Is there any way to match the query, for example, I want to search my number against the rules (table name) through query.
I want to match the number which starts with "333" rules .........
1)3322323
Here is my query
SELECT * FROM demo where rules like '33322323';
I want above query return true. because it matches with my rule.
Below is my table.
id | rules
...............
1 | 333
2 | 22
3 | 442
I have sample data 1) 33331235, 2) 2354545 3) 4424545454 4) 22343434
Case 1 (matching data 1) 33331235)
Suppose I want to check my 33331235 with my rules table so my sample data match with my
row 1 which is 333, because of my data start with 333..... it should return true because of it matched.
Case 2 (matching data 2) 2354545)
Suppose I want to check my 2354545 with my rules table so my sample data does not match with my
Any row because my no rule applies on it..... it should return true because of it matched.
Case 3 (matching data 1) 4424545454)
Suppose I want to check my 4424545454 with my rules table so my sample data match with my
row 1 which is 442, because of my data start with 442..... it should return true because of it matched.
Solved.
I solved this with the help of Forpas I used this query to match number start with
SELECT * FROM demo where '333434334 like rules ||'%';
The number at the end of the string when I use this query.
SELECT * FROM demo where '333434334' like '%' || rules;
The number anywhere in the string then I use this query.
SELECT * FROM demo where '333434334' like '%' || rules ||'%';
You need to use the operator LIKE.
You have tagged your question with both MySQL and SQLite.
For MySQL:
SELECT * FROM demo where '33322323' like concat(rules, '%');
For SQLite:
SELECT * FROM demo where '33322323' like rules || '%';
The above code will return all rows where the rules column value is the starting chars of 33322323.
Related
I have a query that when given a word that starts with a one-letter word followed by space character and then another word (ex: "T Distribution"), does not return results. While given "Distribution" alone returns results including the results for "T Distribution". It is the same behavior with all search terms beginning with a one-letter word followed by space character and then another word.
The problem appears when the search term is of this pattern:
"[one-letter][space][letter/word]". example: "o ring".
What would be the problem that the LIKE operator not working correctly in this case?
Here is my query:
#Cacheable(value = "filteredConcept")
#Query("SELECT NEW sina.backend.data.model.ConceptSummaryVer04(s.id, s.arabicGloss, s.englishGloss, s.example, s.dataSourceId,
s.synsetFrequnecy, s.arabicWordsCache, s.englishWordsCache, s.superId, s.categoryId, s.dataSourceCacheAr, s.dataSourceCacheEn,
s.superTypeCasheAr, s.superTypeCasheEn, s.area, s.era, s.rank, s.undiacritizedArabicWordsCache, s.normalizedEnglishWordsCache,
s.isTranslation, s.isGloss, s.arabicSynonymsCount, s.englishSynonymsCount) FROM Concept s
where s.undiacritizedArabicWordsCache LIKE %:searchTerm% AND data_source_id != 200 AND data_source_id != 31")
List<ConceptSummaryVer04> findByArabicWordsCacheAndNotConcept(#Param("searchTerm") String searchTerm, Sort sort);
the result of the query on the database itself:
link to screenshot
results on the database are returned no matter the letters case:
link to screenshot
I solved this problem.
It was due to the default configuration of the Full-text index on mysql database which is by default set to 2 (ft_min_word_len = 2).
I changed that and rebuilt the index. Then, one-letter words were returned by the query.
12.9.6 Fine-Tuning MySQL Full-Text Search
Use some quotes:
LIKE '%:searchTerm%';
Set searchTerm="%your_word%" and use it on query like this :
... s.undiacritizedArabicWordsCache LIKE :searchTerm ...
I am very new to CYPHER QUERY LANGUAGE AND i am working on relationships between nodes.
I have a CSV file of table containing multiple columns and 1000 rows.
Template of my table is :
cdrType ANUMBER BNUMBER DUARTION
2 123 456 10
2 890 456 5
2 123 666 2
2 123 709 7
2 345 789 20
I have used these commands to create nodes and property keys.
LOAD CSV WITH HEADERS FROM "file:///2.csv" AS ROW
CREATE (:ANUMBER {aNumber:ROW.aNumber} ),
CREATE (:BNUMBER {bNumber:ROW.bNumber} )
Now I need to create relation between all rows in the table and I think FOREACH loop is best in my case. I created this query but it gives me an error. Query is :
MATCH (a:ANUMBER),(b:BNUMBER)
FOREACH(i in RANGE(0, length(ANUMBER)) |
CREATE UNIQUE (ANUMBER[i])-[s:CALLED]->(BNUMBER[i]))
and the error is :
Invalid input '[': expected an identifier character, whitespace,
NodeLabel, a property map, ')' or a relationship pattern (line 3,
column 29 (offset: 100)) " CREATE UNIQUE
(a:ANUMBER[i])-[s:CALLED]->(b:BNUMBER[i]))"
I need relation for every row. like in my case. 123 - called -> 456 , 890 - called -> 456. So I need visual representation of this calling data that which number called which one. For this I need to create relation between all rows.
any one have idea how to solve this ?
What about :
LOAD CSV WITH HEADERS FROM "file:///2.csv" AS ROW
CREATE (a:ANUMBER {aNumber:ROW.aNumber} )
CREATE (b:BNUMBER {bNumber:ROW.bNumber} )
MERGE (a)-[:CALLED]->(b);
It's not more complex than that i.m.o.
Hope this helps !
Regards,
Tom
I want to format query results in oracle and save them into an output file.
I tried this query:
spool "result.txt"
SELECT STA_CODE,DATE_CREATION,DATE_FIN_INSTANCE,DATE_FIN_TRAITEMENT FROM DEMANDE;
spool off;
In my output file, the result looks like:
STA_CODE DATE_CRE DATE_FIN DATE_FIN
------------------------- -------- -------- --------
200 09/05/17 09/05/17 09/05/17
400 09/05/17 09/05/17 09/05/18
I want then to write a java code that takes for each line the result and match it with name of column: for example STA_CODE=200, STA_CODE=400, DATE_CRE=09/05/17, DATE_CRE=09/05/18 ....
I'm biginner in JAVA and I can't write that Bit of code. Is possible to directly format query results and then parse the output file without doing any transformation with java.
If you want each row separated, then use
SELECT 'STA_CODE='||STA_CODE
||', DATE_CRE=' ||to_date(DATE_CREATION,'DD/MM/YY')---other values
from DEMANDE
If you want all STA_CODE first and then all DATE_CRE and then other columns in one line, separated by comma, use something like
select listagg(col1,', ') within group (order by seq)
from (
SELECT 1 as seq,'STA_CODE='||STA_CODE as col1 from DEMANDE
union
SELECT 2 as seq,'DATE_CRE='||to_date(DATE_CREATION,'DD/MM/YY') from DEMANDE
union
---- other select queryies separated by union.
)
NOTE: You cannot guarantee order among each row. So it might happen that second STA_CODE come first and first DATE_CRE come second. To garuntee that, order by a column in all union queries.
I have below records in table.
col1 col2 col3
------------------------
1 Abc IN
2 DEF CA
3 Xyz IN
4 Cae CA
5 Pty IN
6 Zwe DE
7 Zwf US
Here User sends an Input like IN or CA or DE etc. User input has to be mapped against col3. Now I need to query all the records from the table but the records matching the user input (IN or CA or DE) should appear first in the list then all other records should appear. How can I do it using hibernate criteria?
I need the results in below the order if user sends IN as an input.
1 Abc IN
5 Pty IN
3 Xyz IN
2 DEF CA
4 Cae CA
6 Zwe DE
7 Zwf US
You could try to use ORDER BY CASE construct:
order by case when <your entity>.col3 = :parameter then '0' else '1' end asc
There are two ways to solve this problem:
1. Create two queries one with equal to another with not equal to and all results for both in single list.
2. If you don't want to query database twice then you have to write algo in java that will remove elements for your input from list and add it another list and after iteration add remaining list at the end.
try the case ... when statements:
select *, ( case when col3=:input then '0' | col3 else col3 end) as sorter from table order by sorter asc
not sure, if it works, but if it does it would be exactly what you want
I am using current version of neo4j,
I am trying delete or update Node by graph id , when I try to delete passing as parameter for example name, it works normal, but I need delete with id one node with it is relation, and also update node.
String remove = "MATCH (n:Player {ID(n): {id} })-[r]-() DELETE n, r";
ExecutionResult result = engine.execute(remove,
params);
and
String query = "MERGE (n:Person {ID(n): {id}}) ON CREATE SET n.name={name}, n.surname={surname}, n.position={position} ON MATCH SET";
ExecutionResult result = engine.execute(query,
params);
Always I am getting errors like
Invalid input '(': expected an identifier character, whitespace, ':' or '}' (line 1, column 20)
"MERGE (n:Person {ID(n): {id}}) ON CREATE SET n.name={name}, n.surname={surname}, n.position={position} ON MATCH SET"
or
Invalid input '(': expected an identifier character, whitespace, ':' or '}' (line 1, column 20)
"MATCH (n:Player {ID(n): {id} })-[r]-() DELETE n, r"
Usually I am used Spring data neo4j and did not find this type of errors.
Anyone have answers?
Thanks
ID is a function that returns the internal id of a node or relationship, but in your query you use it as if it were a property on a node. The way to match a node by its internal id is
MATCH (n)
WHERE ID (n) = {id}
In your delete case you could do
MATCH (n:Player)-[r]-()
WHERE ID (n) = {id}
DELETE r, n
You can't assign the internal id to a node, Neo4j handles that internally, so it doesn't really make sense to use the ID function with MERGE. You can choose a different uniquely identifying property that you control and for which you create a unique constraint, then use that in most (probably all) places where you now use the internal id.
Armen,
If you already know the Neo4j id value (the node number), then you can write your first query as
START n = node({id}) WITH n MATCH (n)-[r]-() DELETE n, r
However, the more I look at your code, the more I am wondering about your use of id. Do your nodes have a user-defined parameter named id? If so, then this all needs to be approached differently.
Grace and peace,
Jim