How wait() and notifyAll() prevents deadlock in given code snippet? - java

Here is the code snippet:
public class PrintEvenOdd
public static class SynchronizedThreadMonitor {
public final static boolean ODD_TURN = true;
public final static boolean EVEN_TURN = false;
private boolean turn = ODD_TURN;
public synchronized void waitTurn(boolean oldTurn) {
while (turn != oldTurn) {
try {
wait();
} catch (InterruptedException e) {
System.out.println("InterruptedException in wait(): " + e);
}
}
}
public synchronized void toggleTurn(){
turn ^= true;
notify();
}
}
public static class OddThread extends Thread {
private final SynchronizedThreadMonitor monitor;
public OddThread(SynchronizedThreadMonitor monitor) {
this.monitor = monitor;
}
#Override
public void run() {
for (int i=1; i<=100; i+=2) {
monitor.waitTurn(SynchronizedThreadMonitor.ODD_TURN);
System.out.println("i= " + i);
monitor.toggleTurn();
}
}
}
public static class EvenThread extends Thread {
private final SynchronizedThreadMonitor monitor;
public EvenThread(SynchronizedThreadMonitor monitor) {
this.monitor = monitor;
}
#Override
public void run() {
for (int i=2; i<=100; i+=2) {
monitor.waitTurn(SynchronizedThreadMonitor.EVEN_TURN);
System.out.println("i= " + i);
monitor.toggleTurn();
}
}
}
public static void main(String[] args) throws InterruptedException {
SynchronizedThreadMonitor monitor = new SynchronizedThreadMonitor();
Thread t1 = new OddThread(monitor);
Thread t2 = new EvenThread(monitor);
t1.start();
t2.start();
t1.join();
t2.join();
}
}
Using 2 threads to print numbers. One prints odd numbers and another prints even numbers.
In my understanding, both waitTurn and toggleTurn share the same LOCK of the instance. So if one holds the LOCK, the other method could not run. So if EvenThread first invokes waitTurn method and wait for the turn change, it holds the LOCK, then OddThread could not enter the toggleTurn method and set the turn. This should lead to a deadlock as per my understanding. But it did not happen.
Can someone please explain why the deadlock did not happen?

"So IF EvenThread first run waitTurn method and wait for the turn change, it holds the LOCK, the OddThread could NOT enter the toggleTurn method"
It holds the LOCK only small period of time, until method wait() is invoked. Method wait() releases the LOCK and allows another thread to enter the critical section.

Related

how to implement wait,notify with threadexecutor in java

how to implement wait,notify with threadexecutor in java,Suppose I have two objeccts of threadExecutor and I want to perform wait,notify on that objecct can we implement that.
Here is an Example of using wait notify with ThreadExecutor in Java :
public class ExecutorServiceTest {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
ExecutorService executor = Executors.newFixedThreadPool(2);
ThreadB threadB = new ThreadB();
ThreadA threadA = new ThreadA(threadB);
executor.execute(threadA);
executor.execute(threadB);
executor.shutdown();
while (!executor.isTerminated());
System.out.println("Finished all threads");
}
static class ThreadA extends Thread {
private final ThreadB waitThread;
public ThreadA(ThreadB waitThread) {
this.waitThread = waitThread;
}
#Override
public void run() {
synchronized (waitThread) {
try {
waitThread.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("B Count Total : " + waitThread.getCount());
for (int i = waitThread.getCount(); i < 200; i++) {
System.out.println("A Counting " + i);
}
}
}
}
static class ThreadB extends Thread {
private int count = 0;
#Override
public void run() {
synchronized (this) {
while (count < 100) {
System.out.println("B Counting " + count);
count++;
}
notify();
}
}
public int getCount() {
return count;
}
}
}
synchronized
keyword is used for exclusive accessing.
To make a method synchronized, simply add the synchronized keyword to its declaration. Then no two invocations of synchronized methods on the same object can interleave with each other.
synchronized statements must specify the object that provides the intrinsic lock:
wait()
tells the calling thread to give up the monitor and go to sleep until some other thread enters the same monitor and calls notify( ).
notify()
wakes up the first thread that called wait() on the same object.

wait for N-1 out of N threads to end, then issue an instruction for the last thread

So, i apologize for the title. It's quite hard to explain in one sentence what i would like to do if you have no idea on how it is called.
So assume i can only use primitive thread functions (wait, notify, no concurrent package)
The program has 3 threads, all of them are the same and are called by the main thread. They behave normally until one of the three get an exception and so it must wait for the end of the remaining 2 threads in order to start a recovery process.
I was thinking about a static variable but I'm not really sure about it, i would love to keep it as simple as possible.
Each thread starts at the same time.
I don't see any reason why you can't use a static variable like you suggest. Here's how I would do it with an inner class...
private static boolean running = true;
public void test26546397() {
while (true) {
Thread t1 = new Thread(new MyRunnable());
Thread t2 = new Thread(new MyRunnable());
Thread t3 = new Thread(new MyRunnable());
t1.start();
t2.start();
t3.start();
try {
t1.join();
t2.join();
t3.join();
} catch (InterruptedException ex) {
ex.printStackTrace();
}
running = true;
// Do recovery
}
}
public class MyRunnable implements Runnable {
#Override
public void run() {
while (running) {
try {
// doStuff
} catch (Exception ex) {
running = false;
}
}
}
}
I would of course replace the while (true) with something a little more suitable.
I think you need java.concurrent.CountdownLatch, however if the java.concurrent package is not available to you can code this yourself using Object.wait/notify and synchronized blocks.
The latch can then be decremented in a finally {} on each Thread, this will be run if the Thread completes, or an exception occurs.
Your main program then just needs to wait for count to become 0.
public class StackOverflow26546397 {
static class CountdownLatch {
private int count;
private Object monitor = new Object();
public CountdownLatch(int count) {
this.count = count;
}
public void countDown() {
synchronized (monitor) {
count--;
monitor.notifyAll();
}
}
public void await() throws InterruptedException {
synchronized (monitor) {
while (count > 0) {
monitor.wait();
}
}
}
}
static class Job implements Runnable {
private CountdownLatch latch;
public Job(CountdownLatch latch) {
this.latch = latch;
}
#Override
public void run() {
try {
// do work.
Thread.sleep((long) (Math.random() * 3000d));
} catch (InterruptedException e) {
//
} finally {
latch.countDown();
}
}
}
public static void main(String[] args) throws InterruptedException {
CountdownLatch latch = new CountdownLatch(3);
new Thread(new Job(latch)).start();
new Thread(new Job(latch)).start();
new Thread(new Job(latch)).start();
latch.await();
System.out.println("All threads finished");
}
}
Not sure what you are trying to do but this is as simple as I can think of (just native concurrency):
Create a static or shared volatile boolean
private static volatile boolean exceptionOccured=false
Set the above to 'true' when exception occurs:
....}catch(Exception e){
exceptionOccured=true;
}
Check this periodically in you normal thread flow:
if (exceptionOccured)
//enter you synchronized call here
the synchronized method could look something like:
public synchronized void checkAndRecover(){
//decrement a counter or other logic to identify which is the last Thread and then
//perform any recovery logic
}

Java Thread synchronized Deadlock wait(); notifyAll();

Since you are using a Thread, the code further below might give results like:
waiting...One
waiting...Three
waiting...Two
Notified...Two
Notified...Three
Then the code is running until it hits a dead lock. Why is Notified...One missing in the output above? Needs explanation ... (You can get similar result as above when executing following code several time)
class A {
synchronized void waitThread(String threadName) {
System.out.println("waiting..." + threadName);
try {
wait();
} catch(InterruptedException e) { }
System.out.println("Notified..." + threadName);
}
synchronized void notifyThread() {
notifyAll();
}
}
class T1 extends Thread {
A a;
T1(A r, String n) {
a = r;
setName(n);
}
public void run() {
a.waitThread(getName());
}
}
class T2 extends Thread {
A a;
T2(A r, String n) {
a = r;
setName(n);
}
public void run() {
a.notifyThread();
}
}
public class DemoWait {
public static void main(String args[]) {
A a1 = new A();
T1 t1 = new T1(a1,"One");
T1 t2 = new T1(a1,"Two");
T1 t3 = new T1(a1,"Three");
t1.start();
t2.start();
t3.start();
T2 t = new T2(a1,"Four");
t.start();
}
}
You simply have a race condition. It's possible that the thread referenced by the variable t executes notifyAll() before the thread referenced by t1 executes the waitThread(..) method. This is not deadlock. Some of your waits just happen after your notifyAll().
You are facing the problem of Spurious wakeup.So what is happening that the thread which is notifying the all other thread might be call earlier of other thread and after that other thread will run and wait for the wake up.Because of spurious wake up some thread complete.
Change your code...
class A{
boolean flag=true;
synchronized void waitThread(String threadName){
System.out.println("waiting..."+threadName);
try{
while(flag){
wait();
}
}catch(InterruptedException e){ }
System.out.println("Notified..."+threadName);
}
synchronized void notifyThread(){
flag=false;
notifyAll();
} }

Printing "Hello" and "world" multiple times using two threads in java

Assume that one thread prints "Hello" and another prints "World". I have done it successfully for one time, as follows:
package threading;
public class InterThread {
public static void main(String[] args) {
MyThread mt=new MyThread();
mt.start();
synchronized(mt){
System.out.println("Hello");
try {
mt.wait();
i++;
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
class MyThread extends Thread{
public void run(){
synchronized(this){
System.out.println("World!");
notify();
}
}
}
How do I do it for multiple time printing, say for 5 times? I tried putting for loop around the synchronized block, but of no use.
Here being two interdependent threads, we need two synchronizing objects. they could be one of many things. one integer, another object; one Boolean another object; both object; both semaphores and so on. the synchronization technique could be either Monitor or Semaphore any way you like, but they have to be two.
I have modified your code to use semaphore instead of Monitor. The Semaphore works more transparently. You can see the acquire and release happening. Monitors are even higher constructs. Hence Synchronized works under the hood.
If you are comfortable with the following code, then you can convert it to use Monitors instead.
import java.util.concurrent.Semaphore;
public class MainClass {
static Semaphore hello = new Semaphore(1);
static Semaphore world = new Semaphore(0);
public static void main(String[] args) throws InterruptedException {
MyThread mt=new MyThread();
mt.hello = hello;
mt.world = world;
mt.start();
for (int i=0; i<5; i++) {
hello.acquire(); //wait for it
System.out.println("Hello");
world.release(); //go say world
}
}
}
class MyThread extends Thread{
Semaphore hello, world;
public void run(){
try {
for(int i = 0; i<5; i++) {
world.acquire(); // wait-for it
System.out.println(" World!");
hello.release(); // go say hello
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
public class ThreadSeq {
Object hello = new Object();
Object world = new Object();
public static void main(String[] args) throws InterruptedException {
for(int i=0; i<6;i++){
Runnable helloTask = new Runnable(){
#Override
public void run(){
new ThreadSeq().printHello();
}
};
Runnable worldTask = new Runnable(){
#Override
public void run(){
new ThreadSeq().printWorld();
}
};
Thread t1 = new Thread(helloTask);
Thread t2 = new Thread(worldTask);
t1.start();
t1.join();
t2.start();
t2.join();
}
}
public void printHello(){
synchronized (hello) {
System.out.println("Hello");
}
}
public void printWorld(){
synchronized (world) {
System.out.println("World");
}
}
}
The goal here is to synchronize threads so that when one is done it notify the other. If I have to make it, it would be 2 threads executing the same code with different data. Each thread has its own data ("Hello" and true to T1, "World" and false to t2), and share a variable turn plus a separate lock object.
while(/* I need to play*/){
synchronized(lock){
if(turn == myturn){
System.out.println(mymessage);
turn = !turn; //switch turns
lock.signal();
}
else{
lock.wait();
}
}
}
Before you start trying to get it to work five times you need to make sure it works once!
Your code is not guaranteed to always print Hello World! - the main thread could be interrupted before taking the lock of mt (note that locking on thread objects is generally not a good idea).
MyThread mt=new MyThread();
mt.start();
\\ interrupted here
synchronized(mt){
...
One approach, that will generalise to doing this many times, is to use an atomic boolean
import java.util.concurrent.atomic.AtomicBoolean;
public class InterThread {
public static void main(String[] args) {
int sayThisManyTimes = 5;
AtomicBoolean saidHello = new AtomicBoolean(false);
MyThread mt=new MyThread(sayThisManyTimes,saidHello);
mt.start();
for(int i=0;i<sayThisManyTimes;i++){
while(saidHello.get()){} // spin doing nothing!
System.out.println("Hello ");
saidHello.set(true);
}
}
}
class MyThread extends Thread{
private final int sayThisManyTimes;
private final AtomicBoolean saidHello;
public MyThread(int say, AtomicBoolean said){
super("MyThread");
sayThisManyTimes = say;
saidHello = said;
}
public void run(){
for(int i=0;i<sayThisManyTimes;i++){
while(!saidHello.get()){} // spin doing nothing!
System.out.println("World!");
saidHello.set(false);
}
}
}
This is in C:
#include <stdio.h>
#include <pthread.h>
pthread_mutex_t hello_lock, world_lock;
void printhello()
{
while(1) {
pthread_mutex_lock(&hello_lock);
printf("Hello ");
pthread_mutex_unlock(&world_lock);
}
}
void printworld()
{
while(1) {
pthread_mutex_lock(&world_lock);
printf("World ");
pthread_mutex_unlock(&hello_lock);
}
}
int main()
{
pthread_t helloThread, worldThread;
pthread_create(&helloThread,NULL,(void *)printhello,NULL);
pthread_create(&helloThread,NULL,(void *)printhello,NULL);
pthread_join(helloThread);
pthread_join(worldThread);
return 0;
}
There are two thread and both has its own data ("Hello" and true to ht, "World" and false to wt), and share a variable objturn.
public class HelloWorldBy2Thread {
public static void main(String[] args) {
PrintHelloWorld hw = new PrintHelloWorld();
HelloThread ht = new HelloThread(hw);
WorldThread wt = new WorldThread(hw);
ht.start();
wt.start();
}
}
public class HelloThread extends Thread {
private PrintHelloWorld phw;
private String hello;
public HelloThread(PrintHelloWorld hw) {
phw = hw;
hello = "Hello";
}
#Override
public void run(){
for(int i=0;i<10;i++)
phw.print(hello,true);
}
}
public class WorldThread extends Thread {
private PrintHelloWorld phw;
private String world;
public WorldThread(PrintHelloWorld hw) {
phw = hw;
world = "World";
}
#Override
public void run(){
for(int i=0;i<10;i++)
phw.print(world,false);
}
}
public class PrintHelloWorld {
private boolean objturn=true;
public synchronized void print(String str, boolean thturn){
while(objturn != thturn){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.print(str+" ");
objturn = ! thturn;
notify();
}
}
In simple way we can do this using wait() and notify() without creating any extra object.
public class MainHelloWorldThread {
public static void main(String[] args) {
HelloWorld helloWorld = new HelloWorld();
Thread t1 = new Thread(() -> {
try {
helloWorld.printHello();
} catch (InterruptedException e) {
e.printStackTrace();
}
});
Thread t2 = new Thread(() -> {
try {
helloWorld.printWorld();
} catch (InterruptedException e) {
e.printStackTrace();
}
});
// printHello() will be called first
t1.setPriority(Thread.MAX_PRIORITY);
t1.start();
t2.start();
}
}
class HelloWorld {
public void printHello() throws InterruptedException {
synchronized (this) {
// Infinite loop
while (true) {
// Sleep for 500ms
Thread.sleep(500);
System.out.print("Hello ");
wait();
// This thread will wait to call notify() from printWorld()
notify();
// This notify() will release lock on printWorld() thread
}
}
}
public void printWorld() throws InterruptedException {
synchronized (this) {
// Infinite loop
while (true) {
// Sleep for 100ms
Thread.sleep(100);
System.out.println("World");
notify();
// This notify() will release lock on printHello() thread
wait();
// This thread will wait to call notify() from printHello()
}
}
}
}

A good small example to demonstrate wait() and notify() method in java

Can anybody please provide me a good small example demonstrate wait() and notify() functionality in java. I've tried with the below piece of code but it's not showing what i expected.
public class WaitDemo {
int i = 10;
int display() {
System.out.println("Lexmark");
i++;
return i;
}
}
public class ClassDemo1 extends Thread {
private WaitDemo wd = new WaitDemo();
public static void main(String[] args) {
ClassDemo1 cd1 = new ClassDemo1();
ClassDemo1 cd2 = new ClassDemo1();
cd1.setName("Europe");
cd2.setName("America");
cd1.start();
cd2.start();
}
synchronized void display() {
System.out.println("Hello");
notifyAll();
}
public void run() {
synchronized (this) {
try {
{
notify();
System.out.println("The thread is " + currentThread().getName());
wait();
System.out.println("The value is " + wd.display());
}
} catch (InterruptedException e) {
}
}
}
}
The issue is that the method in the class WaitDemo is not getting executed and as per my idea the SOP after wait() should execute. Please help me out on this.
You've got two levels of braces { in your try block. If you remove the inner set (which doesn't appear to do anything), does that fix the problem?
There are several examples around, all of which demonstrate the use. The last link is a set of results that can help you out. If you need more specific things, let me know what it is that your app is trying to do, and I can try to find examples that are more specific to your situation.
http://www.javamex.com/tutorials/wait_notify_how_to.shtml
http://www.java-samples.com/showtutorial.php?tutorialid=306
http://www.coderanch.com/t/234235/threads/java/Wait-Example
https://www.google.com/search?q=wait%28%29+example+java&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a
Below is an example of wait & notify in the Object class. The customer is trying to withdraw money of value 2000 but the account is having only 1000 so it has to wait for the deposit. Once the deposit is made, then the customer will be able to withdraw the amount. Until the deposit is made, the customer will be waiting.
class Cust {
private int totalAmount = 1000;
public synchronized void withdrawal(int amount) {
System.out.println("Total amount " + totalAmount + " withdrawing amount " + amount);
while (this.totalAmount < amount) {
System.out.println("not enough amount..waiting for deposit..");
try { wait(); } catch (Exception e) {}
}
this.totalAmount -= amount;
System.out.println("Withdrawal successful.. Remaining balance is "+totalAmount);
}
public synchronized void deposit(int amount){
System.out.println("Depositing amount "+amount);
this.totalAmount += amount;
System.out.println("deposit completed...and Now totalAmount is " + this.totalAmount);
notify();
}
}
class Depo implements Runnable {
Cust c; int depo;
Depo(Cust c, int depo){
this.c = c;
this.depo = depo;
}
#Override
public void run() {
c.deposit(depo);
}
}
class Withdrawal implements Runnable {
Cust c; int with;
Withdrawal(Cust c, int with){
this.c = c;
this.with = with;
}
#Override
public void run() {
c.withdrawal(with);
}
}
public class ObjectWaitExample {
public static void main(String[] args) {
Cust c = new Cust();
Thread w = new Thread(new Withdrawal(c, 2000));
Thread d1 = new Thread(new Depo(c, 50));
Thread d2 = new Thread(new Depo(c, 150));
Thread d3 = new Thread(new Depo(c, 900));
w.start();
d1.start();
d2.start();
d3.start();
}
}
I created two threads one for printing odd numbers (OddThread) and another for even numbers (EvenThread). Inside the run method of each of the threads I used the shared object of class Print to call printOdd() and printEven() for the Odd and EvenThread respectively. I made the shared object of Print static so that only one copy is made. Now synchronizing on the Print object I used a Boolean flag such that when the odd thread printed an odd number it will be sent into the waiting state and the at the same time notifying the even thread to execute. The logic is written in such a way that the odd thread will always print the odd number first no matter what, as the flag is set to false initially preventing the even thread to execute and sending it to a waiting state.
package com.amardeep.test;
public class ThreadDemo {
// Shared object
static Print print = new Print();
public static void main(String[] args) {
new Thread(new OddThread()).start();
new Thread(new EvenThread()).start();
}
}
class EvenThread implements Runnable {
#Override
public void run() {
ThreadDemo.print.printEven();
}
}
class OddThread implements Runnable {
#Override
public void run() {
ThreadDemo.print.printOdd();
}
}
class Print {
public volatile boolean flag = false;
public synchronized void printEven() {
for (int i = 1; i <= 10; i++) {
if (!flag) {
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else {
if (i % 2 == 0) {
System.out.println("from even " + i);
flag = false;
notifyAll();
}
}
}
}
public synchronized void printOdd() {
for (int i = 1; i <= 10; i++) {
if (flag) {
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else {
if (i % 2 != 0) {
System.out.println("from odd " + i);
flag = true;
notifyAll();
}
}
}
}
}
output:-
from odd 1
from even 2
from odd 3
from even 4
from odd 5
from even 6
from odd 7
from even 8
from odd 9
from even 10
Your problem is that you are creating two instances of the Thread class. Thus when the wait() is called, it is on two different instances, neither of which has another thread that is in contention for your monitor, nor is there another thread to call notifyAll() to wake the thread from its wait state.
Thus each thread you have started will wait forever (or until interrupted for some other reason).
You want to have multiple threads accessing the same monitor, so start by trying to code something in which the code in question is not actually a thread, but is simply being used by a thread.
#normalocity has already provided links to multiple examples.
I just updated this answer to include an SCCE.
The workers call pauseIfNeeded on the WorkerPauseManager. If the manager is paused when the worker thread calls pauseIfNeeded(), we call wait(), which tells the calling thread to wait until a different thread calls notify() or notifyAll() on the object being waited on. This happens when the Swing Event Dispatch Thread calls play() on the manager, which in turn calls notifyAll().
Note that you must have a synchronized lock on the object you are calling wait() or notify() on. Since the methods in WorkerPauseManager are synchronized, all the synchronized methods are getting a synchronized lock on the WorkerPauseManager itself.
import javax.swing.*;
import java.awt.event.ActionEvent;
/**
* #author sbarnum
*/
public class WorkerPauseManagerTest {
public static void main(String[] args) {
final WorkerPauseManager pauseManager = new WorkerPauseManager();
new Worker("Worker 1", pauseManager).start();
new Worker("Worker 2", pauseManager).start();
SwingUtilities.invokeLater(new Runnable() {
public void run() {
JToggleButton playPauseButton = new JToggleButton(new AbstractAction("Pause") {
public void actionPerformed(final ActionEvent e) {
JToggleButton source = (JToggleButton) e.getSource();
if (source.isSelected()) {
pauseManager.start();
source.setText("Pause");
} else {
pauseManager.pause();
source.setText("Play");
}
}
});
playPauseButton.setSelected(true); // already running
JOptionPane.showMessageDialog(null, playPauseButton, "WorkerPauseManager Demo", JOptionPane.PLAIN_MESSAGE);
System.exit(0);
}
});
}
private static class Worker extends Thread {
final String name;
final WorkerPauseManager pauseManager;
public Worker(final String name, final WorkerPauseManager pauseManager) {
this.name = name;
this.pauseManager = pauseManager;
}
#Override
public void run() {
while (!Thread.interrupted()) {
try {
pauseManager.pauseIfNeeded();
System.out.println(name + " is running");
Thread.sleep(1000L);
} catch (InterruptedException e) {
throw new RuntimeException(e);
}
}
}
}
public static final class WorkerPauseManager {
private boolean paused;
public synchronized void pauseIfNeeded() throws InterruptedException {
if (paused) wait();
}
public synchronized void pause() {
this.paused = true;
}
public synchronized void start() {
this.paused = false;
notifyAll();
}
}
}
What wait method does is , when some thread executed a synchronized block by locking some object (we call that object is "a") , then inside that synchronized block when the thread executed the wait method of object "a" like this
A a = new A (); // some class object call "a"
synchronized (a){
a.wait ();//exceptions must be handled
}
Then the a object will release and the thread has to go to the wait state until it has been release from that state.
and anothet thread now can use the a object beacause its a release object. so if another thread locked that object and it executed the notify method from that object like
a.notify ()
Then one of a thread of the threads that went to wait state by object "a" can be released from the wait state. Other wise when call the notifyAll then the all the thread objects will release from that state.
/*
* the below program is like
* tread t1 will first run , and it comes to "notify()" method
* there are no threds waiting bcoz this is the first thread.
* so it will not invoke any other threads. next step is "wait()" method
*will be called and the thread t1 in waiting state. next stament
* "System.out.println("The value is ..."+wd.display());" will not be executed
* because thread t1 is in waiting state.
*
* thread t2 will run ,and it comes to "notify()" method ,there is already
* thread t1 is in waiting state ,then it will be invoked.now thread t1 will
* continue execution and it prints the statement "System.out.println("The value is ..."+wd.display())"
* and thread t2 will be in waiting state now.
*
* if you uncomment "notifyAll()" method then, after t1 thread completes its execution
*then immediately "notifyAll()" method will be called,by that time thread t2 is
* already in waiting state , then thread t2 will be invoked and continues execution.
*or
* if any other threadds are in waiting state all those threads will be invoked.
*/
package threadsex;
/**
*
* #author MaheshM
*/
/**
* #param args the command line arguments
*/
public class WaitNotifyNotifyAllDemo implements Runnable {
WaitDemo wd = new WaitDemo();
public static void main(String[] args) {
WaitNotifyNotifyAllDemo cd1 = new WaitNotifyNotifyAllDemo();
Thread t1 = new Thread(cd1);
t1.setName("mahi1");
Thread t2 = new Thread(cd1);
t2.setName("mahi2");
t1.start();
t2.start();
}
#Override
public void run() {
synchronized (this) {
try {
System.out.println("The thread is=" +
Thread.currentThread().getName());
notify();
wait();
System.out.println("The value is ..." + wd.display());
// notifyAll();
} catch (Exception ex) {
ex.printStackTrace();
}
}
}
}

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