I want to read a number from the user and then sum the last seven digits of the entered number. What is the best way to do this? This is my code, but unfortunately it does not work:
class ersteAufgabe {
public static void main (String[] args)
{
Scanner s = new Scanner(System.in);
double [] a = new double[10];
for (int i = 0;i<10;i++)
{
a[i]=s.nextInt();
}
s.close();
System.out.println(a[0]);
}
}
I wanted only one number to be read and used as an array. Only now he expects 10 inputs from me.
public static int lastDigitsSum(int total) {
try (Scanner scan = new Scanner(System.in)) {
String str = scan.next();
int count = 0;
for (int i = str.length() - 1, j = 0; i >= 0 && j < total; i--, j++) {
if (Character.isDigit(str.charAt(i)))
count += str.charAt(i) - '0';
else
throw new RuntimeException("Input is not a number: " + str);
}
return count;
}
}
First you have to recognize if the entered value is a number and has at least 7 digits. Unless you have to output an error message. Convert the entered value to String and use the class Character.isDigit(); to check if the characters are numbers. Then you can use some methods from the String class like substring(..). At the end do a Unit-Test with erroneous/valid values to see if your code is robust. Close the BufferedReader and Resources when you are done by using finally { br.close() }. Push your code in methods and use an instance class erste-Aufgabe (first exercise).. When you are really really done use JFrame for a GUI-Application.
private static final int SUM_LAST_DIGITS = 7;
public void minimalSolution() {
String enteredValue = "";
showInfoMessage("Please enter your number with at least " + SUM_LAST_DIGITS + " digits!");
try (Scanner scan = new Scanner(System.in)) {
enteredValue = scan.next();
if (enteredValue.matches("^[0-9]{" + SUM_LAST_DIGITS + ",}$")) {
showInfoMessage(enteredValue, lastDigitsSum(enteredValue));
} else {
showErrorMessage(enteredValue);
}
} catch(Exception e) {
showErrorMessage(e.toString());
}
}
public int lastDigitsSum(String value) {
int count = 0;
for (int i = value.length() - 1, j = 0; i >= 0 && j < SUM_LAST_DIGITS; i--, j++)
count += value.charAt(i) - '0';
return count;
}
public void showInfoMessage(String parMessage) {
System.out.println(parMessage);
}
public void showInfoMessage(String parValue, int parSum) {
System.out.println("Your entered value: [" + parValue + "]");
System.out.println("The summed value of the last 7 digits are: [" + parSum + "]");
}
public void showErrorMessage(String parValue) {
System.err.println("Your entered value: [" + parValue + "] is not a valid number!");
}
How can I fill a 3x3 matrix using a 2D array such that the user picks what
position of the array they want to input their String value?
The position format is: (Row Number, Column Number)
For example:
Person 1, please pick where to place an X: (0,1)
Person 2, please pick where to place an O: (0,2)
This is what I have:
import java.util.Scanner;
public class idk {
public static void main(String[] args)
{
int i;
int j;
int arr[][] = new int[3][3];
// Getting user input
Scanner input = new Scanner(System.in);
System.out.println("Enter a number: ");
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
arr[i][j] = input.nextInt();
}
}
// Outputting the user input
System.out.println("The output is: ");
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
System.out.printf("%d ", arr[i][j]);
}
}
}
}
Something like the following has most of the parts you would want, except for error handling. Input is number, space (or any whitespace), finally followed by another number. Input numbers are 1 to 3 inclusive, which is what a normal person would expect.
import java.util.Scanner;
public class TicTacToe {
char board[][] = new char[][]{{'-','-','-'},{'-','-','-'},{'-','-','-'}};
public static void main(String[] args) {
TicTacToe ttt = new TicTacToe();
ttt.run();
}
public void run() {
Scanner input = new Scanner(System.in);
int row = -1, col = -1;//just to initialize
char symbol = 'o';
while (true) {
symbol = (symbol == 'x')?'o':'x';
boolean error = false;
System.out.println("Enter a number: ");
if (input.hasNext()) {
row = input.nextInt();
System.out.println("row: " + row);
} else {
error = true;
}
if (input.hasNext()) {
col = input.nextInt();
System.out.println("col: " + col);
} else {
error = true;
}
if (!error) {
board[row - 1][col - 1] = symbol;
}else{
System.out.println("an error has occurred");
}
input.reset();
this.drawBoard();
}
}
public void drawBoard() {
System.out.println("The output is: ");
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
System.out.printf("%c ", board[i][j]);
}
System.out.println();
}
System.out.println();
}
}
If you look up Scanner you will see an example to parse using a regex, I like that method better since with a regex you can validate the whole string at once but since that was not in the questions code I didn't use that method.
Simply
arr[Row Number][Column Number]=X;
eg
arr[0][1]=X;
or
arr[1][0]=O;
but because it is an int array you cannot place String i.e "O" and "X" in it.
Try making it an String array
Question
Given a string S of length N, that is indexed from 0 to N-1, print it's even indexed and odd indexed characters as 2 space separated strings on a single line.
Assume input starts at index position 0(which is considered even)
Input
The first line contains an integer, T (the number of test cases).
Each line i of the T subsequent lines contain a String, S.
Output
For each string S, print it's even-indexed characters, followed by space, followed by odd-indexed characters.
Sample Input
2
Hacker
Rank
Sample Output
Hce akr
Rn ak
The Code I Wrote
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
int T = scan.nextInt();
scan.nextLine();
for(int i=0 ; i<T ; i++)
{
String myString = scan.nextLine();
int evn = 0,
odd = 0,
len = myString.length();
char strE[] = new char[50],
strO[] = new char[50];
for(int j=0 ; j<len ; j++)
{
if(j%2 == 0)
{
strE[evn] = myString.charAt(j);
evn++;
}
if(j%2 == 1)
{
strO[odd] = myString.charAt(j);
odd++;
}
}
System.out.print(strE);
System.out.print(" ");
System.out.println(strO);
}
}
My Output
Hce akr
Rn ak
The Problem
As you can see, my program successfully meets the test case, and other test cases (using custom input) but every time the HackerRank compiler tells me that my program did not meet the test case.
Clearly, my program is producing the required output but every time the HackerRank compiler tells me that I got the solution wrong.
Could anyone please tell me where I am making a mistake?
Further Modifications
I then decided to change the last 3 lines of print statements into one statement as follows:
System.out.println(strE + " " + strO);
However, this time the program did not produce the desired output and rather printed some garbage values as follows:
[C#5c3f3b9b [C#3b626c6d
[C#3abc8690 [C#2f267610
My Doubts
1. In the first case, when I was printing the two strings separately using 2 print statements, I was getting a correct output everytime but the HackerRank compiler rejected it. Why?
2. In the second case, when I modified the program by using one print statement instead of 3 to get the desired result, the program gave a completely different output and rather printed garbage values! Why?
Here is a link to the HackerRank problem for more info:
hackerrank.com/challenges/30-review-loop
All help and guidance is greatly appreciated and thanks a lot in advance!
Try to submit this:
Scanner scan = new Scanner(System.in);
int T = scan.nextInt();
scan.nextLine();
for (int i = 0; i < T; i++) {
String myString = scan.nextLine();
String even = "";
String odd = "";
for (int j = 0; j < myString.length(); j++) {
if (j % 2 == 0) {
even += myString.charAt(j);
} else {
odd += myString.charAt(j);
}
}
System.out.println(even + " " + odd);
}
i get the right output and it should meet all the requirements. i think your code fails because its not a real string you print in the end and you have empty spots in your arrays
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the no.of test-cases:");
int t = scanner.nextInt();
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the String(s)");
for (int i = 0; i < t; i++) {
String myString = br.readLine();
String even = "";
String odd = "";
for (int j = 0; j < myString.length(); j++) {
if (j % 2 == 0) {
even += myString.charAt(j);
} else {
odd += myString.charAt(j);
}
}
System.out.println(even);
System.out.println(odd);
}
scanner.close();
int T = scan.nextInt();
This reads quantity of test cases, which we're going to process.
String string[] = new String[T];
for(int i = 0; i<T; i++){
string[i] = scan.next();
}
Next we're creating an array named "string" (BTW, this a bad name for variables/objects) which has size T and in the for loop reading test cases from the input T times and saving them in the array.
for(int temp = 0; temp<T; temp++){
Now, for each of test cases we do the following...
for(int j = 0; j<string[temp].length(); j = j+2)
{
System.out.print(string[temp].charAt(j));
}
We create a local variable j, which is visible only in this for loop. j holds index of the string (=string[temp]), which we're processing. So, we're printing a character on position j (by using standard method "charAt" of String class, which returns character of given index of the string) and then increasing it by 2. So, this code will print every even character. For string "example", it will print "eape" (j=0, j=2, j=4, j=6).
System.out.print(" ");
Separating sequences with a space.
for(int j = 1; j<string[temp].length(); j = j+2){
System.out.print(string[temp].charAt(j));
}
System.out.println();
We're doing the same (creating index j, running though all characters of the string), but starting from "1", so it will print all odd characters of the string. For string "example", it will give you "xml" (j=1, j=3, j=5). and After this, it will end the string. I hope, it will help you to understand. :)
I can solve your the second question:
---> System.out.print(strE);-->At the bottom, the method is called( public void print(char s[]));
-->System.out.println(strE + " " + strO);-->At the bottom, the method is called (public void println(String x) )
For your first answer I am unable to answer you as I have no idea about how the compiler works, but I can answer your second question.
The reason why System.out.print(strE); System.out.print(" "); System.out.println(strO); works is because System.out.print(char[]) and System.out.println(char[]) automatically turn the char arrays into a readable string before printing it.
However, in the second case System.out.println(strE + " " + strO);, what you are doing is directly turning the char array into strings, which just prints the class and the hash code of the array object because the toString() method is not overriden in the array class. What you want to do is System.out.println(new String(strE) + " " + new String(strO));. It will give you the result you want.
import java.io.*;
import java.util.*;
public class Solution {
private static void f(String s) {
// TODO Auto-generated method stub
char c[]=s.toCharArray();
int i,j;
for (i = 0; i <c.length;i++){
System.out.print(c[i]);
i+=1;
}
System.out.print(" ");
for (j = 1; j<c.length;j++){
System.out.print(c[j]);
j+=1;
}
}
public static void main(String[] args){
// TODO Auto-generated method stub
Scanner sc=new Scanner(System.in);
int s=sc.nextInt();
while(hasNext()){
//for loop for multiple strings as per the input
for(int m=0;m<= s;m++){
String s1=sc.next();
f(s1);
System.out.println();
}
}
}
}
I've solved this question in 2 ways & both are producing correct output.
Have a look & let me know if you've any problem.
Instead of using char array, you can use String
//char[] even = new char[10000];
String even = "";
Let's look at the code
private static Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
String s = scanner.next();
char[] array = s.toCharArray();
int count=0;
//char[] even = new char[10000];
//char[] odd = new char[10000];
String even = "";
String odd = "";
for(char ch : array){
if(count%2 == 0){
even = even + ch;
}else{
odd = odd + ch;
}
count++;
}
count = 0;
System.out.println(even + " " + odd);
}
Output:
hacker
hce akr
No need of extra char[] or String to store even & odd position characters, we can directly print them using appropriate condition.
private static Scanner scanner = new Scanner(System.in);
public static void main(String[] args){
String s = scanner.next();
char[] array = s.toCharArray();
int count=0;
for(char ch : array){
if(count%2 == 0){
System.out.print(ch);
}
count++;
}
count = 0;
System.out.print(" ");
for(char ch : array){
if(count%2 != 0){
System.out.print(ch);
}
count++;
}
count = 0;
}
Output:
hacker
hce akr
Try this:
public static void main(String[] args) {
System.out.println("Enter string to check:");
Scanner scan = new Scanner(System.in);
String T = scan.nextLine();
String even = "";
String odd = "";
for (int j = 0; j < T.length(); j++) {
if (j % 2 == 0) { //check the position of the alphabet by dividing it by 0
even += T.charAt(j);
} else {
odd += T.charAt(j);
}
}
System.out.println(even + " " + odd);
scan.close();
}
** JavaScript version **
function processData(input) {
for (let i = 1; i < input.length; i++) {
printOutput(input[i]);
}
}
function printOutput(input) {
var result = [];
input.length % 2 == 0 ? result[input.length / 2] = ' ': result[Math.ceil(input.length / 2)] = ' ';
for (let i = 0; i < input.length; i++) {
if (i % 2 == 0) {
result[i / 2] = input[i];
}
else {
result[Math.ceil(input.length / 2) + Math.ceil(i / 2)] = input[i];
}
}
console.log(result.join(''));
}
process.stdin.on("end", function () {
processData(_input.split('\n'));
});
import java.io. * ;
import java.util. * ;
public class Solution {
String myString;
public Solution(String myString) {
this.myString = myString;
int len = myString.length();
for (int j = 0; j < len; j++) {
if (j % 2 == 0) {
System.out.print(myString.charAt(j));
}
}
System.out.print(" ");
for (int j = 0; j < len; j++) {
if (j % 2 == 1) {
System.out.print(myString.charAt(j));
}
}
}
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner sc = new Scanner(System. in );
int T = sc.nextInt();
for (int i = 0; i < T; i++) {
String word = sc.next();
Solution sol = new Solution(word);
System.out.println();
}
sc.close();
}
}
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int T;
T = s.nextInt();
String[] str = new String[T];
int i;
for(i=0;i<T;i++) {
str[i] = s.next();
}
for(i=0;i<T;i++) {
char[] even = new char[5000];
char[] odd = new char[5000];
int ev =0,od=0;
for(int j= 0;j< str[i].length();j++) {
if(j%2== 0) {
even[ev] = str[i].charAt(j);
ev++;
}else {
odd[od] = str[i].charAt(j);
od++;
}
}
String strEven = new String(even);
String strOdd = new String(odd);
System.out.print(strEven.trim());
System.out.print(" ");
System.out.println(strOdd.trim());
}
s.close();
}
}
I am sure that this will work You've forgotten to convert it to a string and also increase the size of the character array
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner scan= new Scanner(System.in);
int n= scan.nextInt();
for(int i=0;i<n;i++){
String s= scan.next();
int len= s.length();
StringBuffer str_e= new StringBuffer();
StringBuffer str_o= new StringBuffer();
for(int j=0;j<len;j++){
if(j%2==0)
str_e= str_e.append(s.charAt(j));
if(j%2==1)
str_o= str_o.append(s.charAt(j));
}
System.out.println(str_e+" "+str_o);
}
}
}
Try this:
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner pp=new Scanner(System.in);
int n=pp.nextInt();
for(int i=0; i<n; i++)
{
String ip=pp.next();
String re1="",
re2="";
for(int j=0; j<ip.length(); j++)
{
if(j%2 == 0)
{
re1+= ip.charAt(j);
}
if(j%2 == 1)
{
re2+= ip.charAt(j);
}
}
System.out.print(re1+" "+re2);
System.out.println("");
}
}
}
public class PrintCharacters{
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int noOfTestCases = sc.nextInt();
sc.nextLine();
String []inputStrings= new String[noOfTestCases];
for(int i=0;i<noOfTestCases;i++) {
inputStrings[i]=sc.nextLine();
}
for(String str: inputStrings) {
String even ="";
String odd ="";
for(int i=0;i<str.length();i++) {
if(i%2==0) {
even+=str.charAt(i);
}else {
odd+=str.charAt(i);
}
}
System.out.println(even+" "+odd);
}
sc.close();
}
}
Input:
2
Hacker
Rank
Output:
Hce akr
Rn ak
import java.util.*;
public class Solution {
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner scan=new Scanner(System.in);
int n=scan.nextInt();
while(n>0) {
String str=scan.next();
for(int i=0;i<str.length();i++) {
if(i%2==0) {
System.out.print(str.charAt(i));
}
}
System.out.print(" ");
for(int i=0;i<str.length();i++) {
if(i%2==1) {
System.out.print(str.charAt(i));
}
}
n--;
System.out.println();
}
}
}
I am a beginner with weak understanding of java. Please could you help me correct the error saying:
// [line 45] Syntax error on token " (", ; expected
On the line:
private static int countWords(String str) {
This error appears twice on this line. I've tried experimenting with adding and deleting brackets and I've tried adding ';' to my code but it only makes the code display more errors. Underneath there is my code to help identify the error better:
import java.util.*;
public class HDtest9 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (true) { // have created infinite loop
System.out.print("Enter text: ");
String sentence = in.nextLine();
System.out.println("You have entered: " + sentence); // to Print string
System.out.println("The total number of characters is " + sentence.length()); // to print Entered string's length
System.out.println("This piece of text has " + countWords(sentence) + " words.");
if (sentence.equals("quit")) { // if enterd value is "quit" than it comes out of loop
break;
} else {
String[] words = sentence.split(" "); // get the individual words
int maxWordLength = 0;
int wordLength = 0;
for (int i = 0; i < array.length; i++) {
wordLength = array[i].length();
if (wordLength > maxWordLength) {
maxWordLength = wordLength;
}
int[] intArray = new int[maxWordLength + 1];
for (int i = 0; i < array.length; i++) {
intArray[array[i].length()]++;
for (int i = 1; i < intArray.length; i++) {
out.printf("%d word(s) of length %d<br>", intArray[i], i);
}
}
for (int i = 0; i < words.length; i++)
System.out.println( "word " + i + ": " + words[i] + " = " + words[i].length() + " characters");
}
}
in.close();
}
private static int countWords(String str) {
String words[] = str.split(" ");
int count = words.length;
return count;
}
}
}
Thank you very much for any help, it's much appreciated!
You are trying to declare your countWords() method inside your main() method, which isn't legal in Java, so the compiler is choking trying to parse your method signature.
If you move it outside where it belongs, you will only have the other 8 or so undeclared and duplicate variable errors left to deal with.
Please use proper indentation and naming in your code. It will help you (and others) read it, and prevent this sort of mistake.
On the line:
for (int i = 0; i < words.length; i++)
You have no opening curly brace
Change to:
for (int i = 0; i < words.length; i++) {
Also, please fix your indentation, it is very hard to read and see if there are any more bugs.
Corrected and working code
import java.util.*;
public class HDtest9 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (true) { // have created infinite loop
System.out.print("Enter text: ");
String sentence = in.nextLine();
System.out.println("You have entered: " + sentence); // to Print string
System.out.println("The total number of characters is " + sentence.length()); // to print Entered string's length
System.out.println("This piece of text has " + countWords(sentence) + " words.");
if (sentence.equals("quit")) { // if enterd value is "quit" than it comes out of loop
break;
} else {
String[] words = sentence.split(" "); // get the individual words
int maxWordLength = 0;
int wordLength = 0;
for (int i = 0; i < words.length; i++) {
wordLength = words[i].length();
if (wordLength > maxWordLength) {
maxWordLength = wordLength;
}
}
int[] intArray = new int[maxWordLength + 1];
for (int i = 0; i < words.length; i++) {
intArray[words[i].length()]++;
}
for (int i = 1; i < intArray.length; i++) {
System.out.printf("%d word(s) of length %d<br>", intArray[i], i);
}
for (int i = 0; i < words.length; i++) {
System.out.println("word " + i + ": " + words[i] + " = " + words[i].length() + " characters");
}
}
}
in.close();
}
private static int countWords(String str) {
String words[] = str.split(" ");
int count = words.length;
return count;
}
}
I have my code for this task mostly done, just can't figure out what is causing the the output to be incorrect. The desired output when using say, 3 and A for the values, should return this:
A
AA
AAA
currently, I'm getting:
AAA
AAA
AAA
code:
import static java.lang.System.*;
public class TriangleThree
{
private int size;
private String letter;
public TriangleThree()
{
}
public TriangleThree(int count, String let)
{
size = count;
letter = let;
}
public void setTriangle( String let, int sz )
{
size = sz;
letter = let;
}
public String getLetter()
{
return letter;
}
public String toString()
{
String output="";
for(int i = 1; i<=size; i++)
{
for(int j = 0; j > i;j++ )
{
output = output + " ";
}
for(int k = size; k>0; k--)
{
output = output + letter;
}
output= output + "\n";
}
return output+"\n";
}
}
and for cross-referencing it with my runner class:
import static java.lang.System.*;
import java.util.Scanner;
public class Lab11c
{
public static void main( String args[] )
{
Scanner keyboard = new Scanner(System.in);
String choice="";
do{
out.print("Enter the size of the triangle : ");
int big = keyboard.nextInt();
out.print("Enter a letter : ");
String value = keyboard.next();
//instantiate a TriangleThree object
TriangleThree tt = new TriangleThree( big, value );
//call the toString method to print the triangle
System.out.println( tt );
System.out.print("Do you want to enter more data? ");
choice=keyboard.next();
}while(choice.equals("Y")||choice.equals("y"));
}
}
You are running your 2nd for loop 3 times (All from size to 0). Change it to: -
for(int k = i; k>0; k--)
{
output = output + letter;
}
This will run 1 time for i = 1, 2 times for i = 2, ...
Also, there is a problem with your first loop: -
for(int j = 0; j > i;j++ )
this should really be: -
for(int j = 0; j < i;j++ )
UPDATE : -
Actually you don't need your first loop, as it is just printing spaces. Rather add spaces to your output in the 2nd loop only: -
for(int k = i; k>0; k--)
{
output = output + letter + " ";
}