private void generateDATFiles() throws Exception {
File shellScriptPath= new File((this.getClass().getResource("/Vorlagen/Simulation/test.sh").toURI()));
ProcessBuilder pb = new ProcessBuilder(shellScriptPath.getAbsolutePath());
Process p = pb.start();
}
So I have a shell script which I want to execute. The problem is that I need the file path and I can get it using getResource but I get the error that my uri is not hierarchical so I found out that I need to use getResourceAsStream to avoid the error, but my question is how I can get the file path using getResourceAsStream?
Unfortunately it won't be an easy thing to do. If you pack the .sh script together with the other part of the program in a single .jar it won't work. You can only access it as a resourcestream and not as an URI (even if in development mode you can get the actual URI). That's because the .sh AND the class files and everything is actually in the same file for the file system (.jar).
It's not so much a java limitation as the OS. If the .sh is bundled in the jar/war/any other archive you cannot run it from the java code. (Actually you cannot do it from the command prompt either).
In order to solve it you can get the input stream and write the contents in a temporary file (you can use the java createTempFile functionality) and then execute that one. Or you can extract the .sh file from the jar(zip) and execute it
Try to do with this way.
class J{
public static void main (String a[]){
{
System.out.println(J.class.getResourceAsStream("/file.txt")
}
}
I have a java application.
I'm using eclipse to write, compile and create a runnable .jar.
The program is used to discover OCF devices.
It uses UDP and multicast.
Multicast code
public static void sendMulticast(byte[] data) throws Exception{
DatagramPacket pack = new DatagramPacket(data, data.length, mgroup, mport);
msocket.send(pack);
}
public static byte[] recieveMulticast(int timeout) throws Exception{
DatagramPacket packet;
byte[] data = new byte[AppConfig.ocf_buffer_size];
packet = new DatagramPacket(data, data.length);
msocket.setSoTimeout(timeout);
msocket.receive(packet);
return data;
}
The code works when I start it from eclipse. It also works when I run the .jar from console on Linux.
But when I start it with a double click, it doesn't work.
When started from console, it finds my test device in less then a second. When started with a double click it doesn't find it ever.
I haven't tested it on Windows yet, but the problem remains on Linux all the same.
What is the difference when you start .jar from console or by double clicking?
Why is it effecting messages on multicast?
I'm using "Package required libraries into generated JAR".
I'm using java 1.7 in eclipse, and 1.8 on Linux, maybe thats the problem? But why does running it from console work?
I would understand if I used sudo, but I didn't.
When you are running any jar from console, Console/Terminal knows which program responsible to run the any jar i.e
java -jar example.jar
but when double-clicking environment, OS/GUI manager doesn't know default responsible program to run the jar. ( Same way when you try to open some unknown extension file, Operating system will ask you open with which program/application)
To make Java open .jar files per default (i.e. double click) right click on any .jar file to select Properties. In the following window select the "Open With" tab to see e.g. the follwing choice:
The problem was in current location, system property
user.dir
This is the first function I call in my main. It doesn't work from eclipse, so I'll put an argument for disabling it (it will be disabled only during development).
static void setCurrentDir() throws URISyntaxException{
String s;
s = ESP8266_Configurator.class.getProtectionDomain().getCodeSource().getLocation().toURI().getPath();
s = s.substring(0, s.lastIndexOf('/'));
System.setProperty("user.dir",s);
}
I hope this helps someone. Code should be exported with extracted libraries, not packaged, otherwise it doesn't work.
I can get working directory of current Java program using this code:
Path path = Paths.get(*ClassName*.class.getProtectionDomain().getCodeSource().getLocation().toURI());
Also I can get CommandLine parameters (but there is no directory in the output) of running Java processes using this command wmic process get CommandLine where name='java.exe' /value
It is possible to get working directory of another Java process (better programmatically)? Probably it can be solved with some jdk/bin utilities?
You can get this information via the Attach API. To use it, you have to add the tools.jar of your jdk to your class path. Then, the following code will print the current working directories of all recognized JVM processes:
for(VirtualMachineDescriptor d: VirtualMachine.list()) {
System.out.println(d.id()+"\t"+d.displayName());
try {
VirtualMachine vm = VirtualMachine.attach(d);
try(Closeable c = vm::detach) {
System.out.println("\tcurrent dir: "+vm.getSystemProperties().get("user.dir"));
}
}
catch(AttachNotSupportedException|IOException ex) {
System.out.println("\t"+ex);
}
}
I have been breaking my head for two days trying to fix the file permissions for my tomcat7 server. I have a library class (.jar file included in myapp/WEB-INF) which needs to run a shell script. The library is written by me and works fine within NetBeans ie. no hassle in creating,reading and deleting files. That is because NetBeans runs the program as blumonkey(my username on my Ubuntu System). But when I import this into tomcat and run it, tomcat "executes" the command, produces no definite output, tries to check for a file(which will be generated when the script succeeds) and throws a FileNotFoundException.
More Details as follows:
Tomcat7 installed using apt-get, has its data in 2 locations - /var/lib/tomcat7 with conf and webapps folders and /usr/share/tomcat7 with the bin and lib folders
The user uploads a .zip file which is stores to /home/blumonkey/data. Rest of the program runs on the documents stored here. All new folders/files uploaded by tomcat have, obviously, tomcat7 as the owner.
I have tried things like changing the ownership to blumonkey, adding tomcat7 to blumonkey user group but none of the methods worked (Somewhere around here I probably messed up changing permissions carelessly :/ ). Apparently tomcat7 is unable to process on the files it owns.(How can this be?).
The script works when I run it in the terminal. But it doesn't work when I do a sudo -u tomcat7 script.sh, ie run it as tomcat7. It just exits with no message. I doubt that this it what is happening as I have tried to debug by redirecting the errors and outputs in ProcessBuilder but they came empty.
Any help regarding how to fix the issue and get the script running would be greatly appreciated. Please comment if you need any more info.
The code for script execution
private static void RunShellCommandFromJava(String command,String fn, String arg1,String arg2) throws Exception
{
try
{
System.out.println(System.getProperty("user.name"));
ProcessBuilder pbuilder = new ProcessBuilder("/bin/bash",command,fn,arg1,arg2);
System.out.println(pbuilder.command());
pbuilder.redirectErrorStream(true);
Process p = pbuilder.start();
p.waitFor();
}
catch(Exception ie)
{
throw ie;
}
}
The command which needs to be executed
"/bin/bash /abs/path/to/script.sh /abs/path/to/doc/in/data-folder maxpages=30 maxsearches=3"
PS : I have followed this question but it didn't help. I also tried other options like Runtime.exec(), bash,/bin/bash/ and /bin/bash/ -c, some of them don't work at all, others give no results.
Try to use Runtime and check standard error to find out what was the problem (probably permissions or paths):
// run command
String[] fixCmd = new String[] { "/bin/bash", "/abs/path/to/script.sh", "/abs/path/to/doc/in/data-folder", "maxpages=30", "maxsearches=3" };
Process start = Runtime.getRuntime().exec(fixCmd);
// monitor standard error to find out what's wrong
BufferedReader r = new BufferedReader(new InputStreamReader(start.getErrorStream()));
String line = null;
while ((line = r.readLine()) != null) {
System.out.println(line);
}
This question already has answers here:
What does "Could not find or load main class" mean?
(61 answers)
Closed 7 years ago.
I am having trouble compiling and running my Java code, intended to allow me to interface Java with a shared object for Vensim, a simulation modeling package.
The following code compiles without error:
javac -d . -cp ./apache-log4j-1.2.16/log4j-1.2.16.jar:./vensim.jar SpatialModel.java VensimHelper.java VensimException.java VensimContextRepository.java
However, when I try to run the following:
java -cp ./apache-log4j-1.2.16/log4j-1.2.16.jar:./vensim.jar SpatialModel vars
I get the following error: "Error: Could not find or load main class SpatialModel
". My SpatialModel.java code does contain a 'main' method (below), so I'm not sure what the problem is - can anyone please help me out? Thanks.
import java.io.File;
import java.text.NumberFormat;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import org.apache.log4j.Logger;
public class SpatialModel {
private VensimHelper vh;
public static final String DLL_LIBNAME_PARAM = "vensim_lib_nam";
public static final String MODEL_PATH_PARAM = "vensim_model_path";
private final static int VENSIM_CONTEXT_CREATION_MAX_FAILURE_COUNT = 10;
public SpatialModel() throws SpatialException {
String libName = System.getProperty(DLL_LIBNAME_PARAM);
String modelPath = System.getProperty(MODEL_PATH_PARAM);
if(libName == null || libName.trim().equals("")) {
log.error("Vensim library name has to be set with -D" + DLL_LIBNAME_PARAM);
throw new SpatialException("Vensim library name has to be set with -D" + DLL_LIBNAME_PARAM);
}
if(modelPath == null || modelPath.trim().equals("")) {
log.error("Model path has to set with -D" + MODEL_PATH_PARAM);
throw new SpatialException("Model path ahs to be set with -D" + MODEL_PATH_PARAM);
}
for (int i = 0; i < VENSIM_CONTEXT_CREATION_MAX_FAILURE_COUNT && vh == null; i++) {
try {
log.info("creating new vensim helper\n\tdll lib: " + libName + "\n\tmodel path: " + modelPath);
vh = new VensimHelper(libName, modelPath);
} catch (Throwable e) {
log.error("An exception was thrown when initializing Vensim, try: " + i, e);
}
}
if (vh == null) {
throw new SpatialException("Can't initialize Vensim");
}
}
public static void main(String[] args) throws VensimException {
long before = System.currentTimeMillis();
String libName = System.getProperty(DLL_LIBNAME_PARAM);
String modelPath = System.getProperty(MODEL_PATH_PARAM);
if (libName == null) {
libName = "libvensim";
}
if(modelPath == null) {
modelPath = "~/BassModel.vmf";
}
System.setProperty(DLL_LIBNAME_PARAM, libName);
System.setProperty(MODEL_PATH_PARAM, modelPath);
if (args.length > 0 && args[0].equals("info")) {
System.out.println(new VensimHelper(libName, modelPath).getVensimInfo());
} else if (args.length > 0 && args[0].equals("vars")) {
VensimHelper helper = new VensimHelper(libName, modelPath);
String[] vars = helper.getVariables();
for (String var : vars) {
System.out.println(helper.getVariableInfo(var));
}
} else {
File f = new File(".");
System.out.println(f.getAbsolutePath());
SpatialModel sm = new SpatialModel();
}
System.out.println("Execution time: " + (System.currentTimeMillis() - before));
}
}
You must ensure that you add the location of your .class file to your classpath. So, if its in the current folder, add . to your classpath.
Note that the Windows classpath separator is a semi-colon, i.e. a ;.
If the class is in a package
package thepackagename;
public class TheClassName {
public static final void main(String[] cmd_lineParams) {
System.out.println("Hello World!");
}
}
Then calling:
java -classpath . TheClassName
results in Error: Could not find or load main class TheClassName. This is because it must be called with its fully-qualified name:
java -classpath . thepackagename.TheClassName
And this thepackagename directory must exist in the classpath. In this example, ., meaning the current directory, is the entirety of classpath. Therefore this particular example must be called from the directory in which thepackagename exists.
To be clear, the name of this class is not TheClassName, It's thepackagename.TheClassName. Attempting to execute TheClassName does not work, because no class having that name exists. Not on the current classpath anyway.
Finally, note that the compiled (.class) version is executed, not the source code (.java) version. Hence “CLASSPATH.”
You can try these two when you are getting the error: 'could not find or load main class'
If your class file is saved in following directory with HelloWorld program name
d:\sample
java -cp d:\sample HelloWorld
java -cp . HelloWorld
I believe you need to add the current directory to the Java classpath
java -cp .:./apache-log4j-1.2.16/log4j-1.2.16.jar:./vensim.jar SpatialModel vars
You have to include classpath to your javac and java commands
javac -cp . PackageName/*.java
java -cp . PackageName/ClassName_Having_main
suppose you have the following
Package Named: com.test
Class Name: Hello (Having main)
file is located inside "src/com/test/Hello.java"
from outside directory:
$ cd src
$ javac -cp . com/test/*.java
$ java -cp . com/test/Hello
In windows the same thing will be working too, I already tried
If you work in Eclipse, just make a cleanup (project\clean.. clean all projects) of the project.
You have to set the classpath if you get the error:
Could not find or load main class XYZ
For example:
E:\>set path="c:\programfiles\Java\jdk1.7.0_17\bin"
E:\>set classpath=%classpath%;.;
E:\>javac XYZ.java
E:\>java XYZ
I got this error because I was trying to run
javac HelloWorld.java && java HelloWorld.class
when I should have removed .class:
javac HelloWorld.java && java HelloWorld
Check your BuildPath, it could be that you are referencing a library that does not exist anymore.
If you're getting this error and you are using Maven to build your Jars, then there is a good chance that you simply do not have your Java classes in src/main/java/.
In my case I created my project in Eclipse which defaults to src (rather than src/main/java/.
So I ended up with something like mypackage.morepackage.myclass and a directory structure looking like src/mypackage/morepackage/myclass, which inherently has nothing wrong. But when you run mvn clean install it will look for src/main/java/mypackage/morepackage/myclass. It will not find the class but it won't error either. So it will successfully build and you when you run your outputted Jar the result is:
Error: Could not find or load main class mypackage.morepackage.myclass
Because it simply never included your class in the packaged Jar.
I know this question was tagged with linux, but on windows, you might need to separate your cp args with a ; instead of a :.
java -cp ./apache-log4j-1.2.16/log4j-1.2.16.jar;./vensim.jar SpatialModel vars
http://docs.oracle.com/javase/7/docs/technotes/tools/windows/classpath.html
If you try to run a java application which needs JDK 1.6 and you are trying to run on JDK 1.4, you will come across this error. In general, trying to run a Java application on old JRE may fail. Try installing new JRE/JDK.
Problem is not about your main function. Check out for
javac -d . -cp ./apache-log4j-1.2.16/log4j-1.2.16.jar:./vensim.jar SpatialModel.java VensimHelper.java VensimException.java VensimContextRepository.java
output and run it.
Project > Clean and then make sure BuildPath > Libraries has the correct Library.
java -verbose:class HelloWorld might help you understand which classes are being loaded.
Also, as mentioned before, remember to call the full qualified name (i.e. include package).
I was using Java 1.8, and this error suddenly occurred when I pressed "Build and clean" in NetBeans. I switched for a brief moment to 1.7 again, clicked OK, re-opened properties and switched back to 1.8, and everything worked perfectly.
I hope I can help someone out with this, as these errors can be quite time-consuming.
This problem occurred for me when I imported an existing project into eclipse. What happens is it copied all the files not in the package, but outside the package. Hence, when I tried run > run configurations, it couldn't find the main method because it was not in the package. All I did was copy the files into the package and Eclipse was then able to detect the main method. So ultimately make sure that Eclipse can find your main method, by making sure that your java files are in the right package.
If so simple than many people think, me included :)
cd to Project Folder/src/package there you should see yourClass.java then run javac yourClass.java which will create yourClass.class then cd out of the src folder and into the build folder there you can run java package.youClass
I am using the Terminal on Mac or you can accomplish the same task using Command Prompt on windows
If you are using Eclipse... I renamed my main class file and got that error. I went to "Run As" configurator and under the class path for that project, it had listed both files in the class path. I removed old class that I renamed and left the class that had the new name and it compiled and ran just fine.
This solved the issue for me today:
cd /path/to/project
cd build
rm -r classes
Then clean&build it and run the individual files you need.
I have a similar problem in Windows, it's related to the classpath. From the command line, navigate until the directory where it's located your Java file (*.java and *.class), then try again with your commands.
I use Anypoint Studio (an Eclipse based IDE). In my case everything worked well, until I found out that while running the java code, something totally different is executed. Then I have deleted the .class files. After this point I got the error message from this question's title. Cleaning the project didn't solve the problem.
After restarting the IDE everything worked well again.