I'm trying to build a simple application, which connects with database and saves some data in it, let's say once per hour. I found some tutorials on pages like baeldung, but their solutions doesn't work for me.
Here is my configuration file:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.1.xsd">
<context:component-scan base-package="io.github.steve"/>
<!-- Step 4: Add support for conversion, formatting and validation support -->
<mvc:annotation-driven/>
<!-- Step 5: Define Spring MVC view resolver -->
<bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basenames" value="messages"/>
</bean>
<bean id="myDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
destroy-method="close">
<property name="driverClass" value="com.mysql.jdbc.Driver"/>
<property name="jdbcUrl" value="jdbc:mysql://localhost:3306/articles?useSSL=false"/>
<property name="user" value="root"/>
<property name="password" value=""/>
<property name="minPoolSize" value="5"/>
<property name="maxPoolSize" value="20"/>
<property name="maxIdleTime" value="30000"/>
</bean>
<bean id="sessionFactoryXXX" class="org.springframework.orm.hibernate5.LocalSessionFactoryBean">
<property name="dataSource" ref="myDataSource"/>
<property name="packagesToScan" value="io.github.steve.webscraping.domain"/>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="myTransactionManager" class="org.springframework.orm.hibernate5.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactoryXXX"/>
</bean>
<tx:annotation-driven transaction-manager="myTransactionManager"/>
</beans>
ArticlesDaoImpl:
#Repository
public class ArticlesDaoImpl implements ArticlesDao {
#Autowired
SessionFactory sessionFactory;
#Override
public List<Article> getAllArticles() {
Session session = sessionFactory.getCurrentSession();
Query<Article> query = session.createQuery("from Article order by uploadDate", Article.class);
return query.getResultList();
}
#Override
public void addArticle(Article article) {
Session session = sessionFactory.getCurrentSession();
session.persist(article);
}
}
ArticlesServiceImpl:
#Service
public class ArticlesServiceImpl implements ArticlesService {
#Autowired
private ArticlesDao articlesDao;
#Override
#Transactional
public List<Article> getAllArticles() {
return articlesDao.getAllArticles();
}
#Override
#Transactional
public void addArticle(Article article) {
articlesDao.addArticle(article);
}
#Override
#Transactional
public void addArticles(List<Article> articles) {
articles.stream().forEach(articlesDao::addArticle);
}
}
And now:
First of all, I don't know where should I put my xml config file.
I have no idea how to build my Main.class. I want to Autowire ArticlesService to Main class and run a method from it. When i use just SpringApplication.run(Main.class, args), it loads and finishing with exit code 1.
Main app:
#SpringBootApplication
#EnableScheduling
public class App {
public static void main(String[] args) {
SpringApplication.run(App.class, args);
}
}
ScheduledTasks:
#Component
public class ScheduledTasks {
#Autowired
ArticlesService articlesService;
private static final Logger log = LoggerFactory.getLogger(ScheduledTasks.class);
#Scheduled(cron = "* * * * *")
public void reportCurrentTime() {
articlesService.addArticles(new MkyongWebScraper().getArticlesList());
}
}
I'm really new in Spring and I know this question is pretty wide, but I can't find any suitable sources for my tasks. What am I doing wrong?
I am afraid the code you are writing, especially the XML config does not take advantage of the easier and more convenient offered with Spring Boot, and Spring Boot 2.
To generate the skeleton of your project, go to Spring Boot Initializer. You can choose the dependencies you want (in your case, it should "JPA" which is based on Spring Data JPA) and then you can download a zip with your project.
You might want to have a look at Spring Boot documentation. There are also some pretty interesting videos to "get started with Spring Boot" on youtube..
Once you have your project, you can add Spring Data JPA code...
Spring Boot documentation has a section about Spring Data JPA, but you can also find more info in the documentation of Spring Data JPA project.
Best of luck
I already solved my problem. I just didn't understood Spring enough. For people like me I recommend Spring in Action by Craig Walls.
Related
I am new in Spring. I have tried a demo project with Spring MVC, Hibernate, Spring-tx and Spring ORM. There I am facing the error. My scenario is:
public interface DaoInterface{
public SessionFactory getSessionFactory();
public Session getSession();
}
Another class BaseDao:
public abstract class BaseDao implements DaoInterface{
#Autowired
private SessionFactory sessionFactory;
private Session session;
public SessionFactory getSessionFactory() {
return this.sessionFactory;
}
public Session getSession() {
this.session = sessionFactory.getCurrentSession();
return this.session;
}
public abstract User retriveUser(String email);
}
Another class UserDao:
#Component
public class UserDao extends BaseDao{
#Override
#Transactional
public User retriveUser(String email) {
System.out.println("In userDao : retriveUser");
//other code
}
}
Now from my service class, when I am going to get UserDao object using BaseDao, I got the error:
org.springframework.beans.factory.BeanNotOfRequiredTypeException: Bean named 'userDao' is expected to be of type 'dao.BaseDao' but was actually of type 'com.sun.proxy.$Proxy94'
My service class code:
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
BaseDao userDao = context.getBean("userDao", BaseDao.class);
If I do the following, no error comes.
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
DaoInterface userDao = context.getBean("userDao", DaoInterface.class);
My applicationContext.xml is as below:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd">
<context:component-scan base-package="model" />
<context:component-scan base-package="dao" />
<mvc:annotation-driven>
<mvc:message-converters>
<bean class="org.springframework.http.converter.StringHttpMessageConverter"/>
</mvc:message-converters>
</mvc:annotation-driven>
<bean id="abcDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource" destroy-method="close">
<property name="driverClass" value="com.mysql.jdbc.Driver"></property>
<property name="jdbcUrl" value="jdbc:mysql://localhost:3306/demo"></property>
<property name="user" value="xxxx"></property>
<property name="password" value="xxxxx"></property>
<property name="minPoolSize" value="5" />
<property name="maxPoolSize" value="10" />
<property name="maxIdleTime" value="30000" />
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate5.LocalSessionFactoryBean">
<property name="dataSource" ref="abcDataSource" />
<property name="packagesToScan" value="model" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="abcTransactionManager" class="org.springframework.orm.hibernate5.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<tx:annotation-driven transaction-manager="abcTransactionManager" />
</beans>
So, my question is, what need to be done in my application, so that I can get UserDao object using BaseDao class reference, not DaoInterface reference?
Some answers are there in this platform, but I am not getting the exact answer. Few solutions I have tried but can't solve.
Spring uses JDK dynamic proxies by default ($Proxy94), that can only proxy interfaces. That's basically why you can cast the userDao bean to the Dao interface, but not to the BaseDao class.
By the way you should prefer coding by interfaces.
However You can use <tx:annotation-driven proxy-target-class="true"/> to instruct Spring to use CGLIB proxies.
In my application we have the following architecture:
Web Layer: JSF+Rich Faces
Service Layer: EJB
DAO Layer: EJB Classes [consist of JDBC Queries]
We want to use Hibernate as ORM framework instead of JDBC in DAO layer. I want to use Spring ORM feature for integrating Hibernate in DAO layer. Now, challenges that we are facing:
DAO layer classes are stateless EJB classes. So,to use Spring DI inside EJB classes, I have to go for an interceptor as follows:
#Stateless(mappedName = "myAppDao")
#Interceptors(SpringBeanAutowiringInterceptor.class)
public class MyAppDaoImpl implements MyAppDaoRemote {
#Autowired
private SessionFactory sessionFactory;
#Override
public void getSession() {
if(sessionFactory!=null){
Session session = null;
try{
session = sessionFactory.getCurrentSession();
}catch (Exception e) {
session = sessionFactory.openSession();
System.out.println("Exception:"+e.getMessage());
}
}
With sessionFactory.getCurrentSession() I am getting this exception:
Exception:Could not obtain transaction-synchronized Session for current thread.
The reason behind this I am not able to use Spring transaction at Service layer since I have EJB classes in my service layer.
Moreover I don't want to use sessionFactory.openSession() as in that case I would have to manually close the session.
These are my Spring configuration files:
1) beanRefContext.xml -> Used by Interceptors
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.2.xsd">
<bean id="businessBeanFctory" class="org.springframework.context.support.ClassPathXmlApplicationContext">
<constructor-arg value="classpath*:daoConfig.xml" />
</bean>
</beans>
2) daoConfig.xml -> Hibernate Configuration
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-4.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.2.xsd">
<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.myapp.model"/>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">false</prop>
</props>
</property>
</bean>
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/MyAppDS" expected-type="javax.sql.DataSource"/>
<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager"/>
<tx:annotation-driven transaction-manager="transactionManager" />
</beans>
I know that there is no point in using EJB along with Spring since they are alternate to each other.But due to some restriction at project level I can't remove EJB for the time being.
So, is there any solution by which we can get the Hibernate current session inside an EJB class through Spring?
If you're using JBossAS/WildFly then you just need:
#Stateless(mappedName = "myAppDao")
public class MyAppDaoImpl implements MyAppDaoRemote {
#PersistenceContext
private Session session;
public void someDaoMethod(YourEntity e) {
// use session directly
// Transactions are automatically managed by the EJB container
// because that's one of EJB's raison d'être
}
}
Ensure that your (traditional) Hibernate configuration specifies JTA transactions.
See the WildFly JPA Reference Guide for more information.
If you're not using one of these JavaEE implementations then you can still use the Spring configuration that you have, but remember to include:
<property name="jtaTransactionManager" value="transactionManager"/>
in your sessionFactory bean.
Additionally, if you're using WebLogic or WebSphere you may need to specify platform dependent JTA transaction managers for these servers, such as WebLogicJtaTransactionManager or org.springframework.transaction.jta.WebSphereUowTransactionManager.
I have modified my daoConfig.xml in following way
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-4.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.2.xsd">
<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="packagesToScan" value="com.oms.model"/>
<property name="jtaTransactionManager" ref="transactionManager"/>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/OMSDS" expected-type="javax.sql.DataSource"/>
<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager"/>
</beans>
I have added <property name="jtaTransactionManager" ref="transactionManager"/>
under sessionFactory bean definition.After this I am able to use
session = sessionFactory.getCurrentSession();in my dao layer class.
I'm getting the above exception with Spring3 and Hibernte4
The following is my bean xml file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd">
<context:annotation-config/>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost:3306/GHS"/>
<property name="username" value="root"/>
<property name="password" value="newpwd"/>
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="hibernateProperties">
<props>
<prop key="dialect">org.hibernate.dialect.MySQL5Dialect</prop>
</props>
</property>
<property name="packagesToScan">
<list>
<value>com.example.ghs.model.timetable</value>
</list>
</property>
</bean>
<bean id="baseDAO"
class="com.example.ghs.dao.BaseDAOImpl"/>
</beans>
My BaseDAO class looks like this
public class BaseDAOImpl implements BaseDAO{
private SessionFactory sessionFactory;
#Autowired
public BaseDAOImpl(SessionFactory sessionFactory){
this.sessionFactory = sessionFactory;
}
#Override
public Session getCurrentSession(){
return sessionFactory.getCurrentSession();
}
}
The following code throws the exception in the title
public class Main {
public static void main(String[] args){
ClassPathXmlApplicationContext context =
new ClassPathXmlApplicationContext("dao-beans.xml");
BaseDAO bd = (BaseDAO) context.getBean("baseDAO");
bd.getCurrentSession();
}
}
Does anyone have an idea about how to solve this problem?
getCurrentSession() only makes sense inside a scope of transaction.
You need to declare an appropriate transaction manager, demarcate boundaries of transaction and perform data access inside it. For example, as follows:
<bean id = "transactionManager" class = "org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name = "sessionFactory" ref = "sessionFactory" />
</bean>
.
PlatformTransactionManager ptm = context.getBean(PlatformTransactionManager.class);
TransactionTemplate tx = new TransactionTemplate(ptm);
tx.execute(new TransactionCallbackWithoutResult() {
public void doInTransactionWithoutResult(TransactionStatus status) {
// Perform data access here
}
});
See also:
10. Transaction Management
13.3 Hibernate
I came across same problem and got solved as below
Added #Transactional on daoImpl class
Added trnsaction manager in configuration file:
<tx:annotation-driven/>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"></property>
</bean>
I'll just add something that took me some time to debug : don't forget that a #Transactional annotation will only work on "public" methods.
I put some #Transactional on "protected" ones and got this error.
Hope it helps :)
http://docs.spring.io/spring/docs/3.1.0.M2/spring-framework-reference/html/transaction.html
Method visibility and #Transactional
When using proxies, you should apply the #Transactional annotation
only to methods with public visibility. If you do annotate protected,
private or package-visible methods with the #Transactional annotation,
no error is raised, but the annotated method does not exhibit the
configured transactional settings. Consider the use of AspectJ (see
below) if you need to annotate non-public methods.
Which package u have put the BaseDAOImpl class in.. I think It requires a package name similar to the one u have used in the application context xml and it requires a relevant annotation too.
I have a small test app for exposing a "Bean" to JMX using Spring. It uses an XML based config and everything works fine:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd">
<context:component-scan base-package="com.dmclaughlin.spring" />
<context:property-placeholder location="classpath:test.properties"/>
<bean id="SimpleJmxController" class="com.dmclaughlin.spring.jmx.SimpleJmxBean">
<property name="activated" value="${some.activated}"/>
</bean>
<!-- Spring JMX -->
<bean id="exporter" class="org.springframework.jmx.export.MBeanExporter" lazy-init="false">
<property name="autodetect" value="true"></property>
<property name="namingStrategy" ref="namingStrategy"></property>
<property name="assembler" ref="assembler"></property>
</bean>
<bean id="attributeSource"
class="org.springframework.jmx.export.annotation.AnnotationJmxAttributeSource"/>
<bean id="assembler"
class="org.springframework.jmx.export.assembler.MetadataMBeanInfoAssembler">
<property name="attributeSource" ref="attributeSource"/>
</bean>
<bean id="namingStrategy"
class="org.springframework.jmx.export.naming.MetadataNamingStrategy">
<property name="attributeSource" ref="attributeSource"/>
</bean>
But the application I need to add this functionality to, uses #Configuration style, and I'm trying to convert the above XML to work. I added something like this:
#Bean
public MetadataNamingStrategy getNamingStrategy() {
MetadataNamingStrategy strategy = new MetadataNamingStrategy();
strategy.setAttributeSource(new AnnotationJmxAttributeSource());
return strategy;
}
#Bean
public MetadataMBeanInfoAssembler getMbeanInfoAssembler() {
return new MetadataMBeanInfoAssembler(new AnnotationJmxAttributeSource());
}
#Bean
public MBeanExporter getExporter() {
MBeanExporter exporter = new MBeanExporter();
exporter.setAutodetect(true);
exporter.setNamingStrategy(getNamingStrategy());
exporter.setAssembler(getMbeanInfoAssembler());
return exporter;
}
And everything compiles, but when I load up JConsole my Bean annotated with #ManagedResource and #ManagedAttribute isn't exposed. Am I missing something simple here?
Edit: the answer below didn't fix my problem (the problem was I was testing my XML in a Tomcat environment, but testing my non-XML config in a standalone application, which meant there was no JMXServer present.. d'oh), but it did help me simplify once I debugged what I messed up.
For me it was enough to add:
#Bean
public AnnotationMBeanExporter annotationMBeanExporter() {
return new AnnotationMBeanExporter();
}
you should configure your mbeanexporter with "eager"
#Bean
#Lazy(false)
public MBeanExporter getExporter() {
...
}
greetings
AccLess
In my service class I need the hibernate session available. I currently do this in the beans.xml:
<bean id = "userDao" class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="target">
<ref bean="userDaoTarget" />
</property>
<property name="proxyInterfaces">
<value>com.app.dao.UserDao</value>
</property>
<property name="interceptorNames">
<list>
<value>hibernateInterceptor</value>
</list>
</property>
<qualifier value="proxy" />
</bean>
...
<bean id="hibernateInterceptor"
class="org.springframework.orm.hibernate3.HibernateInterceptor">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
<bean>
(copied by hand, may be some typos..)
I'm moving to using annotations over XML, I was wondering if there was a way to use them to configure the proxy as I have above including the hibernate interceptor? If not - is there a way that I can reduce the amount of XML (with about 7 DAOs it makes it very cluttered)
Ok, Let's go. You said
I am moving to using annotations over XML
Enable an aspect as follows
package br.com.ar.aop;
#Aspect
public class HibernateInterceptorAdvice {
#Autowired
private HibernateInterceptor hibernateInterceptor;
/**
* I suppose your DAO's live in com.app.dao package
*/
#Around("execution(* com.app.dao.*(..))")
public Object interceptCall(ProceedingJoinPoint joinPoint) throws Throwable {
ProxyFactory proxyFactory = new ProxyFactory(joinPoint.getTarget());
proxyFactory.addAdvice(hibernateInterceptor);
Class [] classArray = new Class[joinPoint.getArgs().length];
for (int i = 0; i < classArray.length; i++)
classArray[i] = joinPoint.getArgs()[i].getClass();
return
proxyFactory
.getProxy()
.getClass()
.getDeclaredMethod(joinPoint.getSignature().getName(), classArray)
.invoke(proxyFactory.getProxy(), joinPoint.getArgs());
}
}
But keep in mind It just works if your DAO's implements some interface (For instance, UserDAOImpl implements UserDAO). Spring AOP uses JDK dynamic proxy in this case. If you does not have any interface, you can rely on your IDE To refactor your code by using Extract interface
Declare your xml as follows (Be aware i am using Spring 2.5 xsd schema)
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-2.5.xsd">
<!--SessionFactory settings goes here-->
<bean class="org.springframework.orm.hibernate3.HibernateInterceptor">
<property name="sessionFactory" ref="sessionFactory"/>
<bean>
<!--To enable AspectJ AOP-->
<aop:aspectj-autoproxy/>
<!--Your advice-->
<bean class="br.com.ar.aop.HibernateInterceptorAdvice"/>
<!--Looks for any annotated Spring bean in com.app.dao package-->
<context:component-scan base-package="com.app.dao"/>
<!--Enables #Autowired annotation-->
<context:annotation-config/>
</beans>
Do not forget To put in the classpath besides Spring libraries
<SPRING_HOME>/lib/asm
<SPRING_HOME>/lib/aopalliance
<SPRING_HOME>/lib/aspectj
Have a look at the #Autowired annotation.