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How can I use generics to provide a "universal getter method"?

This question is more theoretical (what I want to do is more complicated but this is the part I'm stuck on), so apologies for the contrived example which may not make much sense.
Say I have some class that has methods that return its value in different forms:
public class MyObject {
public String getAsString() {...}
public int getAsInt() {...}
// and so on
}
I'm trying to create a single method to allow me to specify which MyObject method to call via its parameters. Something like:
public <T> T getValue(MyObject obj, Class<T> c) {
if (c == String.class) {
return obj.getAsString();
} else if (c == Integer.class) {
return obj.getAsInt();
} // and so on
}
So then I would like to call this method like this, assuming obj is a MyObject:
String s = getValue(obj, String.class);
int i = getValue(obj, Integer.class);
// and so on
I'm getting the compile error "Type mismatch: cannot convert from String to T" (and likewise for Integer) in the getValue method. Clearly I'm just not understanding generics fully, but I thought this was the general idea behind generics - here I'm specifying (or trying to specify, at least) the real type of T via the parameter c. What am I doing wrong?

If you want to to create a single method with really safe casts - then I would suggest to setup a mapping between the expected type and its respective getter.
Given the MyObject class definition as:
public class MyObject {
public int getIntValue() {
return 42;
}
public String getStringValue() {
return "Answer";
}
}
So that the "accessor" class could look as follows (it can be generalized further if needed):
public class MyObjectAccessor {
private final Map<Class<?>, Function<MyObject, ?>> registry = new HashMap<>();
public Accessor() {
registerGetter(Integer.class, MyObject::getIntValue);
registerGetter(String.class, MyObject::getStringValue);
}
private <T> void registerGetter(Class<T> type, Function<MyObject, T> getter) {
registry.put(type, getter);
}
#SuppressWarnings("unchecked")
public <T> Optional<T> getValue(MyObject obj, Class<T> type) {
return (Optional<T>) ofNullable(registry.get(type)).map(getter -> getter.apply(obj));
}
}
This would allow you to make the behavior much more predictable with a control over the unexpected/missing mapping.
(Here it returns an Optional back, but you can also throw an exception or provide a default value or do something else)
Please note that the cast inside getValue is actually a safe checked cast (even though it was marked with #SuppressWarnings) as the "safety" proof here is a little bit beyond current javac's capability of static code analysys.

First of all, if getAsString and getAsInt are not doing any conversion (such as would be the case if all your values were stored as strings), you probably can reduce your method to this:
public <T> T getValue(MyObject obj) {
return (T) obj.value;
}
This will have an unchecked cast warning, but that's not worse than leaving the typing decision to your caller (so I'd just #SuppressWarnings("unchecked") it). If your caller uses the wrong target type, they will get a ClassCastException at runtime, which I assume goes well with your current contract. But you can keep c.cast(obj.getAsX()) if you want the exception to be raised in your own method.
With the above, your callers would just use:
String s = getValue(obj);
int i = getValue(obj);
If, however, you are actually converting data in getAs... methods, then you will need to cast in your generic getter after dispatching to the correct getAsX method, at least as ProGu suggested (i.e., return c.cast(obj.getAsX()) in each branch).

Is there an easier way to retrieve hard-coded type parameters in subclass implementations?

Given the following interface:
public interface GenericInterface<T> {
T getValue();
void setValue(T newVal);
}
And the following impl:
public class FixedImpl implements GenericInterface<String> {
String value;
public FixedImpl(String value) {
this.value = value;
}
#Override
public String getValue() {
return value;
}
#Override
public void setValue(String newVal) {
value = newVal;
}
}
I want to be able to determine that in the case of FixedImpl, String.class is the value for GenericInterface.T by interrogating FixedImpl.class.
My current idea:
Find a method name in GenericInterface that returns a <T> - in this case, there's "getValue".
Go through all the methods declared in FixedImpl.class with the same name, and collect all the different return types.
The return type farthest from Object is my value for GenericInterface.T.
But there's a couple of issues with this process:
It will only work for generic types containing a method that returns <T>. You can't safely do the same trick using setValue(T), because method overloading by parameter / arity is possible to do in Java source. It only works for T getValue() because overloading by return value isn't (unless I'm mistaken).
It might have weird interactions with Java 8 default methods, or a generic method implementation in a (still generic) possibly abstract superclass.
It's kinda kludgey.
Can anybody point me to an easier / more surefire way to get the same information? I can't seem to find one, but I thought I'd ask the superior intellects of the toobs :)
NB: If you're wondering why I'd need this, it's because I want to programatically construct mocks of container classes with similar hard-coded type parameters, but POJO values rather than simple Strings.
EDIT: I eventually worked out the following solution (before seeing #stony-zhang's):
public static <G> List<Class> getConcreteTypes(Class<? extends G> implClass, Class<G> genericClass) {
List<Class> concreteTypes = new ArrayList<Class>();
for (Type type : implClass.getGenericInterfaces()) {
if (!(type instanceof ParameterizedTypeImpl)) continue;
ParameterizedTypeImpl parameterizedType = (ParameterizedTypeImpl) type;
if (parameterizedType.getRawType() != genericClass) continue;
for (Object arg : parameterizedType.getActualTypeArguments()) {
if (!(arg instanceof Class))
throw new IllegalArgumentException("Class " + implClass + " not concrete for generic type " + genericClass);
concreteTypes.add((Class) arg);
}
}
return concreteTypes;
}

You can get the the class of T by the following way, in the interface add a method getMessageClass(), and in the FixedImpl add the implemented method,
#SuppressWarnings("rawtypes")
public Class getMessageClass() {
int index =0; //In the case, you only have a generic type, so index is 0 to get the first one.
Type genType = getClass().getGenericSuperclass();
if (!(genType instanceof ParameterizedType)) {
return Object.class;
}
Type[] params = ((ParameterizedType) genType).getActualTypeArguments();
if (index >= params.length || index < 0) {
throw new RuntimeException("Index outof bounds");
}
if (!(params[index] instanceof Class)) {
return Object.class;
}
return (Class) params[index];
}
In you case, if you have multiple subclass, to use it, create one abstract class to implement the interface GenericInterface, and then the all subclass extends from the new abstract class,
public class abstract abstractImpl<T> implements implements GenericInterface<T> {
#SuppressWarnings("rawtypes")
#Override
public Class getMessageClass() {
...............
}
}

Remember type erasure. At runtime, there is no type information about your generics anymore, unless you specify it yourself. And this is what you should do. Add this to your interface:
Class<T> getTypeOfT();
And add this to your FixedImpl:
#Override
public Class<String> getTypeOfT()
{
return String.class;
}
That way, you can always call getTypeOfT() on your GenericInterface<T> implementations and find out what type you are dealing with.

I don't think that you will be able to get reliable result because of Type Erasure:
Replace all type parameters in generic types with their bounds or Object if the type parameters are unbounded. The produced bytecode, therefore, contains only ordinary classes, interfaces, and methods.
Insert type casts if necessary to preserve type safety.
Generate bridge methods to preserve polymorphism in extended generic types.
Your approach of of using the types of objects returned may at first seem alright, but beyond the issues you have pointed out there is no way (at runtime) to know if The return type farthest from Object is my value for GenericInterface.T.
My suggestion would be to use some kind of configuration XML which could be generated at build time based on the java source (using a build tool such as Ant), which would in turn be used to create Mock objects, or you could simply generate the tests based off the source at buildtime.
If you don't mind changing your runtime code for the purposes of testing, Jan Doereenhaus' answer suggests a simple hard-coded mechanism for retrieving the type
EDIT:
Consider the scenario:
public class FixedImpl implements GenericInterface<SomeClass> {
#Override
public SomeClass getValue() {
return new SomeClass();
}
}
public class FixedImpl2 extends FixedImpl {
#Override
public SomeClass getValue()
{
return new SomeSubClass();
}
}
From this example, you can see that the sub class of FixedImpl is able to return a subclass of T (which is further down the inheritance hierarchy from Object)

Instantiating generics type in java

I would like to create an object of Generics Type in java. Please suggest how can I achieve the same.
Note: This may seem a trivial Generics Problem. But I bet.. it isn't. :)
suppose I have the class declaration as:
public class Abc<T> {
public T getInstanceOfT() {
// I want to create an instance of T and return the same.
}
}

public class Abc<T> {
public T getInstanceOfT(Class<T> aClass) {
return aClass.newInstance();
}
}
You'll have to add exception handling.
You have to pass the actual type at runtime, since it is not part of the byte code after compilation, so there is no way to know it without explicitly providing it.

In the code you posted, it's impossible to create an instance of T since you don't know what type that is:
public class Abc<T>
{
public T getInstanceOfT()
{
// There is no way to create an instance of T here
// since we don't know its type
}
}
Of course it is possible if you have a reference to Class<T> and T has a default constructor, just call newInstance() on the Class object.
If you subclass Abc<T> you can even work around the type erasure problem and won't have to pass any Class<T> references around:
import java.lang.reflect.ParameterizedType;
public class Abc<T>
{
T getInstanceOfT()
{
ParameterizedType superClass = (ParameterizedType) getClass().getGenericSuperclass();
Class<T> type = (Class<T>) superClass.getActualTypeArguments()[0];
try
{
return type.newInstance();
}
catch (Exception e)
{
// Oops, no default constructor
throw new RuntimeException(e);
}
}
public static void main(String[] args)
{
String instance = new SubClass().getInstanceOfT();
System.out.println(instance.getClass());
}
}
class SubClass
extends Abc<String>
{
}

What you wrote doesn't make any sense, generics in Java are meant to add the functionality of parametric polymorphism to objects.
What does it mean? It means that you want to keep some type variables of your classes undecided, to be able to use your classes with many different types.
But your type variable T is an attribute that is resolved at run-time, the Java compiler will compile your class proving type safety without trying to know what kind of object is T so it's impossible for it to let your use a type variable in a static method. The type is associated to a run-time instance of the object while public void static main(..) is associated to the class definition and at that scope T doesn't mean anything.
If you want to use a type variable inside a static method you have to declare the method as generic (this because, as explained type variables of a template class are related to its run-time instance), not the class:
class SandBox
{
public static <T> void myMethod()
{
T foobar;
}
}
this works, but of course not with main method since there's no way to call it in a generic way.
EDIT: The problem is that because of type erasure just one generic class is compiled and passed to JVM. Type checker just checks if code is safe, then since it proved it every kind of generic information is discarded.
To instantiate T you need to know the type of T, but it can be many types at the same time, so one solution with requires just the minimum amount of reflection is to use Class<T> to instantiate new objects:
public class SandBox<T>
{
Class<T> reference;
SandBox(Class<T> classRef)
{
reference = classRef;
}
public T getNewInstance()
{
try
{
return reference.newInstance();
}
catch (Exception e)
{
e.printStackTrace();
}
return null;
}
public static void main(String[] args)
{
SandBox<String> t = new SandBox<String>(String.class);
System.out.println(t.getNewInstance().getClass().getName());
}
}
Of course this implies that the type you want to instantiate:
is not a primitive type
it has a default constructor
To operate with different kind of constructors you have to dig deeper into reflection.

You need to get the type information statically. Try this:
public class Abc<T> {
private Class<T> clazz;
public Abc(Class<T> clazz) {
this.clazz = clazz;
}
public T getInstanceOfT()
throws throws InstantiationException,
IllegalAccessException,
IllegalArgumentException,
InvocationTargetException,
NoSuchMethodException,
SecurityException {
return clazz.getDeclaredConstructor().newInstance();
}
}
Use it as such:
Abc<String> abc = new Abc<String>(String.class);
abc.getInstanceOfT();
Depending on your needs, you may want to use Class<? extends T> instead.

The only way to get it to work is to use Reified Generics. And this is not supported in Java (yet? it was planned for Java 7, but has been postponed). In C# for example it is supported assuming that T has a default constructor. You can even get the runtime type by typeof(T) and get the constructors by Type.GetConstructor(). I don't do C# so the syntax may be invalid, but it roughly look like this:
public class Foo<T> where T:new() {
public void foo() {
T t = new T();
}
}
The best "workaround" for this in Java is to pass a Class<T> as method argument instead as several answers already pointed out.

First of all, you can't access the type parameter T in the static main method, only on non-static class members (in this case).
Second, you can't instantiate T because Java implements generics with Type Erasure. Almost all the generic information is erased at compile time.
Basically, you can't do this:
T member = new T();
Here's a nice tutorial on generics.

You don't seem to understand how Generics work.
You may want to look at http://java.sun.com/j2se/1.5.0/docs/guide/language/generics.html
Basically what you could do is something like
public class Abc<T>
{
T someGenericThing;
public Abc(){}
public T getSomeGenericThing()
{
return someGenericThing;
}
public static void main(String[] args)
{
// create an instance of "Abc of String"
Abc<String> stringAbc = new Abc<String>();
String test = stringAbc.getSomeGenericThing();
}
}

I was implementing the same using the following approach.
public class Abc<T>
{
T myvar;
public T getInstance(Class<T> clazz) throws InstantiationException, IllegalAccessException
{
return clazz.newInstance();
}
}
I was trying to find a better way to achieve the same.
Isn't it possible?

Type Erasure Workaround
Inspired by #martin's answer, I wrote a helper class that allows me to workaround the type erasure problem. Using this class (and a little ugly trick) I'm able to create a new instance out of a template type:
public abstract class C_TestClass<T > {
T createTemplateInstance() {
return C_GenericsHelper.createTemplateInstance( this, 0 );
}
public static void main( String[] args ) {
ArrayList<String > list =
new C_TestClass<ArrayList<String > >(){}.createTemplateInstance();
}
}
The ugly trick here is to make the class abstract so the user of the class is forced to subtype it. Here I'm subclassing it by appending {} after the call to the constructor. This defines a new anonymous class and creates an instance of it.
Once the generic class is subtyped with concrete template types, I'm able to retrieve the template types.
public class C_GenericsHelper {
/**
* #param object instance of a class that is a subclass of a generic class
* #param index index of the generic type that should be instantiated
* #return new instance of T (created by calling the default constructor)
* #throws RuntimeException if T has no accessible default constructor
*/
#SuppressWarnings( "unchecked" )
public static <T> T createTemplateInstance( Object object, int index ) {
ParameterizedType superClass =
(ParameterizedType )object.getClass().getGenericSuperclass();
Type type = superClass.getActualTypeArguments()[ index ];
Class<T > instanceType;
if( type instanceof ParameterizedType ) {
instanceType = (Class<T > )( (ParameterizedType )type ).getRawType();
}
else {
instanceType = (Class<T > )type;
}
try {
return instanceType.newInstance();
}
catch( Exception e ) {
throw new RuntimeException( e );
}
}
}

There are hacky ways around this when you really have to do it.
Here's an example of a transform method that I find very useful; and provides one way to determine the concrete class of a generic.
This method accepts a collection of objects as input, and returns an array where each element is the result of calling a field getter on each object in the input collection. For example, say you have a List<People> and you want a String[] containing everyone's last name.
The type of the field value returned by the getter is specified by the generic E, and I need to instantiate an array of type E[] to store the return value.
The method itself is a bit ugly, but the code you write that uses it can be so much cleaner.
Note that this technique only works when somewhere in the input arguments there is an object whose type matches the return type, and you can deterministically figure it out. If the concrete classes of your input parameters (or their sub-objects) can tell you nothing about the generics, then this technique won't work.
public <E> E[] array (Collection c) {
if (c == null) return null;
if (c.isEmpty()) return (E[]) EMPTY_OBJECT_ARRAY;
final List<E> collect = (List<E>) CollectionUtils.collect(c, this);
final Class<E> elementType = (Class<E>) ReflectionUtil.getterType(c.iterator().next(), field);
return collect.toArray((E[]) Array.newInstance(elementType, collect.size()));
}
Full code is here: https://github.com/cobbzilla/cobbzilla-utils/blob/master/src/main/java/org/cobbzilla/util/collection/FieldTransformer.java#L28

It looks like you are trying to create the class that serves as the entry point to your application as a generic, and that won't work... The JVM won't know what type it is supposed to be using when it's instantiated as you start the application.
However, if this were the more general case, then something like would be what you're looking for:
public MyGeneric<MyChoiceOfType> getMeAGenericObject(){
return new MyGeneric<MyChoiceOfType>();
}
or perhaps:
MyGeneric<String> objMyObject = new MyGeneric<String>();

Abc<String> abcInstance = new Abc<String> ();
..for example

Problem at JUnit test with generics

In my utility method:
public static <T> T getField(Object obj, Class c, String fieldName) {
try {
Field field = c.getDeclaredField(fieldName);
field.setAccessible(true);
return (T) field.get(obj);
} catch (Exception e) {
e.printStackTrace();
fail();
return null;
}
}
The line
return (T) field.get(obj);
gives the warning "Type safety: Unchecked cast from Object to T";
but I cannot perform instanceof check against type parameter T,
so what am I suppose to do here?

The annotation #SuppressWarnings will stop the compiler reporting this warning. I don't think there's any way you can get away from the compiler warning when using reflection like this. Something like the following:
Field field = c.getDeclaredField(fieldName);
field.setAccessible(true);
#SuppressWarnings(value="unchecked")
T t = (T) field.get(obj);
return t;

You can easily solve this problem by adding an additional parameter to your method which will specify the type of the filed, the method will then look as follows:
public static <T> T getField(Class<T> fieldType, Object obj, Class<?> c,
String fieldName)
{
try {
Field field = c.getDeclaredField(fieldName);
field.setAccessible(true);
Object value = field.get(obj);
return fieldType.cast(value);
} catch (Exception e) {
e.printStackTrace();
fail();
return null;
}
}
And here's how you can use it: getField(String.class, new G(), G.class, "s") where G is defined as:
public class G {
String s = "abc";
}
A 2nd improvement is to eliminate the c parameter of getFiled(). c can be obtained inside the method by invoking obj.getClass(). The only caveat is that this will give you the dynamic type of the object so you mat want to loop over all of C's superclasses until you find the field you're looking for, or until you arrive at Object (You will also need to use c.getFields() and look for the field in the resulting array).
I think that these changes will make your method easier to use and less prone to errors so it's worth the effort.

Generics are there to provide type safety in places where you didn't previously have any in Java. So it used to be that if you had a list full of Strings you had to do:
String myString = (String)myList.get(0);
but now you can retrieve it without casting it:
String myString = myList.get(0); //Compiler won't complain
When you generify using the variable T, you are saying T is a placeholder for a specific type, which will be defined on the instance of the class at instantiation time. For instance:
public class ArrayList<T> {
public ArrayList<T> {
....
}
}
allows you to instantiate the list with:
ArrayList<String> myList = new ArrayList<String>();
Now every function on ArrayList will return a String, and the compiler knows this so it doesn't require a cast. Each of those functions was defined much like yours above:
public T get(int index);
public void set(int index, T object);
at compile time they become:
public String get(int index);
public void set(int index, String object);
In your case, however, you seem to be trying to use T as a wildcard, which is different from a placeholder for a specific type. You might call this method three times for three different fields, each of which has a different return type, right? This means that, when you instantiate this class, you cannot pick a single type for T.
In general, look at your method signatures and ask yourself "will a single type be substituted for T for each instance of this class"?
public static <T> T getField(Object obj, Class c, String fieldName)
If the answer is "no", that means this is not a good fit for Generics. Since each call will return a different type, you have to cast the results from the call. If you cast it inside this function, you're losing any benefits Generics would provide, and might as well save yourself the headaches.
If I've misunderstood your design, and T does refer to a single type, then simply annotating the call with #SuppressWarnings(value="unchecked") will do the trick. But if I've understood correctly, fixing this error will just lead you to a long road of confusion unless you grok what I've written above.
Good luck!

As suggested above, you can specify the expected type of the field and call the cast method.
Also. you don't need to pass argument object's class. You can find out what it is by calling obj.getClass()
This simplifies your code to
public static <T> T getField(Object obj, Class<T> fieldClass, String fieldName) {
try {
Class<?> declaringClass = obj.getClass();
Field field = declaringClass.getDeclaredField(fieldName);
field.setAccessible(true);
return fieldClass.cast(field.get(obj));
}
catch (Exception e) {
throw new AssertionFailedError();
}
}

Type-safe method reflection in Java

Is any practical way to reference a method on a class in a type-safe manner? A basic example is if I wanted to create something like the following utility function:
public Result validateField(Object data, String fieldName,
ValidationOptions options) { ... }
In order to call it, I would have to do:
validateField(data, "phoneNumber", options);
Which forces me to either use a magic string, or declare a constant somewhere with that string.
I'm pretty sure there's no way to get around that with the stock Java language, but is there some kind of (production grade) pre-compiler or alternative compiler that may offer a work around? (similar to how AspectJ extends the Java language) It would be nice to do something like the following instead:
public Result validateField(Object data, Method method,
ValidationOptions options) { ... }
And call it with:
validateField(data, Person.phoneNumber.getter, options);

As others mention, there is no real way to do this... and I've not seen a precompiler that supports it. The syntax would be interesting, to say the least. Even in your example, it could only cover a small subset of the potential reflective possibilities that a user might want to do since it won't handle non-standard accessors or methods that take arguments, etc..
Even if it's impossible to check at compile time, if you want bad code to fail as soon as possible then one approach is to resolve referenced Method objects at class initialization time.
Imagine you have a utility method for looking up Method objects that maybe throws error or runtime exception:
public static Method lookupMethod( Class c, String name, Class... args ) {
// do the lookup or throw an unchecked exception of some kind with a really
// good error message
}
Then in your classes, have constants to preresolve the methods you will use:
public class MyClass {
private static final Method GET_PHONE_NUM = MyUtils.lookupMethod( PhoneNumber.class, "getPhoneNumber" );
....
public void someMethod() {
validateField(data, GET_PHONE_NUM, options);
}
}
At least then it will fail as soon as MyClass is loaded the first time.
I use reflection a lot, especially bean property reflection and I've just gotten used to late exceptions at runtime. But that style of bean code tends to error late for all kinds of other reasons, being very dynamic and all. For something in between, the above would help.

There isn't anything in the language yet - but part of the closures proposal for Java 7 includes method literals, I believe.
I don't have any suggestions beyond that, I'm afraid.

Check out https://proxetta.jodd.org/refs/methref. It uses the Jodd proxy library (Proxetta) to proxy your type. Not sure about its performance characteristics, but it does provide type safety.
An example: Suppose Str.class has method .boo(), and you want to get its name as the string "boo":
String methodName = Methref.of(Str.class).name(Str::boo);
There's more to the API than the example above: https://oblac.github.io/jodd-site/javadoc/jodd/methref/Methref.html

Is any practical way to reference a method on a class in a type-safe manner?
First of all, reflection is type-safe. It is just that it is dynamically typed, not statically typed.
So, assuming that you want a statically typed equivalent of reflection, the theoretical answer is that it is impossible. Consider this:
Method m;
if (arbitraryFunction(obj)) {
m = obj.getClass().getDeclaredMethod("foo", ...);
} else {
m = obj.getClass().getDeclaredMethod("bar", ...);
}
Can we do this so that that runtime type exceptions cannot happen? In general NO, since this would entail proving that arbitraryFunction(obj) terminates. (This is equivalent to the Halting Problem, which is proven to be unsolvable in general, and is intractable using state-of-the-art theorem proving technology ... AFAIK.)
And I think that this road-block would apply to any approach where you could inject arbitrary Java code into the logic that is used to reflectively select a method from an object's class.
To my mind, the only moderately practical approach at the moment would be to replace the reflective code with something that generates and compiles Java source code. If this process occurs before you "run" the application, you've satisfied the requirement for static type-safety.
I was more asking about reflection in which the result is always the same. I.E. Person.class.getMethod("getPhoneNumber", null) would always return the same method and it's entirely possible to resolve it at compile time.
What happens if after compiling the class containing this code, you change Person to remove the getPhoneNumber method?
The only way you can be sure that you can resolve getPhoneNumber reflectively is if you can somehow prevent Person from being changed. But you can't do that in Java. Runtime binding of classes is a fundamental part of the language.
(For record, if you did that for a method that you called non-reflectively, you would get an IncompatibleClassChangeError of some kind when the two classes were loaded ...)
It has been pointed out that in Java 8 and later you could declare your validator something like this:
public Result validateField(Object data,
SomeFunctionalInterface function,
ValidationOptions options) { ... }
where SomeFunctionalInterface corresponds to the (loosely speaking) common signature of the methods you are validating.
Then you can call it with a method reference; e.g.
validateField(data, SomeClass::someMethod, options)
This is approach is statically type-safe. You will get a compilation error if SomeClass doesn't have someMethod or if it doesn't conform to SomeFunctionalInterface.
But you can't use a string to denote the method name. Looking up a method by name would entail either reflection ... or something else that side-steps static (i.e. compile time / load time) type safety.

Java misses the syntax sugar to do something as nice as Person.phoneNumber.getter. But if Person is an interface, you could record the getter method using a dynamic proxy. You could record methods on non-final classes as well using CGLib, the same way Mockito does it.
MethodSelector<Person> selector = new MethodSelector<Person>(Person.class);
selector.select().getPhoneNumber();
validateField(data, selector.getMethod(), options);
Code for MethodSelector: https://gist.github.com/stijnvanbael/5965609

Inspired by mocking frameworks, we could dream up the following syntax:
validator.validateField(data, options).getPhoneNumber();
Result validationResult = validator.getResult();
The trick is the generic declaration:
class Validator {
public <T> T validateField(T data, options) {...}
}
Now the return type of the method is the same as your data object's type and you can use code completion (and static checking) to access all the methods, including the getter methods.
As a downside, the code isn't quite intuitive to read, since the call to the getter doesn't actually get anything, but instead instructs the validator to validate the field.
Another possible option would be to annotate the fields in your data class:
class FooData {
#Validate(new ValidationOptions(...))
private PhoneNumber phoneNumber;
}
And then just call:
FooData data;
validator.validate(data);
to validate all fields according to the annotated options.

The framework picklock lets you do the following:
class Data {
private PhoneNumber phoneNumber;
}
interface OpenData {
PhoneNumber getPhoneNumber(); //is mapped to the field phoneNumber
}
Object data = new Data();
PhoneNumber number = ObjectAccess
.unlock(data)
.features(OpenData.class)
.getPhoneNumber();
This works in a similar way setters and private methods. Of course, this is only a wrapper for reflection, but the exception does not occur at unlocking time not at call time. If you need it at build time, you could write a unit test with:
assertThat(Data.class, providesFeaturesOf(OpenData.class));

I found a way to get the Method instance using Lambdas. It works only on interface methods though currently.
It works using net.jodah:typetools which is a very lightweight library.
https://github.com/jhalterman/typetools
public final class MethodResolver {
private interface Invocable<I> {
void invokeWithParams(I instance, Class<?>[] parameterTypes) throws Throwable;
}
interface ZeroParameters<I, R> extends Invocable<I> {
R invoke(I instance) throws Throwable;
#Override
default void invokeWithParams(I instance, Class<?>[] parameterTypes) throws Throwable {
invoke(instance);
}
}
public static <I, R> Method toMethod0(ZeroParameters<I, R> call) {
return toMethod(ZeroParameters.class, call, 1);
}
interface OneParameters<I, P1, R> extends Invocable<I> {
R invoke(I instance, P1 p1) throws Throwable;
#Override
default void invokeWithParams(I instance, Class<?>[] parameterTypes) throws Throwable {
invoke(instance, param(parameterTypes[1]));
}
}
public static <I, P1, R> Method toMethod1(OneParameters<I, P1, R> call) {
return toMethod(OneParameters.class, call, 2);
}
interface TwoParameters<I, P1, P2, R> extends Invocable<I> {
R invoke(I instance, P1 p1, P2 p2) throws Throwable;
#Override
default void invokeWithParams(I instance, Class<?>[] parameterTypes) throws Throwable {
invoke(instance, param(parameterTypes[1]), param(parameterTypes[2]));
}
}
public static <I, P1, P2, R> Method toMethod2(TwoParameters<I, P1, P2, R> call) {
return toMethod(TwoParameters.class, call, 3);
}
private static final Map<Class<?>, Object> parameterMap = new HashMap<>();
static {
parameterMap.put(Boolean.class, false);
parameterMap.put(Byte.class, (byte) 0);
parameterMap.put(Short.class, (short) 0);
parameterMap.put(Integer.class, 0);
parameterMap.put(Long.class, (long) 0);
parameterMap.put(Float.class, (float) 0);
parameterMap.put(Double.class, (double) 0);
}
#SuppressWarnings("unchecked")
private static <T> T param(Class<?> type) {
return (T) parameterMap.get(type);
}
private static <I> Method toMethod(Class<?> callType, Invocable<I> call, int responseTypeIndex) {
Class<?>[] typeData = TypeResolver.resolveRawArguments(callType, call.getClass());
Class<?> instanceClass = typeData[0];
Class<?> responseType = responseTypeIndex != -1 ? typeData[responseTypeIndex] : Void.class;
AtomicReference<Method> ref = new AtomicReference<>();
I instance = createProxy(instanceClass, responseType, ref);
try {
call.invokeWithParams(instance, typeData);
} catch (final Throwable e) {
throw new IllegalStateException("Failed to call no-op proxy", e);
}
return ref.get();
}
#SuppressWarnings("unchecked")
private static <I> I createProxy(Class<?> instanceClass, Class<?> responseType,
AtomicReference<Method> ref) {
return (I) Proxy.newProxyInstance(MethodResolver.class.getClassLoader(),
new Class[] {instanceClass},
(proxy, method, args) -> {
ref.set(method);
return parameterMap.get(responseType);
});
}
}
Usage:
Method method = MethodResolver.toMethod2(SomeIFace::foobar);
System.out.println(method); // public abstract example.Result example.SomeIFace.foobar(java.lang.String,boolean)
Method get = MethodResolver.<Supplier, Object>toMethod0(Supplier::get);
System.out.println(get); // public abstract java.lang.Object java.util.function.Supplier.get()
Method accept = MethodResolver.<IntFunction, Integer, Object>toMethod1(IntFunction::apply);
System.out.println(accept); // public abstract java.lang.Object java.util.function.IntFunction.apply(int)
Method apply = MethodResolver.<BiFunction, Object, Object, Object>toMethod2(BiFunction::apply);
System.out.println(apply); // public abstract java.lang.Object java.util.function.BiFunction.apply(java.lang.Object,java.lang.Object)
Unfortunately you have to create a new interface and method based on the parameter count and whether the method returns void or not.
However, if you have a somewhat fixed/limited method signature/parameter types, then this becomes quite handy.