This question already has answers here:
Java date parsing with microsecond or nanosecond accuracy
(3 answers)
Closed 4 years ago.
I have to parse a date time String being sent over json - using Java 7, with the date time being in this format :
2016-04-26T11:35:30.0543787Z
The problem I'm having is with the extra decimals in the seconds - I can parse it if it is only to 3 decimal places e.g. milliseconds.
I can parse the value using SimpleDateFormat and the format string
"yyyy-MM-dd'T'HH:mm:ss.SSS'Z'" but this gives an incorrect value.
Any help would be appreciated!
Since you are not bother about the precision of the milliseconds, we can remove the decimals from the seconds.
**NB:**And the output would depend on the current timezone of your server/machine. That's why the you felt like the output is different from what you expected.
String time = "2016-04-26T11:35:30.0543787Z";
int l = time.lastIndexOf('.');
time = time.substring(0, l);
time = time+"Z";
System.out.println(time);
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
try {
Date date = dateFormat.parse(time.replaceAll("Z$", "+0000"));
System.out.println(date);
System.out.println("time zone : " + TimeZone.getDefault().getID());
System.out.println(dateFormat.format(date));
} catch (ParseException e) {
e.printStackTrace();
}
Related
This question already has answers here:
Java SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'") gives timezone as IST
(9 answers)
How to validate the DateTime string format "2018-01-22T18:23:00.000Z" in Java?
(2 answers)
parsing date/time to localtimezone
(2 answers)
Closed 3 years ago.
I am having Input Date as "2020-10-31T00:00:00Z". i want to parse this Date to get Long milliseconds.
Note: Converted milliseconds should be in Sydney Time (ie GMT+11).
FYI,
public static long RegoExpiryDateFormatter(String regoExpiryDate)
{
long epoch = 0;
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
df.setTimeZone(TimeZone.getTimeZone("GMT+11"));
Date date;
try {
date = df.parse(regoExpiryDate);
epoch = date.getTime();
} catch (ParseException e) {
System.out.println("Exception is:" + e.getMessage());
e.printStackTrace();
}
System.out.println("Converted regoExpiryDate Timestamp*************** " + epoch);
return epoch;
}
Output: 1604062800000 which gives Date as 30/10/2019 by using Epoch Converter, but in input i'm passing 31st as Date.
Can anyone please clarify this?
By doing df.setTimeZone(TimeZone.getTimeZone("GMT+11"));, you are asking the date formatter to interpret your string in the GMT+11 time zone. However, your string shouldn't be interpreted in that timezone. See that Z in the string? That stands for the GMT time zone, so you should have done this instead:
df.setTimeZone(TimeZone.getTimeZone("GMT"));
In fact, your string is in the ISO 8601 format for an Instant (or a "point in time", if you prefer). Therefore, you could just parse it with Instant.parse, and get the number of milliseconds with toEpochMilli:
System.out.println(Instant.parse("2020-10-31T00:00:00Z").toEpochMilli());
// prints 1604102400000
Warning: you shouldn't really use SimpleDateFormat anymore if the Java 8 APIs (i.e. Instant and such) are available. Even if they are not, you should use NodaTime or something like that.
This question already has answers here:
Java SimpleDateFormat parse result off by one hour (and yes, I set the time zone)
(2 answers)
Closed 6 years ago.
I have used following code to convert UTC time to device current time zone time. It works fine on Indian Standard Time (IST). But it adds 1 hour additionally when device time zone is Sydney, Australia.
For example, I give UTC time like 2016-10-10T09:10:00 and it is converts as 8:10 PM, but actually I need 7:10 PM.What is the problem in my code?
public static String convertToLocalTimeFormat(String utcDateTimeString) {
SimpleDateFormat simpleDateFormat;
String formattedDateString = "";
simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss", Locale.getDefault());
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Date parsedDateObject;
try {
parsedDateObject = simpleDateFormat.parse(utcDateTimeString);
SimpleDateFormat expectedSimpleDateFormat = new SimpleDateFormat("hh:mm a", Locale.getDefault());
formattedDateString = expectedSimpleDateFormat.format(parsedDateObject);
} catch (ParseException e) {
e.printStackTrace();
return formattedDateString;
}
return formattedDateString;
}
I would advise trying
System.out.println(expectedSimpleDateFormat.getTimeZone());
To see if all daylight saving schemes are correct on that device.
This question already has answers here:
java date parse exception while conveting UTC to local time zone
(5 answers)
Closed 7 years ago.
I get this date string from my API : "2015-12-07T14:11:15.596Z"
But this date is in UTC format and I want to convert it in local time, how can I do it ?
I tried this :
try
{
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
return simpleDateFormat.parse(this.created_at);
}
catch (ParseException e)
{
Log.e("Error Date at Whisp", e.getMessage());
return null;
}
But it return me this error :
Unparseable date: "2015-12-07T13:21:17.996Z" (at offset 10)
your Date Format pattern is wrong. Change to:
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.S'Z'");
For more informations see the javadoc of SimpleDateFormat
The T and the Z are not in your mask
Either
created_at = created_at.replace ("T", "").replace ("Z", "");
or modifiy your mask
This question already has answers here:
Java Unparsable date
(4 answers)
Closed 8 years ago.
I'm trying to convert a timestamp coming from a JSON API to a relative time span string like this:
try {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
Date date = sdf.parse(item.getTimeStamp());
long milliseconds = date.getTime();
CharSequence timeAgo = DateUtils.getRelativeTimeSpanString(
milliseconds,
System.currentTimeMillis(), DateUtils.SECOND_IN_MILLIS);
timestamp.setText(timeAgo);
} catch (java.text.ParseException e) {
e.printStackTrace();
}
The timestamp comes back in JSON like this: 2014-07-01T00:05:20Z
I'm throwing the exception for Unparseable date
What am I doing wrong here?
Z expects timezone value, change your pattern to and you don't need SSS since you don't have milliseconds in input
yyyy-MM-dd'T'HH:mm:ss'Z'
This question already has answers here:
Unix epoch time to Java Date object
(7 answers)
Closed 9 years ago.
I need to convert a String which is a epoch (Unix time) format to a Date class an after a String formatted (dd/MM/yyyy).
Thank you for your help !
Unix time is the number of seconds since 1 January 1970, so this should work
Date date = new Date(unixTime * 1000);
String str = new SimpleDateFormat("dd/MM/yyyy").format(date);
BTW SimpleDateFormat accepts millis as argument too, so it is possible to get the same result as
String str = new SimpleDateFormat("dd/MM/yyyy").format(unixTime * 1000);
Date date = new Date(time);
DateFormat format = new SimpleDateFormat("dd/MM/yyyy");
format.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
String formatted = format.format(date);
System.out.println(formatted);