();
}
}
}
public Object getFront() {
if (start != null) {
return start.getData();
} else {
return null;
}
}
public void print() {
Node current = start;
if (current == null) {
System.out.println("SingleLinkedList is Empty");
}
while (current != null) {
System.out.print(current);
current = current.getNext();
if (current != null) {
System.out.print(", ");
}
}
}
public int size() {
int size = 0;
Node current = start;
while (current != null) {
current = current.getNext();
size++;
}
return size;
}
public Node getStart() {
return this.start;
}
public Node getRear() {
Node current = start;
Node previous = current;
while (current != null) {
previous = current;
current = current.getNext();
}
return previous;
}
}
public class AddNumbersInSinglyLinkedList {
public static void main(String[] args) {
SinglyLinkedList listOne = new SinglyLinkedList();
SinglyLinkedList listTwo = new SinglyLinkedList();
listOne.addFront(5);
listOne.addFront(1);
listOne.addFront(3);
listOne.print();
System.out.println();
listTwo.addFront(2);
listTwo.addFront(9);
listTwo.addFront(5);
listTwo.print();
SinglyLinkedList listThree = add(listOne, listTwo);
System.out.println();
listThree.print();
}
private static SinglyLinkedList add(SinglyLinkedList listOne, SinglyLinkedList listTwo) {
SinglyLinkedList result = new SinglyLinkedList();
Node startOne = listOne.getStart();
Node startTwo = listTwo.getStart();
int carry = 0;
while (startOne != null || startTwo != null) {
int one = 0;
int two = 0;
if (startOne != null) {
one = (Integer) startOne.getData();
startOne = startOne.getNext();
}
if (startTwo != null) {
two = (Integer) startTwo.getData();
startTwo = startTwo.getNext();
}
int sum = carry + one + two;
carry = 0;
if (sum > 9) {
carry = sum / 10;
result.addRear(sum % 10);
} else {
result.addRear(sum);
}
}
return result;
}
}
Sample Run
Node:[Data=3], Node:[Data=1], Node:[Data=5]
Node:[Data=5], Node:[Data=9], Node:[Data=2]
Node:[Data=8], Node:[Data=0], Node:[Data=8]

**#In Python:-**
class Node():
def __init__(self,value):
self.value=value
self.nextnode=None
class LinkedList():
def __init__(self):
self.head=None
def add_element(self,value):
node=Node(value)
if self.head is None:
self.head =node
return
crnt_node=self.head
while crnt_node.nextnode is not None:
crnt_node=crnt_node.nextnode
crnt_node.nextnode=node
def reverse_llist(self):
crnt_node=self.head
if crnt_node == None:
print('Empty Linkned List')
return
old_node = None
while crnt_node:
temp_node = crnt_node.nextnode
crnt_node.nextnode = old_node
old_node = crnt_node
crnt_node = temp_node
self.head = old_node
def converted_llist(self):
crnt_node=self.head
carry_value=0
while True:
#print(crnt_node.value)
if (crnt_node.value+1)%10==0:
carry_value=1
crnt_node.value=0
print(crnt_node.value,end='->')
else:
print(crnt_node.value+carry_value,end='->')
if crnt_node.nextnode is None:
break
crnt_node=crnt_node.nextnode
print('None')
def print_llist(self):
crnt_node=self.head
while True:
print(crnt_node.value,end='->')
if crnt_node.nextnode is None:
break
crnt_node=crnt_node.nextnode
print('None')
list_convert=LinkedList()
list_convert.add_element(1)
list_convert.print_llist()
list_convert.add_element(9)
list_convert.print_llist()
list_convert.add_element(9)
list_convert.print_llist()
list_convert.add_element(9)
list_convert.print_llist()
list_convert.reverse_llist()
list_convert.print_llist()
list_convert.converted_llist()

Arrival time cannot be sorted correctly in Java

Greeting to everyone. I currently work on a program that sorting the emergency number of patients(the number that assigned by nurse when they enter the emergency room and this number determines the seriousness of their sickness too). However, if there are more than 1 patient who hold the same emergency numbers(eg: 2 patients hold emergency number 1), the one who came earlier should receive the treatment first. For this reason, I have 2 sortings, one is to sort the emergency number in ascending order and the other is to sort the time in ascending order too. But unfortunately the second sorting cannot work correctly.The following are the explanations for the type of emergency numbers:
Emergency number : 1 – Immediately life threatening
Emergency number : 2 – Urgent, but not immediately life threatening
Emergency number : 3 – Less urgent
So,now comes the coding part(Please note that this is a linkedlist)
Interface:
public interface ListInterface<T> {
public boolean add(T newEntry);
public boolean add(int newPosition, T newEntry);
public T remove(int givenPosition);
public void clear();
public boolean replace(int givenPosition, T newEntry);
public T getEntry(int givenPosition);
public boolean contains(T anEntry);
public int getLength();
public boolean isEmpty();
public boolean isFull();
}
LList class:
/**
* LList.java
* A class that implements the ADT list by using a chain of nodes,
* with the node implemented as an inner class.
*/
public class LList<T> implements ListInterface<T> {
private Node firstNode; // reference to first node
private int length; // number of entries in list
public LList() {
clear();
}
public final void clear() {
firstNode = null;
length = 0;
}
public boolean add(T newEntry) {
Node newNode = new Node(newEntry); // create the new node
if (isEmpty()) // if empty list
firstNode = newNode;
else { // add to end of nonempty list
Node currentNode = firstNode; // traverse linked list with p pointing to the current node
while (currentNode.next != null) { // while have not reached the last node
currentNode = currentNode.next;
}
currentNode.next = newNode; // make last node reference new node
}
length++;
return true;
}
public boolean add(int newPosition, T newEntry) { // OutOfMemoryError possible
boolean isSuccessful = true;
if ((newPosition >= 1) && (newPosition <= length+1)) {
Node newNode = new Node(newEntry);
if (isEmpty() || (newPosition == 1)) { // case 1: add to beginning of list
newNode.next = firstNode;
firstNode = newNode;
}
else { // case 2: list is not empty and newPosition > 1
Node nodeBefore = firstNode;
for (int i = 1; i < newPosition - 1; ++i) {
nodeBefore = nodeBefore.next; // advance nodeBefore to its next node
}
newNode.next = nodeBefore.next; // make new node point to current node at newPosition
nodeBefore.next = newNode; // make the node before point to the new node
}
length++;
}
else
isSuccessful = false;
return isSuccessful;
}
public T remove(int givenPosition) {
T result = null; // return value
if ((givenPosition >= 1) && (givenPosition <= length)) {
if (givenPosition == 1) { // case 1: remove first entry
result = firstNode.data; // save entry to be removed
firstNode = firstNode.next;
}
else { // case 2: givenPosition > 1
Node nodeBefore = firstNode;
for (int i = 1; i < givenPosition - 1; ++i) {
nodeBefore = nodeBefore.next; // advance nodeBefore to its next node
}
result = nodeBefore.next.data; // save entry to be removed
nodeBefore.next = nodeBefore.next.next; // make node before point to node after the
} // one to be deleted (to disconnect node from chain)
length--;
}
return result; // return removed entry, or
// null if operation fails
}
public boolean replace(int givenPosition, T newEntry) {
boolean isSuccessful = true;
if ((givenPosition >= 1) && (givenPosition <= length)) {
Node currentNode = firstNode;
for (int i = 0; i < givenPosition - 1; ++i) {
// System.out.println("Trace| currentNode.data = " + currentNode.data + "\t, i = " + i);
currentNode = currentNode.next; // advance currentNode to next node
}
currentNode.data = newEntry; // currentNode is pointing to the node at givenPosition
}
else
isSuccessful = false;
return isSuccessful;
}
public T getEntry(int givenPosition) {
T result = null;
if ((givenPosition >= 1) && (givenPosition <= length)) {
Node currentNode = firstNode;
for (int i = 0; i < givenPosition - 1; ++i) {
currentNode = currentNode.next; // advance currentNode to next node
}
result = currentNode.data; // currentNode is pointing to the node at givenPosition
}
return result;
}
public boolean contains(T anEntry) {
boolean found = false;
Node currentNode = firstNode;
while (!found && (currentNode != null)) {
if (anEntry.equals(currentNode.data))
found = true;
else
currentNode = currentNode.next;
}
return found;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
boolean result;
if (length == 0)
result = true;
else
result = false;
return result;
}
public boolean isFull() {
return false;
}
public String toString() {
String outputStr = "";
Node currentNode = firstNode;
while (currentNode != null) {
outputStr += currentNode.data + "\n";
currentNode = currentNode.next;
}
return outputStr;
}
private class Node {
private T data;
private Node next;
private Node(T data) {
this.data = data;
this.next = null;
}
private Node(T data, Node next) {
this.data = data;
this.next = next;
}
} // end Node
} // end LList
Patient class:
public class Patient {
private int emergencyNo;
private int queueTime;
private String patientName;
private String patientIC;
private String patientGender;
private String patientTelNo;
private String patientAdd;
private String visitDate;
public Patient() {
}
public Patient(int emergencyNo, int queueTime, String patientName, String patientIC, String patientGender, String patientTelNo, String patientAdd, String visitDate)
{
this.emergencyNo = emergencyNo;
this.queueTime = queueTime;
this.patientName = patientName;
this.patientIC = patientIC;
this.patientGender = patientGender;
this.patientTelNo = patientTelNo;
this.patientAdd = patientAdd;
this.visitDate = visitDate;
}
//set methods
public void setQueueTime(int queueTime)
{
this.queueTime = queueTime;
}
public boolean setEmergencyNo(int emergencyNo)
{
boolean varEmergencyNo = true;
if (emergencyNo != 1 && emergencyNo != 2 && emergencyNo != 3)
{
varEmergencyNo = false;
System.out.println("Emergency number is in invalid format!");
System.out.println("Emergency number is either 1, 2 or 3 only!");
System.out.println("\n");
}
else
{
this.emergencyNo = emergencyNo;
}
return varEmergencyNo;
}
public boolean setPatientName(String patientName)
{
boolean varPatientName = true;
if (patientName.equals("") || patientName.equals(null))
{
varPatientName = false;
System.out.println("The patient name cannot be empty!\n");
}
else
{
this.patientName = patientName;
}
return varPatientName;
}
public boolean setPatientIC(String patientIC)
{
boolean varPatientIC = true;
if(!patientIC.matches("^[0-9]{12}$"))
{
varPatientIC = false;
System.out.println("IC is in invalid format!");
System.out.println("It must consist of 12 numbers only!\n");
}
else
{
this.patientIC = patientIC;
}
return varPatientIC;
}
public boolean setPatientGender(String patientGender)
{
boolean varPatientGender = true;
if(!patientGender.equals("F") && !patientGender.equals("f") && !patientGender.equals("M") && !patientGender.equals("m"))
{
varPatientGender = false;
System.out.println("Gender is in invalid format!");
System.out.println("It must be either 'M' or 'F' only!\n");
}
else
{
this.patientGender = patientGender;
}
return varPatientGender;
}
public boolean setPatientTelNo(String patientTelNo)
{
boolean varPatientTelNo = true;
if((!patientTelNo.matches("^01[02346789]\\d{7}$")) && (!patientTelNo.matches("^03\\d{8}$")))
{
varPatientTelNo = false;
System.out.println("Invalid phone number!");
System.out.println("It must be in the following format : 0167890990 / 0342346789!\n");
System.out.print("\n");
}
else
{
this.patientTelNo = patientTelNo;
}
return varPatientTelNo;
}
public boolean setPatientAdd(String patientAdd)
{
boolean varPatientAdd = true;
if (patientAdd.equals("") || patientAdd.equals(null))
{
varPatientAdd = false;
System.out.println("The patient address cannot be empty!\n");
}
else
{
this.patientAdd = patientAdd;
}
return varPatientAdd;
}
public void setVisitDate(String visitDate)
{
this.visitDate = visitDate;
}
//get methods
public int getQueueTime()
{
return this.queueTime;
}
public int getEmergencyNo()
{
return this.emergencyNo;
}
public String getPatientName()
{
return this.patientName;
}
public String getPatientIC()
{
return this.patientIC;
}
public String getPatientGender()
{
return this.patientGender;
}
public String getPatientTelNo()
{
return this.patientTelNo;
}
public String getPatientAdd()
{
return this.patientAdd;
}
public String getVisitDate()
{
return this.visitDate;
}
#Override
public String toString()
{
return (this.emergencyNo + "\t\t" + this.patientName + "\t\t" + this.patientIC +
"\t\t" + this.patientGender + "\t\t" + this.patientTelNo + "\t\t" + this.patientAdd + "\t\t" + this.visitDate);
}
public String anotherToString()
{
return (this.emergencyNo + "\t\t\t\t\t\t" + this.patientName + "\t\t\t " + this.visitDate);
}
}
EmergencyCmp(Comparator)--->use for sorting the emergency numbers of the patients
import java.util.Comparator;
public class EmergencyCmp implements Comparator<Patient>
{
#Override
public int compare(Patient p1, Patient p2)
{
if(p1.getEmergencyNo() > p2.getEmergencyNo())
{
return 1;
}
else
{
return -1;
}
}
}
QueueCmp(Comparator)--->use for sorting the arrival time of the patients
import java.util.Comparator;
public class QueueCmp implements Comparator<Patient>
{
#Override
public int compare(Patient p1, Patient p2)
{
if(p1.getQueueTime() > p2.getQueueTime())
{
return 1;
}
else
{
return -1;
}
}
}
Main function:
import java.util.Calendar;
import java.util.Scanner;
import java.util.Arrays;
import java.util.*;
public class DSA {
public DSA() {
}
public static void main(String[] args) {
//patient's attributes
int emergencyNo;
int queueTime;
String patientName;
String patientIC;
String patientGender;
String patientTelNo;
String patientAdd;
String visitDate;
//counter
int j = 0;
int x = 0;
int y = 0;
int z = 0;
int count1 = 0;
int count2 = 0;
int count3 = 0;
int countEnteredPatient = 1;
int totalCount = 0;
//calendar
int nowYr, nowMn, nowDy, nowHr, nowMt, nowSc;
//others
boolean enterNewPatient = true;
String continueInput;
boolean enterNewPatient1 = true;
String continueInput1;
boolean continueEmergencyNo;
Scanner scan = new Scanner(System.in);
ListInterface<Patient> patientList = new LList<Patient>();
ListInterface<Patient> newPatientList = new LList<Patient>();
Patient[] patientArr1 = new Patient[10000];
Patient[] patientArr2 = new Patient[10000];
Patient[] patientArr3 = new Patient[10000];
Patient tempoPatient;
do{
//do-while loop for entering new patient details after viewing patient list
System.out.println("Welcome to Hospital Ten Stars!\n");
do{
//do-while loop for entering new patient details
System.out.println("Entering details of patient " + countEnteredPatient);
System.out.println("===================================\n");
Calendar calendar = Calendar.getInstance();
nowYr = calendar.get(Calendar.YEAR);
nowMn = calendar.get(Calendar.MONTH);
nowDy = calendar.get(Calendar.DAY_OF_MONTH);
nowHr = calendar.get(Calendar.HOUR);
nowMt = calendar.get(Calendar.MINUTE);
nowSc = calendar.get(Calendar.SECOND);
queueTime = calendar.get(Calendar.MILLISECOND);
visitDate = nowDy + "/" + nowMn + "/" + nowYr + ", " + nowHr + ":" + nowMt + ":" + nowSc;
//input emergency number
do{
tempoPatient = new Patient();
continueEmergencyNo = false;
int EmergencyNoOption;
try
{
do{
System.out.print("Please select 1 – Immediately life threatening, 2 – Urgent, but not immediately life threatening or 3 – Less urgent(Eg: 1) : ");
EmergencyNoOption = scan.nextInt();
scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setEmergencyNo(EmergencyNoOption) == false);
}
catch(InputMismatchException ex)
{
System.out.print("\n");
System.out.println("Invalid input detected.");
scan.nextLine();
System.out.print("\n");
continueEmergencyNo = true;
}
}while(continueEmergencyNo);
//input patient name
do{
System.out.print("Patient name(Eg: Christine Redfield) : ");
patientName = scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setPatientName(patientName) == false);
//input patient ic no
do{
System.out.print("Patient IC number(Eg: 931231124567) : ");
patientIC = scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setPatientIC(patientIC) == false);
//input patient gender
do{
System.out.print("Patient gender(Eg: M) : ");
patientGender = scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setPatientGender(patientGender) == false);
//input patient tel. no
do{
System.out.print("Patient tel.No(without'-')(Eg: 0162345678/0342980123) : ");
patientTelNo = scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setPatientTelNo(patientTelNo) == false);
//input patient address
do{
System.out.print("Patient address(Eg: 4-C9 Jln Besar 123, Taman Besar, 56000 Kuala Lumpur) : ");
patientAdd = scan.nextLine();
System.out.print("\n");
}while(tempoPatient.setPatientAdd(patientAdd) == false);
tempoPatient.setQueueTime(queueTime);
tempoPatient.setVisitDate(visitDate);
patientList.add(tempoPatient);
//decide whether want to enter a new patient or not
do{
System.out.print("Do you want to enter another new patient?(Eg: Y/N) : ");
continueInput = scan.nextLine();
if(continueInput.equals("Y") || continueInput.equals("y"))
{
enterNewPatient = true;
System.out.print("\n");
}
else if(continueInput.equals("N") || continueInput.equals("n"))
{
enterNewPatient = false;
}
else
{
System.out.println("\n");
System.out.println("Please enter Y/N only.\n");
}
}while(!continueInput.equals("Y") && !continueInput.equals("y") && !continueInput.equals("N") && !continueInput.equals("n"));
countEnteredPatient++;
}while(enterNewPatient); //end do-while loop for entering new patient details
System.out.println("\nWaiting list of patient will be displayed soon.\n");
try{
Thread.sleep(1000);
}
catch (Exception e)
{
}
System.out.println("Waiting list of patients");
System.out.println("========================\n");
System.out.println("Number\t\tEmergency number\t\tPatient name\t\t ArrivalTime");
System.out.println("============================================================================");
for(int i = 1; i <= patientList.getLength(); i++)
{
System.out.println(i + "\t\t\t" + patientList.getEntry(i).anotherToString());
}
do{
System.out.print("\nSo, now do you want to enter another new patient?(Eg: Y/N) : ");
continueInput1 = scan.nextLine();
if(continueInput1.equals("Y") || continueInput1.equals("y"))
{
enterNewPatient1 = true;
System.out.print("\n");
}
else if(continueInput1.equals("N") || continueInput1.equals("n"))
{
enterNewPatient1 = false;
}
else
{
System.out.println("\n");
System.out.println("Please enter Y/N only.\n");
}
}while(!continueInput1.equals("Y") && !continueInput1.equals("y") && !continueInput1.equals("N") && !continueInput1.equals("n"));
}while(enterNewPatient1);//end do-while loop for entering new patient details after viewing patient list
System.out.println("\nNow rearranging the list based on the seriouness and their arrival time.");
try{
Thread.sleep(1000);
}
catch (Exception e)
{
}
//create an unsorted array
Patient[] tempoPatientArr = new Patient[patientList.getLength()];
//copy the contents of patientList into tempoPatientArr
for(int i = 1; i <= patientList.getLength(); i++ )
{
tempoPatientArr[i-1] = patientList.getEntry(i);
}
//sort tempoPatientArr
Arrays.sort(tempoPatientArr, new EmergencyCmp());
//the above part until this comment line does not have problem
//check the emergency no and then categorise accordingly
for(int i = 0; i < tempoPatientArr.length; i++)
{
if(tempoPatientArr[i].getEmergencyNo() == 1)
{
patientArr1[x] = tempoPatientArr[i];
x++;
}
else if(tempoPatientArr[i].getEmergencyNo() == 2)
{
patientArr2[y] = tempoPatientArr[i];
y++;
}
else if(tempoPatientArr[i].getEmergencyNo() == 3)
{
patientArr3[z] = tempoPatientArr[i];
z++;
}
}
//to check how many !null elements by using count for 3 sub-arrays
for(int i = 0; i < patientArr1.length; i++)
{
if(patientArr1[i] != null)
{
count1++;
}
else
{
break;
}
}
for(int i = 0; i < patientArr2.length; i++)
{
if(patientArr2[i] != null)
{
count2++;
}
else
{
break;
}
}
for(int i = 0; i < patientArr3.length; i++)
{
if(patientArr3[i] != null)
{
count3++;
}
else
{
break;
}
}
//new array with elimination of null values
Patient[] newPatientArr1 = new Patient[count1];
Patient[] newPatientArr2 = new Patient[count2];
Patient[] newPatientArr3 = new Patient[count3];
//copy the contents of old sub arrays(the arrays with null values) into the new sub arrays(without null values)
for(int i = 0; i < newPatientArr1.length; i++)
{
newPatientArr1[i] = patientArr1[i];
}
for(int i = 0; i < newPatientArr2.length; i++)
{
newPatientArr2[i] = patientArr2[i];
}
for(int i = 0; i < newPatientArr3.length; i++)
{
newPatientArr3[i] = patientArr3[i];
}
totalCount = count1 + count2 + count3;
//array that used to combine all the sub-arrays
Patient[] newPatientArr = new Patient[totalCount];
//sort all sub new arrays
Arrays.sort(newPatientArr1, new QueueCmp());
Arrays.sort(newPatientArr2, new QueueCmp());
Arrays.sort(newPatientArr3, new QueueCmp());
//combine the contents of sub new arrays into the newPatientArr array
do{
for (int i = 0; i < count1; i++)
{
newPatientArr[j] = newPatientArr1[i];
j++;
}
for (int b = 0; b < count2; b++)
{
newPatientArr[j] = newPatientArr2[b];
j++;
}
for (int c = 0; c < count3; c++)
{
newPatientArr[j] = newPatientArr3[c];
j++;
}
}while(j < totalCount);
//relink the nodes
for(int i = 0; i < newPatientArr.length; i++)
{
newPatientList.add(newPatientArr[i]);
}
System.out.println("\nSorted waiting list of patients");
System.out.println("===============================\n");
System.out.println("Number\t\tEmergency number\t\tPatient name\t\t ArrivalTime");
System.out.println("============================================================================");
for(int i = 1; i <= newPatientList.getLength(); i++)
{
System.out.println(i + "\t\t\t" + newPatientList.getEntry(i).anotherToString());
}
}
}
Interface and LList class definitely do not have problems. So everyone can skip the 2 parts.
For the main function, I have a comment like this:
//the above part until this comment line does not have problem
When you all see the comment, that means the previous code does not have problem and you all may skip it and below is an attachment of the result that I got earlier:
So, from the picture you all can see that the sorting of arrival time is not correct. I hope that I can know why does this problem occurs since I cannot figure it out by myself. Thanks to all of you first.
So, after taking the advice of #Scott Hunter, I have made the following modification to the EmergencyCmp:
#Override
public int compare(Patient p1, Patient p2)
{
int value = 0;
if(p1.getEmergencyNo() > p2.getEmergencyNo())
{
value = 1;
}
else if(p1.getEmergencyNo() < p2.getEmergencyNo())
{
value = -1;
}
else if(p1.getEmergencyNo() == p2.getEmergencyNo())
{
if(p1.getQueueTime() > p2.getQueueTime())
{
return 1;
}
else
{
return -1;
}
}
return value;
}
However, the time sorting still produce a wrong result.

As I understand it (which I may not; you provided a LOT of extraneous stuff), it looks like you are trying to perform 2 distinct sorts, one after the other, such that the second is undoing the work of the first. Instead, you should define a single Comparator which compares emergency numbers and, only if they are the same, compares arrival times.

Making a Tree and Sorting out it's numbers

I have a txtfile with a list of unsorted numbers. I took the list of numbers and made an array. So now i'm trying to make a tree with those numbers and sort them out based off of what on the left and right. Right now its printing, but not sorted. I'm pretty sure the tree isn't being made right but I'm not sure how to fix it. I also want to keep track of any duplicates. In other words I don't want to print out any duplicates but instead just keep track of how many there are. Any help or advice is appreciated. Thanks in advance.
-- I pass the array of numbers in method: dealArray(), which then converts it to a int. From there those #'s are passed in findDuplicate() which I'm not sure I should be doing or not.
BigTree Class:
public class bigTree {
int data; int frequency;
bigTree Left, Right;
public bigTree makeTree(int x) {
bigTree p;
p = new bigTree();
p.data = x;
p.Left = null;
p.Right = null;
return p;
}
public void setLeft(bigTree t, int x) {
if (t.Left != null) {
System.out.println("Error");
}
else {
bigTree q;
q = t.Left;
q = makeTree(x);
}
}
public void setRight(bigTree t, int x) {
if (t.Right != null) {
System.out.println("Error");
} else {
bigTree q;
q = t.Right;
q = makeTree(x);
}
}
public void findDuplicate(int number) {
bigTree tree, p, q;
frequency = 0;
tree = makeTree(number);
//while (//there are still #'s in the list) { //1st while()
p = tree;
q = tree;
while (number != p.data && q != null) { //2nd while()
p = q;
if (number < p.data ) {
q = q.Left;
} else {
q = q.Right;
}
} //end of 2nd while()
if (number == p.data) {
Sort(p);
//System.out.println( p.data );
frequency++;
}
else {
if (number < p.data) {
setLeft(p,number);
}
else {
setRight(p, number);
}
}
//} // End of 1st while()
}
public void Sort(bigTree t) {
if (t.Left != null) {
Sort(t.Left);
}
System.out.println(t.data);
if (t.Right != null) {
Sort(t.Right);
}
//Possible print
}
public void dealArray(String[] x) {
int convert;
for (int i = 0; i < x.length; i++){
convert = Integer.parseInt(x[i]);
findDuplicate(convert);
// System.out.println(x[i]);
}
}

Rather than trying to find duplicates ahead of time, find them while building your Tree.
Your tree should probably consist of a Node like the following:
public class Node {
public int number;
public int count;
public Node left;
public Node right;
}
Build up your Binary Search Tree (There are a million tutorials on this). While adding a new element, if you find that element already exists, increment your count for that node.
Then printing is a matter of pre-order traversal (Again, there are a million tutorials on this)

Use the implementation below for hints on how to do it. Sorry I currently cannot format the code and remove the unnecessary methods.
import java.util.*;
public class TreeNode implements Iterator , Iterable{
public Object value;
public TreeNode prev;
public TreeNode left;
public TreeNode right;
private TreeNode w;
public TreeNode(){
}
public TreeNode(Object value){
this.value= value;
}
public Object[] toArray(){
Object[] a= new Object[this.size()];
int i= 0;
for(Object o : this){
a[i]= o;
i++;
}
return a;
}
public TreeNode delete(Object o){
TreeNode z= this.findNode(o);
if(z==null){
return this;
}
if(z.left != null && z.right != null){
TreeNode z1= z.right.minNode();
z.value= z1.value;
z= z1;
}
if(z.left == null && z.right == null){
TreeNode y= z.prev;
if(y==null){
return null;
}
if(y.right == z){
y.right= null;
}else{
y.left= null;
}
return this;
}
if(z.left == null || z.right == null){
TreeNode y;
if(z.left != null){
y= z.left;
}else{
y= z.right;
}
if(z.prev == null){
y.prev= null;
return y;
}else{
y.prev= z.prev;
if(z.prev.left == z){
z.prev.left= y;
}else{
z.prev.right= y;
}
}
}
return this;
}
public boolean hasNext(){
return w != null;
}
public Object next(){
Object d= w.value;
w= w.nextNode();
return d;
}
public void remove(){
}
public Iterator iterator(){
w= this.minNode();
return this;
}
public Object min(){
if(this.left == null){
return this.value;
}
return this.left.min();
}
public TreeNode minNode(){
if(this.left == null){
return this;
}
return this.left.minNode();
}
public Object max(){
if(this.right == null){
return this.value;
}
return this.right.max();
}
public void print(){
System.out.println(this.value);
if(left != null){
this.left.print();
}
if(right != null){
this.right.print();
}
}
public void printSort(){
if(left != null){
this.left.printSort();
}
System.out.println(this.value);
if(right != null){
this.right.printSort();
}
}
public static String intervals(int n, int p){
String s= " ";
return s.substring(0, n*p);
}
public void printTree(int p){
printTree0(1, p);
}
public void printTree0(int d, int p){
if(this.right != null){
this.right.printTree0(d+1, p);
}
System.out.println(intervals(d, p) + this.value);
if(this.left != null){
this.left.printTree0(d+1, p);
}
}
public boolean add(Object o){
if(this.value.equals(o)){
return false;
}
if( ((Comparable)this.value).compareTo(o) > 0 ){ //left
if(left != null){
left.add(o);
}else{
left= new TreeNode(o);
left.prev= this;
}
}else{ // right
if(right != null){
right.add(o);
}else{
right= new TreeNode(o);
right.prev= this;
}
}
return true;
}
public void addBalanced(Object o){
int l= rang(this.left);
int r= rang(this.right);
boolean ldir= true;
if(l == r){
int ls= size(this.left);
int rs= size(this.right);
if(ls > rs){
ldir= false;
}
}else{
ldir= l <= r;
}
if(ldir){
if(this.left==null){
this.left= new TreeNode(o);
}else{
this.left.addBalanced(o);
}
}else{
if(this.right==null){
this.right= new TreeNode(o);
}else{
this.right.addBalanced(o);
}
}
}
public TreeNode nextNode(){
if(this.right != null){
return this.right.minNode();
}
TreeNode t1= this;
TreeNode t2= this.prev;
while(t2!=null && t2.right==t1){
t1= t2;
t2= t2.prev;
}
return t2;
}
public TreeNode findNode(Object o){
if(this.value.equals(o)){
return this;
}
if( ((Comparable)this.value).compareTo(o) > 0 ){ //left
if(left != null){
return left.findNode(o);
}
}else{ // right
if(right != null){
return right.findNode(o);
}
}
return null;
}
public int size(){
int n= 1;
if(this.left != null){
n= n + this.left.size();
}
if(this.right != null){
n= n + this.right.size();
}
return n;
}
public static int size(TreeNode t){
if(t==null){
return 0;
}
return 1 + TreeNode.size(t.left) + TreeNode.size(t.right);
}
public int rang(){
int l= 0;
int r= 0;
if(left!=null){
l= left.rang();
}
if(right!=null){
r= right.rang();
}
return 1 +( (l > r) ? l : r ) ;
}
public static int rang(TreeNode t){
if(t==null){
return 0;
}
int l= rang(t.left);
int r= rang(t.right);
return 1 +( (l > r) ? l : r ) ;
}
public String toString(){
return "( " + value + " " + left + " " + right + " )";
}
/*
public String toString(){
String s= "( " + this.value + " ";
if(this.left == null && this.right == null){
return s + ")";
}
if(this.left==null){
s= s + "( )";
}else{
s= s + this.left;
}
if(this.right==null){
s= s + "( )";
}else{
s= s + this.right;
}
return s + ")";
}
*/
}

Binary Heap Implemented via a Binary Tree Structure

For an assignment, we were instructed to create a priority queue implemented via a binary heap, without using any built-in classes, and I have done so successfully by using an array to store the queued objects. However, I'm interested in learning how to implement another queue by using an actual tree structure, but in doing so I've run across a bit of a problem.
How would I keep track of the nodes on which I would perform insertion and deletion? I have tried using a linked list, which appends each node as it is inserted - new children are added starting from the first list node, and deleted from the opposite end. However, this falls apart when elements are rearranged in the tree, as children are added at the wrong position.
Edit: Perhaps I should clarify - I'm not sure how I would be able to find the last occupied and first unoccupied leaves. For example, I would always be able to tell the last inserted leaf, but if I were to delete it, how would I know which leaf to delete when I next remove the item? The same goes for inserting - how would I know which leaf to jump to next after the current leaf has both children accounted for?

A tree implementation of a binary heap uses a complete tree [or almost full tree: every level is full, except the deepest one].
You always 'know' which is the last occupied leaf - where you delete from [and modifying it is O(logn) after it changed so it is not a problem], and you always 'know' which is the first non-occupied leaf, in which you add elements to [and again, modifying it is also O(logn) after it changed].
The algorithm idea is simple:
insert: insert element to the first non-occupied leaf, and use heapify [sift up] to get this element to its correct place in the heap.
delete_min: replace the first element with the last occupied leaf, and remove the last occupied leaf. then, heapify [sift down] the heap.
EDIT: note that delete() can be done to any element, and not only the head, however - finding the element you want to replace with the last leaf will be O(n), which will make this op expensive. for this reason, the delete() method [besides the head], is usually not a part of the heap data structure.

I really wanted to do this for almost a decade.Finally sat down today and wrote it.Anyone who wants it can use it.I got inspired by Quora founder to relearn Heap.Apparently he was asked how would you find K near points in a set of n points in his Google phone screen.Apparently his answer was to use a Max Heap and to store K values and remove the maximum element after the size of the heap exceeds K.The approach is pretty simple and the worst case is nlog K which is better than n^2 in most sorting cases.Here is the code.
import java.util.ArrayList;
import java.util.List;
/**
* #author Harish R
*/
public class HeapPractise<T extends Comparable<T>> {
private List<T> heapList;
public List<T> getHeapList() {
return heapList;
}
public void setHeapList(List<T> heapList) {
this.heapList = heapList;
}
private int heapSize;
public HeapPractise() {
this.heapList = new ArrayList<>();
this.heapSize = heapList.size();
}
public void insert(T item) {
if (heapList.size() == 0) {
heapList.add(item);
} else {
siftUp(item);
}
}
public void siftUp(T item) {
heapList.add(item);
heapSize = heapList.size();
int currentIndex = heapSize - 1;
while (currentIndex > 0) {
int parentIndex = (int) Math.floor((currentIndex - 1) / 2);
T parentItem = heapList.get(parentIndex);
if (parentItem != null) {
if (item.compareTo(parentItem) > 0) {
heapList.set(parentIndex, item);
heapList.set(currentIndex, parentItem);
currentIndex = parentIndex;
continue;
}
}
break;
}
}
public T delete() {
if (heapList.size() == 0) {
return null;
}
if (heapList.size() == 1) {
T item = heapList.get(0);
heapList.remove(0);
return item;
}
return siftDown();
}
public T siftDown() {
T item = heapList.get(0);
T lastItem = heapList.get(heapList.size() - 1);
heapList.remove(heapList.size() - 1);
heapList.set(0, lastItem);
heapSize = heapList.size();
int currentIndex = 0;
while (currentIndex < heapSize) {
int leftIndex = (2 * currentIndex) + 1;
int rightIndex = (2 * currentIndex) + 2;
T leftItem = null;
T rightItem = null;
int currentLargestItemIndex = -1;
if (leftIndex <= heapSize - 1) {
leftItem = heapList.get(leftIndex);
}
if (rightIndex <= heapSize - 1) {
rightItem = heapList.get(rightIndex);
}
T currentLargestItem = null;
if (leftItem != null && rightItem != null) {
if (leftItem.compareTo(rightItem) >= 0) {
currentLargestItem = leftItem;
currentLargestItemIndex = leftIndex;
} else {
currentLargestItem = rightItem;
currentLargestItemIndex = rightIndex;
}
} else if (leftItem != null && rightItem == null) {
currentLargestItem = leftItem;
currentLargestItemIndex = leftIndex;
}
if (currentLargestItem != null) {
if (lastItem.compareTo(currentLargestItem) >= 0) {
break;
} else {
heapList.set(currentLargestItemIndex, lastItem);
heapList.set(currentIndex, currentLargestItem);
currentIndex = currentLargestItemIndex;
continue;
}
}
}
return item;
}
public static void main(String[] args) {
HeapPractise<Integer> heap = new HeapPractise<>();
for (int i = 0; i < 32; i++) {
heap.insert(i);
}
System.out.println(heap.getHeapList());
List<Node<Integer>> nodeArray = new ArrayList<>(heap.getHeapList()
.size());
for (int i = 0; i < heap.getHeapList().size(); i++) {
Integer heapElement = heap.getHeapList().get(i);
Node<Integer> node = new Node<Integer>(heapElement);
nodeArray.add(node);
}
for (int i = 0; i < nodeArray.size(); i++) {
int leftNodeIndex = (2 * i) + 1;
int rightNodeIndex = (2 * i) + 2;
Node<Integer> node = nodeArray.get(i);
if (leftNodeIndex <= heap.getHeapList().size() - 1) {
Node<Integer> leftNode = nodeArray.get(leftNodeIndex);
node.left = leftNode;
}
if (rightNodeIndex <= heap.getHeapList().size() - 1) {
Node<Integer> rightNode = nodeArray.get(rightNodeIndex);
node.right = rightNode;
}
}
BTreePrinter.printNode(nodeArray.get(0));
}
}
public class Node<T extends Comparable<?>> {
Node<T> left, right;
T data;
public Node(T data) {
this.data = data;
}
}
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
class BTreePrinter {
public static <T extends Comparable<?>> void printNode(Node<T> root) {
int maxLevel = BTreePrinter.maxLevel(root);
printNodeInternal(Collections.singletonList(root), 1, maxLevel);
}
private static <T extends Comparable<?>> void printNodeInternal(
List<Node<T>> nodes, int level, int maxLevel) {
if (nodes.isEmpty() || BTreePrinter.isAllElementsNull(nodes))
return;
int floor = maxLevel - level;
int endgeLines = (int) Math.pow(2, (Math.max(floor - 1, 0)));
int firstSpaces = (int) Math.pow(2, (floor)) - 1;
int betweenSpaces = (int) Math.pow(2, (floor + 1)) - 1;
BTreePrinter.printWhitespaces(firstSpaces);
List<Node<T>> newNodes = new ArrayList<Node<T>>();
for (Node<T> node : nodes) {
if (node != null) {
String nodeData = String.valueOf(node.data);
if (nodeData != null) {
if (nodeData.length() == 1) {
nodeData = "0" + nodeData;
}
}
System.out.print(nodeData);
newNodes.add(node.left);
newNodes.add(node.right);
} else {
newNodes.add(null);
newNodes.add(null);
System.out.print(" ");
}
BTreePrinter.printWhitespaces(betweenSpaces);
}
System.out.println("");
for (int i = 1; i <= endgeLines; i++) {
for (int j = 0; j < nodes.size(); j++) {
BTreePrinter.printWhitespaces(firstSpaces - i);
if (nodes.get(j) == null) {
BTreePrinter.printWhitespaces(endgeLines + endgeLines + i
+ 1);
continue;
}
if (nodes.get(j).left != null)
System.out.print("//");
else
BTreePrinter.printWhitespaces(1);
BTreePrinter.printWhitespaces(i + i - 1);
if (nodes.get(j).right != null)
System.out.print("\\\\");
else
BTreePrinter.printWhitespaces(1);
BTreePrinter.printWhitespaces(endgeLines + endgeLines - i);
}
System.out.println("");
}
printNodeInternal(newNodes, level + 1, maxLevel);
}
private static void printWhitespaces(int count) {
for (int i = 0; i < 2 * count; i++)
System.out.print(" ");
}
private static <T extends Comparable<?>> int maxLevel(Node<T> node) {
if (node == null)
return 0;
return Math.max(BTreePrinter.maxLevel(node.left),
BTreePrinter.maxLevel(node.right)) + 1;
}
private static <T> boolean isAllElementsNull(List<T> list) {
for (Object object : list) {
if (object != null)
return false;
}
return true;
}
}
Please note that BTreePrinter is a code I took somewhere in Stackoverflow long back and I modified to use with 2 digit numbers.It will be broken if we move to 3 digit numbers and it is only for simple understanding of how the Heap structure looks.A fix for 3 digit numbers is to keep everything as multiple of 3.
Also due credits to Sesh Venugopal for wonderful tutorial on Youtube on Heap data structure

public class PriorityQ<K extends Comparable<K>> {
private class TreeNode<T extends Comparable<T>> {
T val;
TreeNode<T> left, right, parent;
public String toString() {
return this.val.toString();
}
TreeNode(T v) {
this.val = v;
left = null;
right = null;
}
public TreeNode<T> insert(T val, int position) {
TreeNode<T> parent = findNode(position/2);
TreeNode<T> node = new TreeNode<T>(val);
if(position % 2 == 0) {
parent.left = node;
} else {
parent.right = node;
}
node.parent = parent;
heapify(node);
return node;
}
private void heapify(TreeNode<T> node) {
while(node.parent != null && (node.parent.val.compareTo(node.val) < 0)) {
T temp = node.val;
node.val = node.parent.val;
node.parent.val = temp;
node = node.parent;
}
}
private TreeNode<T> findNode(int pos) {
TreeNode<T> node = this;
int reversed = 1;
while(pos > 0) {
reversed <<= 1;
reversed |= (pos&1);
pos >>= 1;
}
reversed >>= 1;
while(reversed > 1) {
if((reversed & 1) == 0) {
node = node.left;
} else {
node = node.right;
}
reversed >>= 1;
}
return node;
}
public TreeNode<T> remove(int pos) {
if(pos <= 1) {
return null;
}
TreeNode<T> last = findNode(pos);
if(last.parent.right == last) {
last.parent.right = null;
} else {
last.parent.left = null;
}
this.val = last.val;
bubbleDown();
return null;
}
public void bubbleDown() {
TreeNode<T> node = this;
do {
TreeNode<T> left = node.left;
TreeNode<T> right = node.right;
if(left != null && right != null) {
T max = left.val.compareTo(right.val) > 0 ? left.val : right.val;
if(max.compareTo(node.val) > 0) {
if(left.val.equals(max)) {
left.val = node.val;
node.val = max;
node = left;
} else {
right.val = node.val;
node.val = max;
node = right;
}
} else {
break;
}
} else if(left != null) {
T max = left.val;
if(left.val.compareTo(node.val) > 0) {
left.val = node.val;
node.val = max;
node = left;
} else {
break;
}
} else {
break;
}
} while(true);
}
}
private TreeNode<K> root;
private int position;
PriorityQ(){
this.position = 1;
}
public void insert(K val) {
if(val == null) {
return;
}
if(root == null) {
this.position = 1;
root = new TreeNode<K>(val);
this.position++;
return ;
}
root.insert(val, position);
position++;
}
public K remove() {
if(root == null) {
return null;
}
K val = root.val;
root.remove(this.position-1);
this.position--;
if(position == 1) {
root = null;
}
return val;
}
public static void main(String[] args) {
PriorityQ<Integer> q = new PriorityQ<>();
System.out.println(q.remove());
q.insert(1);
q.insert(11);
q.insert(111);
q.insert(1111);
q.remove();
q.remove();
q.remove();
q.remove();
q.insert(2);
q.insert(4);
}
}