Say i have a simple sentence as below.
For example, this is what have:
A simple sentence consists of only one clause. A compound sentence
consists of two or more independent clauses. A complex sentence has at
least one independent clause plus at least one dependent clause. A set
of words with no independent clause may be an incomplete sentence,
also called a sentence fragment.
I want only first 10 words in the sentence above.
I'm trying to produce the following string:
A simple sentence consists of only one clause. A compound
I tried this:
bigString.split(" " ,10).toString()
But it returns the same bigString wrapped with [] array.
Thanks in advance.
Assume bigString : String equals your text. First thing you want to do is split the string in single words.
String[] words = bigString.split(" ");
How many words do you like to extract?
int n = 10;
Put words together
String newString = "";
for (int i = 0; i < n; i++) { newString = newString + " " + words[i];}
System.out.println(newString);
Hope this is what you needed.
If you want to know more about regular expressions (i.e. to tell java where to split), see here: How to split a string in Java
If you use the split-Method with a limiter (yours is 10) it won't just give you the first 10 parts and stop but give you the first 9 parts and the 10th place of the array contains the rest of the input String. ToString concatenates all Strings from the array resulting in the whole input String. What you can do to achieve what you initially wanted is:
String[] myArray = bigString.split(" " ,11);
myArray[10] = ""; //setting the rest to an empty String
myArray.toString(); //This should give you now what you wanted but surrouned with array so just cut that off iterating the array instead of toString or something.
This will help you
String[] strings = Arrays.stream(bigstring.split(" "))
.limit(10)
.toArray(String[]::new);
Here is exactly what you want:
String[] result = new String[10];
// regex \s matches a whitespace character: [ \t\n\x0B\f\r]
String[] raw = bigString.split("\\s", 11);
// the last entry of raw array is the whole sentence, need to be trimmed.
System.arraycopy(raw, 0, result , 0, 10);
System.out.println(Arrays.toString(result));
how to remove multiple token from string array in java by split along with [ ]
String Order_Menu_Name= [pohe-7, puri-3];
String [] s2=Order_Menu_Name.split("-|,");
int j = 0;
//out.println("s2.length "+s2.length);
while(j<s2.length){ }
and expected output should be each value separate.
e,g pohe 7 puri 3
Your question is not clear. Assuming that your string contains "pohe-7, puri-3" you can split them using a separator such as "," or "-" or whitespace. See below.
String Order_Menu_Name= "[pohe-7, puri-3]";
To remove "[" and "]" from the above String. you can use Java's replace method as follow:
Order_Menu_Name = Order_Menu_Name.replace("[", "");
Order_Menu_Name = Order_Menu_Name.replace("]", "");
You can replace the above two lines with one using regex expression that matches [....] if you wish to.
After you removed the above characters then you can split your string as follow.
String[] chunks = Order_Menu_Name.split(",");
i = 0;
while(chunks.length) {
System.out.println(chunks[i]);
i++;
}
You can pass one or two params to the Java split() method, one being the regex expression that defines the pattern to be found and the second argument is limit, specifying how many chunks to return, see below:
public String[] split(String regex, int limit)
or
public String[] split(String regex)
For example
String Str = new String("Welcome-to-Stackoverflow.com");
for (String retval: Str.split("-", 3)){
System.out.println(retval);
}
When splitting the above Str using seperator "-" you should get 3 chunks of strings as follow:
Welcome
to
Stackoverflow.com
If you pass the split function a limit of 2 instead of three then you get the following:
Welcome
to-Stackoverflow.com
Notice above "to-Stckoverflow.com" is returned as is because we limited the chunks to 2.
I have string as [arun, joseph, sachin, kavin]. I want to replace this text as ["arun", "joseph", "sachin", "kavin"]. All the values should be in double quotes.
I have tried to do this using replace method. But i could not accomplish. Can anyone help me to resolve this?
Your question is a bit unclear. Do you want to turn a string containing
[arun, joseph, sachin, kavin]
into this string
["arun", "joseph", "sachin", "kavin"]
or do you want to turn it into an actual array containing "arun", "joseph", "sachin" and "kavin"?
Regardless, this is pretty basic string manipulation. Here's what I suggest you try:
Use substring to get rid of the first and last character.
Use split to split the string on ", ".
If you want to add '"' before and after each component in this array, you can do
for (int i = 0; i < array.length; i++)
array[i] = '"' + array[i] + '"';
You could try this,
replace [, ] with an empty string.
Then do splitting according to the comma.
Strings parts[] = string.replaceAll("^\\[|\\]$", "").split("\\s*,\\s*");
^\\[|\\]$ matches the [, ] present at the start and at the end.
replaceAll function then replaces the matched brackets with an empty string.
Then by splitting the resultant string according to
\s* -> zero or more spaces
, -> comma
\s* -> zero or more spaces
will give you the desired output.
I am trying to parse an input string like this
String input = "((1,2,3),(3,4,5),(2,3,4),...)"
with the aim of getting an array of String where each element is an inner set of integers i.e.
array[0] = (1,2,3)
array[1] = (3,4,5)
etc.
To this end I am first of all getting the inner sequence with this regex:
String inner = input.replaceAll("\\((.*)\\)","$1");
and it works. Now I'd like to get the sets and I am trying this
String sets = inner.replaceAll("((\\((.*)\\),?)+","$1")
But I can't get the result I expected. What am I doing wrong?
Don't use replaceAll to remove the parentheses at the ends. Rather use String#substring(). And then to get the individual elements, again rather than using replaceAll, you should use String#split().
String input = "((1,2,3),(3,4,5),(2,3,4))";
input = input.substring(1, input.length() - 1);
// split on commas followed by "(" and preceded by ")"
String[] array = input.split("(?<=\\)),(?=\\()");
System.out.println(Arrays.toString(array));
I have a string that looks like this:
0,0,1,2,4,5,3,4,6
What I want returned is a String[] that was split after every 3rd comma, so the result would look like this:
[ "0,0,1", "2,4,5", "3,4,6" ]
I have found similar functions but they don't split at n-th amount of commas.
NOTE: while solution using split may work (last test on Java 17) it is based on bug since look-ahead in Java should have obvious maximum length. This limitation should theoretically prevent us from using + but somehow \G at start lets us use + here. In the future this bug may be fixed which means that split will stop working.
Safer approach would be using Matcher#find like
String data = "0,0,1,2,4,5,3,4,6";
Pattern p = Pattern.compile("\\d+,\\d+,\\d+");//no look-ahead needed
Matcher m = p.matcher(data);
List<String> parts = new ArrayList<>();
while(m.find()){
parts.add(m.group());
}
String[] result = parts.toArray(new String[0]);
You can try to use split method with (?<=\\G\\d+,\\d+,\\d+), regex
Demo
String data = "0,0,1,2,4,5,3,4,6";
String[] array = data.split("(?<=\\G\\d+,\\d+,\\d+),"); //Magic :)
// to reveal magic see explanation below answer
for(String s : array){
System.out.println(s);
}
output:
0,0,1
2,4,5
3,4,6
Explanation
\\d means one digit, same as [0-9], like 0 or 3
\\d+ means one or more digits like 1 or 23
\\d+, means one or more digits with comma after it, like 1, or 234,
\\d+,\\d+,\\d+ will accept three numbers with commas between them like 12,3,456
\\G means last match, or if there is none (in case of first usage) start of the string
(?<=...), is positive look-behind which will match comma , that has also some string described in (?<=...) before it
(?<=\\G\\d+,\\d+,\\d+), so will try to find comma that has three numbers before it, and these numbers have aether start of the string before it (like ^0,0,1 in your example) or previously matched comma, like 2,4,5 and 3,4,6.
Also in case you want to use other characters then digits you can also use other set of characters like
\\w which will match alphabetic characters, digits and _
\\S everything that is not white space
[^,] everything that is not comma
... and so on. More info in Pattern documentation
By the way, this form will work with split on every 3rd, 5th, 7th, (and other odd numbers) comma, like split("(?<=\\G\\w+,\\w+,\\w+,\\w+,\\w+),") will split on every 5th comma.
To split on every 2nd, 4th, 6th, 8th (and rest of even numbers) comma you will need to replace + with {1,maxLengthOfNumber} like split("(?<=\\G\\w{1,3},\\w{1,3},\\w{1,3},\\w{1,3}),") to split on every 4th comma when numbers can have max 3 digits (0, 00, 12, 000, 123, 412, 999).
To split on every 2nd comma you can also use this regex split("(?<!\\G\\d+),") based on my previous answer
Obligatory Guava answer:
String input = "0,0,1,2,4,5,3,4,6";
String delimiter = ",";
int partitionSize = 3;
for (Iterable<String> iterable : Iterables.partition(Splitter.on(delimiter).split(s), partitionSize)) {
System.out.println(Joiner.on(delimiter).join(iterable));
}
Outputs:
0,0,1
2,4,5
3,4,6
Try something like the below:
public String[] mySplitIntoThree(String str)
{
String[] parts = str.split(",");
List<String> strList = new ArrayList<String>();
for(int x = 0; x < parts.length - 2; x = x+3)
{
String tmpStr = parts[x] + "," + parts[x+1] + "," + parts[x+2];
strList.add(tmpStr);
}
return strList.toArray(new String[strList.size()]);
}
(You may need to import java.util.ArrayList and java.util.List)
Nice one for the coding dojo! Here's my good old-fashioned C-style answer:
If we call the bits between commas 'parts', and the results that get split off 'substrings' then:
n is the amount of parts found so far,
i is the start of the next part,
startIndex the start of the current substring
Iterate over the parts, every third part: chop off a substring.
Add the leftover part at the end to the result when you run out of commas.
List<String> result = new ArrayList<String>();
int startIndex = 0;
int n = 0;
for (int i = x.indexOf(',') + 1; i > 0; i = x.indexOf(',', i) + 1, n++) {
if (n % 3 == 2) {
result.add(x.substring(startIndex, i - 1));
startIndex = i;
}
}
result.add(x.substring(startIndex));