This question already has an answer here:
Gson: java.text.ParseException: Unparseable date: "2018-04-09T09:00:00+02:00"
(1 answer)
Closed 4 years ago.
I have a date in the following format:
2017-04-09T11:15:39.200+03:00
I used the following format string:
new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
But i am getting an exception"
java.text.ParseException: Unparseable date: "2017-04-09T11:15:39.200+03:00"
Thanks
What's wrong is that you didn't read the documentation: https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
You'd see that the pattern to use is X:
new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
And you also didn't check in stackoverflow before posting: in the same tags you used (https://stackoverflow.com/questions/tagged/simpledateformat), there's another question - a very recent one, asked today - with basically the same problem (using 'Z' inside quotes):
Gson: java.text.ParseException: Unparseable date: "2018-04-09T09:00:00+02:00"
The API docs for what you say you want shows this as the for-matter for your output wish.
"yyyy-MM-dd'T'HH:mm:ss.SSSZ"
https://docs.oracle.com/javase/8/docs/api/java/text/SimpleDateFormat.html
Related
This question already has answers here:
Why can't this SimpleDateFormat parse this date string?
(4 answers)
ParseException when parsing 3 character abbreviated month using SimpleDateFormat
(5 answers)
Closed 2 years ago.
I have oracle database with columns data type "TIMESTAMP(0) WITH TIME ZONE" . Which produces
like 14/11/2019 06:30:00, +03:00 in database .
When I am trying to get this timestamp from java
I got java.text.ParseException: Unparseable date: "28-MAY-12 07.40.03 PM +03:00" . Our project java version is 6 . I tried with
new SimpleDateFormat("dd-MM-yy hh.mm.ss") ,
new SimpleDateFormat("dd-MM-yy hh.mm.ss, Z"),
new SimpleDateFormat("dd-MM-yy hh.mm.ss, z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss, z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss, Z") ,
new SimpleDateFormat("dd/MM/yy hh.mm.ss")
But none of them worked for me all of throwing java.text.ParseException: Unparseable date error.
In my java side i have date datatype property in my class and i want to retrieve data from oracle database then parse then set to date data type property like below.
serDto.setTarih(new Timestamp(new SimpleDateFormat("dd-MM-yy hh.mm.ss").parse(str).getTime()));
For ex in db timestamp data looks like : 14/11/2019 06:30:00, +03:00 and i want to retrieve as date like above.
Thank you in advance.
A partial solution is changing the pattern so that it parses the name of the month and the am/pm marker. Change MM to MMM and add a:
new SimpleDateFormat("dd-MMM-yy hh.mm.ss a").parse(str)
However this will ignore the time zone information. It will return a date with the expected time (i.e. 07:40:03 PM) in the default local time zone where this code is running, which might be different from the time zone in the input GMT+0300.
There doesn't seem to be a way to parse +03:00 into a time zone with SimpleDateFormat in Java 6, so if you need to parse the time zone this will require more custom code.
This question already has answers here:
Is java.time failing to parse fraction-of-second?
(3 answers)
Closed 3 years ago.
So I am trying to parse:
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmssSSS");
TemporalAccessor parse = dateTimeFormatter.parse("20180521073438514");
And I receive the following error:
"Text '20180521073438514' could not be parsed at index 0"
But when I try to add sth that will separate "ss" and "SSS" it works:
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss.SSS");
TemporalAccessor parse = dateTimeFormatter.parse("20180521073438.514");
Am I missing some kind of delimiter to separate "ss" and "SSS"?
This is a bug in Java 8 which was fixed in Java 9. Have a look at the official bug report https://bugs.openjdk.java.net/browse/JDK-8031085
This question already has answers here:
Converting ISO 8601-compliant String to java.util.Date
(31 answers)
ISO 8601 String to Date/Time object in Android
(5 answers)
Closed 4 years ago.
I'm trying to parse 1980-02-22T00:00:00Z into "java.util.Date" using
SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SS'Z'").parse(stringdate)
But I got error
caused by: java.text.ParseException: Unparseable date.
How to parse String like this into Date to get time in milliseconds? I've tried to use SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SS'Z'") and SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ")
Just replace:
SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SS'Z'")
by:
SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
If you can use java8, you can use LocalDateTime class,
you can do below:
As per suggestions below, I have corrected my code to parse the date.
String text = "1980-02-22T12:10:02Z";
LocalDateTime dateTime = LocalDateTime.ofInstant(Instant.parse(text),ZoneOffset.UTC);
System.out.println(dateTime);
Result:
1980-02-22T12:10:02
I have a file file_20201013_012417.txt and I want to validate the timestamp 20201013_012417 format of this file is YYYYMMDD_HHmmSS.
I have tried SimpleDateFormat , but getting java.text.ParseException: Unparseable date execption.
Any help is appreciated.
As I known, you can try to edit the concurrency number for your pipeline at the last step of creating.
Please see the figure below.
I am using Simple XML for XML serialization in my Android project. I have problem with parsing a Date object. I receive an exception:
Unparseable date: 2012-05-01T08:22:34+02:00
Can anyone help me how to tell Simple XML what the date format is? Thanks.
SimpleXML only supports some DateFormat's, but you can use a custom Transform for Dates.
Try my example i posted here: Parse date with SimpleFramework
You have a timezone at the end of your date. Java can parse timezone offsets, but without the ยด:' divider between. So if your date timezone were +0200 instead of +02:00, it should work. You could run it through a SimpleDateFormatter.