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Java XML: ClassCastException class com.sun.org.apache.xerces.internal.dom.DeferredTextImpl cannot be cast to class javax.swing.text.Element

Throw this program I'm trying to unzip my xml file and parse it using SAX, for the parsing part I have an exception which appeared about ClassCastException class com.sun.org.apache.xerces.internal.dom.DeferredTextImpl cannot be cast to class javax.swing.text.Element, here is my code :
import java.io.File;
import java.io.IOException;
import javax.swing.text.Element;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import net.lingala.zip4j.ZipFile;
import net.lingala.zip4j.exception.ZipException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class Parser {
public static void main(String[] args) throws IOException, ZipException {
String source = "C:\\Users\\java_program\\xml.zip";
String destination = "C:\\Users\\java_program\\xml";
ZipFile zipFile = new ZipFile(source);
zipFile.extractAll(destination);
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new File ("C:\\Users\\java_program\\xml\\xml.xml"));
document.getDocumentElement().normalize();
NodeList productList = document.getElementsByTagName("product");
for(int i = 0; i<productList.getLength(); i++) {
Node product = productList.item(i);
if (product.getNodeType() == Node.ELEMENT_NODE) {
Element productElement = (Element) product; // the problem is here
NodeList productDetails = product.getChildNodes();
for(int j=0; j<productDetails.getLength(); j++) {
Node detail = productDetails.item(j);
if (product.getNodeType() == Node.ELEMENT_NODE) {
Element detailElement = (Element) detail; // the problem is here
System.out.println(" " + ((org.w3c.dom.Element) detailElement).getTagName() + ": " + detailElement.getAttributes());
}
}
}
}
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
My XML file have this structure :
<?xml version="1.0" encoding="utf-8"?>
<import xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<products>
<product>
<article_sku>000c66dawt</article_sku>
<brand>HUAWEI</brand>
<brand_reference>HUAWEI-NEXUS-6P-64GO-ARGENT</brand_reference>
<category>SMARTP</category>
<ean13>6901443077359</ean13>
<it_cpu_smartphone_type><![CDATA[Qualcomm Snapdragon S810]]></it_cpu_smartphone_type>
</product>
<product>
<article_sku>000cfxlysl</article_sku>
<brand>HERCULES</brand>
<brand_reference>HERCULES-DJCONTROL-COMPACT</brand_reference>
<category>PLATIN-1</category>
<ean13>3362934745288</ean13>
</product>
</products>
</import>
Any help is really appreciated

You imported the wrong Element class.
Change
import javax.swing.text.Element;
to
import org.w3c.dom.Element;
Also you create detail object which is a node and check that if the previously created product variable is an element and then cast detail to Element.
Node detail = productDetails.item(j);
if (product.getNodeType() == Node.ELEMENT_NODE) {
Element detailElement = (Element) detail;
the product line:
Node product = productList.item(i);
I think you should chacnge to conditional to detail.getNodetype() == Node.ELEMENT_NODE

Read the Properties in hibernate Configuration File

For Some reason I want to be able to read the Properties in my hibernate Configuration file, say for example I need to know what dialect is used or what database driver class. I have attempted to do this by parsing the xml But I am not getting past the attributes:
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.IOException;
import java.io.InputStream;
import javax.xml.parsers.ParserConfigurationException;
import org.xml.sax.SAXException;
/**
*
* #author User
*/
public class XmlParser {
public XmlParser() {
}
public void readXml() throws SAXException, IOException, ParserConfigurationException {
InputStream in = this.getClass().getResourceAsStream("/hibernate.cfg.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(in);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("property");
System.out.println("----------------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("\nCurrent Element :" + nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("Driver : " + eElement.getAttribute("name"));
System.out.println("Not Sure : " + eElement.getElementsByTagName("hibernate.connection.url").item(0).getTextContent());
System.out.println(eElement.getElementsByTagNameNS("name", "hibernate.dialect").item(0).getTextContent());
}
}
}
}
My Output is:
Root element :hibernate-configuration
----------------------------
Current Element :property
Driver : hibernate.dialect
null
I need to be able to get the property values any time in my application. Is there another way or what am I missing in this method?

can you try with this
Configuration hibernateConfiguration = new Configuration().configure(new File("/hibernate.cfg.xml"));
String url = configuration.getProperty("hibernate.connection.url");
Like this, you can get all the properties, set the same somewhere in your static hashMap and use throughout your application.

You can use SAXReader to parse the file, here is the code:
import java.io.InputStream;
import java.util.Iterator;
import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;
public class ReadXMLFile {
public static void main(String argv[]) throws DocumentException {
new ReadXMLFile().readMyXML();
}
private void readMyXML() throws DocumentException {
InputStream in = this.getClass().getResourceAsStream(
"/hibernate.cfg.xml");
Document document = new SAXReader().read(in);
Element root = document.getRootElement();
System.out.println("Root element : " + root.getName());
Element sfNode = document.getRootElement().element("session-factory");
Iterator<Element> itr = sfNode.elementIterator("property");
System.out.println("----------Properties-----------");
while (itr.hasNext()) {
Element node = itr.next();
String name = node.attributeValue("name");
String value = node.getText().trim();
System.out.println(name + " = " + value);
}
}
}

splitting xml ino mutiple xmls based on xml tags using java

i need to split my xml into multiple xml based on the tag start and close. For this i tried with the following code
public class XmlSplit {
public static void main(String [] args) throws Exception {
File input = new File("/home/dev702/Desktop/cadgraf-test/Data_Entry.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
Document doc = (Document) dbf.newDocumentBuilder().parse(input);
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodes = (NodeList) xpath.evaluate("//Data_x0020_Entry", doc, XPathConstants.NODESET);
int itemsPerFile = 500;
int fileNumber = 0;
Document currentDoc = (Document) dbf.newDocumentBuilder().newDocument();
Node rootNode;
rootNode = currentDoc.createElement("Data_x0020_Entry");
File currentFile = new File(fileNumber+".xml");
for (int i=1; i <= nodes.getLength(); i++) {
Node imported = currentDoc.importNode(nodes.item(i-1), true);
rootNode.appendChild(imported);
if (i % itemsPerFile == 0) {
writeToFile(rootNode, currentFile);
rootNode = currentDoc.createElement("Data_x0020_Entry");
currentFile = new File((++fileNumber)+".xml");
}
}
writeToFile(rootNode, currentFile);
}
private static void writeToFile(Node node, File file) throws Exception {
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.transform(new DOMSource(node), new StreamResult(new FileWriter(file)));
}
}
In this am getting error on currentDoc.createElement. Am not able to compile this code and it is saying createElement not available.
Sample xml file
<?xml version="1.0" encoding="UTF-8"?>
<dataroot
xmlns:od="urn:schemas-microsoft-com:officedata"
xmlns:xsi="w3.org/2001/XMLSchema-instance" ;
xsi:noNamespaceSchemaLocation="Data%20Entry.xsd"
generated="2014-02-12T14:35:47"
>
<Data_x0020_Entry>
<ID>1004</ID>
<User>006Parthiban</User>
<Data_x0020_Entry_x0020_Date>2013-12-26T00:00:00</Data_x0020_Entry_x0020_Date>
<Publication>Daily Thanthi</Publication>
<Edition>CE City Edition</Edition>
<Location>Bangalore</Location>
</Data_x0020_Entry>
</dataroot>

I could not see any compilation issue in this code. Please check your import statements and verify that you have imported proper classes. the list of classes which I import are as below
import java.io.File;
import java.io.FileWriter;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

i think u have imported import javax.swing.text.Document; change that to import org.w3c.dom.Document;
And if ur using Swing too than use fully qualified that for to create Document
like
org.w3c.dom.Document currentDoc = (org.w3c.dom.Document) dbf.newDocumentBuilder().newDocument();
Update
I think the root element should be "dataroot" for splitted xmls. and you need to change your code to generate correct number of xml files (look at below code)..look at the code below..i tested for
int itemsPerFile = 2; ..it is working fine..
NOTE remove ";" from input xml file after namespcae
import java.io.File;
import java.io.FileWriter;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class XmlSplit {
public static void main(String [] args) throws Exception {
File input = new File("src/test.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
Document doc = (Document) dbf.newDocumentBuilder().parse(input);
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodes = (NodeList) xpath.evaluate("//Data_x0020_Entry", doc, XPathConstants.NODESET);
int itemsPerFile = 2;
int fileNumber = 0;
Document currentDoc = (Document) dbf.newDocumentBuilder().newDocument();
Node rootNode;
rootNode = currentDoc.createElement("dataroot");
File currentFile = new File(fileNumber+".xml");
for (int i=1; i <= nodes.getLength(); i++) {
Node imported = currentDoc.importNode(nodes.item(i-1), true);
rootNode.appendChild(imported);
if (i % itemsPerFile == 0) {
writeToFile(rootNode, currentFile);
rootNode = currentDoc.createElement("dataroot");
currentFile = new File((++fileNumber)+".xml");
}
else
{
writeToFile(rootNode, currentFile);
}
}
}
private static void writeToFile(Node node, File file) throws Exception {
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.transform(new DOMSource(node), new StreamResult(new FileWriter(file)));
}
}
let me know if u face any issues :)

DOM parser doesn't see subnodes

I trying to parse Lingvo xml dictionary with help of DOM parser.
Problem: DOM parser doesn't see the subnodes of card node (see code below).
Question?: How to pull word and translation nodes from card node
My code:
import entity.Item;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
public class DOMParser {
public void parseXMLFile(String xmlFilePath) throws IOException, SAXException {
Document document = builder.parse(ClassLoader.getSystemResourceAsStream(xmlFilePath));
List<Item> itemList = new ArrayList<Item>();
NodeList nodeList = document.getDocumentElement().getChildNodes();
//iterates through cards
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
System.out.println(node.getNodeName());
if (node instanceof Element) {
if ("card".equals(node.getNodeName())) {
// HERE node hasn't got anything!!! I mean attributes, childs etc.
}
}
}
}
}
My xml:
<?xml version="1.0" encoding="UTF-16"?>
<dictionary formatVersion="5" title="User ;vocabulary_user1" sourceLanguageId="1058" destinationLanguageId="1033" nextWordId="611" targetNamespace="http://www.abbyy.com/TutorDictionary">
<statistics readyMeaningsQuantity="90" activeMeaningsQuantity="148" learnedMeaningsQuantity="374" />
<card>
<word>загальна цікавість</word>
<meanings>
<meaning>
<statistics status="4" answered="122914" />
<translations>
<word>genaral wondering</word>
</translations>
</meaning>
</meanings>
</card>
</dictionary>

You can use a recursive approach to read through all your contents without getting into the mess of nested for loops.
For your xml:
public static void main(String[] args) throws ParserConfigurationException,
SAXException, IOException {
InputStream path = new FileInputStream("dom.xml");
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(path);
traverse(document.getDocumentElement());
}
public static void traverse(Node node) {
NodeList list = node.getChildNodes();
for (int i = 0; i < list.getLength(); i++) {
Node currentNode = list.item(i);
traverse(currentNode);
}
if (node.getNodeName().equals("word")) {
System.out.println("This -> " + node.getTextContent());
}
}
Gives,
This -> загальна цікавість
This -> genaral wondering

Parsing xml document Java "cannot be resolved"

I'm going through a tutorial on how to parse an xml document with java and encountering a problem. I am getting the error "dom cannot be resolved" I know it has something to do with the way I am declaring the variables and being out of scope but I can't figure out how to fix it.
Any help would be greatly appreciated, I will post the relevant parts below:
package com.xmlparse;
import java.io.IOException;
import java.util.Iterator;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import com.entities.Employee;
public class XmlParser
{
private void parseXmlFile(){
//get the factory
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
//Using factory get an instance of document builder
DocumentBuilder db = dbf.newDocumentBuilder();
//parse using builder to get DOM representation of the XML file
Document dom = db.parse("test.xml");
} catch(ParserConfigurationException pce) {
pce.printStackTrace();
} catch(SAXException se) {
se.printStackTrace();
} catch(IOException ioe) {
ioe.printStackTrace();
}
}
private void parseDocument() {
Document dom = db.parse("test.xml");
//get the root element
Element docEle = dom.getDocumentElement();
//get a nodelist of elements
NodeList nl = docEle.getElementsByTagName("Employee");
if(nl != null && nl.getLength() > 0) {
for(int i = 0 ; i < nl.getLength(); i++) {
//get the employee element
Element el = (Element)nl.item(i);
//get the Employee object
Employee e = getEmployee(el);
//add it to list
myEmpls.add(e);
}
}
}

As you are using DocumentBuilder db in different methods, you could declare db as a class member variable:
private DocumentBuilder db;
and initialize like so in parseXmlFile:
db = dbf.newDocumentBuilder();

You could change method signature like below and when call to it pass the created document builder instance.
private void parseDocument(DocumentBuilder db)