In my method I initially used RestTemplate postForObject method to post request to an endpoint. Now I have to add default OAuth token and pass it as Post request. Is there any way I can pass both request as well as Default Header as part of POST request by using postForObject?
Initiall I used below postForObject
String result = restTemplate.postForObject(url, request, String.class);
I am looking for something like below
restTemplate.exchange(url,HttpMethod.POST,getEntity(),String.class );
Here is my code
private final String url;
private final MarkBuild header;
public DataImpl(#Qualifier(OAuth) MarkBuild header,RestTemplate restTemplate) {
this.restTemplate= restTemplate;
this.header = header;
}
public void postJson(Set<String> results){
try {
Map<String, String> requestBody = new HashMap<>();
requestBody.put("news", "data");
JSONObject jsonObject = new JSONObject(requestBody);
HttpEntity<String> request = new HttpEntity<String>(jsonObject.toString(), null);
String result = restTemplate.postForObject(url, request, String.class);
}
}
Below is getHttpEntity which I want to pass with Post request
private HttpEntity getHttpEntity(Set <String>results) {
return new HttpEntity<>( null, getHttpHeaders() );
}
private HttpHeaders getHttpHeaders() {
return header.build();
}
}
Is there any way I can pass both request as well as Default Header as
part of POST request by using postForObject?
Yes, there is a way to do that, I can give a basic example:
HttpHeaders lHttpHeaders = new HttpHeaders();
lHttpHeaders.setContentType( MediaType.APPLICATION_JSON );//or whatever it's in your case
String payload="<PAYLOAD HERE>"
try
{
String lResponseJson = mRestTemplate.postForObject( url, new HttpEntity<Object>( payload, lHttpHeaders ), String.class);
return lResponseJson;
}
catch( Exception lExcp )
{
logger.error( lExcp.getMessage(), lExcp );
}
Let me know if this doesn't work!!
I am trying to send a body in a post request in a springboot application using rest template. Here is the controller:(I removed #RequestBody because I used application/x-www-form-urlencoded header)
#RestController
#CrossOrigin
#RequestMapping("/api")
public class SentimentParserController {
#Autowired
private SentimentParserService sentimentParserService;
#RequestMapping(value = "/something", method = RequestMethod.POST, consumes="application/x-www-form-urlencoded")
public ResponseEntity<mcResponse>getTheSentiments( mcSentimentRequestDTO sentimentRequestDTO){
return sentimentParserService.getSentimentsMc(sentimentRequestDTO);
}
}
I want to send the sentimentRequestDTO object(lang, key, and text) as the body in a post request to get the mcResponse:
public mcResponse parseTheSentiments(String text, Languages lang, String key) throws Exception {
RestTemplate restTemplate = new RestTemplate();
String request = "http://localhost:8080";
mcSentimentRequestDTO mSentiments =new mcSentimentRequestDTO(key,"EN",text);
HttpHeaders headers = new HttpHeaders();
headers.add("content-type", "application/x-www-form-urlencoded");
MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
map.add("key", key);
map.add("txt", text);
map.add("lang", Languages.ENGLISH.toString());
HttpEntity<MultiValueMap<String, String>> request1 = new HttpEntity<MultiValueMap<String, String>>(map, headers);
mcResponse response = restTemplate.postForObject(request, request1 , mcResponse.class );
return response;
}
However, I am getting the following error: 404 null.
Can you please help me? Thanks in advance
and here is the service class:
public ResponseEntity<mcResponse> getSentimentsMc(mcSentimentRequestDTO sentimentRequestDTO){
ResponseEntity<mcResponse> dto = null;
try {
dto = sentimentConverter.getTheSentiments(mcsParser.parseTheSentiments(sentimentRequestDTO.getText(),
Languages.ENGLISH, sentimentRequestDTO.getKey()));
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return dto;
}
Looks like variable request should be
String request = "http://localhost:8080/something";
Also if controller class has prefix, this prefix also should be in request.
I mean if your class looks like this
#RestController
#RequestMapping("/myApi")
public class CertificateController {
....
#RequestMapping(value = "/something", method = RequestMethod.POST)
public ResponseEntity<mcResponse>getTheSentiments( mcSentimentRequestDTO sentimentRequestDTO){
return sentimentParserService.getSentimentsMc(sentimentRequestDTO);
}
Then request should be
String request = "http://localhost:8080/myApi/something";
It sounds like the controller isn't getting included in the spring context. If you just have an app annotated with #SpringBootApplication, then make sure that your controller is in a package that is the same as or lower than your annotated application.
To check the controller is being picked up you can add the following logging options to your application.properties
logging.level.org.springframework.beans=debug
logging.level.org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping=trace
When your server starts up you should see something like the following in the log
1. To show the controller is in the spring-context
DefaultListableBeanFactory : Creating shared instance of singleton bean 'sentimentParserController'
2. To show the mapping for the /api/something url
RequestMappingHandlerMapping : Mapped 1 handler method(s) for class SentimentParserController: {public org.springframework.http.ResponseEntity SentimentParserController.getTheSentiments(mcSentimentRequestDTO)={[/api/something],methods=[POST]}}
If you see both of these, then what you say you're doing should work. Just make sure you are sending the request to /api/something and the server is running on port 8080.
Title might look common but none of them fit in my issue.
I have a rest service which accept normal parameters and file in form of multipart.
i want to use resttemplate to send data and file to above rest service.
till the time i was sending normal string data there was no issue. once i add code of sending bytes then i start getting 400 Bad request error.
if i comment code to send ByteArrayResource then it start working for normal parameters.
below is sample code
Rest service controller
#RestController
#RequestMapping(value="/ticket")
public class UserTicketController {
#RequestMapping(value="/createTicket.do",method={RequestMethod.POST},
consumes = {MediaType.MULTIPART_FORM_DATA_VALUE},headers={"content-type="+MediaType.MULTIPART_FORM_DATA_VALUE})
public void createTicket(#ModelAttribute ServiceDeskRequest serviceDeskRequest, HttpServletRequest request,HttpServletResponse response) throws Exception{
}
}
Servicedeskrequest model attribute is
public class ServiceDeskRequest implements Serializable{
private String jsonData;
private MultipartFile attachment;
}
application-context.xml
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
</bean>
Client Side code
RestTemplate restTemplate = new RestTemplate();
MultiValueMap<String, Object> requestParamerterMap = new LinkedMultiValueMap<String, Object>();
requestParamerterMap.add("jsonData", jsonData);
MultipartFile attachment = userRequest.getAttachment();
if(attachment!=null && attachment.getOriginalFilename()!=null) {
ByteArrayResource byteArrayResource = new ByteArrayResource(attachment.getBytes(), attachment.getOriginalFilename());
requestParamerterMap.add("attachment", byteArrayResource);
}
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<MultiValueMap<String, Object>>(requestParamerterMap, headers);
String response = restTemplate.postForObject(targetUrl, requestEntity, String.class);
I figured it out. There are two piece in this puzzle. No change in service code.
Providing right converter to resttemplate. In list of default converts spring doesn't add FormHttpMessageConverter.
FormHttpMessageConverter converter = new FormHttpMessageConverter();
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(converter);
overriding bytearrayresource class. plz note you need to override getFilename method so that document name can be received at service side.
public class MultipartByteArrayResource extends ByteArrayResource{
private String fileName;
public MultipartByteArrayResource(byte[] byteArray) {
super(byteArray);
}
public String getFilename() {
return fileName;
}
public void setFilename(String fileName) {
this.fileName= fileName;
}
}
After above changes client code will be
FormHttpMessageConverter converter = new FormHttpMessageConverter();
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(converter);
MultiValueMap<String, Object> requestParamerterMap = new LinkedMultiValueMap<String, Object>();
requestParamerterMap.add("jsonData", jsonData);
MultipartFile attachment = userRequest.getAttachment();
if(attachment!=null && attachment.getOriginalFilename()!=null) {
//ByteArrayResource byteArrayResource = new ByteArrayResource(attachment.getBytes(), attachment.getOriginalFilename());
MultipartByteArrayResource resource = new MultipartByteArrayResource(attachment.getBytes());
//pass file name sepratly
resource.setFilename(attachment.getOriginalFilename());
requestParamerterMap.add("attachment", resource);
}
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<MultiValueMap<String, Object>>(requestParamerterMap, headers);
String response = restTemplate.postForObject(targetUrls.get("sdCreateTicketsUrl"), requestEntity, String.class);
First, value="/createTicket.do" is way off the REST convention. Same goes for /ticket.
Creation of a ticket should be done by POST to URL: .../tickets/
private ArrayList<NameValuePair> mParams;
HttpClient client = new DefaultHttpClient();
mParams = new ArrayList<NameValuePair>();
mParams.add(new BasicNameValuePair("testKey", "John"));
mParams.add(new BasicNameValuePair("testSerial", "003-100"));
HttpPost request = new HttpPost("http://localhost:8080/test/getRequiredEnv");
request.setEntity(new UrlEncodedFormEntity(mParams, HTTP.UTF_8));
HttpResponse response = client.execute(request);
// TestController.java
#RestController
public class TestController {
private static final Logger logger = Logger.getLogger(TestController.class);
#RequestMapping(value = "/getRequiredEnv", method = RequestMethod.POST)
public #ResponseBody ResponseInfo getRequiredEnv(
#RequestParam("testKey") String testKey,
#RequestParam("testValue") String testValue,
#RequestHeader HttpHeaders headers) {
logger.info("Test Key [" + testKey + "]");
logger.info("Test Value [" + testValue + "]");
return new TestResponseInfo("0001", "ABC");
}
Can someone please tell me is this the correct way to get data from 'Request.setEntity' in SpringMVC rest controller or I am missing something?
Secondly, in postman "httpPost" request I pass the parameters (testKey & testValue) as headers or as body?
Thirdly, without knowing the parameters in httpPost request can I able to parse the incoming request and extract the parameters from it in Spring controller?
First of all it would be good to know the content-type of the request that is sent.
So I guess you want to get the body of the request. To get all request parameters if you don't know the parameter names beforehand you can use #RequestParam with type Map<String, String> to get all params:
#RequestMapping(value = "/getRequiredEnv", method = RequestMethod.POST)
public #ResponseBody ResponseInfo getRequiredEnv(
#RequestParam Map<String, String> allParams,
#RequestHeader HttpHeaders headers)
But I am not sure if this works because it also depends on the content-type. E.g. for form data (application/x-www-form-urlencoded) have a look at the Spring documentation about #RequestBody which states about one of the default message converters FormHttpMessageConverter:
FormHttpMessageConverter converts form data to/from a MultiValueMap.
So try:
#RequestMapping(value = "/getRequiredEnv", method = RequestMethod.POST)
public #ResponseBody ResponseInfo getRequiredEnv(
#RequestBody MultiValueMap<String, String>,
#RequestHeader HttpHeaders headers)
Alternatively there is also HttpServletRequest.getParameterMap() which gets you a Map. You can get the request by just including HttpServletRequest request as a method argument.
If you know the paramters beforehand, annotating your POJO that resembles the form data with #ModelAttribute should also work like so:
#RequestMapping(value = "/getRequiredEnv", method = RequestMethod.POST)
public #ResponseBody ResponseInfo getRequiredEnv(
##ModelAttribute Test myTestPojo,
#RequestHeader HttpHeaders headers)
Or you could also send data as application/json and when including jackson as a dependency, #Requestbody will map your data to a POJO. Have a look at e.g. Spring JSON request body not mapped to Java POJO.
In regard to your second question httpPost will pass the parameters as body since it is a POST request.
I have build a web application using spring mvc framework to publish REST services.
For example:
#Controller
#RequestMapping("/movie")
public class MovieController {
#RequestMapping(value = "/{id}", method = RequestMethod.GET)
public #ResponseBody Movie getMovie(#PathVariable String id, #RequestBody user) {
return dataProvider.getMovieById(user,id);
}
Now I need to deploy my application but I have the following problem:
The clients do not have direct access to the computer on which the application resides (There is a firewall). Therefore I need a redirection layer on a proxy machine (accessible by the clients) which calls the actual rest service.
I tried making a new call using RestTemplate:
For Example:
#Controller
#RequestMapping("/movieProxy")
public class MovieProxyController {
private String address= "http://xxx.xxx.xxx.xxx:xx/MyApp";
#RequestMapping(value = "/{id}", method = RequestMethod.GET)
public #ResponseBody Movie getMovie(#PathVariable String id,#RequestBody user,final HttpServletResponse response,final HttpServletRequest request) {
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
RestTemplate restTemplate = new RestTemplate();
return restTemplate.exchange( address+ request.getPathInfo(), request.getMethod(), new HttpEntity<T>(user, headers), Movie.class);
}
This is ok but I need to rewrite each method in the controller to use the resttemplate. Also, this causes redundant serialization/deserialization on the proxy machine.
I tried writing a generic function using restemplate, but it did not work out:
#Controller
#RequestMapping("/movieProxy")
public class MovieProxyController {
private String address= "http://xxx.xxx.xxx.xxx:xx/MyApp";
#RequestMapping(value = "/**")
public ? redirect(final HttpServletResponse response,final HttpServletRequest request) {
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
RestTemplate restTemplate = new RestTemplate();
return restTemplate.exchange( address+ request.getPathInfo(), request.getMethod(), ? , ?);
}
I could not find a method of resttemplate which works with request and response objects.
I also tried spring redirect and forward. But redirect does not change the request's client ip address so i think it is useless in this case. I could not forward to another URL either.
Is there a more appropriate way to achieve this?
You can mirror/proxy all requests with this:
private String server = "localhost";
private int port = 8080;
#RequestMapping("/**")
#ResponseBody
public String mirrorRest(#RequestBody String body, HttpMethod method, HttpServletRequest request) throws URISyntaxException
{
URI uri = new URI("http", null, server, port, request.getRequestURI(), request.getQueryString(), null);
ResponseEntity<String> responseEntity =
restTemplate.exchange(uri, method, new HttpEntity<String>(body), String.class);
return responseEntity.getBody();
}
This will not mirror any headers.
Here's my modified version of the original answer, which differs in four points:
It does not make the request body mandatory, and as such does not let GET requests fail.
It copies all headers present in the original request. If you are using another proxy/web server, this can cause issues due to content length/gzip compression. Limit the headers to the ones you really need.
It does not reencode the query params or the path. We expect them to be encoded anyway. Note that other parts of your URL might also be encoded. If that is the case for you, leverage the full potential of UriComponentsBuilder.
It does return error codes from the server properly.
#RequestMapping("/**")
public ResponseEntity mirrorRest(#RequestBody(required = false) String body,
HttpMethod method, HttpServletRequest request, HttpServletResponse response)
throws URISyntaxException {
String requestUrl = request.getRequestURI();
URI uri = new URI("http", null, server, port, null, null, null);
uri = UriComponentsBuilder.fromUri(uri)
.path(requestUrl)
.query(request.getQueryString())
.build(true).toUri();
HttpHeaders headers = new HttpHeaders();
Enumeration<String> headerNames = request.getHeaderNames();
while (headerNames.hasMoreElements()) {
String headerName = headerNames.nextElement();
headers.set(headerName, request.getHeader(headerName));
}
HttpEntity<String> httpEntity = new HttpEntity<>(body, headers);
RestTemplate restTemplate = new RestTemplate();
try {
return restTemplate.exchange(uri, method, httpEntity, String.class);
} catch(HttpStatusCodeException e) {
return ResponseEntity.status(e.getRawStatusCode())
.headers(e.getResponseHeaders())
.body(e.getResponseBodyAsString());
}
}
You can use Netflix Zuul to route requests coming to a spring application to another spring application.
Let's say you have two application: 1.songs-app, 2.api-gateway
In the api-gateway application, first add the zuul dependecy, then you can simply define your routing rule in application.yml as follows:
pom.xml
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-zuul</artifactId>
<version>LATEST</version>
</dependency>
application.yml
server:
port: 8080
zuul:
routes:
foos:
path: /api/songs/**
url: http://localhost:8081/songs/
and lastly run the api-gateway application like:
#EnableZuulProxy
#SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
Now, the gateway will route all the /api/songs/ requests to http://localhost:8081/songs/.
A working example is here: https://github.com/muatik/spring-playground/tree/master/spring-api-gateway
Another resource: http://www.baeldung.com/spring-rest-with-zuul-proxy
#derkoe has posted a great answer that helped me a lot!
Trying this in 2021, I was able to improve on it a little:
You don't need #ResponseBody if your class is a #RestController
#RequestBody(required = false) allows for requests without a body (e.g. GET)
https and port 443 for those ssl encrypted endpoints (if your server serves https on port 443)
If you return the entire responseEntity instead of only the body, you also get the headers and response code.
Example of added (optional) headers, e.g. headers.put("Authorization", Arrays.asList(String[] { "Bearer 234asdf234"})
Exception handling (catches and forwards HttpStatuses like 404 instead of throwing a 500 Server Error)
private String server = "localhost";
private int port = 443;
#Autowired
MultiValueMap<String, String> headers;
#Autowired
RestTemplate restTemplate;
#RequestMapping("/**")
public ResponseEntity<String> mirrorRest(#RequestBody(required = false) String body, HttpMethod method, HttpServletRequest request) throws URISyntaxException
{
URI uri = new URI("https", null, server, port, request.getRequestURI(), request.getQueryString(), null);
HttpEntity<String> entity = new HttpEntity<>(body, headers);
try {
ResponseEntity<String> responseEntity =
restTemplate.exchange(uri, method, entity, String.class);
return responseEntity;
} catch (HttpClientErrorException ex) {
return ResponseEntity
.status(ex.getStatusCode())
.headers(ex.getResponseHeaders())
.body(ex.getResponseBodyAsString());
}
return responseEntity;
}
proxy controller with oauth2
#RequestMapping("v9")
#RestController
#EnableConfigurationProperties
public class ProxyRestController {
Logger logger = LoggerFactory.getLogger(this.getClass());
#Autowired
OAuth2ProtectedResourceDetails oAuth2ProtectedResourceDetails;
#Autowired
private ClientCredentialsResourceDetails clientCredentialsResourceDetails;
#Autowired
OAuth2RestTemplate oAuth2RestTemplate;
#Value("${gateway.url:http://gateway/}")
String gatewayUrl;
#RequestMapping(value = "/proxy/**")
public String proxy(#RequestBody(required = false) String body, HttpMethod method, HttpServletRequest request, HttpServletResponse response,
#RequestHeader HttpHeaders headers) throws ServletException, IOException, URISyntaxException {
body = body == null ? "" : body;
String path = request.getRequestURI();
String query = request.getQueryString();
path = path.replaceAll(".*/v9/proxy", "");
StringBuffer urlBuilder = new StringBuffer(gatewayUrl);
if (path != null) {
urlBuilder.append(path);
}
if (query != null) {
urlBuilder.append('?');
urlBuilder.append(query);
}
URI url = new URI(urlBuilder.toString());
if (logger.isInfoEnabled()) {
logger.info("url: {} ", url);
logger.info("method: {} ", method);
logger.info("body: {} ", body);
logger.info("headers: {} ", headers);
}
ResponseEntity<String> responseEntity
= oAuth2RestTemplate.exchange(url, method, new HttpEntity<String>(body, headers), String.class);
return responseEntity.getBody();
}
#Bean
#ConfigurationProperties("security.oauth2.client")
#ConditionalOnMissingBean(ClientCredentialsResourceDetails.class)
public ClientCredentialsResourceDetails clientCredentialsResourceDetails() {
return new ClientCredentialsResourceDetails();
}
#Bean
#ConditionalOnMissingBean
public OAuth2RestTemplate oAuth2RestTemplate() {
return new OAuth2RestTemplate(clientCredentialsResourceDetails);
}
If you can get away with using a lower-level solution like mod_proxy that would be the simpler way to go, but if you need more control (e.g. security, translation, business logic) you may want to take a look at Apache Camel: http://camel.apache.org/how-to-use-camel-as-a-http-proxy-between-a-client-and-server.html
I got inspired by Veluria's solution, but I had issues with gzip compression sent from the target resource.
The goal was to omit Accept-Encoding header:
#RequestMapping("/**")
public ResponseEntity mirrorRest(#RequestBody(required = false) String body,
HttpMethod method, HttpServletRequest request, HttpServletResponse response)
throws URISyntaxException {
String requestUrl = request.getRequestURI();
URI uri = new URI("http", null, server, port, null, null, null);
uri = UriComponentsBuilder.fromUri(uri)
.path(requestUrl)
.query(request.getQueryString())
.build(true).toUri();
HttpHeaders headers = new HttpHeaders();
Enumeration<String> headerNames = request.getHeaderNames();
while (headerNames.hasMoreElements()) {
String headerName = headerNames.nextElement();
if (!headerName.equals("Accept-Encoding")) {
headers.set(headerName, request.getHeader(headerName));
}
}
HttpEntity<String> httpEntity = new HttpEntity<>(body, headers);
RestTemplate restTemplate = new RestTemplate();
try {
return restTemplate.exchange(uri, method, httpEntity, String.class);
} catch(HttpStatusCodeException e) {
return ResponseEntity.status(e.getRawStatusCode())
.headers(e.getResponseHeaders())
.body(e.getResponseBodyAsString());
}
}
You need something like jetty transparent proxy, which actually will redirect your call, and you get a chance to overwrite the request if you needed. You may get its detail at http://reanimatter.com/2016/01/25/embedded-jetty-as-http-proxy/