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Setting up an incoming webhook for Hangouts Chat API with Java?

I followed the example here (Incoming webhook with Python), which sends a simple message to a Hangouts chat room and works as expected
from httplib2 import Http
from json import dumps
def main():
url = 'https://chat.googleapis.com/v1/spaces/AAAAUfABqBU/messages?key=<WEBHOCK-KEY>'
bot_message = {
'text' : 'Hello from Python script!'}
message_headers = { 'Content-Type': 'application/json; charset=UTF-8'}
http_obj = Http()
response = http_obj.request(
uri=url,
method='POST',
headers=message_headers,
body=dumps(bot_message),
)
print(response)
if __name__ == '__main__':
main()
Now I want achive the same simple thing using Java and tried it with this code
private void sendPost() throws IOException {
String url = "https://chat.googleapis.com/v1/spaces/AAAAUfABqBU/messages?key=<WEBHOCK-KEY>";
final HttpClient client = new DefaultHttpClient();
final HttpPost request = new HttpPost(url);
final HttpResponse response = client.execute(request);
request.addHeader("Content-Type", "application/json; charset=UTF-8");
final StringEntity params = new StringEntity("{\"text\":\"Hello from Java!\"}", ContentType.APPLICATION_FORM_URLENCODED);
request.setEntity(params);
final BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer result = new StringBuffer();
String line;
while ((line = rd.readLine()) != null) {
result.append(line);
}
System.out.println(result.toString());
}
But this leads to an error message saying
{
"error": {
"code": 400,
"message": "Message cannot be empty. Discarding empty create message request in spaces/AAAAUfABqBU.",
"status": "INVALID_ARGUMENT"
}
}
I assume there is something wrong with the way I add the json object. Does anybody see the mistake?

Kind of dump, but moving the line final HttpResponse response = client.execute(request); after setting the request body solves the issue.
private void sendPost() throws IOException {
String url = "https://chat.googleapis.com/v1/spaces/AAAAUfABqBU/messages?key=<WEBHOCK-KEY>";
final HttpClient client = new DefaultHttpClient();
final HttpPost request = new HttpPost(url);
// FROM HERE
request.addHeader("Content-Type", "application/json; charset=UTF-8");
final StringEntity params = new StringEntity("{\"text\":\"Hello from Java!\"}", ContentType.APPLICATION_FORM_URLENCODED);
request.setEntity(params);
// TO HERE
final HttpResponse response = client.execute(request);
final BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer result = new StringBuffer();
String line;
while ((line = rd.readLine()) != null) {
result.append(line);
}
System.out.println(result.toString());
}
Order sometimes does matter :)

Android Bad Request IOException when retrieving JSON from URL

I am using the following code to get a JSON object from a URL :
public JSONObject makeRequest(String url) throws IOException, JSONException {
JSONObject response;
String jsonString;
HttpClient httpclient = new DefaultHttpClient();
// create the request
HttpUriRequest request = new HttpGet(url);
request.addHeader("Accept-Encoding", "gzip");
// execute the request
HttpResponse resp = httpclient.execute(request);
StatusLine statusLine = resp.getStatusLine();
// check the request response status. Should be 200 OK
if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
Header contentEncoding = resp.getFirstHeader("Content-Encoding");
InputStream instream = resp.getEntity().getContent();
// was the returned response gzip'ed?
if (contentEncoding != null && contentEncoding.getValue().equalsIgnoreCase("gzip")) {
instream = new GZIPInputStream(instream);
}
BufferedReader reader = new BufferedReader(new InputStreamReader(instream));
StringBuilder responseString = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
responseString.append(line);
}
jsonString = responseString.toString();
response = new JSONObject(jsonString);
} else {
resp.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
return response;
}
But I get an error saying bad request on this line :
throw new IOException(statusLine.getReasonPhrase());
and the result is not returned.
How do I fix this ?
Thanks !

Try to use this code instead. Much simplified.
try {//Making a request to server getting entities
JSONObject json = new JSONObject(EntityUtils.toString(new DefaultHttpClient().execute(new HttpGet(URL)).getEntity()));
//getting json root object
JSONObject obj = json.getJSONObject("ROOT_ELEMENT");
} catch (JSONException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

HTTP POST request with JSON String in JAVA

I have to make a http Post request using a JSON string I already have generated.
I tried different two different methods :
1.HttpURLConnection
2.HttpClient
but I get the same "unwanted" result from both of them.
My code so far with HttpURLConnection is:
public static void SaveWorkflow() throws IOException {
URL url = null;
url = new URL(myURLgoeshere);
HttpURLConnection urlConn = null;
urlConn = (HttpURLConnection) url.openConnection();
urlConn.setDoInput (true);
urlConn.setDoOutput (true);
urlConn.setRequestMethod("POST");
urlConn.setRequestProperty("Content-Type", "application/json");
urlConn.connect();
DataOutputStream output = null;
DataInputStream input = null;
output = new DataOutputStream(urlConn.getOutputStream());
/*Construct the POST data.*/
String content = generatedJSONString;
/* Send the request data.*/
output.writeBytes(content);
output.flush();
output.close();
/* Get response data.*/
String response = null;
input = new DataInputStream (urlConn.getInputStream());
while (null != ((response = input.readLine()))) {
System.out.println(response);
input.close ();
}
}
My code so far with HttpClient is:
public static void SaveWorkflow() {
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost(myUrlgoeshere);
StringEntity input = new StringEntity(generatedJSONString);
input.setContentType("application/json;charset=UTF-8");
postRequest.setEntity(input);
input.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json;charset=UTF-8"));
postRequest.setHeader("Accept", "application/json");
postRequest.setEntity(input);
HttpResponse response = httpClient.execute(postRequest);
BufferedReader br = new BufferedReader(
new InputStreamReader((response.getEntity().getContent())));
String output;
while ((output = br.readLine()) != null) {
System.out.println(output);
}
httpClient.getConnectionManager().shutdown();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
Where generated JsonString is like this:
{"description":"prova_Process","modelgroup":"","modified":"false"}
The response I get is:
{"response":false,"message":"Error in saving the model. A JSONObject text must begin with '{' at 1 [character 2 line 1]","ids":[]}
Any idea please?

Finally I managed to find the solution to my problem ...
public static void SaveWorkFlow() throws IOException
{
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost post = new HttpPost(myURLgoesHERE);
List<NameValuePair> params = new ArrayList<>();
params.add(new BasicNameValuePair("task", "savemodel"));
params.add(new BasicNameValuePair("code", generatedJSONString));
CloseableHttpResponse response = null;
Scanner in = null;
try
{
post.setEntity(new UrlEncodedFormEntity(params));
response = httpClient.execute(post);
// System.out.println(response.getStatusLine());
HttpEntity entity = response.getEntity();
in = new Scanner(entity.getContent());
while (in.hasNext())
{
System.out.println(in.next());
}
EntityUtils.consume(entity);
} finally
{
in.close();
response.close();
}
}

Another way to achieve this is as shown below:
public static void makePostJsonRequest(String jsonString)
{
HttpClient httpClient = new DefaultHttpClient();
try {
HttpPost postRequest = new HttpPost("Ur_URL");
postRequest.setHeader("Content-type", "application/json");
StringEntity entity = new StringEntity(jsonString);
postRequest.setEntity(entity);
long startTime = System.currentTimeMillis();
HttpResponse response = httpClient.execute(postRequest);
long elapsedTime = System.currentTimeMillis() - startTime;
//System.out.println("Time taken : "+elapsedTime+"ms");
InputStream is = response.getEntity().getContent();
Reader reader = new InputStreamReader(is);
BufferedReader bufferedReader = new BufferedReader(reader);
StringBuilder builder = new StringBuilder();
while (true) {
try {
String line = bufferedReader.readLine();
if (line != null) {
builder.append(line);
} else {
break;
}
} catch (Exception e) {
e.printStackTrace();
}
}
//System.out.println(builder.toString());
//System.out.println("****************");
} catch (Exception ex) {
ex.printStackTrace();
}
}

How to get text from website to string?

How to get XML from this URL into String on Android? I was trying to do it with tutorials, but no way was successful. Here is my code:
public String getXmlFromUrl(String url) {
String text = "";
try {
HttpGet get = new HttpGet(url);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(get);
InputStream inputStream = response.getEntity().getContent();
String line = "";
BufferedReader rd = new BufferedReader(new InputStreamReader(inputStream));
while ((line = rd.readLine()) != null) {
text += line;
}
} catch (Exception e) {
e.printStackTrace();
}
return text;
}

Send key-value parametres and json message body throught http post request

I need to send http POST request from mobile android application to the server side applcation.
This request need to contain json message in body and some key-value parametres.
I am try to write this method:
public static String makePostRequest(String url, String body, BasicHttpParams params) throws ClientProtocolException, IOException {
Logger.i(HttpClientAndroid.class, "Make post request");
HttpPost httpPost = new HttpPost(url);
StringEntity entity = new StringEntity(body);
httpPost.setParams(params);
httpPost.setEntity(entity);
HttpResponse response = getHttpClient().execute(httpPost);
return handleResponse(response);
}
Here i set parametres to request throught method setParams and set json body throught setEntity.
But it isn't work.
Can anybody help to me?

You can use a NameValuePair to do this..........
Below is the code from my project where I used NameValuePair to sent the xml data and receive the xml response, this will provide u some idea about how to use it with JSON.
public String postData(String url, String xmlQuery) {
final String urlStr = url;
final String xmlStr = xmlQuery;
final StringBuilder sb = new StringBuilder();
Thread t1 = new Thread(new Runnable() {
public void run() {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(urlStr);
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
1);
nameValuePairs.add(new BasicNameValuePair("xml", xmlStr));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
Log.d("Vivek", response.toString());
HttpEntity entity = response.getEntity();
InputStream i = entity.getContent();
Log.d("Vivek", i.toString());
InputStreamReader isr = new InputStreamReader(i);
BufferedReader br = new BufferedReader(isr);
String s = null;
while ((s = br.readLine()) != null) {
Log.d("YumZing", s);
sb.append(s);
}
Log.d("Check Now",sb+"");
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
});
t1.start();
try {
t1.join();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("Getting from Post Data Method "+sb.toString());
return sb.toString();
}