This question already has answers here:
How To Convert A Bitmap Image To Uri
(2 answers)
Closed 3 years ago.
I'm using a library that returns a bitmap image if I want to share this image to another application or send it via email? I don't have the Uri of the image then what should I do
It all depends on your environment:
- you can get hand over the complete image (e.g. an attachment in an email)
- if you have an solution which could be accessed from the target, then you can create your own uri. On a local system, you could store the image in a file. Or if you have a web application, you might want to make the image available so that you can provide an url to the image, too)
So it mainly depends on the whole Szenario: where does the image come from, how big is it? What is the target? ....
And sorry, that I do Not write this as a comment - need a reputation of 50 to write comments first ....
convert your bitmap into a file:
String path = Environment.getExternalStorageDirectory();
File file = new File(path + "/image_name.jpg");
OutputStream fOut = new FileOutputStream(file);
pictureBitmap.compress(Bitmap.CompressFormat.JPEG, 85, fOut); // saving the Bitmap to a file compressed as a JPEG with 85% compression rate
fOut.flush(); // Not really required
fOut.close(); // do not forget to close the stream
Get the URI from the file:
Uri yourUri = Uri.fromFile(file);
Addition: for android 7.0+ you need a different way to get URI from file.
Saving file to the default main directory is only an example but maybe not the best practice.
Related
I have a EBCDIC file from which i extracted images. However, there is some data on the images which is key source in identifying my transactions.
Assume that i have an image as "stackoverflow logo" stored under name "img1.jpg" on my desktop and when i read it using the following code, it works
String inputImage = "C:\\Desktop\\img1.jpg";
File imageFile = new File(inputImage);
BufferedImage image1 = ImageIO.read(imageFile);
System.out.println(image1);
However, when i attempt the same with an image decoded from EBCDIC conversion, it returns null.
The difference i observed is that there is no color associated in the decoded image. Is there any way to read these images and retrieve the text on the image. Following is not the exact image which i am working on, but just to give an idea i am sharing a sample from internet.
Note: The image am working on looks like a Scanned image (Grayscale)
Example:
Also, I observed that if i open the decode file and do a screen capture via snipping tool and store it as jpg file (which already is jpg) and read it, system is reading that file. not sure where is the issue, is it compression or color coding or format.
Thank you everyone.
I used Tess4j to decode the TIFF image. Unfortunately the information i was looking for isn't available in the decoded text. But, done with the POC.
used the following library and added eng.traineddata in the folder where images exist
import net.sourceforge.tess4j.*;
String inputImage = "C:\\Desktop\\img1.tiff";
File imageFile = new File(inputImage);
ITesseract imageRead = new Tesseract();
imageRead.setDataPath("C:\\Desktop\\");
imageRead.setLanguage("eng");
String imageText = imageRead.doOCR(imageFile);
System.out.println(imageText);
The typical way (based on research) for saving bitmap images from a remote url is:
Bitmap bmImage = null;
InputStream in = new java.net.URL(imageUrl).openStream();
bmImage = BitmapFactory.decodeStream(in);
File file = new File(myPath);
FileOutputStream outputStream;
outputStream = new FileOutputStream(file);
bmImage.compress(Bitmap.CompressFormat.PNG, 100, outputStream);
outputStream.close();
I cannot save bitmap unless it is compressed (Bitmap is always uncompressed).
The remote image size is 32KB, after compression it gets 110KB.
I know I have to lower compression parameter to get smaller size, but the remote image is optimize and much more efficient.
Is there a way I can save the remote image on mobile storage without compressing it?
===== ANSWER TO MY PROBLEM =====
First I apologize for misleading content; all I wanted is to save images that could be png|jpeg|gif|etc.. Probably I mislead you guys that the image I am trying to save is in BMP format, but it is not.
Nevertheless, for those who want to save images WITHOUT compressing, have a look to this answer
Use AndroidBmpUtil as shown in the code below:
new AndroidBmpUtil().save(bmImage, file);
This question already has answers here:
Including Images with an executable jar
(2 answers)
Closed 9 years ago.
I want to read a bunch of image files from my current package because I want to get access to the files when my package which includes my image files is exported to others' computer.
I just want to make sure my program can read the images no matter if the package is in my computer.
I tried
File file = new File("images.jpg"); // It is wrong because the path is wrong.
// I want to assign the image as BuffuredImage
BufferedImage dealerCardImage1 = ImageIO.read(file);
I was wondering how the path of the files should be. What should I do?
put your image file inside the package of current class file and try this:
BufferedImage dealerCardImage1 = ImageIO.read(getClass().getResourceAsStream("images.jpg"));
Note that, getClass().getResourceAsStream(path) returns an InputStream that points to a path that starts from current package.
For example if you have a class file named HelloWorld inside package com.example, then HelloWorld.class.getResourceAsStream("images.jpg") returns an InputStream to image with this path: com/example/images.jpg
if you read from file use
Image image = new Image();
image = ImageIO.read(file);
// Read from an input stream
InputStream is = getClass()
.getResourceAsStream("/com/statement/SamplePDFStatementFile.txt");
image = ImageIO.read(is);
//if you read from url
// Read from a URL
URL url = new URL("http://hostname.com/image.gif");
image = ImageIO.read(url);
ImageIO.read(file); will return null if no registered ImageReader is not found.
Please check whether you have registered any ImageReader or not.
I think this code snippet could help you
File file = new File("images.jpg"); // Assuming images.jpg in my working directory
FileInputStream fis = new FileInputStream(file);
BufferedImage image = ImageIO.read(fis); //reading the image file
You just need to wrap the file into an FileInputStream and then pass it to read()
I have a byte[] of an image and I need to upload it as an image to picasa.
According to the documentation, an image is uploaded as follows.
MediaFileSource myMedia = new MediaFileSource(new File("lights.jpg"), "image/jpeg");
which means I need to create a File, out of the byte[].
The catch is, I have to do this without using FileOutputStream as it is not supported by Google App Engine (which is the environment I am using)
Is there any way to do this?
You don't have to use MediaFileSource to upload a photo, you can use MediaByteArraySource and pass it to photo.setMediaSource(...).
I need to upload an image file and generate a thumbnail for the uploaded file in my JSF webapplication. The original image is stored on the server in /home/myname/tomcat/webapps/uploads, while the thumbnail is stored in /home/myname/tomcat/webapps/uploads/thumbs. I'm using the thumbnail generator class I copied from philreeve.com.
I have successfully uploaded the file with help from BalusC. But using Toolkit.getImage(), I can't access the image.
I used the uploaded file's absolute path, like so:
inFilename = file.getAbsolutePath();
The relevant code from the thumbnail generator is:
public static String createThumbnail(String inFilename, String outFilename, int largestDimension) {
...
Image inImage = Toolkit.getDefaultToolkit().getImage(inFilename);
if (inImage.getWidth(null) == -1 || inImage.getHeight(null) == -1) {
return "Error loading file: \"" + new File(inFilename).getAbsolutePath() + "\"";
}
...
}
Since I am already using the absolute path, I don't understand why it is not working. I have also used the following values for inFilename, but I always get the "Error loading file...".
/home/myname/tomcat/webapps/uploads/filename.ext
/uploads/filename.ext
But I did check the directory, and the image is there. (I uploaded using /home/myname/tomcat/webapps/uploads/filename.ext, and it works.) What is the correct path for the image in that directory? Thank you.
Update
I got the code to work by using:
Image inImage = ImageIO.read(new File(inFilename));
I still don't understand why Toolkit.getImage() does not work though.
Are you sure it's a JPEG file? Use an image viewer to make sure nothing bad happened to the file during upload (or that it was an image to begin with).
Also, use new File(inFilename).exists() to make sure the path is correct. I also suggest to print new File(inFilename).getAbsolutePath() in error messages because relative paths can hurt you.
That said, the rest of the code looks correct.
The problem is that Toolkit.getImage() does not return the image immediately. The issue is well-described in this bug report, a relevant extract of which is here:
This is not a bug. The submitter is not properly using the asynchronous
Image API correctly. He assumes that getImage loads all of the image's bits
into memory. However, it is well documented that the actual loading of
bits does not take place until a call to Component.prepareImage or
Graphics.drawImage. In addition, these two functions return before the
Image is fully loaded. Developers are required to install an ImageObserver
to listen for notification that the Image has been fully loaded. Once they
receive this notification, they can repaint the Image.
I found that the answer to this question works well:
Image image = new ImageIcon(this.getClass().getResource("/images/bell-icon16.png")).getImage();