How to draw a ring shape in Java using unit circle trig - java

I have to draw a ring using lines (drawLine) in Java that should look like the attached picture. We are provided with the classDrawingPanel that can be found here.
I've made a regular circle using lines, but I'm unsure how to get the ring shape. I'm new to programming and this is my first post, so apologies if I've missed something important.
This is my code so far:
public static int panelSize = 400;
public static void drawCircle()
{
double radius = 200;
int x2 = 200;
int y2 = 200;
DrawingPanel dp = new DrawingPanel(panelSize, panelSize);
dp.setBackground(Color.CYAN);
Graphics dpGraphics = dp.getGraphics();
dpGraphics.setColor(Color.RED);
for (int circle = 0; circle <= 360; circle++)
{
int x = (int)(x2 + Math.sin(circle * (Math.PI / 180)) * radius);
int y = (int)(y2 + Math.cos (circle * (Math.PI / 180)) * radius);
dpGraphics.drawLine(x, y, x2, y2);
}
}
This is what the final result should look like:

Such a figure can be drawn by drawing a line from one point to a point farther away on the circle, passing the starting point several times.
This is what I came up with:
// Radius
int radius = 200;
// center of the circle
int centerX = 300, centerY = 300;
// The number of edges. Set to 5 for a pentagram
int mod = 136;
// The number of "points" to skip - set to 2 for a pentagram
int skip = 45;
// Precalculated multipier for sin/cos
double multi = skip * 2.0 * Math.PI / mod;
// First point, calculated by hand
int x1 = centerX; // sin(0) = 0
int y1 = centerY + radius; // cos(0) == 1
for (int circle = 1; circle <= mod; circle++)
{
// Calculate the end point of the line.
int x2 = (int) (centerX + radius * Math.sin(circle * multi));
int y2 = (int) (centerY + radius * Math.cos(circle * multi));
dpGraphics.drawLine(x1, y1, x2, y2);
// Next start point for the line is the current end point
x1 = x2;
y1 = y2;
}
The result looks like this:

Related

(Java / Processing) How to create several instances of an object on different positions on the screen?

I am unable to create several instances of the waveClock object even though I have put it in an array and marked the centre positions for each object. I would like to create 4 objects in one window, all responding to different sound frequencies/beat onsets etc
Could someone shed some light on how to go about this? I believe it may be an issue with the centerX and centerY variables in the waveClock class
ArrayList<waveClock> waveClocks = new ArrayList<waveClock>();
//global variables
float angnoise, radiusnoise;
float xnoise, ynoise;
float angle = -PI/6;
float radius;
float strokeCol = 254;
int strokeChange = -1;
int speed; //changes speed of visualisation once beat is detected?
void setup()
//for every waveClock we need 180 pixels width, then add 20 pixels for first gap
size(740, 650);
background(255);
//code is called
waveClocks.add(new waveClock(100, height/2, minRadius, bassColour, lowBassBand, highBassBand, numberOfLowOnsetsThreshold));
waveClocks.add(new waveClock(280, height/2, minRadius, midColour, lowMidBand, highMidBand, numberOfMidOnsetsThreshold));
waveClocks.add(new waveClock(460, height/2, minRadius, highColour, lowHighBand, highHighBand, numberOfHighOnsetsThreshold));
waveClocks.add(new waveClock(640, height/2, minRadius, veryHighColour, lowVeryHighBand, highVeryHighBand, numberOfVeryHighOnsetsThreshold));
//set the min and max radius of each of the viz circles
/* for (int i = 0; i < waveClocks.size(); i++) {
//go through the arraylist of waveClocks and set the min and max radius of each circle
waveClocks.get(i).setMinMaxRadius(minRadius, maxRadius);
}*/
song.play();
beat = new BeatDetect(song.bufferSize(), song.sampleRate());
bl = new BeatListener(beat, song);
}
void draw() {
//clear the screen by painting it black
//background(0);
for (int i = 0; i < waveClocks.size(); i++) {
//has there been a beat in the range? get(circle ID).low band, high band etc.
if (beat.isRange(waveClocks.get(i).getLowBand(), waveClocks.get(i).getHighBand(), waveClocks.get(i).getOnsetThreshold())) {
waveClocks.get(i).setMaxRadius();
}
//waveClocks.get(i).drawCircle();
waveClocks.get(i).drawWaveClock();
}
}
waveClock class in a separate tab
//class is an architecture blueprint
//objects are the actual buildings built from the methods (can make as many as you like)
//constructor is the builder/constructor literally
class waveClock {
float centerX; //co-ordinates of circle's position
float centerY; //co-ordinates of circle's position
float radius; //avg radius
// float minRadius; //smallest size it can be
// float maxRadius; //biggest size it can be
color col; //colour
int onsetThreshold; //
int lowBand; //looks at lowest band of frequency and makes circle sensitive to it
int highBand; //looks at highest band of frequency and makes circle sensitive to it
boolean onset; //has there been an onset (beat has occurred or not?)
//the constructor
waveClock(float x, float y, float r, color c, int lb, int hb, int t) {
centerX = x;
centerY = y;
radius = r;
col = c;
lowBand = lb;
highBand = hb;
onsetThreshold = t;
}
void drawWaveClock() {
radiusnoise += 0.005;
radius = (noise(radiusnoise)*350) + 1;
angnoise += 0.005;
angle += (noise(angnoise)*6) - 3;
if (angle > 360) {
angle -= 360;
} else if (angle < 0) {
angle += 360;
}
xnoise += 0.01;
ynoise =+ 0.01;
float centerX = width/2 + (noise(xnoise)*100) - 50;
float centerY = height/2 + (noise(ynoise)*100) - 50;
float rad = radians(angle);
float x1 = centerX + (radius*cos(rad));
float y1 = centerY + (radius*sin(rad));
float opprad = rad + PI;
float x2 = centerX + (radius*cos(opprad));
float y2 = centerY + (radius*sin(opprad));
strokeCol += strokeChange;
if (strokeCol > 354) {
strokeChange = -1;
} else if (strokeCol < 0) {
strokeChange = 1;
}
stroke(strokeCol, 60);
strokeWeight(1);
line(x1, y1, x2, y2);
}
}
You aren't ever using the class-level centerX and centerY variables. Instead, you're recalculating a new centerX and centerY in the drawWaveClock() function.
float centerX = width/2 + (noise(xnoise)*100) - 50;
float centerY = height/2 + (noise(ynoise)*100) - 50;
These are all drawn from the center of the screen, so the waves will end up in the same position.
In the future, please try to narrow your problem down to a MCVE that demonstrates the problem. Also please use proper naming conventions- classes start with an upper-case letter, for example. Good luck.

How do I do anti-aliasing in java? (WITHOUT built in methods)

I am going to try my best to give context for the below code. This is a method used to draw a circle and its center point in a 50x50 white square background. The following variables were used:
xc,yx - the center coordinates used to compute the circle
r - the radius of the circle
STEP - how often a new point is drawn on the circumference of the circle
x,y - the coordinates of each point that will make up the circle
Right now, my method uses a for loop to compute each points R,G, and B coordinates along the circumference of the circle based on the center point and the radius. What I am trying to do is anti-alias my output circle so that the round parts are not as jagged. However, I want to do this using only math and variables and I do not want to use any of Java's build in methods. Thank you to anyone who can help or point me in the right direction.
Below is my routine:
protected void proc_21() {
info = "Draw anti-aliased circle";
int xc = (int) rand(1, imgW - 2);
int yc = (int) rand(1, imgH - 2);
int r = (int) rand(4, 0.35f * (imgW + imgH));
int STEP = (2 * (int) Math.PI * r) * 57;
System.out.printf("circle centered at (%d,%d), radius = %d, draw in %d steps. \n", xc,yc,r,STEP);
for (int i = 0; i < STEP; i++) {
int x = (int) Math.round(xc + r * Math.cos(i));
int y = (int) Math.round(yc + r * Math.sin(i));
if (0 <= x && x < imgW) {
if ( 0 <= y && y < imgH) {
imgNew.setR(x, y, 0);
imgNew.setG(x, y, 0);
imgNew.setB(x, y, 1);
}
}
}
// set center to red
imgNew.setR(xc, yc, 1);
imgNew.setG(xc, yc, 0);
imgNew.setB(xc, yc, 0);
}

Ellipse2D draws with poor accuracy

I'm making an application about space physics, so I do lots with orbits. Naturally, I encounter the Ellipse2D.Double to draw my orbits on the screen.
Whenever my JPanel refreshes, I draw the orbit of a body using an Ellipse2D, as well as the body itself with a different method.
Essentially, I discovered that when numbers get very large (whether it be the size of the orbits get large or the visualization is zoomed in very far), the position of the body and the Ellipse2D do not line up.
I calculate the position of the body using a conversion from polar coordinates to rectangular coordinates, and I leave the math for the Ellipse2D up to the geom package.
Take a look at this code sample. It's the most self-contained version of my problem that I can make, since scale of the circle has to be very large:
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Line2D;
import java.math.BigDecimal;
import javax.swing.JFrame;
import javax.swing.JPanel;
public class EllipseDemo extends JPanel {
public static void main(String[] args) {
JFrame frame = new JFrame();
frame.setSize(500, 500);
frame.add(new EllipseDemo());
frame.setVisible(true);
}
#Override
public void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g;
// These values allow for a very zoomed in view of a piece of the circle
BigDecimal[] circleCenter = { new BigDecimal(-262842.5), new BigDecimal(-93212.8) };
BigDecimal circleRadius = new BigDecimal(279081.3);
// Draw the circle at the given center, with the given width and height
// x = centerx - radius, y = centery - radius, w = h = radius * 2
g2d.draw(new Ellipse2D.Double(circleCenter[0].subtract(circleRadius).doubleValue(),
circleCenter[1].subtract(circleRadius).doubleValue(), circleRadius.multiply(new BigDecimal(2)).doubleValue(),
circleRadius.multiply(new BigDecimal(2)).doubleValue()));
// Get a rectangular conversion of a point on the circle at this angle
BigDecimal angle = new BigDecimal(0.34117696217);
BigDecimal[] rectangular = convertPolarToRectangular(new BigDecimal[] {
circleRadius, angle });
// Draw a line from the center of the circle to the point
g2d.draw(new Line2D.Double(circleCenter[0].doubleValue(), circleCenter[1].doubleValue(),
circleCenter[0].add(rectangular[0]).doubleValue(), circleCenter[1]
.add(rectangular[1]).doubleValue()));
}
public BigDecimal[] convertPolarToRectangular(BigDecimal[] polar) {
BigDecimal radius = polar[0];
BigDecimal angle = polar[1];
BigDecimal x = radius.multiply(new BigDecimal(Math.cos(angle.doubleValue())));
BigDecimal y = radius.multiply(new BigDecimal(Math.sin(angle.doubleValue())));
return new BigDecimal[] { x, y };
}
}
The code above essentially draws a circle on the screen very far away with a large radius. I've picked the dimension so that a piece of the circle is visible in the small window.
Then it draws a line from the center of the circle to a point on the circle that's visible in the window: I picked an angle that was visible on the window and used geometry to convert that angle and the radius of the circle into rectangular coordinates.
This is what the program displays:
Notice that the line doesn't actually end up touching the ellipse. Now, I decided I had to find out whether it was the point I calculated or the ellipse that were incorrect. I did the math on my calculator, and found that the line was correct, and the ellipse incorrect:
Considering that the calculator is probably not wrong, I am led to believe the Ellipse2D is not drawing correctly. However, I tried many other angles, and this is the pattern I found:
And that leads me to believe the calculations are somehow wrong.
So that's my problem. Should I be using something other than Ellipse2D? Maybe Ellipse2D is not accurate enough? I used BigDecimals in my code sample because I thought it would give me more precision - is that the wrong approach? My ultimate goal is to be able to calculate the rectangular position of a point on an ellipse at a specific angle.
Thanks in advance.
You see this error because Ellipse2D is approximated by four cubic curves. To make sure just take a look at its path iterator defining shape border: http://grepcode.com/file/repository.grepcode.com/java/root/jdk/openjdk/6-b14/java/awt/geom/EllipseIterator.java#187
To improve quality we should approximate ellipse by higher number of cubic curves. Here is an extention of standard java implementation with changeable number of segments:
class BetterEllipse extends Ellipse2D.Double {
private int segments;
public BetterEllipse(int segments, double x, double y, double w, double h) {
super(x, y, w, h);
this.segments = segments;
}
public int getSegments() {
return segments;
}
#Override
public PathIterator getPathIterator(final AffineTransform affine) {
return new PathIterator() {
private int index = 0;
#Override
public void next() {
index++;
}
#Override
public int getWindingRule() {
return WIND_NON_ZERO;
}
#Override
public boolean isDone() {
return index > getSegments() + 1;
}
#Override
public int currentSegment(double[] coords) {
int count = getSegments();
if (index > count)
return SEG_CLOSE;
BetterEllipse ellipse = BetterEllipse.this;
double x = ellipse.getCenterX() + Math.sin(2 * Math.PI * index / count) * ellipse.getWidth() / 2;
double y = ellipse.getCenterY() + Math.cos(2 * Math.PI * index / count) * ellipse.getHeight() / 2;
if (index == 0) {
coords[0] = x;
coords[1] = y;
if (affine != null)
affine.transform(coords, 0, coords, 0, 1);
return SEG_MOVETO;
}
double x0 = ellipse.getCenterX() + Math.sin(2 * Math.PI * (index - 2) / count) * ellipse.getWidth() / 2;
double y0 = ellipse.getCenterY() + Math.cos(2 * Math.PI * (index - 2) / count) * ellipse.getHeight() / 2;
double x1 = ellipse.getCenterX() + Math.sin(2 * Math.PI * (index - 1) / count) * ellipse.getWidth() / 2;
double y1 = ellipse.getCenterY() + Math.cos(2 * Math.PI * (index - 1) / count) * ellipse.getHeight() / 2;
double x2 = x;
double y2 = y;
double x3 = ellipse.getCenterX() + Math.sin(2 * Math.PI * (index + 1) / count) * ellipse.getWidth() / 2;
double y3 = ellipse.getCenterY() + Math.cos(2 * Math.PI * (index + 1) / count) * ellipse.getHeight() / 2;
double x1ctrl = x1 + (x2 - x0) / 6;
double y1ctrl = y1 + (y2 - y0) / 6;
double x2ctrl = x2 + (x1 - x3) / 6;
double y2ctrl = y2 + (y1 - y3) / 6;
coords[0] = x1ctrl;
coords[1] = y1ctrl;
coords[2] = x2ctrl;
coords[3] = y2ctrl;
coords[4] = x2;
coords[5] = y2;
if (affine != null)
affine.transform(coords, 0, coords, 0, 3);
return SEG_CUBICTO;
}
#Override
public int currentSegment(float[] coords) {
double[] temp = new double[6];
int ret = currentSegment(temp);
for (int i = 0; i < coords.length; i++)
coords[i] = (float)temp[i];
return ret;
}
};
}
}
And here is how you can use it in your code instead of standard one (I use 100 segments here):
g2d.draw(new BetterEllipse(100, circleCenter[0].subtract(circleRadius).doubleValue(),
circleCenter[1].subtract(circleRadius).doubleValue(), circleRadius.multiply(new BigDecimal(2)).doubleValue(),
circleRadius.multiply(new BigDecimal(2)).doubleValue()));

Calculating if mouse position is within bounds of a diamond polygon

I have a diamond drawn on a panel and I'm trying to calculate if the mouse position is within its bounds. The problem is trying to the diamond, it needs four coordinates making up four lines to create the shape.
The easy thing to do is to create/fit a square within the bounds of the diamond, but I want to account for the remaining triangular areas outside. I initially thought I trying to calculate the slope between two points and figuring out if the x and y of the mouse intersects the line by adding the slope into the the equation, but it proved to be a lot more difficult when it comes to the lines that make up the TOP->RIGHT, RIGHT->BOTTOM and BOTTOM->LEFT given that the center of the diamond is not zero.
Is there an easier implementation to check if the mouse's x,y is within the bounds of the diamond?
In pseudo-code (to be more readable):
Point org = new Point(64, 32); // Center.
Point radii = new Point(32, 16); // Half the size.
Point mousePos = ...
mousePos -= org; // Relative to the center.
boolean inside = Math.abs(mousePos.x) * radii.y + Math.abs(mousePos.y) * radii.x
<= radii.x * radii.y;
Of math one knows (0, radii.y) and (radii.x, 0) determine the border line in the positive quadrant.
That comes down to the formula above.
static boolean isInsideDiamond(int x, int y, int[] xs, int[] ys) {
int minX = xs[0];
int maxX = minX;
int minY = ys[0];
int maxY = minY;
for (int i = 1; i < 4; ++i) {
minX = Math.min(minX, xs[i]);
maxX = Math.max(maxX, xs[i]);
minY = Math.min(minY, ys[i]);
maxY = Math.max(maxY, ys[i]);
}
int orgX = (minX + maxX) / 2;
int orgY = (minY + maxY) / 2;
int radX = (maxX - minX) / 2;
int radY = (maxY - minY) / 2;
return isInsideDiamond(x, y, orgX, orgY, radX, radY);
}
static boolean isInsideDiamond(int x, int y, int orgX, int orgY, int radX,
int radY) {
x -= orgX;
x = Math.abs(x);
y -= orgY;
y = Math.abs(y);
return x * radY + y * radX <= radX * radY;
}
By the way:
Polygon diamond = new Polygon(xs, ys, 4);
boolean inside = diamond.contains(x, y);

Need a function to limit a line (known by its coordinates) in its length

I need a function which takes a line (known by its coordinates)
and return a line with same angle, but limited to certain length.
My code gives correct values only when the line is turned 'right'
(proven only empirically, sorry).
Am I missing something?
public static double getAngleOfLine(int x1, int y1, int x2, int y2) {
double opposite = y2 - y1;
double adjacent = x2 - x1;
if (adjacent == Double.NaN) {
return 0;
}
return Math.atan(opposite / adjacent);
}
// returns newly calculated destX and destY values as int array
public static int[] getLengthLimitedLine(int startX, int startY,
int destX, int destY, int lengthLimit) {
double angle = getAngleOfLine(startX, startY, destX, destY);
return new int[]{
(int) (Math.cos(angle) * lengthLimit) + startX,
(int) (Math.sin(angle) * lengthLimit) + startY
};
}
BTW: I know that returning arrays in Java is stupid,
but it's just for the example.
It would be easier to just treat it as a vector. Normalize it by dividing my its magnitude then multiply by a factor of the desired length.
In your example, however, try Math.atan2.
In Python because I don't have a Java compiler handy:
import math
def getLengthLimitedLine(x1, y1, x2, y2, lengthLimit):
length = math.sqrt((x2-x1)**2 + (y2-y1)**2)
if length > lengthLimit:
shrink_factor = lengthLimit / length
x2 = x1 + (x2-x1) * shrink_factor
y2 = y1 + (y2-y1) * shrink_factor
return x2, y2
print getLengthLimitedLine(10, 20, 25, -5, 12)
# Prints (16.17, 9.71) which looks right to me 8-)
It's an easy problem if you understand something about vectors.
Given two points (x1, y1) and (x2, y2), you can calculate the vector from point 1 to 2:
v12 = (x2-x1)i + (y2-y2)j
where i and j are unit vectors in the x and y directions.
You can calculate the magnitude of v by taking the square root of the sum of squares of the components:
v = sqrt((x2-x2)^2 + (y2-y1)^2)
The unit vector from point 1 to point 2 equals v12 divided by its magnitude.
Given that, you can calculate the point along the unit vector that's the desired distance away by multiply the unit vector times the length and adding that to point 1.
Encapsulate Line in a class, add a unit method and a scale method.
public class Line {
private float x;
private float y;
public Line(float x1, float x2, float y1, float y2) {
this(x2 - x1, y2 - y1);
}
public Line(float x, float y) {
this.x = x;
this.y = y;
}
public float getLength() {
return (float) Math.sqrt((x * x) + (y * y));
}
public Line unit() {
return scale(1 / getLength());
}
public Line scale(float scale) {
return new Line(x * scale, y * scale);
}
}
Now you can get a line of arbitrary length l by calling
Line result = new Line(x1, x2, y1, y2).unit().scale(l);
No need to use trig, which can have some nasty edge cases. Just use similar triangles:
public static int[] getLengthLimitedLine(int startX, int startY,
int destX, int destY, int lengthLimit)
{
int deltaX = destX - startX;
int deltaY = destY - startY;
int lengthSquared = deltaX * deltaX + deltaY * deltaY;
// already short enough
if(lengthSquared <= lengthLimit * lengthLimit)
return new int[]{destX, destY};
double length = Math.sqrt(lengthSquared);
double newDeltaX = deltaX * lengthLimit / length;
double newDeltaY = deltaY * lengthLimit / length;
return new int[]{(int)(startX + newDeltaX), (int)(startY + newDeltaY)};
}
Just use the Pythagorean theorem, like so:
public static int[] getLengthLimitedLine(int start[], int dest[], int lengthLimit) {
int xlen = dest[0] - start[0]
int ylen = dest[1] - start[1]
double length = Math.sqrt(xlen * xlen + ylen * ylen)
if (length > lengthLimit) {
return new int[] {start[0], start[1],
start[0] + xlen / lengthLimit,
start[1] + ylen / lengthLimit}
} else {
return new int[] {start[0], start[1], dest[0], dest[1];}
}
}

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