I have a button in my application which opens the imdb application in the phone with a imdb id I received from https://developers.themoviedb.org/3/getting-started/introduction
But I couldnt find anyway(using intents) to make my app recognize the imdb app and open it and if imdb app do not exist then I want to open the web site. How can I accomplish this?
I think I may be able to point you in the right direction. Just to be sure, you seem to be using TMDB but wish to open in the IMDB app?
The code below is from the Android documentation.
It will start your intent if the package manager can find an app with the appropriate intent filter installed on your device. If multiple apps are able to open this intent then an app chooser should pop up, unless the user has previously set a default for this kind of URI.
Intent sendIntent = new Intent(Intent.ACTION_SEND);
// Always use string resources for UI text.
// This says something like "Share this photo with"
String title = getResources().getString(R.string.chooser_title);
// Create intent to show the chooser dialog
Intent chooser = Intent.createChooser(sendIntent, title);
// Verify the original intent will resolve to at least one activity
if (sendIntent.resolveActivity(getPackageManager()) != null) {
startActivity(chooser);
}
If you add an else onto that then you can use a view intent like this :
Intent internetIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(movieUrl));
//Watch out here , There is a URI and Uri class!!!!
if (internetIntent.resolveActivity(getPackageManager()) != null){
startActivity(internetIntent);
}
I also found this (rather old) post about calling an explicit imdb uri
Imdb description
startActivity(android.intent.action.VIEW, imdb:///title/<titleID>);
// take note of the Uri scheme "imdb"
I hope this helps. If you post some more detail , code, links , I might be able to work through this with you.
If my answer is way off base then please be kind and set me right. We are all learning every day!
Good Luck.
Related
I've added a button to my application which is supposed to open the download folder of the phone, and from there you should be able to click on files that were stored there, from the same app. Right now im saving some data there.
Problem is; I cant open the saved files in the folder.
I can see the files stored right there, but when I press one of them you immediatley go back to the app and not the file that you pressed.
Is there something I'm missing? Are you not supposed to open files stored in external storage from another app?
I've tried adding permissions in manifest and checkSelfpermission for checks in runtime, but with no success.
Here's the button for opening download folder:
private void openSavedLocation(){
if (ContextCompat.checkSelfPermission(ExportAndImport.this, Manifest.permission.READ_EXTERNAL_STORAGE) != PackageManager.PERMISSION_GRANTED)
{
ActivityCompat.requestPermissions(ExportAndImport.this, new String[] {Manifest.permission.READ_EXTERNAL_STORAGE}, 1);
}
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
Uri uri = Uri.parse(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS).getPath());
intent.setDataAndType(uri, "text/xml");
startActivity(Intent.createChooser(intent, "Open Folder"));}
I can open the file perfectly when Im opening it outside the app, not via this "createChooser". What could i be missing?
Any help is appreciated.
but when I press one of them you immediatley go back to the app and not the file that you pressed
That is what your code does. ACTION_GET_CONTENT says "let the user pick a piece of content". It does not say "open that piece of content in some other app". There is no single Intent action for saying "let the user pick a piece of content, then open that piece of content in some other app".
Is there something I'm missing?
If you want to try to open the XML in some other app:
Use startActivityForResult(), not startActivity(), for your ACTION_GET_CONTENT request (and get rid of the createChooser() bit)
Override onActivityResult() to get the result of the user's choice
If the user chose something (i.e., you get RESULT_OK in onActivityResult()), create an ACTION_VIEW Intent wrapped around the Uri that you get from the Intent passed into onActivityResult(), and call startActivity() on the ACTION_VIEW Intent
If, instead, your objective is to open this XML in your app, you would:
Use startActivityForResult(), not startActivity(), for your ACTION_GET_CONTENT request (and get rid of the createChooser() bit)
Override onActivityResult() to get the result of the user's choice
If the user chose something (i.e., you get RESULT_OK in onActivityResult()), get the Uri of the content from the Intent passed into onActivityResult(), then use ContentResolver to do something useful with that Uri (e.g., openInputStream() to read in the content)
Here's the button for opening download folder
ACTION_GET_CONTENT uses the MIME type. It will not necessarily honor your supplied starting Uri.
This question already has answers here:
Android ACTION_SEND event: "messaging failed to upload attachment"
(2 answers)
Closed 5 years ago.
I am trying to create a Sharing Intent for an Android App to share images to other apps. However, I'm getting this really weird result when implementing this feature.
I have a share button that when I click on the button, it runs the following method:
private void shareIntent() {
Uri currUri = Uri.parse(data.get(pos).getUrl());
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
sharingIntent.setAction(Intent.ACTION_SEND);
sharingIntent.putExtra(Intent.EXTRA_STREAM, currUri);
sharingIntent.setType("image/jpg");
startActivity(Intent.createChooser(sharingIntent, getResources().getText(R.string.share_to)));
}
data.get(pos).getUrl() returns the URL of a custom class I made that implements Parcelable, and when printing it out, it returns a directory like the following: "/storage/emulated/0/Pictures/primitive/Primitive-79538313.jpg"
The intent works at first, opening the sharing menu. However, when I click on most applications, it either crashes the application or it gives an error... except with Google Photos, which uploads the photo properly to the gallery.
Firstly, I'm wondering what I'm doing wrong to cause this issue in the other apps. Also, I'd like to know if someone has an explanation as to why only Google Photos allows the sharing feature to work, while many of the other apps I've tested do not.
For reference, here are some examples I've run with the sharing intent. When I try to share the image, it crashes Hangouts. It gives a "failed to load image" error message in Snapchat, "Unable to share file" in Slack and Gmail, "Upload was unsuccessful" in Drive, "Messenger was unable to process the file" in, well, Messenger, and "Couldn't load image" in GroupMe. It doesn't load the image in Facebook but doesn't crash nor give an error.
Thank you for any help or feedback you can provide!
EDIT:
This seemed to work without trying to get around App Permissions:
private void shareIntent() {
File imageFile = new File(data.get(pos).getUrl());
Uri uriToImage = FileProvider.getUriForFile(
this, BuildConfig.APPLICATION_ID + ".provider", imageFile);
Intent shareIntent = ShareCompat.IntentBuilder.from(DetailActivity.this)
.setStream(uriToImage)
.getIntent();
shareIntent.setData(uriToImage);
shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
shareIntent.setType("image/jpeg");
startActivity(Intent.createChooser(shareIntent, "Share image"));
}
Thank you to everyone that responded!
Change your code to this
private void shareIntent() {
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setType("image/jepg");
shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse("file://"+data.get(pos).getUrl()));
startActivity(Intent.createChooser(shareIntent, "Share image"));
}
Add this code in your activity onCreate()
StrictMode.VmPolicy.Builder builder = new StrictMode.VmPolicy.Builder();
StrictMode.setVmPolicy(builder.build());
I am trying to share a link from my app with direct share. The share dialog must be like the image below with the most used contacts from messaging apps, like WhatsApp contacts.
This is the Intent structure which I am using for share the link:
Intent shareIntent = ShareCompat.IntentBuilder
.from(getActivity())
.setType("text/plain")
.setText(sTitle+ "\n" + urlPost)
.getIntent();
if (shareIntent.resolveActivity(
getActivity().getPackageManager()) != null)
startActivity(shareIntent);
And this is what my app shows:
Any idea how to achieve that?
You should use .createChooserIntent() instead of .getIntent()
Like this code below, you can use Intent.createChooser
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
Uri screenshotUri = Uri.parse("file://" + filePath);
sharingIntent.setType("image/png");
sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
startActivity(Intent.createChooser(sharingIntent, "Share image using"));
You should use .createChooserIntent() instead of .getIntent()
Docs: This uses the ACTION_CHOOSER intent, which shows
an activity chooser, allowing the user to pick what they want to before proceeding. This can be used as an alternative to the standard activity picker that is displayed by the system when you try to start an activity with multiple possible matches, with these differences in behavior:
You can specify the title that will appear in the activity chooser.
The user does not have the option to make one of the matching activities a preferred activity, and all possible activities will
always be shown even if one of them is currently marked as the
preferred activity.
This action should be used when the user will naturally expect to
select an activity in order to proceed. An example if when not to use
it is when the user clicks on a "mailto:" link. They would naturally
expect to go directly to their mail app, so startActivity() should be
called directly: it will either launch the current preferred app, or
put up a dialog allowing the user to pick an app to use and optionally
marking that as preferred.
In contrast, if the user is selecting a menu item to send a picture
they are viewing to someone else, there are many different things they
may want to do at this point: send it through e-mail, upload it to a
web service, etc. In this case the CHOOSER action should be used, to
always present to the user a list of the things they can do, with a
nice title given by the caller such as "Send this photo with:".
I am currently in the process of creating direct intents to a selection of popular platforms in an Android app to share some text. I am currently trying to get a direct intent working with LinkedIn.
I have currently got a direct intent working for Twitter like so:
shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setClassName("com.twitter.android",
"com.twitter.android.PostActivity");
shareIntent.setType("text/*");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, text);
startActivityForResult(shareIntent, 9);
What I need now is the same for LinkedIn. So far I know the base package for LinkedIn after searching on the internet. That being "com.linkedin.android" (Please correct me if this is wrong). However, the key part I am missing is the name of the class that deals with sharing in the LinkedIn app. I.e. com.linkedin.android.?.
I managed to find the intent by extracting the LinkedIn Manifest file from the APK.
The class name is: com.linkedin.android.home.UpdateStatusActivity
My code for anyone interested is:
if(Utils.doesPackageExist(getSherlockActivity(), "com.linkedin.android"))
{
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setClassName("com.linkedin.android",
"com.linkedin.android.home.UpdateStatusActivity");
shareIntent.setType("text/*");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, shareText);
startActivity(shareIntent);
}
else
{
Toast.makeText(getSherlockActivity(), "Please install the LinkedIn app to share your result", Toast.LENGTH_LONG).show();
}
Credit to Ryszard Wiśniewski for his work on http://code.google.com/p/android-apktool/
As of my writing, the new class name is:
com.linkedin.android.infra.deeplink.DeepLinkHelperActivity
So all together:
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setClassName("com.linkedin.android",
"com.linkedin.android.infra.deeplink.DeepLinkHelperActivity");
shareIntent.setType("text/*");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, shareText);
startActivity(shareIntent);
It is com.linkedin.android.publishing.sharing.ShareActivity , you can download this app and see what is the current Activity name thats running on your phone https://play.google.com/store/apps/details?id=com.willme.topactivity ... But com.linkedin.android.publishing.sharing.ShareActivity seems its a private class and you can't access as you access Twitter
I'm trying to make a button in my App open the built in gallery.
public void onClick(View v) {
Intent intentBrowseFiles = new Intent(Intent.ACTION_VIEW);
intentBrowseFiles.setType("image/*");
intentBrowseFiles.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intentBrowseFiles);
}
This results in an error message "The application Camera (process com.android.gallery) has stopped unexpectedly."
If I set the Intent action to ACTION_GET_CONTENT it manages to open the gallery but then simply returns the image to my app when a picture is selected which is not what I want.
I'm trying to make a button in my App open the built in browser.
Your question subject says "Gallery". Your first sentence in the question says "browser". These are not the same thing.
If I set the Intent action to ACTION_GET_CONTENT it manages to open the gallery but then simply returns the image to my app when a picture is selected which is not what I want.
Of course, actually telling us "what [you] want" would just be too useful, so you are making us guess.
I am going to go out on a limb and guess that you are trying to open the Gallery application just as a normal application. Note that there is no Gallery application in the Android OS. There may or may not be a Gallery application on any given device, and it may or may not be one from the Android open source project.
However, for devices that have the Android Market on them, they should support an ACTION_VIEW Intent with a MIME type obtained from android.provider.MediaStore.Images.Media.CONTENT_TYPE.