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How to extract specific String values using regex

I am a newbie in regex, I want to extract values between commas but I don't know how.
I have values like this :
[1000, Value_to_extract, 1150370.5]
and I used this Technic to simplify it:
String val = "[1000, Value_to_extract, 1150370.5]";
String designation=val.replace("[", "").replace("]", "").trim();
It give's me this result :
1000, Value_to_extract, 1150370.5
I don't know how to extract only Value_to_extract
I tried : String designation=val.replace("[", "").replace("]", "").replaceAll(".*, ,.*", "").trim();
but i doesn't work .
Thank you for your help.

String input = "[1000, Value_to_extract, 1150370.5]";
String[] parts = input.replaceAll("\\[\\] ", "") // strip brackets and whitespace
.split(","); // split on comma into an array
String valueToExtract = parts[1]; // grab the second entry
Notes:
You might also be able to use a regex here, q.v. the answer by #Thomas, but a regex will become unwieldy for extracting values from a CSV string of arbitrary length. So in general, I would prefer splitting here to using a regex.

someting like this:
,[ ]?([0-9]+[.]?[0-9]+),
breakdown
, // literal ,
[ ]? // 0 or 1 spaces
([0-9]+[.]?[0-9]+) // capture a number with or without a dot
, // another litteral ,
https://regex101.com/r/oR7nI8/1

Here are some options:
String val = "[1000, Value_to_extract, 1150370.5]";
//you can remove white space by
String noSpaces = val.trim();
System.out.println(noSpaces);
//you can split the string into string[] settting
//the delimiting regular expression to ", "
String[] strings = noSpaces.split(", ");
//the strings[1] will hold the desired string
System.out.println(strings[1]);
//in the private case of val, only Value_to_extract contains letters and "_" ,
//so you can also extract it using
System.out.println(val.replaceAll("[^a-zA-Z_]", ""));
If val does not well represent the more general need, you need to define the need more precisely.

Split string using reges

I have following string
String str = "url:http://www.google.com"
Now I want to split the above string using :.
If I split above string using : then above string split into 3 segments.
But I want whole URL in one segment. How can I get the whole URL?
Three is an one way that I found using substring
String webURL = str.substring(4, str.length());
Is there any other best way to that?

You can call String.split(String, int) where the second argument is a limit (or count). Something like,
String str = "url:http://www.google.com";
String[] arr = str.split(":", 2);
System.out.println(arr[1]);
Output is (as requested)
http://www.google.com

String str= "url:http://www.google.com";
// find the first : and take string beyond that
str = str.substring(str.indexOf(':')+1);
System.out.println(str);

Java- Extract part of a string between two similar special characters

Java- Extract part of a string between two similar special characters.
I want to substring the second number, example :
String str = '1-10-251';
I want the result to be: 10

String str = "1-10-251";
String[] strArray = str.split("-");
System.out.println(strArray[1]);

Splitting string into substring in Java

I have one string and I want to split it into substring in Java, originally the string is like this
Node( <http://www.mooney.net/geo#wisconsin> )
Now I want to split it into substring by (#), and this is my code for doing it
String[] split = row.split("#");
String word = split[1].trim().substring(0, (split[1].length() -1));
Now this code is working but it gives me
"wisconsin>"
the last work what I want is just the work "wisconsin" without ">" this sign, if someone have an idea please help me, thanks in advance.

Java1.7 DOC for String class
Actually it gives you output as "wisconsin> " (include space)
Make subString() as
String word = split[1].trim().substring(0, (split[1].length()-3));
Then you will get output as
wisconsin
Tutorials Point String subString() method reference

Consider
String split[] = row.split("#|<|>");
which delivers a String array like this,
{"http://www.mooney.net/geo", "wisconsin"}
Get the last element, at index split.length()-1.

String string = "Enter parts here";
String[] parts = string.split("-");
String part1 = parts[0];
String part2 = parts[1];

you can just split like you did before once more (with > instead of #) and use the element [0] istead of [1]

You can just use replace like.
word.replace(char oldChar, char newChar)
Hope that helps

You can use Java String Class's subString() method.
Refer to this link.

Java String Tokenize from backwards

I have a string
ContactPerson.BusinessPartner.name1,ContactPerson.BusinessPartner.name2,ContactPerson.fullname
Here i need to break the string based on comma and i have done that
ContactPerson.BusinessPartner.name1
ContactPerson.BusinessPartner.name2
ContactPerson.fullname
But i need to tokenize this again from the end that is i need to extract name1 and should store it corresponding to Businesspartner.Same case for name 2.It should be stored corresponding to the Busineespartner. For fullname also i should extract fullname and store to corresponding contactperson.So what i need is i should split the string from backwards where i encounter the (.) first and should split the string into two and store the string corresponding to the String before. The example i gave is simple. Normally we get
Strings like
Contactperson.Customer.Company.Businesspartner.name1 etc
so name1 should be stored correspndingly to th businesspartner.
Can anybody help me how to do this any idea??

You can get the last parts like this:
String input = "ContactPerson.BusinessPartner.name1,ContactPerson.BusinessPartner.name2,ContactPerson.fullname";
String[] parts = input.split(",");
for (String part : parts) {
String[] subparts = part.split("\\.");
String last = subparts[subparts.length - 1];
}
last will then contain name1, name2, ...
See String.split() for details.

try
String s = "ContactPerson.BusinessPartner.name1";
String name = s.replaceAll(".+\\.([^.]+)", "$1");