Initializing 2D ArrayList for for-loop summation (Java) - java

I am trying to sum N pairs of ints--an Nx2 ArrayList--and return the N summations as an ArrayList. While I understand it is not necessary to set up a class to accomplish this, I would like to do so as practice for future projects.
import java.util.ArrayList;
public class SumsInLoop {
public SumsInLoop(int numberOfPairs, ArrayList<ArrayList<Integer>> numbersList) {}
public ArrayList<Integer> getSums(int numberOfPairs, ArrayList<ArrayList<Integer>> numbersList) {
ArrayList<Integer> pairsOfSums = new ArrayList<Integer>();
for (ArrayList<Integer> Pair : numbersList) {
int x = Pair.get(0);
int y = Pair.get(1);
int sum = x + y;
pairsOfSums.add(sum);
}
System.out.println(pairsOfSums);
return pairsOfSums;
}
The data that I am given is a random assortment of N pairs (numbersOfPairs) of integers, e.g. 612673 108695. I would like to add these pairs of integers to a 2D ArrayList (numbersList) that will be called by getSums.
However, I am having difficulties initializing numbersList. My main function is as follows:
public static void main(String[] args) {
int myNumberOfPairs = 13;
ArrayList[][] myNumbersList = new ArrayList[13][2];
myNumbersList[0][0] = new ArrayList<>();
myNumbersList[0][0].add(612673);
myNumbersList[0][1].add(108695);
myNumbersList[1][0] = new ArrayList<>();
myNumbersList[1][0].add(756875);
myNumbersList[1][1].add(496058);
SumsInLoop mySum = new SumsInLoop(myNumberOfPairs,myNumbersList);
mySum.getSums(myNumberOfPairs, myNumbersList);
The last two lines of code throw errors, asking me to change myNumbersList to type ArrayList<List<Integer>> which throws even more errors, even after changing all 2D ArrayLists to type ArrayList<List<Integer>>.
So, my two questions are as follows:
How can I initialize an NxM ArrayList and populate it correctly?
Is there a faster way of accomplishing this task while still using a class method?
P.S. I'm used to coding in Python and am self-teaching myself Java, so any other information or resources you can provide me with are much appreciated.

You may want to simplify your input by using 2D array of int : int[][] myNumbersList = new int[13][2];
The expected output in that case is a 1D array of int[13] that can be obtained as follows (demonstrated with 2 pairs. See mcve ) :
public class SumsInLoop {
//pairsOfInts should be an [n][2] array
private static int[] sumOfPairs(int[][] pairsOfInts) {
int[] sums = new int[pairsOfInts.length];
for(int pairIndex = 0; pairIndex < pairsOfInts.length; pairIndex++) {
sums[pairIndex]= pairsOfInts[pairIndex][0]+pairsOfInts[pairIndex][1];
}
return sums;
}
public static void main(String[] args) {
int numberOfPairs = 2;
int[][] pairsOfInts = new int[numberOfPairs][2];
pairsOfInts[0] = new int[] {612673,108695 };
pairsOfInts[1] = new int[] {756875,496058 };
int[] sumOfPairs = sumOfPairs(pairsOfInts);
System.out.println(Arrays.toString(sumOfPairs));
}
}
If you want a solution implemented with List you can make use of javafx Pair (or make your own pair class.
The input can be defined as List<Pair<Integer,Integer>> pairsOfInts = new ArrayList<>();
The out put can be an array as above, or a List<Integer>:
import java.util.ArrayList;
import java.util.List;
import javafx.util.Pair;
public class SumsInLoop {
private static List<Integer> sumOfPairs(List<Pair<Integer, Integer>> pairsOfInts) {
List<Integer> sums = new ArrayList<>();
for(Pair<Integer,Integer> pair : pairsOfInts) {
sums.add(pair.getKey()+ pair.getValue());
}
return sums;
}
public static void main(String[] args) {
List<Pair<Integer,Integer>> pairsOfInts = new ArrayList<>();
pairsOfInts.add (new Pair<>(612673,108695 ));
pairsOfInts.add (new Pair<>(756875,496058));
List<Integer> sumOfPairs = sumOfPairs(pairsOfInts);
System.out.println(sumOfPairs);
}
}

The (compile) exception you are getting is due to the fact that you expect a ArrayList<ArrayList<Integer>>, but pass an ArrayList[][]. (which is not the same in Java)
In your case you'd need (in the main method):
ArrayList<ArrayList<Integer>> myNumbersList = new ArrayList</* when java > 6 ;)*/>(13);
this only sets the capacity of the (parent) list (..and the underlying/internal backing array)
to initialize the child lists, you'd not come around looping (somehow...even not in python :):
for (int i = 0; i < 13; i++) {
myNumbersList.add(new ArrayList<Integer>(2));
}
Depends on what means "correctly" ...but I assume with "random data", ideally you would again inner loop:
java.util.Random rnd = new Random(/*seed default current timestamp*/);
//...
for (int i = 0; i < 13; i++) {
ArrayList<Integer> innerList = new ArrayList<>(2);
for (int j = 0; j < 2; j++) {
innerList.add(rnd.netxInt(/*bound default Integer.MAX_VALUE*/) /*+/-/% offset*/);
}
myNumberList.add(innerList);
}
Sorry I am not aware of one (faster way), but much depends on the "input format".

Since you already know the amount of values in a pair, an ArrayList is unnecessary. You can create your own, simpler implementation of a pair.
class Pair {
public final int left;
public final int right;
public Pair(int left, int right){
this.left = left;
this.right = right;
}
}
You can then access the values by creating a pair object and accessing its fields.
Pair p = new Pair(10, 7);
System.out.println(p.left); // 10
System.out.println(p.right); // 7
You can then more easily redefine your getSums method.
public static List<Integer> getSums(List<Pair> pairs){
List<Integer> pairsOfSums = new ArrayList<>();
for(Pair pair : pairs){
int sum = pair.left + pair.right;
pairsOfSums.add(sum);
}
return pairsOfSums;
}
Please also notice the function can be static and you don't need to pass the number of pairs. The for-each loop will cycle through all of them regardless.
Initializing the array is then easier than the method you have described in the question.
List<Pair> pairs = new ArrayList<>();
pairs.add(new Pair(7, 10));
pairs.add(new Pair(18, 3));
pairs.add(new Pair(-6, 0));
pairs.add(new Pair(4, 2));
System.out.println(SumsInLoop.getSums(pairs));

Related

random elements from a list DURING the addition

There are 20 names in my code.
my function has 2 options to add elements to a list I've:
1.
Inserting all the 20 names to the list:
public void addNames() {
list.add("name1");
list.add("name2");
...
list.add("name20");
}
2.
Adding only 5 random names(from the 20 names) to the list. For doing it, I thought about 2 ways. What's the best way to random 5 names from the 20? maybe you have a better way.
A.
Using a random set of indices (each value will be between 0 to 19 because there are 20 names) and before the 'add' I'll check if adding them or not by some counter:
public void addNames() {
// adding 5 random indices between 0 to 19 to the set
Set<Integer> set = new HashSet<Integer>();
Random r = new Random();
Set<Integer> indices = new HashSet<>(numRandomNames); //==5
for (int i = 0; i < numRandomNames; ++i) {
int index = r.nextInt(numNames - 0); //==19
indices.add(index);
}
int counter = 0;
if (indices.contains(counter)) {
list.add("name1");
}
counter++;
if (indices.contains(counter)) {
list.add("name2");
}
counter++;
if (indices.contains(counter)) {
list.add("name3");
}
...
}
B.
RandomList that extends List and overrides the 'add' function to do the same as 'A.' does BUT the override 'add' will decide whether adding the value inside the function so my function will look the same as 1. with the override 'add' function
Do you think about a better solution? if not, then which one is better? (A or B?). I just saw that people recommends not to extend the java collection but I think it's the best solution from these 2 solutions.
NOTE
====
my code can have 10000 names or more even so I don't want to add all the 10,000 names to this\other list and then random 5 of them to other list. I prefer to do it DURING the addition in order to avoid many places of the list while I don't really need them.
EDIT
an answer to ProgrammerTrond:
I'm not sure I'll do it but what I asked me to show is my suggestion of 2.B:
public class RandomList<Integer> implements List<Integer> {
private int addCallsCounter;
private Set<Integer> setIndices = null;
public RandomList(final int numElements, final int maxVal, final int minVal) {
addCallsCounter = 0;
setIndices = new HashSet<Integer>(numElements);
Random r = new Random();
while (setIndices.size() < numElements) {
int index = r.nextInt(maxVal - minVal + 1) + minVal;
if (setIndices.contains(index) == false) {
setIndices.add(index);
}
}
}
#Override
public boolean add(Integer object) {
if (setIndices.contains(addCallsCounter++)) {
this.add(object);
return true;
}
return false;
}
}
and from my code I'll do so:
RandomList randList = new RandomList(5);
randList.add("name1");
randList.add("name2");
randList.add("name3");
...
randList.add("name19");
randList.add("name20");
but my problem is that I need to implement MANY abstract methods of List pfff. RandomList cann't be abstract too because then it won't be able to be instantiated.
try this:
List<Integer> index = new ArrayList<>();
List<String> five_names = new ArrsyList<>();
List<String> allnames = new ArrayList<>();
store five random values
for(int i = 0;i < 5;i++){
int index_no = getrandomNumber();
index.add(index_no);
five_names.add(allnames.get(index_no));
}
getRandomNumber method:
public int getRandomNumber(){
Random rnd = new Random();
int x = rnd.nextInt(20);
if(index.contains(x)){
return getRandomNumber();
}else{
return x
}
}
Why not like this? You don't need the random index list in your list implementation. Didn't you just want a method that would add to a list 5 random names drawn from a set of available names?
import java.util.*;
public class ListAdding {
private static List<String> allNames = Arrays.asList("name1", "name2", "name3", "name4", "name5", "name6", "name7");
public static void main(String[] args) {
new Temp().test();
}
void test() {
List<String> list = new ArrayList<>();
list.add("Bernie");
addFiveRandom(list);
for (int i = 0; i < list.size(); i++) {
System.out.println(i + ": " + list.get(i));
}
// Example: 0: Bernie
// 1: name2
// 2: name3
// 3: name6
// and so on
}
void addFiveRandom(List<String> toBeAddedTo) {
List<Integer> indices = new ArrayList<>();
while (indices.size() < 5) {
int newIndex = new Random().nextInt(5);
if (!indices.contains(newIndex))
indices.add(newIndex);
}
for (Integer index : indices) {
toBeAddedTo.add(allNames.get(index));
}
}
}

How do you make an Arraylist of RandomNumber integers? java

So I am relatively new to the programming scene and I am confused as to why my code doesn't work. I am trying to make an arraylist of flowers and then use a random number generator to create a random number of certain flowers, and store them in the array. In my logic, I thought that I created a variable to store the numbers (ex randomRoses) and stored the number in the array so I could easily print out how many of each flower there is by just calling the arraylist and the position. (ex flowerArray[0] would print out 8 Roses) but sadly it does not.
public class Flower
{
private int randomRoses;
private int randomTulips;
private int randomOrchids;
public ArrayList <Integer> flowerArray;
public Flower()
{
r = new Random();
t = new Random();
o = new Random();
int randomRoses = (r.nextInt(10) + 0);
int randomTulips = (t.nextInt(10) + 0);
int randomOrchids = (o.nextInt(10) + 0);
flowerArray = new ArrayList<Integer>
}
public void add2Array ()
{
flowerArray.add(randomRoses); //flowerArray[0] is the # of roses
flowerArray.add(randomTulips); //flowerArray[1] is the # of tulips
flowerArray.add(randomOrchids); //flowerArray[2] is the # of orchids
}
public void printArray()
{
System.out.println(flowerArray[0]);
}
You can use the same random object, no need to create 3 instances of it for the random integer generation,
Random r = new Random();
for (int i = 0; i < 3; i++) {
flowerArray.add(r.nextInt(10));
}
System.out.println(flowerArray);
you can not do flowerArray[0] because you have an arrayList and not an array.
you can instead do: flowerArray.get(0) for getting the integer at pos zero
Here your array list is associated with a class object. When you initialize your array list you need to add your entries to the array list in the constructor itself. So when you say object.printArray() its actually returning you the empty array list, that's why you are getting 0 every time. Try This.
class Flower
{
private int randomRoses;
private int randomTulips;
private int randomOrchids;
public ArrayList<Integer> flowerArray;
public Flower()
{
Random r = new Random();
Random t = new Random();
Random o = new Random();
int randomRoses = (r.nextInt(10));
int randomTulips = (t.nextInt(10));
int randomOrchids = (o.nextInt(10));
System.out.println(randomRoses);
System.out.println(randomTulips);
System.out.println(randomOrchids);
flowerArray = new ArrayList<Integer>();
flowerArray.add(randomRoses); //flowerArray[0] is the # of roses
flowerArray.add(randomTulips); //flowerArray[1] is the # of tulips
flowerArray.add(randomOrchids); //flowerArray[2] is the # of orchids
}
public void printArray()
{
System.out.println(flowerArray.get(0));
}
}
public class Test {
public static void main(String[] args) {
Flower f = new Flower();
f.printArray();
}
}
And in array list you can get elements by using get(index) method.
This will give the output you expect.
public void printArray
{
System.out.println(flowerArray.get(0)+" Roses");
System.out.println(flowerArray.get(1)+" Tulips");
System.out.println(flowerArray.get(2)+" Orchids");
}
Also you missed a semi-colon after the statement defining the arraylist.
Make the correction:
flowerArray=new ArrayList<Integer>;
How did it compile without that semi-colon?
It is not working because your syntax for getting the ith flower is wrong.
You're using a java.util.ArrayList so the correct way to get an object from that ArrayList is by calling the get() method.
System.out.println(flowerArray.get(0));
Hope that helps.

How to make generic Counting Sort Method?

Okay I am a pretty beginner java coder, and I am doing an assignment where I am stuck. I need to create a generic method (sort) that sorts a Type array according to frequency, basically, I am taking the CountingSort Algorithm and making it a generic method. This is where I am lost. I can't seem to figure out how to do this.
Here is a link to my instructions,
https://classes.cs.siue.edu/pluginfile.php/7068/mod_assign/intro/150mp08.pdf
Code:
Driver Class
package mp08;
public class Main {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
Lists array = new Lists();
array.populateLists();
System.out.println("Original Int List: \n");
array.sort(Lists.intList);
System.out.println("Sorted Int List: \n");
}
}
Lists Class
package mp08;
import java.util.Arrays;
import java.util.Random;
public class Lists {
public static Integer[] intList;
public static Integer[] sortedintList;
public static Integer[] frequency;
public static Character[] charList;
public static Character[] sortedcharList;
public static int MAX_SIZE = 101;
public static int lengthInt;
public static int lengthChar;
public Lists(){
this.intList = new Integer[MAX_SIZE];
this.sortedintList = new Integer[MAX_SIZE];
this.charList = new Character[MAX_SIZE];
this.sortedcharList = new Character[MAX_SIZE];
this.frequency = new Integer[MAX_SIZE];
this.lengthInt = 0;
this.lengthChar = 0;
}
//Makes random integer for populated lists method.
public int randomInt(int min, int max){
Random rand = new Random();
int randomNum = rand.nextInt((max-min)+1)+min;
return randomNum;
}
//Makes random character for populated lists method.
public char randomChar(){
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int N = alphabet.length();
Random rand = new Random();
char randomLet = alphabet.charAt(rand.nextInt(N));
return randomLet;
}
//Populates intList and charList with random values.
public void populateLists(){
for (int i = 0; i < MAX_SIZE; i++) {
intList[i] = randomInt(1,100);
lengthInt++;
}
for (int i = 0; i < MAX_SIZE; i++) {
charList[i] = randomChar();
lengthChar++;
}
}
//Returns sorted array
public Integer[] sorted(){
return intList;
}
public static <T> void sort(T[] array) {
// array to be sorted in, this array is necessary
// when we sort object datatypes, if we don't,
// we can sort directly into the input array
Integer[] aux = new Integer[array.length];
// find the smallest and the largest value
int min = 1;
int max = 101;
// init array of frequencies
int[] counts = new int[max - min + 1];
// init the frequencies
for (int i = 0; i < array.length; i++) {
counts[array[i] - min]++;
}
// recalculate the array - create the array of occurence
counts[0]--;
for (int i = 1; i < counts.length; i++) {
counts[i] = counts[i] + counts[i-1];
}
/*
Sort the array right to the left
1) Look up in the array of occurences the last occurence of the given value
2) Place it into the sorted array
3) Decrement the index of the last occurence of the given value
4) Continue with the previous value of the input array (goto set1),
terminate if all values were already sorted
*/
for (int i = array.length - 1; i >= 0; i--) {
aux[counts[array[i] - min]--] = array[i];
}
}
public static void main(String[] args) {
Integer [] unsorted = {5,3,0,2,4,1,0,5,2,3,1,4};
System.out.println("Before: " + Arrays.toString(unsorted));
Integer [] sorted = sort(unsorted);
System.out.println("After: " + Arrays.toString(sorted));
}
}
I obviously have not finished my driver class yet and I would appreciate any help I can get!
There's no generic way for any Comparable type to get its ordinal number. Sometimes such numbers do not exist at all (for example, String is Comparable, but you cannot map any String to the integer number). I can propose two solutions.
First one is to store counts not in the array, but in TreeMap instead creating new entries on demand (using Java-8 syntax for brevity):
public static <T extends Comparable<T>> void sort(T[] array) {
Map<T, Integer> counts = new TreeMap<>();
for(T t : array) {
counts.merge(t, 1, Integer::sum);
}
int i=0;
for(Map.Entry<T, Integer> entry : counts.entrySet()) {
for(int j=0; j<entry.getValue(); j++)
array[i++] = entry.getKey();
}
}
public static void main(String[] args) {
Integer[] data = { 5, 3, 0, 2, 4, 1, 0, 5, 2, 3, 1, 4 };
System.out.println("Before: " + Arrays.toString(data));
sort(data);
System.out.println("After: " + Arrays.toString(data));
Character[] chars = { 'A', 'Z', 'B', 'D', 'F' };
System.out.println("Before: " + Arrays.toString(chars));
sort(chars);
System.out.println("After: " + Arrays.toString(chars));
}
Such solution looks clean, but probably not very optimal (though its advantage is that it does not care whether all numbers are from 1 to 100 or not).
Another possible solution is to create some additional interface which defines ordering for given type:
public interface Ordering<T> {
int toOrdinal(T obj);
T toObject(int ordinal);
}
public class IntegerOrdering implements Ordering<Integer> {
#Override
public int toOrdinal(Integer obj) {
return obj;
}
#Override
public Integer toObject(int ordinal) {
return ordinal;
}
}
public class CharacterOrdering implements Ordering<Character> {
#Override
public int toOrdinal(Character obj) {
return obj;
}
#Override
public Character toObject(int ordinal) {
return (char)ordinal;
}
}
Now you may make your sort method accepting the ordering parameter:
public static <T> void sort(T[] array, Ordering<T> ordering) { ... }
Every time you need to get counts array index by T object, just call ordering.toOrdinal(object). Every time you need to get object by array index, just use ordering.toObject(index). So, for example, instead of
counts[array[i] - min]++;
Use
counts[ordering.toOrdinal(array[i]) - min]++;
And call the sorting method like this:
sort(characterArray, new CharacterOrdering());
sort(integerArray, new IntegerOrdering());

Comparing int to arraylist of integer

I have an int element and I would like to know if this int is higher than all the integers of an Arraylist ?
Example :
int a ; // Contain an int (i.e 51 or 54 or 989...etc)
ArrayList<Integer> list = new ArrayList<Integer>(); // contain a list of Integers
My purpose is to know if a is higher than any number in the arraylist.
Thanks in advance
Sorting is complete overkill. You just need to compare your value to the highest value in the list. Here's a way to do this with existing library functions:
if (a > Collections.max(list)) {
//a is higher than anything in list
}
Note:
This carries a caveat of always going through the whole list even if the very first element is larger than a. But it's a tradeoff you're usually willing to make because the code reads so nice. If you really want the early exit, you can roll your own approach like in Austin's answer, or in Java 8, it would look something like this:
if ( list.stream().allMatch(element -> a > element) ) {
//...a is higher than anything in list
}
you can just iterate the array to see if any other value is higher..
int a = _whateverInt ; // Contain an int (i.e 51 or 54 or 989...etc)
ArrayList<Integer> list = new ArrayList<Integer>();
boolean isHigher = true;
for(int i = 0; i < list.size() && isHigher; i ++)
{
isHigher = a > list.get(i);
}
Solution 1:
public class Test {
public static void main(String[] args) {
int a = 150;
ArrayList<Integer> arrayList = new ArrayList<Integer>();
arrayList.add(50);
arrayList.add(100);
arrayList.add(30);
System.out.println(a > Collections.max(arrayList));
}
}
Solution 2:
public class Test {
public static void main(String[] args) {
int a = 150;
ArrayList<Integer> arrayList = new ArrayList<Integer>();
arrayList.add(50);
arrayList.add(100);
arrayList.add(30);
Collections.sort(arrayList);
System.out.println(a > arrayList.get(arrayList.size() - 1));
}
}
int a;
ArrayList<Integer> list = new ArrayList<Integer>();
int max = Collections.max(list);
if(a>max)
{
//this is what you want
}
Hope you find this useful...
edit: oops someone already answered the same trick :(
private boolean isLargest(int a, ArrayList<Integer> list)
{
ArrayList<Integer> sortedList = Collections.sort(list);
if(a > sortedList.get(0))
return true;
return false;
}
It is not efficient, but this approach leaves the ordering in the original list in-tact.

Adding Multiple Values in ArrayList at a single index

I have a double ArrayList in java like this.
List<double[]> values = new ArrayList<double[]>(2);
Now what I want to do is to add 5 values in zero index of list and 5 values in index one through looping.
The zeroth index would have values {100,100,100,100,100}
The index 1 would have values {50,35,25,45,65}
and all of these values are stored in a double array in following order
double[] values = {100,50,100,35,100,25,100,45,100,65}
How can i do it?
#Ahamed has a point, but if you're insisting on using lists so you can have three arraylist like this:
ArrayList<Integer> first = new ArrayList<Integer>(Arrays.AsList(100,100,100,100,100));
ArrayList<Integer> second = new ArrayList<Integer>(Arrays.AsList(50,35,25,45,65));
ArrayList<Integer> third = new ArrayList<Integer>();
for(int i = 0; i < first.size(); i++) {
third.add(first.get(i));
third.add(second.get(i));
}
Edit:
If you have those values on your list that below:
List<double[]> values = new ArrayList<double[]>(2);
what you want to do is combine them, right? You can try something like this:
(I assume that both array are same sized, otherwise you need to use two for statement)
ArrayList<Double> yourArray = new ArrayList<Double>();
for(int i = 0; i < values.get(0).length; i++) {
yourArray.add(values.get(0)[i]);
yourArray.add(values.get(1)[i]);
}
How about
First adding your desired result as arraylist and
and convert to double array as you want.
Try like this..
import java.util.ArrayList;
import java.util.List;
public class ArrayTest {
/**
* #param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
// Your Prepared data.
List<double[]> values = new ArrayList<double[]>(2);
double[] element1 = new double[] { 100, 100, 100, 100, 100 };
double[] element2 = new double[] { 50, 35, 25, 45, 65 };
values.add(element1);
values.add(element2);
// Add the result to arraylist.
List<Double> temp = new ArrayList<Double>();
for(int j=0;j<values.size(); j++) {
for (int i = 0; i < values.get(0).length; i++) {
temp.add(values.get(0)[i]);
temp.add(values.get(1)[i]);
}
}
// Convert arraylist to int[].
Double[] result = temp.toArray(new Double[temp.size()]);
double[] finalResult = new double[result.length]; // This hold final result.
for (int i = 0; i < result.length; i++) {
finalResult[i] = result[i].doubleValue();
}
for (int i = 0; i < finalResult.length; i++) {
System.out.println(finalResult[i]);
}
}
}
ArrayList<ArrayList> arrObjList = new ArrayList<ArrayList>();
ArrayList<Double> arrObjInner1= new ArrayList<Double>();
arrObjInner1.add(100);
arrObjInner1.add(100);
arrObjInner1.add(100);
arrObjInner1.add(100);
arrObjList.add(arrObjInner1);
You can have as many ArrayList inside the arrObjList. I hope this will help you.
create simple method to do that for you:
public void addMulti(String[] strings,List list){
for (int i = 0; i < strings.length; i++) {
list.add(strings[i]);
}
}
Then you can create
String[] wrong ={"1","2","3","4","5","6"};
and add it with this method to your list.
Use two dimensional array instead. For instance, int values[][] = new int[2][5]; Arrays are faster, when you are not manipulating much.
import java.util.*;
public class HelloWorld{
public static void main(String []args){
List<String> threadSafeList = new ArrayList<String>();
threadSafeList.add("A");
threadSafeList.add("D");
threadSafeList.add("F");
Set<String> threadSafeList1 = new TreeSet<String>();
threadSafeList1.add("B");
threadSafeList1.add("C");
threadSafeList1.add("E");
threadSafeList1.addAll(threadSafeList);
List mainList = new ArrayList();
mainList.addAll(Arrays.asList(threadSafeList1));
Iterator<String> mainList1 = mainList.iterator();
while(mainList1.hasNext()){
System.out.printf("total : %s %n", mainList1.next());
}
}
}
You can pass an object which is refering to all the values at a particular index.
import java.util.ArrayList;
public class HelloWorld{
public static void main(String []args){
ArrayList<connect> a=new ArrayList<connect>();
a.add(new connect(100,100,100,100,100));
System.out.println(a.get(0).p1);
System.out.println(a.get(0).p2);
System.out.println(a.get(0).p3);
}
}
class connect
{
int p1,p2,p3,p4,p5;
connect(int a,int b,int c,int d,int e)
{
this.p1=a;
this.p2=b;
this.p3=c;
this.p4=d;
this.p5=e;
}
}
Later to get a particular value at a specific index, you can do this:
a.get(0).p1;
a.get(0).p2;
a.get(0).p3;.............
and so on.

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