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convert xmlGregorianCalendar to Date and reverse

i all, i have a spring boot application. what i want in specific is to convert a class (that have nestet object field) in his corrispective entity. example:
public class example{
String string;
ObjectExample object;
}
public class ObjectExample{
String oneString;
XMLGregorianCalendar date;
}
this 2 object are also marked in another package as entities, but ovviusly in the ObjectExampleEntity i have Date date instead XMLGregorianCalendar, like this with the example
#Entity
public class example{
String string;
ObjectExample object;
}
#Entity
public class ObjectExample{
String oneString;
Date date;
}
because i have a big model and big entity (this above is only an example) with a lot of nested classes , i use dozer to convert from the model to the class.
consider for example that the repository jpa is only created for the father example class.
i want to know how i can with dozer convert from Date (entity) to XMLGregorianCalendar (model) and reverse. the model and the entity,i repeat are equal. the only difference is the type of the date. thanks

I am assuming:
Since your variable is named date it contains a calendar date (without time of day).
You are tied to XMLGregorianCalendar because of a WSDL outside your control, but you can change type on the entity side.
Based on these assumptions I recommend LocalDate on the entity side. It’s part of java.time, the modern Java date and time API, and represents exactly a date without time of day. The Date class that you used is poorly designed, long outdated and not recommended. Also despite the name a Date never represented a date, but a point in time.
There are more options. I am presenting three.
Option 1: transfer individual fields
From XMLGregorianCalendar to LocalDate:
DatatypeFactory xmlFactory = DatatypeFactory.newInstance();
XMLGregorianCalendar wsDate = xmlFactory
.newXMLGregorianCalendarDate(2019, DatatypeConstants.MARCH, 30,
DatatypeConstants.FIELD_UNDEFINED);
// Validate
if ((wsDate.getHour() != 0 && wsDate.getHour() != DatatypeConstants.FIELD_UNDEFINED)
|| (wsDate.getMinute() != 0 && wsDate.getMinute() != DatatypeConstants.FIELD_UNDEFINED)
|| (wsDate.getSecond() != 0 && wsDate.getSecond() != DatatypeConstants.FIELD_UNDEFINED)
|| (wsDate.getMillisecond() != 0 && wsDate.getMillisecond() != DatatypeConstants.FIELD_UNDEFINED)) {
System.out.println("Warning: time of day will be lost in conversion");
}
if (wsDate.getTimezone() != DatatypeConstants.FIELD_UNDEFINED) {
System.out.println("Warning: UTC offset will be lost in conversion");
}
// Convert
LocalDate entityDate = LocalDate.of(wsDate.getYear(), wsDate.getMonth(), wsDate.getDay());
System.out.println(entityDate);
The output is in this case:
2019-03-30
From LocalDate to XMLGregorianCalendar:
LocalDate entityDate = LocalDate.of(2019, Month.MARCH, 31);
XMLGregorianCalendar wsDate = xmlFactory.newXMLGregorianCalendarDate(
entityDate.getYear(),
entityDate.getMonthValue(),
entityDate.getDayOfMonth(),
DatatypeConstants.FIELD_UNDEFINED);
System.out.println(wsDate);
2019-03-31
Advantage of this way: It’s pretty straightforward. Disadvantage: You and your reader need to take care that the fields are mentioned in the right order.
Option 2: convert via strings
// Validate as before
// Convert
LocalDate entityDate = LocalDate.parse(wsDate.toXMLFormat());
Result is as before.
XMLGregorianCalendar wsDate
= xmlFactory.newXMLGregorianCalendar(entityDate.toString());
Advantage: it’s brief, and there’s no surprise that the results are correct. Disadvantage: To me it feels like a waste to format into a string only to parse it back.
Option 3: convert via GregorianCalendar and ZonedDateTime
ZonedDateTime zdt = wsDate.toGregorianCalendar().toZonedDateTime();
// Validate
if (! zdt.toLocalTime().equals(LocalTime.MIN)) {
System.out.println("Warning: time of day will be lost in conversion");
}
if (! zdt.getZone().equals(ZoneId.systemDefault())) {
System.out.println("Warning: UTC offset will be lost in conversion");
}
// Finish conversion
LocalDate entityDate = zdt.toLocalDate();
And the other way:
// It doesn’t matter which time zone we pick
// since we are discarding it after conversion anyway
ZonedDateTime zdt = entityDate.atStartOfDay(ZoneOffset.UTC);
GregorianCalendar gCal = GregorianCalendar.from(zdt);
XMLGregorianCalendar wsDate = xmlFactory.newXMLGregorianCalendar(gCal);
wsDate.setTime(DatatypeConstants.FIELD_UNDEFINED, DatatypeConstants.FIELD_UNDEFINED,
DatatypeConstants.FIELD_UNDEFINED, DatatypeConstants.FIELD_UNDEFINED);
wsDate.setTimezone(DatatypeConstants.FIELD_UNDEFINED);
The validation I present here is a bit simpler but also not quite so strict. If you want strict validation, you can just use the validation from before.
Advantages: I think it’s the official way; at least it uses the conversion methods offered. What I like is that the conversion itself is direct and brief. Disadvantage: When converting to XMLGregorianCalendar we need to set the unused fields to undefined manually, which makes it wordy.
Conclusion
I have presented three options each with their pros and cons. You may also mix, of course, but using a similar conversion both ways is probably less confusing in the end.

Java local variable vs global field - Performance

I have a private method which takes date in as String type and returns XMLGregorianCalendar object with specific format. This method is being invoked from various other methods within the same class.
The format defined as SimpleDateFormat which is same for every invocation. Below are the 2 versions of the method.
Version 1:
private XMLGregorianCalendar getXmlGregorianCalendar(final String strDt) throws ParseException, DatatypeConfigurationException{
Date date = null;
// local variable dtFormat
DateFormat dtFormat = new SimpleDateFormat("yyyy-MM-dd-hh.mm.ss");
if (strDt != null) {
date = dtFormat.parse(strDt);
GregorianCalendar cal = new GregorianCalendar();
cal.setTime(date);
XMLGregorianCalendar xmlCal = DatatypeFactory.newInstance().newXMLGregorianCalendar(cal);
return xmlCal;
}else {
return DatatypeFactory.newInstance().newXMLGregorianCalendar(new GregorianCalendar());
}
}
Version 2:
// declare date format once, global variable
private DateFormat dtFormat = new SimpleDateFormat("yyyy-MM-dd-hh.mm.ss");
// getter setter for dtFormat
private XMLGregorianCalendar getXmlGregorianCalendar(final String strDt) throws ParseException, DatatypeConfigurationException{
Date date = null;
if (strDt != null) {
date = this.dtFormat.parse(strDt); // of course, getDtFormat() can be used
GregorianCalendar cal = new GregorianCalendar();
cal.setTime(date);
XMLGregorianCalendar xmlCal = DatatypeFactory.newInstance().newXMLGregorianCalendar(cal);
return xmlCal;
}else {
return DatatypeFactory.newInstance().newXMLGregorianCalendar(new GregorianCalendar());
}
}
Version 1 vs Version 2. Which has better performance?
Note: The enclosed class is annotated as #Component and involved in creating response for my web service.

SimpleDateFormat is not thread-safe, so that would be something to consider. Performance has little to do with this question, unless you really don't have any other performance hotspots (which would be surprising).
You can however use a ThreadLocal SimpleDateFormat, but remember that ThreadLocals have their own issues, and it probably doesn't really matter.

If that SimpleDateFormat is a constant, you can make it static final and it would improve your performance just a little bit. But you should be aware of the concept of static fields in classes. static fields are allocated once in memory for all instances of your #Component class. So if this cannot creating a bug in your code, it's better to define it as a constant using static final keywords.

Does Joda-Time have a method called isToday

I need to check if a given timestamp is today. I am using Joda-Time. Is there a method or a simple way to check this? What Joda-Time class is better suited for this? LocalDate? DateTime?

The date can be compared by single statement so why you need a special function.
when dateTimeis an object of DateTime()
if((dateTime.toLocalDate()).equals(new LocalDate()))
when date is an object of java.util.date
if((new DateTime(date).toLocalDate()).equals(new LocalDate()))
What Joda-time class is better suited for this? LocalDate? DateTime?
The understanding that you need to know what is LocalDate and DateTime.
LocalDate() is an immutable datetime class representing a date without a
time zone. So is not having a time part.
DateTime() is the standard implementation of an unmodifiable datetime
class. Its having all the attributes of the Date, which includes
date, time and timezone.
So if you need to compare both the date and time better go with datetime, if you just need to check the date you must use localDate because the datetime will produce a false if an .equal operator is used, unless the time including the seconds part are same for both the objects.

Here are some simple methods to check if a DateTime is today, tomorrow or yesterday:
public boolean isToday(DateTime time) {
return LocalDate.now().compareTo(new LocalDate(time)) == 0;
}
public boolean isTomorrow(DateTime time) {
return LocalDate.now().plusDays(1).compareTo(new LocalDate(time)) == 0;
}
public boolean isYesterday(DateTime time) {
return LocalDate.now().minusDays(1).compareTo(new LocalDate(time)) == 0;
}

One possibility is to create an interval covering the whole day in question, and then check if the various timestamps are contained in this interval.
Constructing the initial interval could look like:
Interval today = new Interval(DateTime.now().withTimeAtStartOfDay(), Days.ONE);
Then the timestamps could be checked like so:
today.contains(DateTime.now()); // True
today.contains(DateTime.now().minusDays(1)); // False
today.contains(DateTime.now().plusDays(1)); // False
today.contains(someOtherTimeStamp.toDateTime()); // And so on...

The recommended way to do this would be:
DateTime midnightToday = DateTime.now().withTimeAtStartOfDay();
DateTime myDateTime = <whatever>;
if(myDateTime.isAfter(midnightToday)) {
}
I think you need Joda 2.5 to do this, but that should do the trick.

I like #JustinMorris's answer. But I found this even better:
public static boolean isToday(DateTime time) {
return LocalDate.now().equals(new LocalDate(time));
}
public static boolean isTomorrow(DateTime time) {
return LocalDate.now().plusDays(1).equals(new LocalDate(time));
}
public static boolean isYesterday(DateTime time) {
return LocalDate.now().minusDays(1).equals(new LocalDate(time));
}

AFAIK there is no direct method available by which you can check the Date is Today Date or not.
The simplest approach will be constructing two DateTime one with the Timestamp, and another with today Date and then comparing day from dayOfYear() and year from year() but do remember whether both Date are in UTC or in Local Time Zone.
A small sample,
DateTime date = new DateTime(TimeStamp);
DateTime todayDate = new DateTime();
if(date.dayOfYear().get() == todayDate.dayOfYear().get() && date.year().get() == todayDate.year().get())
{
System.out.println("Date is today date");
}

Joda time actually have a method for this:
DateUtils#isToday(ReadablePartial);
DateUtils#isToday(ReadableInstant);

Simplest way I've found:
public boolean isToday(DateTime dateTime) {
return dateTime.withTimeAtStartOfDay().getMillis() ==
new DateTime().withTimeAtStartOfDay().getMillis();
}

Add time unit to Joda DateTime object

Is there a better way to add a certain unit of time to a DateTime object?
I would like to do something similar to:
TimeUnit unit = TimeUnit.valueOf("days");
DateTime date = new DateTime().add(unit, 20);
This is my current implementation.
int number = 20;
MutableDateTime now = new MutableDateTime();
String timeUnit = getTimeUnit(); // returns "days", "months", "years"
if (timeUnit.equals("days"))
now.addDays(number);
else if (timeUnit.equals("months"))
now.addMonths(number);
else
now.addYears(number);
return now.toDateTime();

The answer of Sotirios Delimanolis is right. JodaTime has no enum-like concept because it was developed before the introduction of Java generics and enums in JDK5. In Java 8 you can also go this way or similar:
String name = "days"; // or months or years
ChronoUnit unit = ChronoUnit.valueOf(name.toUpperCase());
LocalDateTime ldt = LocalDateTime.of(...);
ldt = ldt.plus(number, unit);
Or consider using ZonedDateTime instead of LocalDateTime. The new approach is much more elegant (yes JodaTime becomes old).

I don't know of a built-in way to do it. Instead, you can create a Map of String names mapped to corresponding DurationFieldType objects. For example
static Map<String, DurationFieldType> durationFieldTypes = new HashMap<>();
static {
durationFieldTypes.put("days", DurationFieldType.days());
durationFieldTypes.put("months", DurationFieldType.months());
...
}
And then just query that Map for the appropriate object
MutableDateTime dateTime = new MutableDateTime();
String timeUnit = getTimeUnit(); // returns "days", "months", "years"
dateTime.add(durationFieldTypes.get(timeUnit), amount);
You will possibly need some fail safe for invalid timeUnit values.

Java system time

I have this code copied from one of questions from SO:
public static String getCurrentTimeStamp() {
SimpleDateFormat sdfDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date now = new Date();
String strDate = sdfDate.format(now);
return strDate;
}
I want to get only the system time and NOT the date. Then I must change second line of code to:
SimpleDateFormat sdfDate = new SimpleDateFormat(" HH:mm:ss") ;
Then, DATE() must get the current time. Clear upto this point but I can't understand the format() function used.
I mean cant we simply output variable now instead of strdate?
Is it just because that the return type of function getCurrentTimeStamp() is String?
Please clarify and if there is any other simpler and one line code for getting system time alone, do share.

I mean cant we simply output variable now instead of strdate.
Well you could return now.toString() - but that will use the format that Date.toString() happens to choose, whereas you want a specific format. The point of the SimpleDateFormat object in this case is to convert a Date (which is a point in time, without reference to any particular calendar or time zone) into a String, applying an appropriate time zone, calendar system, and text format (in your case HH:mm:ss).
You can still simplify your method somewhat though, by removing the local variables (which are each only used once):
public static String getCurrentTimeStamp() {
return new SimpleDateFormat("HH:mm:ss").format(new Date());
}
Or maybe you'd find it more readable to keep the variable for the date format, but not the date and the return value:
public static String getCurrentTimeStamp() {
DateFormat format = new SimpleDateFormat("HH:mm:ss");
return format.format(new Date());
}
Personally I'd recommend using Joda Time instead, mind you - it's a much nicer date/time API, and its formatted are thread-safe so you could easily keep a reference to a single formatting object.

public static String getCurrentTimeStampwithTimeOnly() {
return new SimpleDateFormat("HH:mm:ss").format(new Date());
}
Helps you to do this.

you can call this line any time
Date now = new Date();
The now variable will contain the current timestamp
The format function just generates a String from this timestamp
also take a look at the Calendar class ( Calendar.getInstance())