following is my post re quest , in console i am able to see the log i want to store in variable.:
RestAssured.baseURI = "https://www.dummy.com//services";
RestAssured.given().
headers("data",crypto).
when().
post("//auth.svc/auth").
then().contentType(ContentType.JSON).log().all();
Response response = RestAssured.given().
headers("data",crypto).
when().
post("//auth.svc/auth").
then().contentType(ContentType.JSON).
extract().response();
Afterwards you could save the response as a string with response.asString() or inspect the json with a JsonPath object. For example:
JsonPath jsonPathEvaluator = response.jsonPath();
jsonPathEvaluator.get("xyz");
Related
I'm trying to make a POST request with custom headers and json as string on body
Here's my code
HttpRequest request2 = HttpRequest.newBuilder()
.uri(URI.create(POSTS_API_URL))
.headers("accept", "text/plain; charset=UTF-8", "XF-Api-Key", "MYAPIKEY")
.POST(HttpRequest.BodyPublishers.ofString(json))
.build();
System.out.println(request2); //result : https://******.fr/api/auth/ POST
System.out.println(request2.headers()); //result : java.net.http.HttpHeaders#8e33ff08 { {accept=[text/plain; charset=UTF-8], XF-Api-Key=[MYAPIKEY]} }
HttpResponse<String> response2 = client.send(request2, HttpResponse.BodyHandlers.ofString());
// print status code
System.out.println(response2.statusCode()); //400
// print json code
System.out.println(json); //{"login":"LunaLune","password":"***********"}
// print response body
System.out.println(response2.body()); //mandatory input missing : login, password
And my json String
String json = "{" +
"\"login\":\"LunaLune\"," +
"\"password\":\"*********\"" +
"}";
But when I print the request I get : https://*******.fr/api/auth/ POST
the POST request is empty
I googled many forums, code examples ect... but I see that my code where correct according many examples I seen.
So if someone know what is my problem ?
Thanks in advance !
You need to set "Content-Type" as "application/json" in the request header.
See: Which JSON content type do I use?
I try to put data from the NewOrderRequest(pojo) class into the parameters :
#Query("params") NewOrderRequest params
but I get this result:
resultQueryString: params com.example.city.Model.NewOrderRequest#f45c8ad
expectation result:
resultQueryString: params +911
Data setting:
NewOrderRequest newOrderRequest = new NewOrderRequest();
newOrderRequest.setPhone("+911");
NetworkService.getInstance()
.service()
.newOrder(newOrderRequest)
Request:
#Headers({"Accept:application/json", "Content-Type:application/json;"})
#POST("RemoteCall?method=Taxi.WebAPI.NewOrder")
Call<RegResponse>newOrder(#Header("Cookie") String setCookie,#Query("params") NewOrderRequest params);
Please tell me how to pass the phone to the parameter?
You are sending an Object in #Query param, Only #Body accepts the object as its param. What you want is to convert your Object into JsonObject. I assume you're using Gson Library.
NewOrderRequest newOrderRequest = new NewOrderRequest();
newOrderRequest.setPhone("+911");
NetworkService.getInstance()
.service()
.newOrder(new Gson().toJson(newOrderRequest))
Try below code
#Headers({"Accept:application/json", "Content-Type:application/json;"})
#POST("RemoteCall?method=Taxi.WebAPI.NewOrder")
Call<RegResponse>newOrder(#Header("Cookie") String setCookie,#Query("params") String phone);
As it is a post request, and the intention is to send the data as an json object, the data is better sent in the request body rather than query param. Also any sensitive details should be part of request body.
I need to send a video file and JSON object in Rest Assured post call.
Structure is like the following:
{ "sample" : {
"name" : "sample-name",
"kind" : "upload",
"video_file" : multipart file here } }
So I did like the following
Code:
given()
.header("Accept", "application/json")
.header(auth)
.config(rConfig)
.body(body)
.multiPart("sample[video_file]", new File("path"), "video/mp4")
.formParam("sample[name]", "Video Upload")
.formParam("sample[kind]", "upload")
.log().all().
expect()
.statusCode(expectedStatusCode)
.post(url);
I can't use application/JSON while using multipart in Rest Assured. I explicitly hardcoded the value in the form param and sent the media file in multipart and now it is working fine.
How can I send all the form param data in a single inner object.
You can do this by using RequestSpecBuilder. It supports all the request parameters and you can easily create multipart request.
Sample code taken from https://github.com/rest-assured/rest-assured/wiki/Usage
RequestSpecBuilder builder = new RequestSpecBuilder();
builder.addParam("parameter1", "parameterValue");
builder.addHeader("header1", "headerValue");
RequestSpecification requestSpec = builder.build();
given().
spec(requestSpec).
param("parameter2", "paramValue").
when().
get("/something").
then().
body("x.y.z", equalTo("something"));
Thanks for your response rohit. I was post this question for handling inner object with formParams. I've completed by creating a Hash Map for formParams. Because formParams method of rest assured can accept Hash map.
Form params map creation:
private static Map<String, String> createFormParamsMap(VideoTagInput videoTag) {
Map<String, String> formParams = new HashMap<>();
formParams.put(createFormParamKey("name"), "name");
formParams.put(createFormParamKey("kind"), "kind");
return formParams;
}
private static String createFormParamKey(String paramKey) {
return "sample[" + paramKey + "]";
// output is like "sample[name]" - I'm forming inner object here for my purpose.
}
Finally send the map to Rest Assured post call function
given()
.header("Accept", "application/json")
.header(auth)
.config(rConfig)
.multiPart("sample[video_file]", new File("path"), "video/mp4")
.formParams(requestParamsMap) // requestParamsMap here.
.log().all().
expect()
.statusCode(expectedStatusCode)
.post(url);
Your approach is definitely not standard.
You cannot have a multipart request and a JSON body, you need to pick one over the 2 approaches: multipart/form-data or application/json request.
The standard way is to have a multipart request with a "json" param containing the serialized JSON payload, and a "file" param with the multipart file.
given()
.contentType(MediaType.MULTIPART_FORM_DATA_VALUE)
.multiPart(file)
.param("json", "{\"sample\":{\"name\":\"sample- name\",\"kind\":\"upload\",\"video_file\":<this is not needed>}}")
But this involves changing your server-side logic.
If you cannot change your server-side logic, you need to serialize your file as (for instance as an array of bytes, or as base64 string) to be set as video_file in your JSON payload. In which case you'll have an application/json content type request, not a 'multipart/form-data'.
I got the following response from the API call :
[{"id":63,"name":"Apple Inc.","ticker":"AAPL","website":"www.apple.com","street1":null,"street2":null,"country":null,"postal_code":null,"city":null,"state":null,"type_value":"PUBLIC","person":[{"id":6854208},{"id":6854192},{"id":7795},{"id":6837866},{"id":6854188},{"id":6840774},{"id":6838278},{"id":7637},{"id":6839671},{"id":6837862},{"id":6840759},{"id":6840766},{"id":6838242},{"id":6840830},{"id":6840838},{"id":7875},{"id":3038662},{"id":865765},{"id":6839669},{"id":6837834},{"id":6839685},{"id":6839931},{"id":6840777},{"id":6838232},{"id":6838260},{"id":1859904},{"id":6854204},{"id":6838238},{"id":6839751}],"type":3001,"revenue":null,"industry":[{"industry":"Computer Hardware","industry_id":5009},{"industry":"Electronics","industry_id":5016},{"industry":"Technology - All","industry_id":5044}],"description":null}]
How do I get the value of name from the response?
This is what I have right now:
System.err.println("fullBspApiUrl"+fullBspApiUrl);
Response resp = get(fullBspApiUrl);
System.err.println("This is response"+resp);
String bJson = resp.asString();
System.err.println("This is response after string conversion"+bJson);
JsonPath jsonpath = new JsonPath(bJson);
System.err.println("Instantiate JsonPath "+jsonpath);
//String bspOrgName = jsonpath.getString("organizationName[0]");
String bspOrgName = jsonpath.getString("organizationName[0]");
System.err.println("This is response after JsonPath string conversion "+bspOrgName);
assertEquals(resp.getStatusCode(),200);
assertEquals(bspOrgName,"Apple Inc");
It returns Null instead of Apple.
get(fullBspApiUrl).then().statusCode(200).
and().assertThat().body(name[0], equalTo("Apple Inc"))
name[0] works fine. The previous response had it as OrganizationName
I'm sending a http post request from javascript, with some json data.
Javascript
var data = {text : "I neeed to store this string in database"}
var xhr= new XMLHttpRequest();
xhr.open("POST","http://localhost:9000/postJson" , true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
xhr.send(data);
xhr.setRequestHeader("Connection", "close");
//Also, I've tried a jquery POST
//$.post('postJson', {'data=' : JSON.stringify(data)});
//But this doesn't make a request at all. What am I messing up here?
Route
POST /postJson controllers.Application.postJson()
Controller
public static Result postJson(){
//What should I write here to get the data
//I've tried the below but values is showing null
RequestBody rb=request().body();
final Map<String,String[]> values=rb.asFormUrlEncoded();
}
What is the way to parse the POST request body?
Much thanks!
Retreive the request body directly as JSON... no need to complicate your life.
public static Result postJson() {
JsonNode rb = request().body().asJson();
//manipulate the result
String textForDBInsertion = rb.get("text").asText(); //retreives the value for the text key as String
Logger.debug("text for insertion: " + textForDBInsertion
+ "JSON from request: " + rb);
return ok(rb);
}
Also, I recommend you use the AdvancedRestClient Chrome plugin for testing. This way you can eliminate from the equation client-side code errors.
Cheers!