Issue in DateTime conversion to local Time - java

I am facing issue in Android with DateTime conversion to local Time with timezone. I am using the below method to convert to local time but i get the 'Year' and 'Time' wrong.
P.S The DateTime received is in Bangladesh Standard Time "Asia/Dhaka", "(GMT +06:00) Dhaka"
public String localToGMT(String serverDate) {
String DATE_FORMAT = "dd.mm.yyyy HH:MM";//15.06.18 6:00
String strDate = "";
///Date date = new Date();
try {
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT);
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
Date gmt = null;
gmt = sdf.parse(serverDate);
strDate = sdf.format(gmt);
} catch (ParseException e) {
e.printStackTrace();
}
return strDate;
}
Input : 22.06.2018 00:00
My output : 22.06.2017 00:12
Can someone help me with this?

MM stands for month, mm stands for minutes, and you need re-set the timezone, try this:
public static void main(String[] args) throws Exception {
String serverDate = "22.06.2018 16:00";
String DATE_FORMAT = "dd.MM.yyyy HH:mm";
String strDate;
SimpleDateFormat sdf = new SimpleDateFormat(DATE_FORMAT);
sdf.setTimeZone(TimeZone.getTimeZone("Asia/Dhaka"));
Date gmt = sdf.parse(serverDate);
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
strDate = sdf.format(gmt);
System.out.println(strDate); // 22.06.2018 10:00
}

Related

How change String to Date format

I have this string: 2018-09-22 10:17:24.772000
I want to convert it to Date:
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
but it shows: Sat Sep 22 10:17:24 GMT+03:30 2018
Here is what you should do instead, you are printing date object itself, you should print its format.
I will provide the code with old date api and new local date api :
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
System.out.println(dateFrom); // this is what you do
System.out.println(simpleDateFormat.format(dateFrom)); // this is what you should do
// below is from new java.time package
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSS");
System.out.println(LocalDateTime.parse(sdate, formatter).format(formatter));
output is :
Sat Sep 22 10:30:16 EET 2018
2018-09-22 10:30:16.000000
2018-09-22 10:17:24.772000
Hope This will help you
public class Utils {
public static void main(String[] args) {
String mytime="2018-09-22 10:17:24.772000";
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSSSSS");
Date myDate = null;
try {
myDate = dateFormat.parse(mytime);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat timeFormat = new SimpleDateFormat("yyyy-MM-dd");
String finalDate = timeFormat.format(myDate);
System.out.println(finalDate);
}
}
Looks to me like you have converted it to a Date. What is your desired result? I suspect what you are wanting to do is to create another Simple date format that shows your expected format and then use simpledateformat2.format(dateFrom)
I should also point out based on past experience that you should add a Locale to your simple date formats otherwise a device with a different language setting may not be able to execute this code
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS", Locale.US);

Remove the hour,minute and seconds from date gotten from server as JSON

I am getting some JSON data from server that includes dates too. But it shows the date like this 2017-07-20 00:00:00 but I want to just see the date like this:2017-07-20, and i checked the previous questions about this issue but all of them were based on the date in the android side. And the problem is that I get the date as JSON and because of that I don't know how to remove Time from it.
Did you try to simple parse this string like this?
String date_string = "2017-07-20 00:00:00";
String[] parsed = date_string.split(" ");
String your_wanted_string = parsed[0];
System.out.println(your_wanted_string);
EDIT
You have to convert string into Date like here : https://stackoverflow.com/a/4216767/1979882
Convert Date to milliseconds. Or use Calendar class.
Calculate the difference between the values.
An example:
http://www.mkyong.com/java/how-do-get-time-in-milliseconds-in-java/
public class TimeMilisecond {
public static void main(String[] argv) throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("dd-M-yyyy hh:mm:ss");
String dateInString = "22-01-2015 10:20:56";
Date date = sdf.parse(dateInString);
System.out.println(dateInString);
System.out.println("Date - Time in milliseconds : " + date.getTime());
Calendar calendar = Calendar.getInstance();
calendar.setTime(date);
System.out.println("Calender - Time in milliseconds : " + calendar.getTimeInMillis());
}
}
String date_from_json="your date goes here";
parseDate(date_from_json);
public String parseDate(String s) {
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
SimpleDateFormat outputFormat = new SimpleDateFormat("yyyy-mm-dd");
Date date = null;
String str = null;
try {
date = inputFormat.parse(s);
str = outputFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return str;
}
You can use my javascript function to do this task from client side:
function formatDate(dateString) {
var date = new Date("2017-07-20 00:00:00"),
dd = date.getDate(),
mm = date.getMonth() + 1,
yyyy = date.getFullYear();
mm = mm < 10 ? '0' + mm : mm;
return dd + '-' + mm +'-' + yyyy;
}
call:
var dateStr = formatDate("2017-07-20 00:00:00");
demo

Android Convert Ruby on Rails Timestamp to Date Time

I am building an Android App, Fetching Data from API that is build in Ruby On Rails Framework.
Here is my timestamp string
2000-01-01T12:00:00.000Z
I need to convert it to Readable date and time format i.e "Saturday January 1st, 2000 12:00 am"
You can try this:
public static String convertDate(String oldDateString){
String format = "yyyy-MM-dd'T'HH:mm:ss.sssZZZZ";
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date date = null;
try {
date = sdf.parse(oldDateString);
} catch (ParseException e) {
// handle exception here !
}
String newFormatString = "MMMM dd, yyyy 'at' HH:mm a";
SimpleDateFormat newFormatter = new SimpleDateFormat(newFormatString);
String newDateString = newFormatter.format(date);
return newDateString;
}
I had the same issue and I tried #real19 answer but it gave me errors.
I came with that then :
public static String convertDate(String oldDateString){
String format = "yyyy-MM-dd'T'HH:mm:ss.sss";
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date date = null;
try {
date = sdf.parse(oldDateString);
} catch (ParseException e) {
// handle exception here !
e.printStackTrace();
}
String newFormatString = "EEEE MMMM dd, yyyy 'at' HH:mm a";
SimpleDateFormat newFormatter = new SimpleDateFormat(newFormatString);
String newDateString = newFormatter.format(date);
return newDateString;
}
Formatting gave me jeudi décembre 22, 2016 at 16:42 PM but you can adjust your DateFormat

How to convert java.util.Date to GMT format

I have a string "2014-07-02T17:12:36.488-01:00" which shows the Mountain time zone. I parsed this into java.util.date format. Now I need to convert this to GMT format. Can anyone help me??
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
Object dd = null;
try {
dd=sdf.parseObject("2014-07-02T17:12:36.488-01:00");
System.out.println(dd);
} catch (ParseException e) {
e.printStackTrace();`enter code here`
}
SimpleDateFormat gmtDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
gmtDateFormat.setTimeZone(java.util.TimeZone.getTimeZone("GMT"));
System.out.println("Current Date and Time in GMT time zone:+ gmtDateFormat.format(dd));
There are a few problems in your code. For example, the format string doesn't match the actual format of the string you are parsing.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
Object dd = null;
try {
dd = sdf.parse("2014-07-02T17:12:36.488-01:00");
System.out.println(dd);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat gmtDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ssX");
gmtDateFormat.setTimeZone(java.util.TimeZone.getTimeZone("GMT"));
System.out.println("Current Date and Time in GMT time zone:" + gmtDateFormat.format(dd));
To print the current date in whatever timezone you like, set the timezone you want to use on the SimpleDateFormat object. For example:
// Create a Date object set to the current date and time
Date now = new Date();
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
df.setTimeZone(TimeZone.getTimeZone("GMT"));
System.out.println("Current date and time in GMT: " + df.format(now));
df.setTimeZone(TimeZone.getTimeZone("IST"));
System.out.println("Current date and time in IST: " + df.format(now));

How to convert the following string to date or calendar object in Java?

Have a string like 2011-03-09T03:02:10.823Z, how to convert it to Date or calendar object in Java?
You can use SimpleDateFormat#parse() to convert a String in a date format pattern to a Date.
String string = "2011-03-09T03:02:10.823Z";
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";
Date date = new SimpleDateFormat(pattern).parse(string);
System.out.println(date); // Wed Mar 09 03:02:10 BOT 2011
For an overview of all pattern characters, read the introductory text of SimpleDateFormat javadoc.
To convert it further to Calendar, just use Calendar#setTime().
Calendar calendar = Calendar.getInstance();
calendar.setTime(date);
// ...
I want to show "2017-01-11" to "Jan 11" and this is my solution.
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat df_output = new SimpleDateFormat("MMM DD");
Calendar cal=Calendar.getInstance();
Date date = null;
try {
date = df.parse(selectedDate);
String outputDate = df.format(date);
date = df_output.parse(outputDate);
cal.setTime(date);
} catch (ParseException e) {
e.printStackTrace();
}
import java.util.*;
import java.text.*;
public class StringToCalender {
public static void main(String[] args) {
try { String str_date="11-June-07";
DateFormat formatter ;
Date date ;
formatter = new SimpleDateFormat("dd-MMM-yy");
date = (Date)formatter.parse(str_date);
Calendar cal=Calendar.getInstance();
cal.setTime(date);
System.out.println("Today is " +date );
} catch (ParseException e)
{System.out.println("Exception :"+e); }
}
}
Your given date is taken as a string that is converted into a date type by using the parse() method. The parse() method invokes an object of DateFormat. The setTime(Date date) sets the formatted date into Calendar. This method invokes to Calendar object with the Date object.refer
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
Date date = sdf.parse(strDate);
Calendar cal = Calendar.getInstance();
cal.setTime(date);
try this.(strDate id your string format of Date)

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