How to fix this VarArgs build error? - java

Here's the main method:
package main;
import varArgs.VarArgs;
public class Main {
public static void main(String[] args) {
int answer;
answer = VarArgs.sum(new int[]{1,2,3});
System.out.println("sum of ints = " + answer);
answer = VarArgs.sum(new int[]{1,2,3}, new int[] {100, 200, 300});
System.out.println("sum of ints = " + answer);
}
}
Here's the var args method:
package varArgs;
public class VarArgs {
/***
* Add an array of integers
* #param numbers Some array of integers
* #return The sum of all the elements in num
*/
public static int sum(int... numbers) {
int result = 0;
for (int i : numbers) {
result += i;
}
return result;
}
}
Here's the error I get:

A varargs parameter can only accept a single array. If you want to pass in a variable number of arrays, you need to do this:
public static int sum(int[]... arrays) {
int sum = 0;
for (int[] numbers : arrays) {
for (int i : numbers) {
sum += i;
}
}
return sum;
}

Related

How to apply a method from my main file in my JUnit test?

Our assignment says we should "write the source code and test code for a function named sumArray that accepts an array of ints and returns the sum of all elements from the array".
I think I've got SumArray.java to return sum OK, but I'm struggling to apply my method to the test input. Any help please? TIA.
SumArray.java
package sumarray;
import java.util.Scanner;
public class SumArray {
private static int n, sum = 0;
public static int sumArray() {
Scanner s = new Scanner(System.in);
System.out.print("Enter no. of elements you want in array:");
n = s.nextInt();
int a[] = new int[n];
System.out.println("Enter the elements. (Press [return] after each one)");
for (int i = 0; i < n; i++) {
a[i] = s.nextInt();
sum = sum + a[i];
}
System.out.println("Sum:" + sum);
return sum;
}
public static void main(String[] args) {
sumArray();
}
}
SumArrayTest.java
package sumarray;
import org.junit.Test;
import static org.junit.Assert.*;
public class SumArrayTest {
public SumArrayTest() {
}
/**
* Test of main method, of class SumArray.
*/
#Test
public void testMain() {
System.out.println("main");
String[] args = null;
SumArray.main(args);
int[] intArray = new int[]{2, 3, 4};
int expectedResult = 9;
// int testResult = sumArray({2, 3, 4});
int testResult = SumArray sumArray(intArray);
assertEquals(expectedResult, testResult);
// fail("The test case is a prototype.");
}
}
Edit: I've tried to implement what's been suggested so far with some changes; really not sure of any of this is right; a lot of it is guesswork TBH.
package sumarray;
import java.util.Scanner;
public class SumArray {
private static int n, sum = 0;
public static int sumArray;
public static int sumArray(int[] arr) {
return sum;
}
public static SumArray input() {
Scanner s = new Scanner(System.in);
System.out.print("Enter no. of elements you want in array:");
n = s.nextInt();
int a[] = new int[n];
System.out.println("Enter the elements. (Press [return] after each one)");
for (int i = 0; i < n; i++) {
a[i] = s.nextInt();
sum = sum + a[i];
}
System.out.println("Sum:" + sum);
return new SumArray();
}
public static void main(String[] args) {
SumArray result = input();
System.out.println(result.sumArray(SumArray));
}
}
package sumarray;
import org.junit.Test;
import static org.junit.Assert.*;
public class SumArrayTest {
public SumArrayTest() {
}
#Test
public void testSumArray() {
System.out.println("main");
String[] args = null;
int[] intArray = new int[]{2, 3, 4};
int expectedResult = 9;
assertEquals(expectedResult, SumArray.sumArray(intArray));
// fail("The test case is a prototype.");
}
}
The only error I'm seeing currently is 'cannot find symbol' for SumArray in main.
package sumarray;
import java.util.Scanner;
public class SumArray {
private static int n, sum = 0;
public static int sumArray() {
Scanner s = new Scanner(System.in);
System.out.print("Enter no. of elements you want in array:");
n = s.nextInt();
int a[] = new int[n];
System.out.println("Enter the elements. (Press [return] after each one)");
for (int i = 0; i < n; i++) {
a[i] = s.nextInt();
sum = sum + a[i];
}
System.out.println("Sum:" + sum);
return sum;
}
public static void main(String[] args) {
sumArray();
}
}
The above is the original code you posted. Now, you say you get the correct output. Yes, here you do:
package sumarray;
import java.util.Scanner;
public class SumArray {
private static int n, sum = 0;
public static int sumArray() {
Scanner s = new Scanner(System.in);
System.out.print("Enter no. of elements you want in array:");
n = s.nextInt();
int a[] = new int[n];
System.out.println("Enter the elements. (Press [return] after each one)");
for (int i = 0; i < n; i++) {
a[i] = s.nextInt();
sum = sum + a[i];
}
System.out.println("Sum:" + sum);
return sum;
}
public static void main(String[] args) {
sumArray(); // this one will return the correct answer
sumArray(); // this one will not
}
}
The second one will return wrong data, because you don't reset the value of sum.
You should split the tasks: sumArray should receive an array, and should return the sum of the elements. Either you should change the name of the method, or change the implementation, that is what Mahmoud told you.
package sumarray;
import java.util.Scanner;
public class SumArray {
private static Scanner scan = new Scanner(System.in); // create this on class level, not every execution of your method
public static int[] buildArray(int elements) {
int[] arr = new int[elements];
for ( int i = 0; i < elements; i++ ) {
System.out.println("Enter element nr: " + (i+1));
arr[i] = scan.nextInt();
}
return arr;
}
public static int sumArray(int[] input) {
int sum = 0; // don't use a class level one. especially not a static one, it's value could be altered by another thread
for ( int in : input ) { // iterate over the array and add the values
sum += in; // this should be in -> each iteration we add the value of in (the element of the array) to sum
}
return sum;
}
public static void main(String[] args) {
System.out.println("Provide the size of the array: ");
int param = scan.nextInt();
int[] array = buildArray(param);
int result = sumArray(array);
System.out.println("The sum of the array is: " + result);
}
}
This approach will land you with far lesser issues. It also doesn't have static variables like n and sum in your class that might lead to wrong results.
The main() method is the entry point into the application, you shouldn't test the main() method. Instead, you should test the sumArray() method and compare the expected Vs. the actual returned value from the method.
As a side note, you can better pass the input array to the sumArray() method as a parameter instead of reading it from System.in within the method body.
So your method signature can look like this:
public static int sumArray(int[] arr). The client code which uses this method, which is the main method in your case (or the unit test) can pass the array without bothering the method how this input array was got.

How to call an Array between classes?

Hello I am new to java so please be gentle,
class Result{
public float Mean(){
//find the mean of the array
}
public float lowest(){
// find the lowest
}
}
public class Main{
public static void main(String[] args) {
float arr[] = {1.1,2.2,3.3};
}
}
What I want to do is to take the array arr from Main, and bring it to class Result so that I can use it
in Mean() and Lowest().
Thank you.
Try add the array as part of constructor of Result/Solve, then you could work with numbers inside the instance you create.
class Solve {
final float[] numbers;
public Result(final float[] numbers){
this.numbers = numbers;
}
public float mean(){
//find the mean using the this.numbers
}
public float lowest(){
// find the lowest using this.numbers
}
}
public class Main{
public static void main(String[] args) {
float numbers[] = new float[]{1.1,2.2,3.3};
Solve solve = new Solve(numbers);
float mean = solve.mean();
float lowest = solve.lowest();
System.out.println("Mean: " + mean);
System.out.println("Lowest: " + lowest);
}
}
Another option is to make your methods static and pass the numbers as part of the methods, similar to Math class.
class Solve {
public static float mean(float[] numbers){
}
public static float lowest(float[] numbers) {
}
}
public class Main{
public static void main(String[] args) {
float numbers[] = new float[]{1.1,2.2,3.3};
float mean = Solve.mean(numbers);
float lowest = Solve.lowest(numbers);
System.out.println("Mean: " + mean);
System.out.println("Lowest: " + lowest);
}
}
Here's how I would handle this:
Result class:
class Result {
public static float mean(float... arr) { //make the method static, and have it take the array as a parameter
float sum = 0f;
for (float f : arr) { //add each number in the array to the sum variable
sum += f;
}
return sum / arr.length; //return sum / length, which is average
}
public static float lowest(float... arr) { //same as the above method
float lowest = arr[0];
for (float f : arr) { //loop through the array
if (f < lowest) { //if this number is lower than the current "lowest" number, set lowest to be this number
lowest = f;
}
}
return lowest; //return the lowest number
}
}
Main class:
public class Main {
public static void main(String[] args) {
float[] arr = new float[] { 1.1f, 2.2f, 3.3f }; //here's the array
System.out.println(Result.mean(arr)); //I pass it to the method as a parameter
System.out.println(Result.lowest(arr)); //same here
}
}
An alternative solution would be to use Java streams instead of for loops. Java streams can get more complicated than for loops, but they can be much cleaner and easier to read. Here's how I would rewrite the Result class using streams:
class Result {
public static float mean(float... arr) {
return (float) IntStream.range(0, arr.length)
.mapToDouble((i) -> arr[i])
.average()
.getAsDouble(); //returns the average of the array
}
public static float lowest(float... arr) {
return (float) IntStream.range(0, arr.length)
.mapToDouble((i) -> arr[i])
.min()
.getAsDouble(); //returns the minimum value in the array
}
}
Pass your array as an argument to the other object’s method.
float[] arr = { 1.1F, 2.2F, 3.3F } ;
Result r = new Result() ;
float output = r.lowest( arr ) ;
Define that argument on the method.
class Result{
public float mean( float[] input ){
// … find the mean of the array
}
public float lowest( float[] input ){
// … find the lowest
}
}
See this code run live at IdeOne.com.
Passing an argument/parameter to a method is a basic minimal skill in Java. You should study the Java Tutorials by Oracle, and consult a textbook to get the basics down.

How to make generic Counting Sort Method?

Okay I am a pretty beginner java coder, and I am doing an assignment where I am stuck. I need to create a generic method (sort) that sorts a Type array according to frequency, basically, I am taking the CountingSort Algorithm and making it a generic method. This is where I am lost. I can't seem to figure out how to do this.
Here is a link to my instructions,
https://classes.cs.siue.edu/pluginfile.php/7068/mod_assign/intro/150mp08.pdf
Code:
Driver Class
package mp08;
public class Main {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
Lists array = new Lists();
array.populateLists();
System.out.println("Original Int List: \n");
array.sort(Lists.intList);
System.out.println("Sorted Int List: \n");
}
}
Lists Class
package mp08;
import java.util.Arrays;
import java.util.Random;
public class Lists {
public static Integer[] intList;
public static Integer[] sortedintList;
public static Integer[] frequency;
public static Character[] charList;
public static Character[] sortedcharList;
public static int MAX_SIZE = 101;
public static int lengthInt;
public static int lengthChar;
public Lists(){
this.intList = new Integer[MAX_SIZE];
this.sortedintList = new Integer[MAX_SIZE];
this.charList = new Character[MAX_SIZE];
this.sortedcharList = new Character[MAX_SIZE];
this.frequency = new Integer[MAX_SIZE];
this.lengthInt = 0;
this.lengthChar = 0;
}
//Makes random integer for populated lists method.
public int randomInt(int min, int max){
Random rand = new Random();
int randomNum = rand.nextInt((max-min)+1)+min;
return randomNum;
}
//Makes random character for populated lists method.
public char randomChar(){
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int N = alphabet.length();
Random rand = new Random();
char randomLet = alphabet.charAt(rand.nextInt(N));
return randomLet;
}
//Populates intList and charList with random values.
public void populateLists(){
for (int i = 0; i < MAX_SIZE; i++) {
intList[i] = randomInt(1,100);
lengthInt++;
}
for (int i = 0; i < MAX_SIZE; i++) {
charList[i] = randomChar();
lengthChar++;
}
}
//Returns sorted array
public Integer[] sorted(){
return intList;
}
public static <T> void sort(T[] array) {
// array to be sorted in, this array is necessary
// when we sort object datatypes, if we don't,
// we can sort directly into the input array
Integer[] aux = new Integer[array.length];
// find the smallest and the largest value
int min = 1;
int max = 101;
// init array of frequencies
int[] counts = new int[max - min + 1];
// init the frequencies
for (int i = 0; i < array.length; i++) {
counts[array[i] - min]++;
}
// recalculate the array - create the array of occurence
counts[0]--;
for (int i = 1; i < counts.length; i++) {
counts[i] = counts[i] + counts[i-1];
}
/*
Sort the array right to the left
1) Look up in the array of occurences the last occurence of the given value
2) Place it into the sorted array
3) Decrement the index of the last occurence of the given value
4) Continue with the previous value of the input array (goto set1),
terminate if all values were already sorted
*/
for (int i = array.length - 1; i >= 0; i--) {
aux[counts[array[i] - min]--] = array[i];
}
}
public static void main(String[] args) {
Integer [] unsorted = {5,3,0,2,4,1,0,5,2,3,1,4};
System.out.println("Before: " + Arrays.toString(unsorted));
Integer [] sorted = sort(unsorted);
System.out.println("After: " + Arrays.toString(sorted));
}
}
I obviously have not finished my driver class yet and I would appreciate any help I can get!
There's no generic way for any Comparable type to get its ordinal number. Sometimes such numbers do not exist at all (for example, String is Comparable, but you cannot map any String to the integer number). I can propose two solutions.
First one is to store counts not in the array, but in TreeMap instead creating new entries on demand (using Java-8 syntax for brevity):
public static <T extends Comparable<T>> void sort(T[] array) {
Map<T, Integer> counts = new TreeMap<>();
for(T t : array) {
counts.merge(t, 1, Integer::sum);
}
int i=0;
for(Map.Entry<T, Integer> entry : counts.entrySet()) {
for(int j=0; j<entry.getValue(); j++)
array[i++] = entry.getKey();
}
}
public static void main(String[] args) {
Integer[] data = { 5, 3, 0, 2, 4, 1, 0, 5, 2, 3, 1, 4 };
System.out.println("Before: " + Arrays.toString(data));
sort(data);
System.out.println("After: " + Arrays.toString(data));
Character[] chars = { 'A', 'Z', 'B', 'D', 'F' };
System.out.println("Before: " + Arrays.toString(chars));
sort(chars);
System.out.println("After: " + Arrays.toString(chars));
}
Such solution looks clean, but probably not very optimal (though its advantage is that it does not care whether all numbers are from 1 to 100 or not).
Another possible solution is to create some additional interface which defines ordering for given type:
public interface Ordering<T> {
int toOrdinal(T obj);
T toObject(int ordinal);
}
public class IntegerOrdering implements Ordering<Integer> {
#Override
public int toOrdinal(Integer obj) {
return obj;
}
#Override
public Integer toObject(int ordinal) {
return ordinal;
}
}
public class CharacterOrdering implements Ordering<Character> {
#Override
public int toOrdinal(Character obj) {
return obj;
}
#Override
public Character toObject(int ordinal) {
return (char)ordinal;
}
}
Now you may make your sort method accepting the ordering parameter:
public static <T> void sort(T[] array, Ordering<T> ordering) { ... }
Every time you need to get counts array index by T object, just call ordering.toOrdinal(object). Every time you need to get object by array index, just use ordering.toObject(index). So, for example, instead of
counts[array[i] - min]++;
Use
counts[ordering.toOrdinal(array[i]) - min]++;
And call the sorting method like this:
sort(characterArray, new CharacterOrdering());
sort(integerArray, new IntegerOrdering());

How to initialize an Array object?

I'm having trouble initializing an Array and don't really understand how to do it.
public class Array {
int[] array;
public Array(int[] array) {
this.array = array;
}
public int sum() {
int sum = 0;
for (int i = 0; i < this.array.length; i++) {
sum = sum + array[i];
}
return sum;
}
public double average() {
double av = this.sum() / this.array.length;
return av;
}
public static void main(String[] args) {
Array a = new Array[3];
}
}
I keep getting an error that says required: Array found: array[]
I want to make a scanner and have user input on the array but I don't even know how to initialize it in the first place
You have to change
Array a = new Array[3];
To
Array a = new Array(new int[3]);
Constructor of Array is taking int[] as input arguments.

How Can I display the contents of void method?

I am new to programming and Java as well. I need to write a void method which sorts the array entered, I have the code written but do not know how to display the sorted list from void method. Anyone willing to help. It will be greatly appreciated.
package util.assign4;
import java.util.StringTokenizer;
import javax.swing.JOptionPane;
import util.IO;
public class UtilAssign4 {
public static int[] getData (String input){
StringTokenizer st = new StringTokenizer(input);
int []x = new int[st.countTokens()];
for(int i = 0;st.hasMoreTokens(); i++){
try{
x[i] = Integer.parseInt(st.nextToken());
}
catch(Exception e){
JOptionPane.showMessageDialog(null," Invalid input");
System.exit(1);
}
}
return x;
}
public static int getHighest(int g[]){
int hi = g[0];
for( int k = 1; k <g.length;k++)
if(g[k]> hi) hi = g[k];
return hi;
}
public static int getSmallest(int p[]){
int sm = p[0];
for(int l = 1;l<p.length;l++)
if(p[l] < sm) sm = p[l];
return sm;
}
public static float getAverage(int n[]){
float sum = 0.0f;
for(int y = 0;y <n.length; y++) sum += n[y];
return sum/n.length;
}
public static void getSorted(int grades []){
for(int i = 0; i<grades.length-1;i++){
int largest =i;
for(int j = 0;j<grades.length;j++)
if(grades[j]>grades[largest]) largest = j;
int temp = grades[largest];
grades[largest] = grades[i];
grades[i]=temp;
}
}
public static void main(String[] args) {
String input = JOptionPane.showInputDialog("Enetr one or more grades:");
int [] x = getData(input);
int j = getHighest(x);
int m = getSmallest(x);
float a = getAverage(x);
IO.showMsg("Array you entered:" + input + String.format("\nThe"
+ " higheset grade is:%2d \n"
+ "The Lowest Grade is:%2d \n"+"The average is:%2.2f\n"
+ "The sorted list: ",
j,m,a));
}
}
You are not supposed to print the contents of the array in the sort method. Your requirement (I wager) is to sort the array supplied to the method 'in-place' (which it already looks like you are doing). What this means is that given an array:
int[] grades = new int[] {34, 76, 12, 0, -1};
That when you call:
UtilAssign4.getSorted(grades);
That the array passed into the method is actually sorted inside the method, and as such does not need to be returned (that's why your return type is void). So to summarize, before calling the sort method, your array is unsorted. After the call completes, tbe very same array has now been sorted.
So now you can then print out the sorted array in the calling method (in this case main(String[]):
getSorted(x); // <-- call the sort function, on your array
String msg = String.format("\nThe higheset grade is:%2d \n"
+ "The Lowest Grade is:%2d \nThe average is:%2.2f\n"
+ "The sorted list: %s", j, m, a, Arrays.toString(x));
IO.showMsg(msg);
Note the Arrays.toString(x)? That will take your sorted array, and convert it into a string representation (will look something like this: [76, 34, 12, 0, -1]).
in void method short your array in any field Array that is
public class UtilAssign4 {
private Integer[] shorted = new Integer[100];
public static int[] getData (String input){
.
.
}
and do your stuff with above array in your void method and use this where you want

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