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Hibernate: column does not exist

When I try to load an Entity with Hibernate I get the following error in postgres-log:
ERROR: column appuser0_.device_token does not exist at character 35
STATEMENT: select appuser0_.id as id1_27_0_, appuser0_.device_token as device_t2_27_0_,....
The column device_token definitely exists - and if I copy-paste the whole logged statement and execute it in PGAdmin, I get the expected result.
So what do I forget? What is the difference between the Hibernate statement and the manually executed one?

This issue was caused by the multi tenant configuration so that the wrong DataSource has been chosen.

Depending on how you defined the query, the problem might be located somewhere else: For example, HQL Queries are using the "property-names" of the class, not the column names.
And if you have something like:
#Column("device_token")
private String deviceToken;
Then your HQL-Query should target "deviceToken" and not "device_token". We also encountered a similar error once: Hibernate was reporting "user_id" is missing, because we named the property "userId" with the underscored version for the column name only.
This might be not the problem for you but worth double checking it.

Spring Batch Paging with sortKeys and parameter values

I have a Spring Batch project running in Spring Boot that is working perfectly fine. For my reader I'm using JdbcPagingItemReader with a MySqlPagingQueryProvider.
#Bean
public ItemReader<Person> reader(DataSource dataSource) {
MySqlPagingQueryProvider provider = new MySqlPagingQueryProvider()
provider.setSelectClause(ScoringConstants.SCORING_SELECT_STATEMENT)
provider.setFromClause(ScoringConstants.SCORING_FROM_CLAUSE)
provider.setSortKeys("p.id": Order.ASCENDING)
JdbcPagingItemReader<Person> reader = new JdbcPagingItemReader<Person>()
reader.setRowMapper(new PersonRowMapper())
reader.setDataSource(dataSource)
reader.setQueryProvider(provider)
//Setting these caused the exception
reader.setParameterValues(
startDate: new Date() - 31,
endDate: new Date()
)
reader.afterPropertiesSet()
return reader
}
However, when I modified my query with some named parameters to replace previously hard coded date values and set these parameter values on the reader as shown above, I get the following exception on the second page read (the first page works fine because the _id parameter hasn't been made use of by the paging query provider):
org.springframework.dao.InvalidDataAccessApiUsageException: No value supplied for the SQL parameter '_id': No value registered for key '_id'
at org.springframework.jdbc.core.namedparam.NamedParameterUtils.buildValueArray(NamedParameterUtils.java:336)
at org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.getPreparedStatementCreator(NamedParameterJdbcTemplate.java:374)
at org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.query(NamedParameterJdbcTemplate.java:192)
at org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.query(NamedParameterJdbcTemplate.java:199)
at org.springframework.batch.item.database.JdbcPagingItemReader.doReadPage(JdbcPagingItemReader.java:218)
at org.springframework.batch.item.database.AbstractPagingItemReader.doRead(AbstractPagingItemReader.java:108)
Here is an example of the SQL, which has no WHERE clause by default. One does get created automatically when the second page is read:
select *, (select id from family f where date_created between :startDate and :endDate and f.creator_id = p.id) from person p
On the second page, the sql is modified to the following, however it seems that the named parameter for _id didn't get supplied:
select *, (select id from family f where date_created between :startDate and :endDate and f.creator_id = p.id) from person p WHERE id > :_id
I'm wondering if I simply can't use the MySqlPagingQueryProvider sort keys together with additional named parameters set in JdbcPagingItemReader. If not, what is the best alternative to solving this problem? I need to be able to supply parameters to the query and also page it (vs. using the cursor). Thank you!

I solved this problem with some intense debugging. It turns out that MySqlPagingQueryProvider utilizes a method getSortKeysWithoutAliases() when it builds up the SQL query to run for the first page and for subsequent pages. It therefore appends and (p.id > :_id) instead of and (p.id > :_p.id). Later on, when the second page sort values are created and stored in JdbcPagingItemReader's startAfterValues field it will use the original "p.id" String specified and eventually put into the named parameter map the pair ("_p.id",10). However, when the reader tries to fill in _id in the query, it doesn't exist because the reader used the non-alias removed key.
Long story short, I had to remove the alias reference when defining my sort keys.
provider.setSortKeys("p.id": Order.ASCENDING)
had to change to in order for everything to work nicely together
provider.setSortKeys("id": Order.ASCENDING)

I had the same issue and got another possible solution.
My table T has a primary key field INTERNAL_ID.
The query in JdbcPagingItemReader was like this:
SELECT INTERNAL_ID, ... FROM T WHERE ... ORDER BY INTERNAL_ID ASC
So, the key is: in some conditions, the query didn't return results, and then, raised the error above No value supplied for...
The solution is:
Check in a Spring Batch decider element if there are rows.
If it is, continue with chunk: reader-processor-writer.
It it's not, go to another step.
Please, note that they are two different scenarios:
At the beginning, there are rows. You get them by paging and finally, there are no more rows. This has no problem and decider trick is not required.
At the beginning, there are no rows. Then, this error raised, and the decider solved it.
Hope this helps.

Discriminator value from separate table in Hibernate inheritance mapping

I have two tables, price_feed and price_feed_type. Price feed will contain the data for different implementations of price feeds.
Now, this would usually be done through the <discriminator> tag, with a discriminator field in the price_feed table. However, it would be preferable in the context of the system to have this field in the price_feed_type table. I've come across the <discriminator formula="..."/> method, and tried working with this.
One solution is as follows (assume this is entered in the formula attribute):
(SELECT implementing_class FROM price_feed_type INNER JOIN price_feed ON price_feed.price_feed_type_id = price_feed_type.price_feed_type_id")
Another solution is the following, and I should note that I've tried with both priceFeedID and price_feed.price_feed_type_id
(SELECT implementing_class FROM price_feed_type WHERE price_feed_type.price_feed_type_id = price_feed.price_feed_type)
Either one gives the following error:
org.postgresql.util.PSQLException: ERROR: column timedprice3_.implementing_class does not exist
An extra note, without the parantheses, I get the error:
org.postgresql.util.PSQLException: ERROR: syntax error at or near "SELECT"
Any ideas as to how to fix this?
EDIT:
To add what I've found so far:
Using either one, if I do SELECT *, and then do SELECT implementing_class outside, it gives a different error. Full code:
(SELECT implementing_class FROM (SELECT * FROM price_feed_type INNER JOIN price_feed ON price_feed.price_feed_type_id = price_feed_type.price_feed_type_id) AS foo)
The error is:
org.postgresql.util.PSQLException: ERROR: syntax error at or near "."

JPA: querying FK

I'm using EclipseLink(JPA 2.0) under Netbeans 7.0 with JDK 7. Adding more, this is a JavaSE.
I have this tables, Employee and Record where in the relation is Employee(1) --- (*)Records.
Adding more about the structure of the Record: RecordID (PK), EmployeeID(FK), Status, etc.
I wanted to query out from the Record Table (not using the Employee->Rental Collection) what records has a relation with the employee..
I tried using the query, it always returns an exception
Exception Description: Error compiling the query [SELECT r FROM Record r WHERE
r.employeeid = :employeeid], unknown state or association field
[employeeid] of class [Record].

From the information given it's not completely clear, but I believe you need to reference the id inside the Employee object.
eg. the correct query is probably:
SELECT r FROM Record r WHERE r.employee.id = :employeeid
(notice the extra dot in employee.id)
If this doesn't work, please provide us with some actual code of your Java classes.

"No row with the given identifier exists" although it DOES exist

I am using Hibernate and getting
Exception in thread "main" org.hibernate.ObjectNotFoundException: No row with the given identifier exists: [#271]
What is pretty weird about this error is, that the object with the given id exists in the database. I inserted the problematic record in another run of the application. If I access it in the same run (i.e. same hibernate session) there seem to be no problems retrieving the data.
Just because it could be a fault of the mapping:
public class ProblemClass implements Persistent {
#ManyToOne(optional = false)
private MyDbObject myDbObject;
}
public class MyDbObject implements Persistent {
#OneToMany(mappedBy = "myDbObject")
private List<ProblemClass> problemClasses;
#ManyToOne(optional = false)
private ThirdClass thirdClass;
}
I have absolutely no clue even where to look at. Any hints highly appreciated!
Just to clarify:
The data was inserted in another RUN of the application. It is definitely in the database, as I can see it via an SQL-Query after the application terminated. And after THAT, i.e. when starting the application again, I get the error in the FIRST query of the database -- no deletion, no rollback involved.
Addition:
Because it was asked, here is the code to fetch the data:
public List<ProblemClass> getProblemClasses() {
Query query = session.createQuery("from ProblemClass");
return query.list();
}
And just to make it complete, here is the generic code to insert it (before fetching in another RUN of the application):
public void save(Persistent persistent) {
session.saveOrUpdate(persistent);
}

Eureka, I found it!
The problem was the following:
The data in the table ThirdClass was not persisted correctly. Since this data was referenced from MyDbObject via
optional = false
Hibernate made an inner join, thus returning an empty result for the join. Because the data was there if executed in one session (in the cache I guess), that made no problems.
MySQL does not enforce foreign key integrity, thus not complaining upon insertion of corrupt data.
Solution: optional = true or correct insertion of the data.

Possible reasons:
The row was inserted by the first session, but transaction was not committed when second session tried to access it.
First session is roll-backed due to some reason.

Sounds like your transaction inserting is rollbacked

Main reason behind this issue is data mismatch, for example i have entity mapping class called "X" and it has column "column1" and it has reference to the table "Y" column "column1" as below
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "column1", referencedColumnName = "column1")
public Y getColumn1() {
return Y;
}
In this if X table column1 has value but Y table column1 is not having the value. Here link will be failed.
This is the reason we will get Hibernate objectNotFound exception
This issue can also be resolved by creating proper data model like creating proper indexing and constraints (primary key/foreign key) ..

This might be your case, kindly check my answer on another post.
https://stackoverflow.com/a/40513787/6234057
I had the same Hibernate exception.
After debugging for sometime, i realized that the issue is caused by the Orphan child records.
As many are complaining, when they search the record it exists.
What i realized is that the issue is not because of the existence of the record but hibernate not finding it in the table, rather it is due to the Orphan child records.
The records which have reference to the non-existing parents!
What i did is, find the Foreign Key references corresponding to the Table linked to the Bean.
To find foreign key references in SQL developer
1.Save the below XML code into a file (fk_reference.xml)
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.table_name,
a.constraint_name,
a.status
from all_constraints a
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
2.Add the USER DEFINED extension to SQL Developer
Tools > Preferences
Database > User Defined Extensions
Click "Add Row" button
In Type choose "EDITOR", Location - where you saved the xml file above
Click "Ok" then restart SQL Developer
3.Navigate to any table and you will be able to see an additional tab next to SQL, labelled FK References, displaying FK information.
4.Reference
http://www.oracle.com/technetwork/issue-archive/2007/07-jul/o47sql-086233.html
How can I find which tables reference a given table in Oracle SQL Developer?
To find the Orphan records in all referred tables
select * from CHILD_TABLE
where FOREIGNKEY not in (select PRIMARYKEY from PARENT_TABLE);
Delete these Orphan records, Commit the changes and restart the server if required.
This solved my exception. You may try the same.

Please update your hibernate configuration file as given below:
property start tag name="hbm2ddl.auto" create/update property close tag

I have found that in Oracle this problem can also be caused by a permissions issue. The ProblemClass instance referred to by the MyDbObject instance may exist but have permissions that do not allow the current user to see it, even though the user can see the current MyDbObject.