String s = "author= {insert text here},";
Trying to get the inside of the string, ive looked around but couldn't find a resolution with just split or tokenizer...
so far im doing this
arraySplitBracket = s.trim().split("\\{", 0);
which gives me insert text here},
at array[1] but id like a way to not have } attached
also tried
StringTokenizer st = new StringTokenizer(s, "\\{,\\},");
But it gave me author= as output.
public static void main(String[] args) {
String input="{a c df sdf TDUS^&%^7 }";
String regEx="(.*[{]{1})(.*)([}]{1})";
Matcher matcher = Pattern.compile(regEx).matcher(input);
if(matcher.matches()) {
System.out.println(matcher.group(2));
}
}
You can use \\{([^}]*)\\} Regex to get string between curly braces.
Code Snap :
String str = "{insert text here}";
Pattern p = Pattern.compile("\\{([^}]*)\\}");
Matcher m = p.matcher(str);
while (m.find()) {
System.out.println(m.group(1));
}
Output :
insert text here
String s = "auther ={some text here},";
s = s.substring(s.indexOf("{") + 1); //some text here},
s = s.substring(0, s.indexOf("}"));//some text here
System.out.println(s);
How about taking a substring by excluding the character at arraySplitBracket.length()-1
Something like
arraySplitBracket[1] = arraySplitBracket[1].substring(0,arraySplitBracket.length()-1);
Or use String Class's replaceAll function to replace } ?
Related
I have a String xxxxxxxxsrc="/slm/attachment/63338424306/Note.jpg"xxxxxxxx Now, I want to extract substrings slm/attachment/63338424306/Note.jpg & Note.jpg from the String in to variables i.e. temp1 & temp2.
How can I do that using regex in Java?
Note: 63338424306 could be any random no. & Note.jpg could be anything
like Note.png or abc.jpg or xxxx.yyy etc.
Please help me to extract these two strings using regex.
You can use negative look behind to get file name
((?:.(?<!/))+)\"
and below regex to get full path
/(.*)\"
Sample code
public static void main(String[] args) {
Pattern pattern = Pattern.compile("/(.*)\"");
Pattern pattern1 = Pattern.compile("((?:.(?<!/))+)\"");
String matchString = "/slm/attachment/63338424306/Note.jpg\"xxxxxxxx";
Matcher matcher = pattern.matcher(matchString);
String fullString = "";
while (matcher.find()) {
fullString = matcher.group(1);
}
matcher = pattern1.matcher(matchString);
String fileName = "";
while (matcher.find()) {
fileName = matcher.group(1);
}
System.out.println(fullString + " " + fileName);
}
As per your comment taking the string as declared below in my code:
Please clarify if your input string is not like this or I'm missing something.
public static void main(String[] args) {
String str = "xxxxxxxxsrc=\"/slm/attachment/63338424306/Note.jpg\"xxxxxxxx";
String url = null;
// The below pattern will grab string between quotes
Pattern p = Pattern.compile("\"([^\"]*)\"");
Matcher m = p.matcher(str);
while (m.find()) {
System.out.println(m.group(1));
url = m.group(1);
}
// and this will grab filename from the path(url)
p = Pattern.compile("(?:.(?<!/))+$");
m = p.matcher(url);
while (m.find()) {
System.out.println(m.group());
}
}
I have the follow urls.
https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY/edit#gid=1842172258
https://docs.google.com/a/example.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6PTKTzY0xOM5c6TXY/edit#gid=1842172258
https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY
Foreach url, I need to extract the sheet id: 1mrsetjgfZI2BIypz7SGHMOfHGv6PTKTzY0xOM5c6TXY into a java String.
I am thinking of using split but it can't work with all test cases:
String string = "https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY/edit#gid=1842172258";
String[] parts = string.split("/");
String res = parts[parts.length-2];
Log.d("hello res",res );
How can I that be possible?
You can use regex \/d\/(.*?)(\/|$) (regex demo) to solve your problem, if you look closer you can see that the ID exist between d/ and / or end of line for that you can get every thing between this, check this code demo :
String[] urls = new String[]{
"https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY/edit#gid=1842172258",
"https://docs.google.com/a/example.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6PTKTzY0xOM5c6TXY/edit#gid=1842172258",
"https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY"
};
String regex = "\\/d\\/(.*?)(\\/|$)";
Pattern pattern = Pattern.compile(regex);
for (String url : urls) {
Matcher matcher = pattern.matcher(url);
while (matcher.find()) {
System.out.println(matcher.group(1));
}
}
Outputs
1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY
1mrsetjgfZI2BIypz7SGHMOfHGv6PTKTzY0xOM5c6TXY
1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY
it looks like the id you are looking for always follow "/spreadsheets/d/" if it is the case you can update your code to that
String string = "https://docs.google.com/spreadsheets/d/1mrsetjgfZI2BIypz7SGHMOfHGv6kTKTzY0xOM5c6TXY/edit#gid=1842172258";
String[] parts = string.split("spreadsheets/d/");
String result;
if(parts[1].contains("/")){
String[] parts2 = parts[1].split("/");
result = parts2[0];
}
else{
result=parts[1];
}
System.out.println("hello "+ result);
Using regex
Pattern pattern = Pattern.compile("(?<=\\/d\\/)[^\\/]*");
Matcher matcher = pattern.matcher(url);
System.out.println(matcher.group(1));
Using Java
String result = url.substring(url.indexOf("/d/") + 3);
int slash = result.indexOf("/");
result = slash == -1 ? result
: result.substring(0, slash);
System.out.println(result);
Google use fixed lenght characters for its IDs, in your case they are 44 characters and these are the characters google use: alphanumeric, -, and _ so you can use this regex:
regex = "([\w-]){44}"
match = re.search(regex,url)
I want to split some XML text into parts:
xmlcontent = "<tagA>text1<tagB>text2</tagB></tagA>";
In C# i use
string[] splitedTexts = Regex.Split(xmlcontent, "(<.*?>)|(.+?(?=<|$))");
The result is
splitedTexts = ["<tagA>", "text1", "<tagB>", "text2", "</tagB>", "</tagA>"]
How can do it in Java?
I have tried
String[] splitedTexts = xmlcontent.split("(<.*?>)");
but the result is not like my expecting.
The parameter to split defines the delimiter to split at. You want to split before < and after > hence you can do:
String[] splitedTexts = xmlcontent.split("(?=<)|(?<=>)");
If you want to use Regex:
public static void main(String[] args) {
String xmlContent = "<xml><tagA>text1</tagA><tagB>text2</tagB></xml>";
Pattern pattern = Pattern.compile("(<.*?>)|(.+?(?=<|$))");
Matcher matcher = pattern.matcher(xmlContent);
while (matcher.find()) {
System.out.println(matcher.group());
}
}
I need to change somethign like this -> Hello, go here http://www.google.com for your ...
grab the link, and change it in a method i made, and replace it back into the string like this
-> Hello, go here http://www.yahoo.com for your...
Here is what i have so far:
if(Text.toLowerCase().contains("http://"))
{
// Do stuff
}
else if(Text.toLowerCase().contains("https://"))
{
// Do stuff
}
All i need to do is change the URL in the String to something different. The Url in the String will not always be http://www.google.com, so i can not just say replace("http://www.google.com","")
Use regex:
String oldUrl = text.replaceAll(".*(https?://)www((\\.\\w+)+).*", "www$2");
text = text.replaceAll("(https?://)www(\\.\\w+)+", "$1" + traslateUrl(oldUrl));
Note: code changed to meet extra requirements in comments below.
you can grab the link from the string using below code. I assumed the string will contain only .com domain
String input = "Hello, go here http://www.google.com";
Pattern pattern = Pattern.compile("http[s]{0,1}://www.[a-z-]*.com");
Matcher m = pattern.matcher(input);
while (m.find()) {
String str = m.group();
}
Have you tried something like:
s= s.replaceFirst("http:.+[ ]", new link);
This will find any word beginning with http up till the first white space and replace it with whatever you want
if you want to keep the link then you can do:
String oldURL;
if (s.contains("http")) {
String[] words = s.split(" ");
for (String word: words) {
if (word.contains("http")) {
oldURL = word;
break;
}
}
//then replace the url or whatever
}
You can try this
private String removeUrl(String commentstr)
{
String urlPattern = "((https?|ftp|gopher|telnet|file|Unsure|http):((//)|(\\\\))+[\\w\\d:##%/;$()~_?\\+-=\\\\\\.&]*)";
Pattern p = Pattern.compile(urlPattern,Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(commentstr);
int i = 0;
while (m.find()) {
commentstr = commentstr.replaceAll(m.group(i),"").trim();
i++;
}
return commentstr;
}
guys, I wanna extract the content in a string, the content is before "&" and after the "=", like this example:
asdfaf=afl10109&adsfjkl
I want to extract "afl10109" out of the string, can anyone teach me how to do this, I am very new to regex expression...
Use replaceAll() to replace the whole input with just what you want:
String target = str.replaceAll(".*=(.*)&.*", "$1");
The target is captured in a group (group number 1), which is then referenced in the replacement string.
try
public static void main(String args[]) {
String input="asdfaf=afl10109&adsfjkl";
Pattern pattern = Pattern.compile("=[^&]*&");
Matcher m = pattern.matcher(input);
while (m.find()) {
String str = m.group();
System.out.println( str.substring(1,str.length()-1));
}
}
This is not regex but you can also use split()
String str = "asdfaf=afl10109&adsfjkl";
System.out.println(str.split("=")[1].split("&")[0]);
Output:
afl10109
Using good old String#substring()
String str = "foo=bar&baz";
int begin = str.indexOf('=');
if (begin != -1) {
int end = str.indexOf('&', begin);
if (end != -1) {
System.out.println(str.substring(begin+1, end)); // bar
}
}