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Need help shifting latin square in Java

I'm currently making a latin square that starts with a user-set number but for simplicity's sake I'll exclude Scanner code.
public static void main(String[] args){
int first = 2; // starting integer on square
int order = 4; //max integer
String space = new String(" ");
for (int row = 0; row < order; row++)
{
for (int column = 0; column < order; column++)
{
for (int shift = 0; shift < order; shift++)
{
int square = ((column+(first-1)) % order + 1); //this makes a basic square with no shifting
int latin = square+shift; //this is where my code becomes a mess
System.out.print(latin + space);
}
System.out.println();
}
}
}
}
Which prints out:
2 3 4 5
3 4 5 6
4 5 6 7
1 2 3 4
2 3 4 5
3 4 5 6
4 5 6 7
1 2 3 4
It's so close, considering the fact that it does start with my pre-determined first digit and it's printing only 4 integers.
The problem I'm running into is the fact that it's going further than my order integer and that it's printing double the rows.
Any idea what I can do to fix this?
For reference, this is what I want it to print:
2 3 4 1
3 4 1 2
4 1 2 3
1 2 3 4

It seems that the innermost loop for (int shift...) is redundant and it causes duplication of the output, the latin value should be calculated using row parameter:
public static void main(String args[]) {
int first = 2; // starting integer on square
int order = 4; //max integer
String space = " ";
for (int row = 0; row < order; row++) {
for (int column = 0; column < order; column++) {
int latin = (row + column + first - 1) % order + 1;
System.out.print(latin + space);
}
System.out.println();
}
}
Output:
2 3 4 1
3 4 1 2
4 1 2 3
1 2 3 4

How do i fix the angle of my mathematical triangle of squares?

I need to fix my output as shown at the bottom, i have code that outputs the correct math values
but it does not output the correct angle that is expected of the example output that i have provided below. ( I know this is pretty simple for most of you stack users but im a beginner in java and this is something that confuses me ). I have not come up with any ideas on what i can do to fix this issue and put in the correct angle.
Instructions:
-Write a program using a Scanner that asks the user for a number
n between 1 and 9 (inclusive).
-The program prints a triangle with n rows.
-The first row contains only the square of 1, and it is right-justified.
-The second row contains the square of 2 followed by the square of 1,
and is right justified.
-Subsequent rows include the squares of 3, 2, and 1, and then 4, 3, 2
and 1, and so forth until n rows are printed.
Assuming the user enters 4, the program prints the following triangle to the console
1
4 1
9 4 1
16 9 4 1
Code:
import java.util.Scanner;
public class Triangle {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter a number between 1 and 9 inclusive:");
int n = scan.nextInt();
for (int i = 1 ; i <=n; i++) {
for (int j = n-i; j >=1; j--) {
System.out.print("");
}
for (int k = i; k <= n; k++ ) {
System.out.print(" " + i * i);
}
System.out.println(" ");
}
scan.close();
}
}
My output:
Please enter a number between 1 and 9 inclusive: 4
1 1 1 1
4 4 4
9 9
16

Here is a short and simple variant.
for (int row = 1; row <= n; row ++) {
for (int col = n; col >= 1; col--) {
if (col <= row) {
System.out.print(String.format("%2d ", col * col));
} else {
System.out.print(" ");
}
}
System.out.println();
}
Here is the output generated for input 9:
1
4 1
9 4 1
16 9 4 1
25 16 9 4 1
36 25 16 9 4 1
49 36 25 16 9 4 1
64 49 36 25 16 9 4 1
81 64 49 36 25 16 9 4 1

TL;DR; Use a pen and paper for annoying logic problems.
The easiest way to do a problem like this is to write out the locations you're printing in terms of the variables you are iterating through. An extra variable, col helps us keep track of the current column opposite of the direction we are iterating from.
We can notice that the number just corresponds to the column position, squared, if we were counting columns from right to left.
We can also notice that the number of blank spaces is equal to n - one less than the current row iteration (since that starts at 0).
1
4 1
9 4 1
16 9 4 1
All of that nonsense aside, we can use String.format() to make the output even for double digit numbers.
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter a number between 1 and 9 inclusive:");
int n = scan.nextInt();
for (int i = n; i > 0; i--) {
int col = 4;
// Print spaces
for (int j = 0; j < (i-1); j++) {
System.out.print(" ");
col--;
}
// Print numbers
for (int j = (i-1); j < n; j++) {
System.out.print(String.format("%2d", col*col) + " ");
col--;
}
System.out.println();
}
scan.close();
}

I have used the code you guys provided and it had some logical issues when inputting a number past 4 it would not square the triangle correctly and would only create the shape. I have solved the issue by adding a while loop and editing the for loops and not it outputs correctly.
Incorrect output:
Please enter a number between 1 and 9 inclusive: 8
9
4 9
1 4 9
0 1 4 9
1 0 1 4 9
4 1 0 1 4 9
9 4 1 0 1 4 9
16 9 4 1 0 1 4 9
Correct Code Given:
import java.util.Scanner;
public class AverageGrades {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter a number between 1 and 9 inclusive:");
int n = scan.nextInt();
for (int row = 1; row <= n; row ++) {
for (int col = n; col >= 1; col--) {
if (col <= row) {
System.out.print(String.format("%2d ", col * col));
} else {
System.out.print(" ");
}
}
System.out.println();
}
}
}
My Code:
import java.util.Scanner;
public class TriangleTest {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter Number between 1 and 9 : ");
int n = scan.nextInt();
while(n < 0 || n > 9)
{
System.out.print("Please enter a valid value between 1 and 9 :");
n = scan.nextInt();
}
for(int i = 0; i < n; i++)
{
for(int j = 0; j <= n*2-(i + i); j++)
{
System.out.print(" ");
}
for(int l = i + 1; l > 0; l--)
{
int r = l*l;
System.out.print(r + " ");
}
System.out.println("\n");
}
scan.close();
}
}
Correct Output:
Enter Number between 1 and 9 : 10
Please enter a valid value between 1 and 9 :9
1
4 1
9 4 1
16 9 4 1
25 16 9 4 1
36 25 16 9 4 1
49 36 25 16 9 4 1
64 49 36 25 16 9 4 1
81 64 49 36 25 16 9 4 1

java print other side of pyramid nested loop

I'm currently stuck on creating the other side of my pyramid. I would like for my program to ask the user for a number between 5 and 15. Use that number to print out a square and a triangle. I have been able to do everything up until I get to the pyramid. I can create one side of the pyramid but I noticed i'm overlooking something when it comes to creating the other side. Any guidance on putting me in the right direction would be greatly appreciated.
import java.util.Scanner;
public class doLoop {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int number;
final int minimum = 5;
final int maximum = 15;
do {
System.out.print("Enter a number between" + " " + minimum + " " + "and" + " " + maximum + ":" );
number = input.nextInt();
for(int i = 1; i <= number; i++) {
for(int j = 1; j <= number; j++) {
System.out.print(j + " ");
}
System.out.println();
}
for(int column = 1; column <= number; column++) {
for(int row = 1; row <= number ; row++) {
if(column >= row) {
System.out.print(row);
} else {
System.out.print(" ");
}
}
System.out.println(" ");
}
if (number <= minimum || number >= 15)
System.out.println("Sorry, invalid");
} while (number <= minimum || number >= maximum);
}
}
**Here is my current output:**
Enter a number between 5 and 15:5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1
12
123
1234
12345
Sorry, invalid
Enter a number between 5 and 15:
**This is what i'm working towards:**
Enter a number between 5 and 15: 2
Sorry, 2 is invalid. Please try again.
Enter a number between 5 and 15: 20
Sorry, 20 is invalid. Please try again.
Enter a number between 5 and 15: 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1
2 1 2
3 2 1 2 3
4 3 2 1 2 3 4
5 4 3 2 1 2 3 4 5
6 5 4 3 2 1 2 3 4 5 6
7 6 5 4 3 2 1 2 3 4 5 6 7
8 7 6 5 4 3 2 1 2 3 4 5 6 7 8
9 8 7 6 5 4 3 2 1 2 3 4 5 6 7 8 9
10 9 8 7 6 5 4 3 2 1 2 3 4 5 6 7 8 9 10

You code has multiple errors!!!
your code will loop forever
you don't need a do loop
If I understand correrctly your problem is that you want the left side of the pyramid. You can achieve it by looping from negative user input to the values inserted by the user
Here's a snipped code, you need some tweaking based on your needs!!!
import java.util.Scanner;
public class doLoop {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int number;
final int minimum = 5;
final int maximum = 15;
System.out.print("Enter a number between" + " " +
minimum + " " + "and" + " " + maximum + ":");
number = input.nextInt();
if (number <= minimum || number >= 15) {
System.out.println("Sorry, invalid");
return;
}
for (int i = 1; i <= number; i++) {
for (int j = 1; j <= number; j++) {
System.out.print(j + " ");
}
System.out.println();
}
for (int row = 1; row < number; row++) {
for (int column = -(number - 1); column <= number; column++) {
int absValue = Math.abs(column);
// you need to use the absolute value
// to print the positive value and to perform column checks
if (absValue <= row)
System.out.print(absValue);
else {
// if the absolute value is greater the the current print 1 or 2 spaces
// based on the value of the column
//(2 spaces if lower then 10 otherwise 1 space only)
System.out.print(absValue < 10 ? " " : " ");
}
// If the absolute value of column is -1 or 1 you need to change
// the value to "1" to bypass the printing of 101
if (absValue == 1)
{
column = 1;
}
}
System.out.println();
}
}
}

I would rather edit what I have worked on as opposed to just copying what you did. Plus, I don't understand all of your code. I was able to complete the triangle I was looking for. But for some reason I can't get my loop to follow the conditions I set. It worked initially before I added the for loops for the shapes but now i'm stuck on how to get it to follow them again. Any advice?
import java.util.Scanner;
public class doLoop {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int number;
final int minimum = 5;
final int maximum = 15;
do {
System.out.print("Enter a number between" + " " + minimum + " " + "and" + " " + maximum + ":" );
number = input.nextInt();
if (number <= minimum || number >= maximum) {
System.out.println("Sorry, invalid");
break;
}
for(int i = 1; i <= number; i++) {
for(int j = 1; j <= number; j++) {
System.out.print(j + " ");
}
System.out.println();
}
int columns = 1;
for (int i = number; i >= 1; i--)
{
for (int j = 1; j <= i*2; j++)
{
System.out.print(" ");
}
for (int j = i; j <= number; j++)
{
System.out.print(j + " ");
}
for (int j = number - 1; j >= i; j--)
{
System.out.printf(j + " ");
}
System.out.println();
columns++;
}
} while (number <= minimum || number >= maximum);
}
}

Pascal Triangle Not Printing Correctly in Java?

I got an assignment that requires us to print out pascal's triangles based on the user entered value of N. We were provided a main that allows the user to calculate Pascal’s Triangle based on a value of n. In this case if n is 0, then Pascal’s Triangle is 1. Otherwise for n being greater than 0, the appropriate Pascal’s Triangle will be created and displayed. Here is the main:
public class CSCD210Lab13
{
public static void main(String[] args)
{
int n = 0;
int [][] pascal = null;
do
{
n = Lab13Methods.readN();
pascal = Lab13Methods.createPascalsTriangle(n);
Lab13Methods.printPascals(pascal);
}while(MyUtil.goAgain());
}// end main
}// end class
Here is my Methods file:
import java.util.*;
public class Lab13Methods
{
public static int readN()
{
Scanner kb = new Scanner(System.in);
System.out.println("Enter N: ");
int n = kb.nextInt();
while(n < 0)
{
System.out.println("Number Below 1. Re-Enter: ");
n = kb.nextInt();
}
return n;
}
public static int[][] createPascalsTriangle(int n)
{
int[][]pascalTri = new int[n + 1][(n + 1) * 2];
int sideOne, side;
pascalTri[0][n - 1] = 1;
sideOne = side = n - 1;
for (int y = 1; y < n; y++)
{
pascalTri[y][sideOne] = 1;
pascalTri[y][side] = 1;
sideOne--;
side++;
for (int k = 1; k <= y; k++)
{
int left = pascalTri[y - 1][sideOne + (2 * k) - 1];
int right = pascalTri[y - 1][sideOne + (2 * k) + 1];
pascalTri[y][sideOne + (2 * k)] = left + right;
}
}
return pascalTri;
}
public static void printPascals(int[][]pascal)
{
for (int f = 0; f < pascal.length; f++)
{
for (int v = 0; v < pascal[f].length; v++)
{
if (pascal[f][v] == 0)
{
System.out.print("");
}
else
{
System.out.print(pascal[f][v]+" ");
}
}
System.out.println();
}
}
}
Here is my goAgain file:
public static boolean goAgain()
{
boolean goAgain = false;
String answer;
Scanner kb = new Scanner(System.in);
System.out.println();
System.out.print("Do you want to go again? ");
answer = kb.nextLine();
while(!answer.equalsIgnoreCase("yes") && !answer.equalsIgnoreCase("no"))
{
System.out.print("Invalid Input. Do you want to go again? ");
answer = kb.nextLine();
}
if(answer.equalsIgnoreCase("yes"))
{
goAgain = true;
}
else if(answer.equalsIgnoreCase("no"))
{
goAgain = false;
}
return goAgain;
}
}
My question is about how it's printing. If I enter 10 to be the value of N, this is how it is supposed to print:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
1 9 36 84 126 126 84 36 9 1
1 10 45 120 210 252 210 120 45 10 1
However, this is how mine prints:
1
1 1 1 1
1 1 2 1 1
1 1 3 3 1 1
1 1 4 6 4 1 1
1 1 5 10 10 5 1 1
1 1 6 15 20 15 6 1 1
1 1 7 21 35 35 21 7 1 1
1 1 8 28 56 70 56 28 8 1 1
What am I doing wrong?

I think your error may be here:
pascalTri[y][sideOne] = 1;
pascalTri[y][side] = 1;
sideOne--;
side++;
Your program is designed to fill in the cells of the array in a checkerboard pattern:
for any two adjacent rows, one row will have non-zero entries only
in even-numbered locations, and the other will have non-zero entries
only in odd-numbered locations.
Notice that right after you do pascalTri[y][sideOne] = 1;, you decrement sideOne.
That means if you are in a row that should be using odd-numbered cells,
sideOne now is odd, but when you did pascalTri[y][sideOne] = 1;,
sideOne was still even. So you have put an even-numbered entry in a row that
should have only odd-numbered entries.
That is where all the extra 1s are coming from in your output.
Just delete these lines:
pascalTri[y][sideOne] = 1;
pascalTri[y][side] = 1;
All they are doing is creating those extra, unwanted 1 values. All the correct values
are being written in the array by other statements.

I don't know if you know what a pascal triangle is let me explain to you what it is.
11^0 = 1
11^1 = 11
11^2 = 121
11^3 = 1331
11^4 = 14641
11^5 = 161051
I don't know why have you done some much code all when you need was
public static void printPascalsTriangle(int n)
{
long number=11l;
for(int i=0;i<=n;i++)
{
System.out.println(new Double(Math.pow(number,i)).longValue());
}
}
You would need a case more that five which can be handled like this link.

Refer this short pascal code i have written which is depend on user input:
public class Pascal {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner= new Scanner(System.in);
System.out.println("Enter the Number of levels of Pascal");
int levelCount = scanner.nextInt();
for(int i =0;i<levelCount;i++) {
int value = 1;
for(int j=0;j<=i;j++) {
System.out.println(value);
value = value * (i - j) / (j + 1);
}
System.out.println("\n");
}
}
}
Enjoy..!!

Pyramid Pattern in Java

It was so hard to ask such a newbie question on this advanced site. But after so much tries and even loosing my hope i was forced to bring my self here. I am not been able to print the following pattern:
1
1 2 1
1 2 4 2 1
1 2 4 8 4 2 1
1 2 4 8 16 8 4 2 1
1 2 4 8 16 32 16 8 4 2 1
But with my tiresome efforts i reached the following:
public static void main(String[] args) {
int num = 1;
for (int i = 0; i < 15; i++) {
for (int j = 0; j < 15 - i; j++) {
System.out.print(" ");
}
for (int k = 0; k <= i; k++) {
System.out.print(num + " ");
}
System.out.println();
}
}
1
1 1
1 1 1
1 1 1 1
1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1 1
1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1

Here ya go
public static void main(String[] args) {
int max = 6;
int padLength = (int) Math.ceil(Math.log10(Math.pow(2, max) + 1)) + 2;
for (int i = 0; i < max; i++) {
for (int j = 1; j < max - i; j++) {
System.out.print(pad(" ", padLength));
}
for (int k = 0; k <= i; k++) {
System.out.print(pad(Math.pow(2, k), padLength));
}
for (int k = i - 1; k >= 0; k--) {
System.out.print(pad(Math.pow(2, k), padLength));
}
System.out.println();
}
}
public static String pad(double d, int l) {
Integer i = (int) d;
return pad(i.toString(), l);
}
public static String pad(String s, int l) {
return String.format("%-" + l + "s", s);
}
Explanation
int padLength = (int) Math.ceil(Math.log10(Math.pow(2, max) + 1)) + 2;
Math.pow(2,max) - Gives me maximal number I will have to display
Math.ceil(Math.log10(number + 1)) - I use this to determine length of string representation of specific number. Please refer to wikipedia to check what logarithm is. I add 1 to skip edge case when number is exact power of 10 e.g. log10(10)->1 (this will never occur in task specified in question, it's just for purity of solution). Ceil just rounds number up.
+2 - minimum gap between two numbers is specified example was 2 spaces long so I just add this
You could use here Integer.toString(((int)Math.pow(2, max))).length()+2 but it's not as pretty :)
return String.format("%-" + l + "s", s);
First I build format string that looks like e.g. %-3s, which means print String with minimum length of 3, padding on the right. Second argument is the String I want to print. Refer to documentation
Running example

I find the other answer very overwhelming and dramatic. You don't need much maths and complexity to solve this problem. This might not be the best code but I think it is easy to understand. Not even an explanation is needed, it is a row by row approach, It's good to keep things simple.
public static void main(String[] args) {
// Init
int row = 0;
int maxRows = 6;
int num = 1;
int indent = maxRows - 1;
// Printing loop
while (row < maxRows) {
// Indent
for (int i = 0; i < indent; ++i)
System.out.print(" ");
// Print nums
for (int i = 0; i < num; ++i)
System.out.printf("%4d", (int) Math.pow(2.0, i));
for (int i = num - 2; i >= 0; --i)
System.out.printf("%4d", (int) Math.pow(2.0, i));
// New line
System.out.println("");
// Adjustments
++row;
--indent;
++num;
}
Output:
1
1 2 1
1 2 4 2 1
1 2 4 8 4 2 1
1 2 4 8 16 8 4 2 1
1 2 4 8 16 32 16 8 4 2 1