I have place the locator in properties file like :
header.navigation.product.link = //div[contains(#class,'grid-')]//li/a[contains(.,'%s')]
and while I'm using this locator in my code-
String headerproductlink = String.format(ConfigurationManager.getBundle()
.getString("header.navigation.category.link"), category)
And category = Women's Gym Clothing
While I'm trying to locate the element it unable to find.
even i have tried as Women\'s Gym Clothing but no success.
Can someone please suggest a way ?
In XPath 1.0 you can use either single quotes or double quotes to delimit a string literal, and you can use the other kinds of quotes to represent itself within the string. You can't have a string literal containing both single and double quotes, but you can use concat() to get around this limitation:
concat('He said: "', "I won't", '"')
The situation is complicated if the XPath expression appears within a host language that imposes its own constraints; in that case any quotes within the XPath expression must be escaped using host language conventions, for example \" in Java, " in XML.
Below different ways worked for me:
Locator in Property file:
another.header=xpath=//h1[contains(.,"%s")]
Java code:
String t = "st. john\'s bay - women";
String header = String.format(getBundle().getString("another.header"), t);
CommonStep.get("https://www.jcpenney.com/g/st-johns-bay-women/N-bwo3xZ1z0nvauZ1z0nh7w");
String headerText=ElementFactory.$(header).getText();
Below also worked fine
Locator in Property file:
another.header={'locator':'xpath=//h1[contains(.,"%s")]'}
Java code:
String t = "st. john\\'s bay - women";
...
Or
Locator in Property file:
another.header={"locator":"xpath=//h1[contains(.,\\"%s\\")]"}
Java code:
String t = "st. john's bay - women";
...
Related
I have a CSV file below from one of the system.
""demo"",""kkkk""
""demo " ","fg"
" " demo" "
"demo"
"value1","" frg" ","vaue5"
"val3",""tttyy " ",""hjhj","ghuy"
Objective is get all the 2 pair double quotes removed and only one set of double quote is allowed like below. The spaces between the sets of double quote is not a fixed value. This has to be handled in a Java program using replaceAll
function in Java
"demo","kkkk"
"demo","fg"
"demo"
"demo"
"value1","frg","vaue5"
"val3","tttyy","hjhj","ghuy"
I tired this on regex101 with "[ ]*" and it works for PHP>=7.3 version but not in Java.
Also tried [\"][\"]|[^\"]\s+[\"] but still not getting desired output. Any suggestion please for the regular expression which can be used in Java program?
Based on shown sample data, you can use:
String repl = str.replaceAll("(?:\\h*\"){2}\\h*", "\"");
RegEx Demo
RegEx Details:
(?:\h*\"){2}: Match a pair of double quotes that have 0 or more whitespaces between them
\h*: Match 0 or more whitespace
Replacement is just a "
My String is like this.
{\\\"692950841314120\\\":[{\\\"type\\\":\\\"ads_management\\\",\\\"call_count\\\":3,\\\"total_cputime\\\":1,\\\"total_time\\\":5,\\\"estimated_time_to_regain_access\\\":0}]}
Since the key here is a variable value I am trying to replace this 692950841314120(or the values which I get from sever) with a constant like ID. My main goal is to parse this as POJO. I have tried using..
string.replaceAll("^[0-9]{15}$","ID")
but due to Slashes I think i am not able to get the desired value. Is there any better way to do this. I know I can do below Code but I don't want any ID123 if I added extra value and distort any other info in JSON.
string.replaceAll("[0-9]{15}","ID")
Strictly speaking, if you have a valid JSON string, you should parse it using something like GSON, rather than using regex. That being said, if you must use regex, you could try removing the starting and ending anchors:
string.replaceAll("[0-9]{15}", "ID")
Or maybe use double quotes instead:
string.replaceAll("\"[0-9]{15}\"", "ID")
It is safer to assume the value is inisde \" and \":.
You can then use
.replaceAll("(\\\\\")[0-9]{15}(\\\\\":)", "$1ID$2")
The regex is (\\")[0-9]{15}(\\":) and it means:
(\\") - match and capture \" substring into Group 1
[0-9]{15} - fifteen digits
(\\":) - Group 2: a \": substring.
The $1 and $2 are placeholders holding the Group 1 and 2 values.
You should use "A word boundary" \b.
Try this.
public static void main(String[] args) {
String input = "{\\\"692950841314120\\\":"
+ "[{\\\"type\\\":\\\"12345678901234567890\\\","
+ "\\\"call_count\\\":3,"
+ "\\\"total_cputime\\\":1,"
+ "\\\"total_time\\\":5,"
+ "\\\"estimated_time_to_regain_access\\\":0}]}";
System.out.println(input.replaceAll("\\b[0-9]{15}\\b", "ID"));
}
output:
{\"ID\":[{\"type\":\"12345678901234567890\",\"call_count\":3,\"total_cputime\":1,\"total_time\":5,\"estimated_time_to_regain_access\":0}]}
<element>
<Argument Name="AWSAccessKeyId" Value="APOEIUVWIE8E78E6"></Argument>
<Argument Name="SearchIndex" Value="Apparel"></Argument>
<LegalDisclaimer>Leriya Fashion products,on amazon.in."Leriya Fashion" in search.</LegalDisclaimer>
</element>
I want to replace only quotes in this word ("Leriya Fashion").I have tried many regular expression but they replace all the quotes.Right now we know this word but what if we don't know the actual word.
"|[a-z]$$|"$
"|"+\s
I want to replace it with blank or space. And the main problem is occurred when we convert this xml to json. Because json take this double quoted as value but in actual its not a value its just a name which is double quoted.So for me its very tough to replace this quote with blank in json thats why I'm trying to replace this in xml file.
If it's only "Leriya Fashion", then why not just use String::replace
str = str.replace("\"Leriya Fashion\"", "Leriya Fashion");
I'm assuming you just want to remove the quotes.
Lambda replaceAll
str = Pattern.compile("(.)\"([^\"\r\n]*\"").matcher(str)
.replaceAll(mr -> mr.group(1).equals("=") ? mr.group()
: mr.group(1) + mr.group(2));
This will replace all quotes from any text "..." from non-HTML-attributes (="...").
The dangerous assumption is that quotes only appear in pairs.
I have a String with single quote. I want to replace the single quote with 2 single quotes.
I tried using
String s="Kathleen D'Souza";
s.replaceAll("'","''");
s.replaceAll("\'","\'\'");
s.replace("'","''");
s.replace("\'","\'\'");
But the single quote is not getting replaced with 2 single quotes.
reassign the replaced string to s
String s="Kathleen D'Souza";
s = s.replaceAll("'","''");
Please try
s= "test ' test";
`s.replaceAll("'","\"");` => test " test
`s.replaceAll("'","''");` => test '' test
Strings are immutable. Assign the result of replaceAll to your String:
s = s.replaceAll("'","''");
String s="Kathleen D'Souza";
s= s.replace("'", "''");
Try String#replace(). It will replace all occurrence of single ' with double ''.
Note, with the given solutions successive single quotes will be doubled, so Kathleen D''Souza turns into Kathleen D''''Souza. (I've seen users outsmart themselves like this.) If that is something you are concerned about, you can match successive single quotes with:
s = s.replaceAll("''*","''");
need to find an expression for the following problem:
String given = "{ \"questionID\" :\"4\", \"question\":\"What is your favourite hobby?\",\"answer\" :\"answer 4\"},{ \"questionID\" :\"5\", \"question\" :\"What was the name of the first company you worked at?\",\"answer\" :\"answer 5\"}";
What I want to get: "{ \"questionID\" :\"4\", \"question\":\"What is your favourite hobby?\",\"answer\" :\"*******\"},{ \"questionID\" :\"5\", \"question\" :\"What was the name of the first company you worked at?\",\"answer\" :\"******\"}";
What I am trying:
String regex = "(.*answer\"\\s:\"){1}(.*)(\"[\\s}]?)";
String rep = "$1*****$3";
System.out.println(test.replaceAll(regex, rep));
What I am getting:
"{ \"questionID\" :\"4\", \"question\":\"What is your favourite hobby?\",\"answer\" :\"answer 4\"},{ \"questionID\" :\"5\", \"question\" :\"What was the name of the first company you worked at?\",\"answer\" :\"******\"}";
Because of the greedy behaviour, the first group catches both "answer" parts, whereas I want it to stop after finding enough, perform replacement, and then keep looking further.
The pattern
("answer"\s*:\s*")(.*?)(")
Seems to do what you want. Here's the escaped version for Java:
(\"answer\"\\s*:\\s*\")(.*?)(\")
The key here is to use (.*?) to match the answer and not (.*). The latter matches as many characters as possible, the former will stop as soon as possible.
The above pattern won't work if there are double quotes in the answer. Here's a more complex version that will allow them:
("answer"\s*:\s*")((.*?)[^\\])?(")
You'll have to use $4 instead of $3 in the replacement pattern.
The following regex works for me :
regex = "(?<=answer\"\\s:\")(answer.*?)(?=\"})";
rep = "*****";
replaceALL(regex,rep);
The \ and " might be incorrectly escaped since I tested without java.
http://regexr.com?303mm