How can I find the total sum for each two dimensional array row? I'm completely stuck...
public static void main(String[] args) {
int [][] grid = new int [10][10];
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[i].length; j++) {
grid[i][j] = (int)(Math.random()*99);
}
}
for(int i = 0; i < 10; i++) {
for(int j = 0; j < 10; j++) {
System.out.print("1.");
System.out.printf("%5d ", grid[i][j]);
}
System.out.println();
}
}
My current output is:
How can I show the total sum for each row in the end of the row and show column numbers
For the sum of a row, this should do. In a similar way within the i loop, if you need to count the column as well;
for(int i = 0; i < 10; i++) {
int jSum = 0;
for(int j = 0; j < 10; j++) {
jSum += grid[i][j];
System.out.print("1.");
System.out.printf("%5d ", grid[i][j]);
}
System.out.printf(" %5d", jSum);
System.out.println();
}
On the column numbering:
Either you just pust put a static print in the beginning (like print "1 2 3 4..."), or you put the following with the j loop:
if (i == 0) System.out.printf("%5d ", j); // only prints in first loop / row - print 1,2,3,4,5....
Related
I made 2D arrray which prints some random elements.
Now i need a method which calculates the sum of that elements but just elements below the main diagonal.
Here is my code...
class Init {
public static void main(String[] args) {
int n = 0;
int m = 0;
int aray[][];
Random random = new Random();
Scanner tastatura = new Scanner(System.in);
int[][] array = new int[n][m];
n = tastatura.nextInt();
m = tastatura.nextInt();
array = new int[n][m];
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array[i].length; j++) {
array[i][j] = random.nextInt(20);
}
}
for (int[] a : array) {
System.out.println(Arrays.toString(a));
}
}
}
I did it like this... Now i can sum, but when i try to multyply same numbers i am geting 0 Why is that?
Scanner scanner = new Scanner(System.in);
System.out.print("Unesite duzinu kolona i redova : ");
int rows = scanner.nextInt();
int columns = rows;
int[][] matrix = new int[rows][rows];
Random random = new Random();
System.out.println("Nasumicni/random brojevi su :");
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix[i].length; j++) {
matrix[i][j] = random.nextInt(20);
}
}
for (int[] a : matrix) {
System.out.println(Arrays.toString(a));
}
//here is the logic which sum those elements
int sum = 0;
for (int i = 1; i < rows; i++) {
for (int j = i - 1; j >= 0; j--) {
sum = sum + matrix[i][j];
}
}
System.out.println("\nMatrix is : ");
for (int i = 0; i < rows; i++) {
for (int j = 0; j < columns; j++) {
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
System.out.println("Proizvod elemenata ispod glavne dijagonale je: " + sum);
What about this?
int s = 0;
for(int i = 1; i < m; ++i)
for(int j = 0; j < i; ++j)
s += a[i][j];
This selectively loops through the elements below the main diagonal and sums them up, without looping through the entire matrix and making it lengthier.
The main diagonal of a matrix consists of those elements that lie on the diagonal that runs from top left to bottom right. But since you want those elements "below" the main diagonal, here is an algorithm I came up with for that.
int sum = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j < m; j++)
if (i == j && (i + 1 < n))
{
int temp = i + 1;
while (temp < n)
{
sum += arr[temp][j];
temp++;
}
}
Also, you declare int[][] array multiple times. You need to declare it only once, after you get the values for n and m.
for(i=0;i
for(j=0;j
{
if(j>i)
d1+=a[i][j];. // Above the diagon
else
if(i>j)
d2+=a[i][j];. // Below the diagonal
}
I'm stuck on how to find the sums of each column & row of Matrix in Java. I don't know how to find the result of column and row separately. Thank you in advance.
public static void main(String[] args) {
double [][] a = new double [2][3];
a[0][0] = 1;
a[0][1] = 2;
a[0][2] = 3;
a[1][0] = 4;
a[1][1] = 5;
a[1][2] = 6;
for (int i = 0; i < a.length; i++) {
String str = "";
for (int j = 0; j < a[i].length; j++) {
str += a[i][j] + "\t";
}
System.out.println(str);
}
// column sums
double[] b = new double[a[0].length];
// row sums
Use two nested loops:
for(int i = 0; i < b.length; i++) {
b[i] = 0;
for(int j = 0; j < a.length(); j++) {
b[i] += a[j][i];
}
}
You get the sum of a one-dimensional segment of a n-dimensional array, you will need to form a nested loop to iterate through n-dimensional array, with a loop for each dimension. At the deepest step of each iteration, once you are inside the inner-most nested loop, you can increment the total value by the value referenced at that particular point in iteration.
double[][] a = new double[2][3];
a[0][0] = 1;
a[0][1] = 2;
a[0][2] = 3;
a[1][0] = 4;
a[1][1] = 5;
a[1][2] = 6;
for (int row = 0; row < a.length; row++) {
for (int col = 0; col < a[row].length; col++) {
System.out.print(a[row][col] + "\t");
}
System.out.println("");
}
double[] rowTotals = new double[a.length];
double[] colTotals = new double[a[0].length];
for (int row = 0; row < a.length; row++) {
for (int col = 0; col < a[row].length; col++) {
rowTotals[row] += a[row][col];
colTotals[col] += a[row][col];
}
}
I notice in your question you wanted to find the row and column totals separately. If this is a must (I can't see why), you can simply duplicate the nested loop and dedicate one loop for column totals and one for row totals.
//Considering
// row1: 123
// row2: 456
List<Double> colsSum = new ArrayList<>(Collections.nCopies(a[0].length, 0.0));
List<Double> rowsSum = new ArrayList<>();
for(int i = 0; i < a.length; i++){
double row = 0;
for(int j = 0; j < a[i].length; j++){
row += a[i][j];
colsSum.set(j, colsSum.get(j) == 0 ? a[i][j]
: colsSum.get(j) + a[i][j]);
}
rowsSum.add(row);
}
I'm trying to fill a matrix vertically, but 1 row is missing. Can you help me ? There is the code. Maybe there is an easier way to fill a matrix verically, but i cant find it.
public static void main(String[]args){
Scanner input = new Scanner(System.in);
System.out.print("Enter the value of matrix: ");
int n = input.nextInt();
int [][] matrix = new int [n][n];
for (int i = 1; i < matrix.length; i++) {
matrix[0][i] = matrix[0][i -1] + n;
}
for(int i = 1; i < matrix.length; i++){
for (int j = 0; j < matrix.length; j++){
matrix[i][j] = matrix[i -1][j] + 1;
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
input.close();
}
Output:
Enter the value of matrix: 4
1 5 9 13
2 6 10 14
3 7 11 15
Your row is missing because you never printed it in your first loop (the one that is initializing your first line) - you should have a row of 0 4 10 12 at the beginning. But you could do it much easier with only one nested loop.
Try
public static void main(String[]args){
Scanner input = new Scanner(System.in);
System.out.print("Enter the value of matrix: ");
int n = input.nextInt();
int [][] matrix = new int [n][n];
matrix[0][0]=0; //you have forgotten the first value
for (int i = 1; i < matrix.length; i++) {
matrix[0][i] = matrix[0][i -1] + n;
//initializing the first line
}
for(int i = 1; i < matrix.length; i++){
for (int j = 0; j < matrix.length; j++){
matrix[i][j] = matrix[i -1][j] + 1;
}
// re-loop to display but this time start with i=0
for(int i = 0; i < matrix.length; i++){
for (int j = 0; j < matrix.length; j++){
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
input.close();
}
To fill a matrix vertically, you must loop through columns in the outer loop and through rows in the inner(nested) loop. For example:
for(int j = 0; j < matrix.length; j++) {
for(int i = 0; i < matrix.length; i++) {
matrix[i][j] = /* The value you want to fill */;
.../* Other stuff you wanna do */
}
}
There is an easier way of doing this:
keep a variable like count and iterate the matrix on columns first then rows:
int count = 1; // or 0 if you start with 0
int[][] a = new int[n][n];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++) {
a[j][i] = count; // notice j first then i
count++;
}
After that you can easly print out the values:
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
System.out.println(a[i][j]);
Here is what the shapes should look like :
Here is my code so far:
public class Diamonds {
public static void main(String[] args) {
for (int i = 1; i < 10; i += 2) {
for (int j = 0; j < 9 - i / 2; j++) {
System.out.print(" ");
}
for (int j = 0; j < i; j++) {
System.out.print("*");
}
System.out.print("\n");
}
for (int i = 7; i > 0; i -= 2) {
for (int j = 0; j < 9 - i / 2; j++) {
System.out.print(" ");
}
for (int j = 0; j < i; j++) {
System.out.print("*");
}
System.out.print("\n");
}
}
}
I am having trouble getting the second shape
In order to not spoil your fun with this problem, I will explain what you need to do without writing any code.
To get the second shape in there, you would need to add two additional nested for loops into each of the two "outer" loops that you already have.
Loops number three will produce a fixed number of spaces. Note that the distance between the right edge of the first shape and the left edge of the second shape is constant, so your third loops will be easy to code up.
Loops number four will loop like your first loop, but they would change places: the first inner loop from the first outer loop will be the forth inner loop in the second outer loop, and vice versa.
By examining the shape on the right, we can notice that for each N asterisks on the line in the left shape, the right one has 10 - N, so, taking your code and extending it, we can get:
public class Diamonds {
public static final String SPACE = " ";
public static void main(String[] args) {
for (int i = 1; i < 10; i += 2) {
for (int j = 0; j < 9 - i / 2; j++)
System.out.print(" ");
for (int j = 0; j < i; j++)
System.out.print("*");
System.out.print(SPACE);
for (int j = 0; j < 10 - i; j++)
System.out.print("*");
System.out.print("\n");
}
for (int i = 7; i > 0; i -= 2) {
for (int j = 0; j < 9 - i / 2; j++)
System.out.print(" ");
for (int j = 0; j < i; j++)
System.out.print("*");
System.out.print(SPACE);
for (int j = 0; j < 10 - i; j++)
System.out.print("*");
System.out.print("\n");
}
}
}
And if we extract some common code:
public class Diamonds {
public static final String SPACE = " ";
public static void main(String[] args) {
for (int i = 1; i < 10; i += 2) {
drawLine(i);
System.out.print("\n");
}
for (int i = 7; i > 0; i -= 2) {
drawLine(i);
System.out.print("\n");
}
}
private static void drawLine(int i) {
for (int j = 0; j < 9 - i / 2; j++)
System.out.print(" ");
for (int j = 0; j < i; j++)
System.out.print("*");
System.out.print(SPACE);
for (int j = 0; j < 10 - i; j++)
System.out.print("*");
}
}
public class ReverseDiamond {
public static void main(String[] ar) {
int rows = 10;
ReverseDiamond diamond = new ReverseDiamond();
for(int i = 0; i < rows; i++)
diamond.printLine(rows, i);
for(int i = rows - 2; i >= 0; i--)
diamond.printLine(rows, i);
}
private void printLine(int rows, int currRow) {
for(int space = 1; space <= currRow; space++)
System.out.print(" ");
for(int star = 1; star < 2 * (rows - currRow); star++)
System.out.print("*");
System.out.println();
}
}
You may like that :
public class Diamonds {
public static void main(String[] args) {
int totalStars = 9;
int rows = 9;
for (int r = 0,stars=-1,gap=totalStars; r < rows; r++ ) {
stars+= (r<=rows/2) ?2:-2;
gap=totalStars-stars;
printChars(' ', gap);
printChars('*', stars);
printChars(' ', gap);
int gap2=stars+1;
int stars2=gap+1;
printChars(' ', gap2);
printChars('*', stars2);
printChars(' ', gap2);
System.out.println();
}
}
private static void printChars(char c ,int times) {
for (int i = 0; i < times; i++) {
System.out.print(c);
}
}
}
try this :
public static void main(String[] args) {
for (int i = 9; i > 0; i -= 2) {
for (int j = 0; j < 9 - i / 2; j++)
System.out.print(" ");
for (int j = 0; j < i; j++)
System.out.print("*");
System.out.print("\n");
}
for (int i = 2; i < 10; i += 2) {
for (int j = 0; j < 9 - i / 2; j++)
System.out.print(" ");
for (int j = 0; j <= i; j++)
System.out.print("*");
System.out.print("\n");
}
}
output :
*********
*******
*****
***
*
***
*****
*******
*********
My professor wants me to print out the matrices side by side with the "+" between the two matrices and then a "=" sign. In the end he wants us to add the matrices together.
This is the work so far.
So the result would come out as:
1 2 3 9 8 7 10 10 10
4 5 6 + 6 5 4 = 10 10 10
7 8 9 3 2 1 10 10 10
enter code here public static void main(String[] args) {
int matrix1[][] = {{1,2,3},{4,5,6},{6,7,8}};
int matrix2[][] = {{9,8,7},{6,5,4},{3,2,1}};
int result1;
int[][] result2 = new int[2][3];
for (int i = 0; i < matrix1.length; i++) {
for (int j = 0; j < matrix1[0].length; j++) {
System.out.printf(matrix1[i][j] + " ");
System.out.print("");
}
System.out.println("");
}
for (int i = 0; i < matrix2.length; i++) {
for (int j = 0; j < matrix2[0].length; j++) {
System.out.printf(matrix2[i][j] + " ");
}
System.out.println("");
}
}
My problem is, how could I print it side by side with the solutions?
Consider the two printing loops for your matrices:
for (int i = 0; i < matrix1.length; i++) {
for (int j = 0; j < matrix1[0].length; j++) {
System.out.printf(matrix1[i][j] + " ");
}
System.out.println("");
}
for (int i = 0; i < matrix2.length; i++) {
for (int j = 0; j < matrix2[0].length; j++) {
System.out.printf(matrix2[i][j] + " ");
}
System.out.println("");
}
They print matrix 1, then 2 - and so the matrices will be below each other.
If you want the matrices side by side, you need to print line 1 of every matrix, then - after a new line - line 2 of every matrix, etc. By re-arranging how the loops go through the matrices, you could have your new layout.
You unfortunately cannot print them one at a time, you need to take it row by row. This solution requires both matrix1 and matrix2 to be of equal height. But here's a template that should get you started.
for (int i = 0; i < matrix1.length; i++) {
for (int j = 0; j < matrix1[i].length; j++) {
}
if (i == matrix1/2) {
} else { //One part of if handles when "+" is needed, other one doesn't
}
for (int j = 0; j < matrix2[i].length; j++) {
}
if (i == matrix1/2) {
}
for (int j = 0; j < ???; j++) {
}
}