I'm new using magento api, so I generate the classes using Eclipse.
create -> new -> other -> WebService client / put de magento api wsdl.
then Eclipse creates for me the classes.
I can list all catalog_products.list using the api.
But I dont know how to create a product using the api "catalog_product.create"
I am following this docummentation to create a product but there's only example in PHP.
https://devdocs.magento.com/guides/m1x/api/soap/catalog/catalogProduct/catalog_product.create.html
here's my code.
public void consumirWebService() throws Exception {
BindingStub service = (BindingStub) new MagentoServiceLocator().getPort();
String token = service.login("user", "password");
Map<String, String>[] mapss = new Map[1];
Map<String, String> mapProduto = new HashMap<String, String>();
mapProduto.put("type", "virtual");
mapProduto.put("sessionId", "1");
mapProduto.put("set", "4");
mapProduto.put("sku", "7622300243449");
mapProduto.put("storeView", "1");
mapProduto.put("name", "NOME PRODUTO");
mapProduto.put("description", "descricao");
mapProduto.put("short_description", "short description");
mapProduto.put("weight", "1");
mapProduto.put("status", "1");
mapProduto.put("price", "100");
mapProduto.put("visibility", "4");
mapProduto.put("tax_class_id", "1");
mapProduto.put("website_ids", "1");
mapProduto.put("categories_ids", "1");
mapss[0] = mapProduto;
Object o = service.call(token, "catalog_product.create", mapss);
System.out.println("ID" + o);
}
i get this exception always :
Invalid data given. Details in error message.
Can anyone help me please
The example should be enough to understand how you create something with a SOAP Client. The names of the methods and classes are all the same , only different langauge. Try to find the equivalent of each inside your generated java classes.
Related
I am playing with Stripe-Java and I'm trying to add a card to a customer.
My code looks like this:
Customer stripeCustomer = Customer.retrieve("cus_xxxxxxx");
Map<String, Object> cardParam = new HashMap<String, Object>();
cardParam.put("number", "4242424242424242");
cardParam.put("exp_month", "11");
cardParam.put("exp_year", "2022");
cardParam.put("cvc", "123");
//token
Map<String, Object> tokenParam = new HashMap<String, Object>();
tokenParam.put("card", cardParam);
Token token = Token.create(tokenParam);
//user token
Map<String, Object> sourceParam = new HashMap<String, Object>();
sourceParam.put("source", token.getId());
//add to customer
stripeCustomer.getSources().create(sourceParam);
This works successfully on Stripe-Java version 19.45.0 but not on 20.0.0 or any versions above. Has the method to add a card changed?
A nullpointer exception is thrown
Thanks
This : stripeCustomer.getSources() will be null in v20.0.0 and above of the library because it pins to API version 2020-08-27 where customer.sources was removed by default. [0] [1]
The sources property on Customers is no longer included by default.
You can expand the list but for performance reasons we recommended
against doing so unless needed.
You would need to explicitly expand [2] "sources" when retrieving the Customer in order to populate customer.getSources()
CustomerRetrieveParams params = CustomerRetrieveParams.builder()
.addExpand("sources").build();
Customer stripeCustomer = Customer.retrieve("cus_xxxxxxx", params, null);
Also, your code uses the legacy Token API, and is passing raw card details from your server that puts you in PCI scope, you should look into the recommended integration paths : https://stripe.com/docs/payments/accept-a-payment
[0] https://github.com/stripe/stripe-java/blob/master/CHANGELOG.md#2000---2020-08-31
[1] https://stripe.com/docs/upgrades#2020-08-27
[2] https://stripe.com/docs/expand
I am messing around with RapidAPI and i dont undertand the code they give.
Could someone give me a teardown? It says in order to access api i have to write the following code
Map<String, Argument> body = new HashMap<String, Argument>();
body.put("ParameterKey1", new Argument("data", "ParameterValue1"));
body.put("ParameterKey2", new Argument("data", "ParameterValue2"));
try {
Map<String, Object> response = connect.call("APIName", "FunctionName", body);
if(response.get("success") != null) { }
what are parameter keys 1 and 2, the data, and the parameter values
edit1:this is the code snippet i want to use in android studio
HttpResponse<JsonNode> response = Unirest.get("https://spoonacular-recipe-
food-nutrition-v1.p.mashape.com/recipes/search?
diet=vegetarian&excludeIngredients=coconut&instructionsRequired=
false&intolerances=egg%2C+gluten&limitLicense=false&number=
10&offset=0&query=burger&type=main+course")
.header("X-Mashape-Key",
"Xxxxxx")
.header("X-Mashape-Host", "spoonacular-recipe-food-nutrition-
v1.p.mashape.com")
.asJson();
Your example code is using this https://github.com/zeeshanejaz/unirest-android. If you want to use that snippet you could start with that.
I have java web application (servlet) that does user authentication using SalesForce Server OAuth Authentication Flow. This OAuth Authentication provides "state" query parameter to pass any data on callback. I have a bunch of parameters that I want to pass through this "state" query param. What is the best way to do it? In java in particularly?
Or in other words, what is the best way to pass an array or map as a single http query parameter?
You can put all in json or xml format or any other format and then encode in base64 as a one large string. Take care that params can impose some hard limit on some browser/web server.
So, I have done it this way. Thank you guys! Here are some code snippets to illustrate how it works for me:
// forming state query parameter
Map<String, String> stateMap = new HashMap<String, String>();
stateMap.put("1", "111");
stateMap.put("2", "222");
stateMap.put("3", "333");
JSONObject jsonObject = new JSONObject(stateMap);
String stateJSON = jsonObject.toString();
System.out.println("stateJSON: " + stateJSON);
String stateQueryParam = Base64.encodeBase64String(stateJSON.getBytes());
System.out.println("stateQueryParam: " + stateQueryParam);
// getting map from state query param
ObjectMapper objectMapper = new ObjectMapper();
stateMap = objectMapper.readValue(Base64.decodeBase64(stateQueryParam.getBytes()), LinkedHashMap.class);
System.out.println("stateMap: " + stateMap);
Here is output:
stateJSON: {"1":"111","2":"222","3":"333"}
stateQueryParam: eyIxIjoiMTExIiwiMiI6IjIyMiIsIjMiOiIzMzMifQ==
stateMap: {1=111, 2=222, 3=333}
while trying to create a new bug in bugzilla, i am getting an error
"You must log in before using this part of Bugzilla"
Code looks like
`HttpClient httpClient = new HttpClient();
XmlRpcClient rpcClient = new XmlRpcClient();
XmlRpcCommonsTransportFactory factory = new XmlRpcCommonsTransportFactory(rpcClient);
XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
factory.setHttpClient(httpClient);
rpcClient.setTransportFactory(factory);
config.setServerURL(new URL("http://192.168.0.203/xmlrpc.cgi"));
rpcClient.setConfig(config);
// map of the login data
Map<String, String> loginMap = new HashMap<String, String>();
loginMap.put("login", "bugzilla.admin#abcd.com");
loginMap.put("password", "bugzilla#admin");
loginMap.put("rememberlogin", "Bugzilla_remember");
// login to bugzilla
Object loginResult = rpcClient.execute("User.login", new Object[]{loginMap});
System.err.println ("loginResult=" + loginResult);
// map of the bug data
Map<String, String> bugMap = new HashMap<String, String>();
bugMap.put("product", "Demo");
bugMap.put("component", "Demo_project");
bugMap.put("summary", "Bug created for test");
bugMap.put("description", "This is text ");
bugMap.put("version", "unspecified");
bugMap.put("op_sys", "Windows");
bugMap.put("platform", "PC");
bugMap.put("priority", "P2");
bugMap.put("severity", "Normal");
bugMap.put("status", "NEW");
// create bug
Object createResult = rpcClient.execute("Bug.create", new Object[]{bugMap});
System.err.println("createResult = " + createResult);
`
At first i am able to login and the response I get is-: loginResult={id=1, token=1-AJ4uG13zlJ}
but when creating a new bug error occurs
`Exception in thread "main" org.apache.xmlrpc.XmlRpcException: You must log in before using this part of Bugzilla.
at org.apache.xmlrpc.client.XmlRpcStreamTransport.readResponse(XmlRpcStreamTransport.java:197)
at org.apache.xmlrpc.client.XmlRpcStreamTransport.sendRequest(XmlRpcStreamTransport.java:156)
at org.apache.xmlrpc.client.XmlRpcHttpTransport.sendRequest(XmlRpcHttpTransport.java:143)
at org.apache.xmlrpc.client.XmlRpcClientWorker.execute(XmlRpcClientWorker.java:56)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:167)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:137)
at org.apache.xmlrpc.client.XmlRpcClient.execute(XmlRpcClient.java:126)
at com.abcd.BugCreator2.main(BugCreator2.java:52)`
Why do I get this error of login again, when I am already logged in.
Edit-:
The above code works fine when tried on https://bugzilla.mozilla.org
It seems there is some problem while configuration of Bugzilla on local server.
first of all thanks to you i was searching code just like yours...
and if you still get that error you should know that you also need to send login and password parameters for create method.
just try like this ..
add this
bugMap.put("login", "bugzilla.admin#abcd.com");
bugMap.put("password", "bugzilla#admin");
before this
bugMap.put("product", "Demo");
bugMap.put("component", "Demo_project");
bugMap.put("summary", "Bug created for test");
bugMap.put("description", "This is text ");
bugMap.put("version", "unspecified");
bugMap.put("op_sys", "Windows");
bugMap.put("platform", "PC");
bugMap.put("priority", "P2");
bugMap.put("severity", "Normal");
bugMap.put("status", "NEW");
I have a template like this in properties file: Dear xxxxxx, you are payment is succesfull.
After loading this template from properties file, I want to replace that "xxxxxx" with dynamic data in Java class.
Please help me on this.
I used Message.format("template",object array which is having dynamic data);
Try this way
placeholderReplacementMap is map that contain your static value and dynamic value key pair
Map<String, Object> placeholderReplacementMap = new HashMap<>();
StrSubstitutor substitutor = new StrSubstitutor(placeholderReplacementMap);
placeholderReplacementMap.put("xxxxxx", dynamicValue);
String newString = substitutor.replace("Dear xxxxxx","you are payment is succesful");