I'm implementing a web application with Java which in a part of it, I create a SWI-Prolog file. I know about the consult command in Prolog but this command needs an absolute path. But, because i use MongoDB to store my results i would like to store that file in Mongo and not to create directory on my project filesystem to consult the file. Is it possible to consult the file to Prolog without having the actual *.pl file in the root directory?
The argument of consult/1 does not need to be an absolute path. It is just relative to the working directory of Prolog that you may get using ?- pwd.
That still requires you to save the file. That too is not necessary if you can transfer the data through some other means (e.g., networking). If you can somehow get a Prolog stream to the data you can use load_files/2 using the stream(In) option to load the program file.
Related
I am using Talend Studio for Data Integration v5.3.1.
In that I created a Job for fileDelimited. I have uploaded a CSV file and it is reading the file.
I exported the Job as a Zip file, extracted it, and I run the sh file in Terminal. And it was reading the file and displaying it in the console.
Now I want to read a different file in some other file location. is it possible to read the different file by running the same shell script? If so, where I have to change?
you can do it using context variables, and context load.
create configuration file which will have all the required input location path and other details.
you have different files on different location and you just wanted upload files without file parsing right? if so then
first create configuration file with two parameters.
FilePath|FileName
\\Folderone\|File1.txt
\\Foldertwo\|File2.txt
create two context variables in context named as FilePath & FileName
and then used tContextLoad to load above configuration details to context variable
used these variables to provide file and path at runtime from configuration.
See my answer here : https://stackoverflow.com/a/17565718/921244 to have guidance on how to open the Demo project.
There you will find a demo job for loading Context variables.
If you want an online example, take a look at the official documentation : http://www.talendforge.org/tutorials/tutorial.php?language=english&idTuto=34
Android uses a static resource file R. This file (at least in eclipse) is automatically updated when ever you add new id's of any sort. How can I create/implement the same feature in a normal java application? Is it as simple as just writing an xml parser and just updating the resource file after the xml is modified?
In a way, yes. You need to create a custom build script/program which runs at the start of each build (before anything else), scans your resource folder files (and if they are XML files it needs to read in the XML files and parse out the string resources or whatever from those), then write it all to a Java file in some manner (e.g. R.string_name = "string value").
Make sure the XML files aren't actually packaged in your .jar, since all that information will be stored inside your Java resources file now.
For things which aren't XML files you could just store the filename as a string in the Java resources file.
You didn't specified the type or the use of the resources. I don't know android, but I'll try to help; If you just need to access some resource in your application you can use properties or resource, there are some differences see this other question Properties vs Resource Bundle
Anyone plz let us know what to do when we have some configuration file which is basically xml.I want to for example give the path to save the image(for my java program) in a folder from some config file (xml in my case).In that case where should the config file be kept.Rt now every thing is converted to jar file when i create a java standalone package.But i want to give some setting from xml file.What to do in that case.How is it possible.This article only provides to create a single jar file for java project but talks nothing about the configuration settings that u can provide from some external source.
Regards
Sagar
I'm not sure I fully understand your question, but if it is where to put the XML file with configuration information, you can place your xml file in the same directory as your jar file, and then pass the XML file name and path into the Jar on the command line when calling the Jar. If you're running it in Windows, this is often done using a shortcut. Then you can get the full path string for the Jar from the main method's String[] arg array that accepts the command parameters.
Sagar,
The fact your java program is a standalone package (.jar file) has no bearing on where your configuration file is stored. Your java package is a program and that program can read any file from the file system that it so desires; it does not have to be part of the code inside the IDE i.e. you don't have to write it when you write the program. What you do need is some way, when you start the program, to find and read said configuration file.
Depending on how you expect the program to be configured, you might put that file in a number of locations. For example, /etc/yourimageprogram/config.xml or c:\program files\yourimageprogram\config.xml or perhaps c:\users\Sagar\Application Settings\yourimageprogram\config.xml. Which you choose of those options really depends on what the use case is and that I can't help with.
However, there are some main points to reading any file:
Does it exist?
Are we allowed to open it for reading?
Are we allowed to open it for writing? Might want to know if we want to update the config?
In Java, typically, you would test this with:
File configfile = new File("C:\test.xml");
if ( configfile.exists() && configfile.canRead() )
{
// read the file
}
else
{
// decide what to do if no config exists.
// might be first run of app.
}
The next stage is to parse the file. There are a number of parsers available for XML including sax and org.w3c.dom. What you need to do is to use these to extract the information you require and store that in a class. Probably a singleton class as you're unlikely to have multiple configuration instances per instance of the program.
I suggest you read about XML Parsers and File Handling under Java. Also look at the File object. See all your options for file io in java. These should give you some indication of how to proceed.
I’m trying to figure out how to include a reference to a external data file (in text form) that I want distributed along with my application via Web Start (JNLP). Sifting through the documentation for the JNLP structure, I see that you can include references to JAR, nativelib, and extensions – however, I don’t see a means to include a text file resource. How can I accomplish this so that Web Start will download the text file from the server and store it locally along with my application?
I don't believe you can do that.
You can, however, put it on your classpath (in a jar) and reference it through getResourceAsStream().
i just checked that jnlp file is also available as jar file also and as exe file also, so can i open these in a java gui and load my xml file
I want to know how I can use ResourceBundle.getBundle() in an Android application given that I use it in my Java applications. For example:
I have a properties file, "MyOrg.properties", which I've included in a JAR file named "MyOrg.jar". The path information in the JAR file associated with "MyOrg.jar" is "myorg\" (this is on a Windows system). I build my Java application using "myorg.jar" and note that the following line of code works as expected, which is that it loads the file "MyOrg.properties" from "MyOrg.jar" as a java.util.ResourceBundle:
ResourceBundle resources = ResourceBundle.getBundle( "myorg.MyOrg" );
Next, I place a modified copy of the file "MyOrg.properties" on the file system in the directory "c:\myorg", which is on my Java application's class path. I now rerun my Java application and note that the Resource.getBundle() returns, as expected, a bundle for the modified copy of "MyOrg.properties" (the one that is on the file system).
The behavior I've just described is what I would like to be able to accomplish with an Android application. However, ResourceBundle.getBundle() throws a MissingResourceException; it fails to find "MyOrg.properties" in either the JAR file or as a stand-alone file.
So I have two questions:
1) - Is it possible for an Android application to retrieve a resource from a JAR file using ResourceBundle.getBundle() (or any other way for that matter)?
2) - Is it possible for an Android application to retrieve a resource from a file using ResourceBundle.getBundle()?
Regarding 2): I'm using the nbandroid plugin with NetBeans 6.7.1 and I've placed copies of "MyOrg.properties" on the file system as follows prior to building my Android application:
MyProject
-- build
-- classes
myorg (directory contains "MyOrg.properties")
...
src
myorg (directory contains "MyOrg.properties")
you need to make sure the properties file makes it to the .apk file. your best bet is probably in res/raw/ or assets/. see also PropertyResourceBundle's constructors (since it's easy to get hold of an InputStream).