I am trying to remove namespaces in an xml document and getting the following error:
ERROR: 'The prefix "car" for element "car:name" is not bound.'
ERROR: 'com.sun.org.apache.xml.internal.utils.WrappedRuntimeException: The prefix "car" for element "car:name" is not bound.'
Here's my xml file:
<car:name>Toyota Corolla</car:name>
<car:year>2000</car:year>
Here's my removeNs.xslt
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:variable name="vLowercase" select="'abcdefghijklmnopqrstuvwxyz'" />
<xsl:variable name="vUppercase" select="'ABCDEFGHIJKLMNOPQRSTUVWXYZ'" />
<xsl:template match="*">
<xsl:element
name="{concat(translate(substring(local-name(), 1, 1),
$vUppercase, $vLowercase),
substring(local-name(), 2))}">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name(.)}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
and my java method:
private static String stripNameSpaces(String inXml) {
String outputXml = "";
try {
StringWriter writer = new StringWriter();
TransformerFactory factory = TransformerFactory.newInstance();
Source xslt = new StreamSource(new File("./src/main/resources/removeNs.xslt"));
Transformer transformer = factory.newTransformer(xslt);
Source text = new StreamSource(new StringReader(inXml));
transformer.transform(text, new StreamResult(writer));
outputXml = writer.toString();
} catch (TransformerConfigurationException tcEx) {
tcEx.printStackTrace();
return tcEx.getMessage();
} catch (TransformerException tEx) {
tEx.printStackTrace();
return tEx.getMessage();
}
return outputXml;
}
My guess is that I have to add something to removeNs.xslt but have not been able to figure out what. If someone could help me with this, I'd really appreciate it
Related
I am using javax.xml.transform API to do XSL transformation . The API only allows one XML document as an input to apply transformation as below .
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
StringWriter stringWriter = new StringWriter();
File xml = new File("C:\\abc");
File xsl = new File("C:\\def.xsl");
factory.setNamespaceAware(true);
DocumentBuilder builder = factory.newDocumentBuilder();
document = builder.parse(xml);
TransformerFactory transformerFactory =
TransformerFactory.newInstance();
StreamSource style = new StreamSource(xsl);
Transformer transformer = transformerFactory.newTransformer(style);
DOMSource source = new DOMSource(document);
Also , can pass simple String params as below , without any issue as below :
transformer.setParameter("mode", "CREATE");
But , i want to pass an XML Document as a parameter to the XSL file . I tried below code as suggested on one of SO pages , as below :
DocumentBuilder builder = factory.newDocumentBuilder();
final Document documentFile = builder.parse(xml2);
Map<String, Document> docs = new HashMap<String, Document>();
docs.put("lookup", documentFile);
transformer.setURIResolver(new DocumentURIResolver(docs));
And i set , the tag in XML to receive value as below :
<xsl:variable name="lookup" select="('documentFile')/> .
But its not working for me . Can anyone help me out with the correct pay to pass multiple XML documents to any XSL file via javax.xml.transform API ?
Update
Still stuck with the issue ,can any one let me how can i pass XML object into a XSLT 2.0 stylesheet as a param . I have tried different approaches but no luck still . I need to know a way out via JAVA xsl transform API .
I think your issue is in the XSLT. Change
<xsl:variable name="lookup" select="('documentFile')/> .
to
<xsl:variable name="lookup" select="document('lookup')/>
this will cause the transformer to make the DOM of your document accessible in the variable lookup. The key lookup comes from docs.put("lookup", documentFile);
Dynamically Pass Multiple XML Sources to XSL Transformation via URIResolver.
Full Working Example:
Be there three XML files: repo.xml, books.xml and articles.xml. The repo.xml contains status information about books and articles. The files articles.xml and books.xml contain title information about each item. The goal is to print status information of all books and articles together with the title information. The entries in all files are connected via id keys.
Find complete example at github or copy/paste the listings below.
repo.xml
<repository>
<book>
<id>1</id>
<status>available</status>
</book>
<book>
<id>2</id>
<status>lost</status>
</book>
<article>
<id>1</id>
<status>in transit</status>
</article>
</repository>
books.xml
<books>
<book id="1">
<title>Book One</title>
</book>
<book id="2">
<title>Book Two</title>
</book>
<book id="3">
<title>Book Three</title>
</book>
</books>
articles.xml
<articles>
<article id="1">
<title>Article One</title>
</article>
<article id="2">
<title>Article Two</title>
</article>
<article id="3">
<title>Article Three</title>
</article>
</articles>
join.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
<titleStatusJoin>
<xsl:for-each select="//book">
<xsl:variable name="myId" select="id" />
<book>
<status>
<xsl:value-of select="status" />
</status>
<title>
<xsl:for-each select="document('bookFile')//book">
<xsl:variable name="bookId" select="#id" />
<xsl:choose>
<xsl:when test="$myId = $bookId">
<xsl:value-of select="title" />
</xsl:when>
</xsl:choose>
</xsl:for-each>
</title>
</book>
</xsl:for-each>
<xsl:for-each select="//article">
<xsl:variable name="myId" select="id" />
<article>
<status>
<xsl:value-of select="status" />
</status>
<title>
<xsl:for-each select="document('articleFile')//article">
<xsl:variable name="bookId" select="#id" />
<xsl:choose>
<xsl:when test="$myId = $bookId">
<xsl:value-of select="title" />
</xsl:when>
</xsl:choose>
</xsl:for-each>
</title>
</article>
</xsl:for-each>
</titleStatusJoin>
</xsl:template>
</xsl:stylesheet>
Use this Java code...
#Test
public void useMultipleXmlSourcesInOneXsl3() {
InputStream xml = Thread.currentThread().getContextClassLoader().getResourceAsStream("stack54335576/repo.xml");
InputStream xsl = Thread.currentThread().getContextClassLoader().getResourceAsStream("stack54335576/join3.xsl");
InputStream booksXml = Thread.currentThread().getContextClassLoader()
.getResourceAsStream("stack54335576/books.xml");
InputStream articlesXml = Thread.currentThread().getContextClassLoader()
.getResourceAsStream("stack54335576/articles.xml");
Document booksDom = readXml(booksXml);
Document articlesDom = readXml(articlesXml);
Map<String, Document> parameters = new HashMap<>();
parameters.put("bookFile", booksDom);
parameters.put("articleFile", articlesDom);
xslt(xml, xsl, parameters);
}
public final void xslt(InputStream xml, InputStream xsl, Map<String, Document> parameters) {
try {
TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer(new StreamSource(xsl));
transformer.setURIResolver((href, base) -> new DOMSource(parameters.get(href)));
transformer.transform(new StreamSource(xml), new StreamResult(System.out));
} catch (Exception e) {
throw new RuntimeException(e);
}
}
private Document readXml(InputStream xmlin) {
try {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
DocumentBuilder db = dbf.newDocumentBuilder();
return db.parse(xmlin);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
...to produce this output
<?xml version="1.0" encoding="UTF-8"?>
<titleStatusJoin>
<book>
<status>available</status>
<title>Book One</title>
</book>
<book>
<status>lost</status>
<title>Book Two</title>
</book>
<article>
<status>in transit</status>
<title>Article One</title>
</article>
</titleStatusJoin>
Did you already try this ?
org.w3c.dom.Document doc = ... // Your xml document
transformer.setParameter("demo", doc.getDocumentElement());
(Answer expanded to handle passing in a parsed W3C DOM document via a URIResolver)
This can be done in pure XSLT/XPath using the version of the Xalan XSLT processor that is supplied with the JRE.
As an example, say if the name of one of the input documents is passed in as a parameter to the Transformer:
File parentDir = new File("c:\\dir");
StringWriter stringWriter = new StringWriter();
File xml = new File(parentDir, "input.xml");
File xsl = new File(parentDir, "xslt-document-param.xslt");
Source xsltSource = new StreamSource(xsl);
Source xmlSource = new StreamSource(xml);
TransformerFactory transformerFactory = TransformerFactory
.newInstance();
Transformer transformer = transformerFactory.newTransformer(xsltSource);
transformer.setParameter("doc-name", "basic.xml");
transformer.transform(xmlSource, new StreamResult(stringWriter));
System.out.println(stringWriter);
This parameter can then be passed into the document() function in XPath as follows:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xalan="http://xml.apache.org/xalan"
version="1.0"
exclude-result-prefixes="xalan">
<xsl:output
method="xml"
indent="yes"
xalan:indent-amount="2"/>
<xsl:param name="doc-name"/>
<xsl:template match="/">
<xsl:variable name="doc-content" select="document($doc-name)"/>
<parent>
<xsl:for-each select="$doc-content/basic/*">
<child>
<xsl:value-of select="name(.)"/>
</child>
</xsl:for-each>
</parent>
</xsl:template>
</xsl:stylesheet>
This is able to read this basic.xml (from the parameter):
<basic>
<one/>
<two/>
<three/>
</basic>
And transform it to:
<parent>
<child>one</child>
<child>two</child>
<child>three</child>
</parent>
The parameter to the document() function is a URI. A relative path is resolved relative to the XSL file. Equally this could be a full URL, or resolved via a custom transformer.setURIResolver() as in the question.
(edit from here...)
To work with passing in a pre-parsed Document object to the XSLT, the URIResolver approach is able to handle passing this back to the document() function.
For example, with the lookup in the question:
File lookupXml = new File(parentDir, "basic.xml");
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(lookupXml);
Map<String, Document> docs = new HashMap<>();
docs.put("lookup", document);
transformer.setURIResolver((href, base) -> new DOMSource(docs.get(href)));
This XSL is able to iterate through the same basic.xml as above...
<xsl:template match="/">
<xsl:variable name="doc-content" select="document('lookup')"/>
<parent>
<xsl:for-each select="$doc-content/basic/*">
<child>
<xsl:value-of select="name(.)"/>
</child>
</xsl:for-each>
</parent>
</xsl:template>
... and output the same result.
Not sure about your issue , if you give usecase and ask how to solve will be more helpful insted of asking how to fix your code as we are not having end to end visiblity of your code and xml.
Following could be possible solution :
1) We can convert xml to string
try {
StringReader _reader = new StringReader("<xml>vkhan</xml>");
StringWriter _writer = new StringWriter();
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(
new javax.xml.transform.stream.StreamSource("styler.xsl"));//ur xsl
transformer.transform(
new javax.xml.transform.stream.StreamSource(_reader),
new javax.xml.transform.stream.StreamResult(_writer));
String result = writer.toString();
} catch (Exception e) {
e.printStackTrace();
}
2) Modify below code as per your requirments pass as List of object of call in for loop.
public class Data {
public static final Document transformXmlDocument(Document sourceDocument, InputStream xsltFile) {
DOMSource xmlSource = new DOMSource(sourceDocument);
StreamSource xsltSource = new StreamSource(xsltFile);
Document transformedData = null;
try {
TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer(xsltSource);
ByteArrayOutputStream output = new ByteArrayOutputStream();
StreamResult result = new StreamResult(output);
transformer.transform(xmlSource, result);
DocumentBuilder resultBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
transformedData = resultBuilder.parse(
new InputSource(
new StringReader(
new String(output.toByteArray())
)
)
);
} catch (Exception e) {
Log.e("XSLT Transformation", e.getMessage());
}
return transformedData;
}
}
https://gist.github.com/dazfuller/1559935/b84ee72db0e1de8ea25c54fbc744defbe4705ad9
Try to replace your <xsl:variable name="lookup" select="('documentFile')"/> instruction with <xsl:variable name="documentFile" select="document($lookup)"/> and pass your XML Document as a parameter with transformer.setParameter("lookup", "myfile.xml"); which means : load the document referenced by the lookup parameter into the documentFile variable.
See also Extract data from External XML file using XSL
I have an xml file like the following:
<?xml version="1.0"?>
<Book>
<Title>Ulysses</Title>
<Author>James <b>Joyce</b></Author>
</Book>
I need to parse this using Java into a pojo like
title="Ulysses"
author="James <b>Joyce</b>"
In other words, I need the html or possible custom xml tags to remain as plain text rather than xml elements, when parsing.
I can't edit the XML at all but it would be ok for me to create a custom xslt file to transform the xml.
I've got the following Java code for using xslt to assist with the reading of the xml,
TransformerFactory factory = TransformerFactory.newInstance();
Source stylesheetSource = new StreamSource(new File(stylesheetPathname).getAbsoluteFile());
Transformer transformer = factory.newTransformer(stylesheetSource);
Source inputSource = new StreamSource(new File(inputPathname).getAbsoluteFile());
Result outputResult = new StreamResult(new File(outputPathname).getAbsoluteFile());
transformer.transform(inputSource, outputResult);
This does apply my xslt to the file which is written out but I can't come up with the correct xslt to do it. I had a look at Add CDATA to an xml file but this does not work for me.
Essentially, I believe I want the file to look like
<?xml version="1.0"?>
<Book>
<Title>Ulysses</Title>
<Author><![CDATA[James <b>Joyce</b>]]></Author>
</Book>
Then I can extract
"James <b>Joyce</b>". I tried the approach suggested here: Add CDATA to an xml file
But it did not work for me.
I used the following xslt:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
<xsl:template match="Author">
<xsl:copy>
<xsl:text disable-output-escaping="yes"><![CDATA[</xsl:text>
<xsl:copy-of select="*"/>
<xsl:text disable-output-escaping="yes">]]></xsl:text>
</xsl:copy>
</xsl:template>
and this produced:
<?xml version="1.0" encoding="UTF-8"?>
Ulysses
<Author><![CDATA[
<b>Joyce</b>]]></Author>
Can you please help with this? I want the original document to be written out in it's entirety but with the CDATA surrounding everything within the author element.
Thanks
Isn't using a simple html/xml parser like Jsoup a better way of solving this?
Using Jsoup you can try something like this:
import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
import org.jsoup.nodes.Element;
import org.jsoup.parser.Parser;
import org.jsoup.select.Elements;
public class Example {
public static void main(String[] args) {
String xml = "<?xml version=\"1.0\"?>\n"
+ "<Book>\n"
+ " <Title>Ulysses</Title>\n"
+ " <Author>James <b>Joyce</b></Author>\n"
+ "</Book>";
Document doc = Jsoup.parse(xml, "", Parser.xmlParser());
doc.outputSettings().prettyPrint(false);
Elements books = doc.select("Book");
for(Element e: books){
Book b = new Book(e.select("Title").html(),e.select("Author").html());
System.out.println(b.title);
System.out.println(b.author);
}
}
public static class Book{
String title;
String author;
public Book(String title, String author) {
this.title = title;
this.author = author;
}
}
}
With XSLT 3.0 as supported by Saxon 9.8 HE (available on Maven and Sourceforge) you can use XSLT as follows:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
exclude-result-prefixes="xs math"
version="3.0">
<xsl:output cdata-section-elements="Author"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="Author">
<xsl:copy>
<xsl:apply-templates select="#*"/>
<xsl:value-of select="serialize(node())"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
As for your attempt, you basically need to "implement" the identity transformation template concisely written in XSLT 3.0 as <xsl:mode on-no-match="shallow-copy"/> as a template
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
in XSLT 1.0 so that those nodes not handled by more specialized template (like the one for Author elements) are recursively copied through.
Then, with the copy-of selecting all child nodes node() and not only the element nodes * you get
<xsl:template match="Author">
<xsl:copy>
<xsl:apply-templates select="#*"/>
<xsl:text disable-output-escaping="yes"><![CDATA[</xsl:text>
<xsl:copy-of select="node()"/>
<xsl:text disable-output-escaping="yes">]]></xsl:text>
</xsl:copy>
</xsl:template>
I am able to generate CSV file from XML file using XSLT, but the only header of XML file header is only showing on CSV file. The Values are not showing up.
Here is my java code:-
import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import org.w3c.dom.Document;
public class xml2csv {
public static void main() throws Exception {
File stylesheet = new File("C:/Users/Admin/Desktop/out.xslt");
File xmlSource = new File("C:/Users/Admin/Desktop/out.xml");
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(xmlSource);
StreamSource stylesource = new StreamSource(stylesheet);
Transformer transformer = TransformerFactory.newInstance().newTransformer(stylesource);
Source source = new DOMSource(document);
Result outputTarget = new StreamResult(new File("C:/Users/Admin/Desktop/out.csv"));
transformer.transform(source, outputTarget);
}
}
the XML file:-
<root>
<header>Symbol</header>
<row>NIFTY 50</row>
<row>LUPIN</row>
<header>Open</header>
<row>9,670.35</row>
<row>1,082.90</row>
<header>High</header>
<row>9,684.25</row>
<row>1,137.00</row>
</root>
XSLT file:-
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" >
<xsl:output method="text" omit-xml-declaration="yes" indent="no"/>
<xsl:template match="/">
Symbol,Open,High
<xsl:for-each select="//header">
<xsl:value-of select="concat(Symbol, ',', Open, ',', High)"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
So, I am getting only header of XML using this XSLT, where am I going wrong?
If I am guessing correctly at what you're trying to accomplish here, you will need to do something like:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="text"/>
<xsl:template match="/root">
<!-- header -->
<xsl:text>Symbol,Open,High
</xsl:text>
<!-- data -->
<xsl:variable name="n" select="count(row) div 3" />
<xsl:for-each select="row[position() <= $n]">
<xsl:variable name="i" select="position()" />
<xsl:text>"</xsl:text>
<xsl:value-of select="."/>
<xsl:text>","</xsl:text>
<xsl:value-of select="../row[$n + $i]"/>
<xsl:text>","</xsl:text>
<xsl:value-of select="../row[2 * $n + $i]"/>
<xsl:text>"
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Applied to your input example, the result will be:
Symbol,Open,High
"NIFTY 50","9,670.35","9,684.25"
"LUPIN","1,082.90","1,137.00"
I have added quotes around the values because some of them contain commas - but I did not handle the possibility of some them containing a quote.
As I mentioned in a comment to your question, this could be a lot easier if your XML were structured in a more friendly way.
I have an xml document that I need to sort by date. I have a java program that calls an xsl stylesheet template. The output is just the same xml but should be sorted by date descending. The sort is not working. The result I get is the output looks the same as the input.
Here is what the source xml looks like:
<?xml version="1.0"?>
<ABCResponse xmlns="http://www.example.com/Schema">
<ABCDocumentList>
<ABCDocument>
<DocumentType>APPLICATION</DocumentType>
<EffectiveDate>20140110010000</EffectiveDate>
<Name>JOE DOCS</Name>
</ABCDocument>
<ABCDocument>
<DocumentType>FORM</DocumentType>
<EffectiveDate>20140206010000</EffectiveDate>
<Name>JOE DOCS</Name>
</ABCDocument>
<ABCDocument>
<DocumentType>PDF</DocumentType>
<EffectiveDate>20140120010000</EffectiveDate>
<Name>JOE DOCS</Name>
</ABCDocument>
</ABCDocumentList>
</ABCResponse>
Java:
import java.io.File;
import java.io.StringReader;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
public class TestMisc {
/**
* #param args
*/
public static void main(String[] args) {
Source xmlInput = new StreamSource(new File("c:/temp/ABCListDocsResponse.xml"));
Source xsl = new StreamSource(new File("c:/temp/DocResponseDateSort.xsl"));
Result xmlOutput = new StreamResult(new File("c:/temp/ABC_output1.xml"));
try {
javax.xml.transform.TransformerFactory transFact =
javax.xml.transform.TransformerFactory.newInstance( );
javax.xml.transform.Transformer trans = transFact.newTransformer(xsl);
trans.transform(xmlInput, xmlOutput);
} catch (TransformerException e) {
}
}
}
Here is the XSL
XSL:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ABCResponse/ABCDocumentList/ABCDocument">
<xsl:copy>
<xsl:apply-templates select="#*|node()">
<xsl:sort select="EffectiveDate" data-type="number" order="descending"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you want to sort the ABCDocuments, you need to stop one level higher. You also need to use namespaces correctly since your source XML uses namespaces:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ex="http://www.example.com/Schema">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ex:ABCDocumentList">
<xsl:copy>
<xsl:apply-templates select="ex:ABCDocument">
<xsl:sort select="ex:EffectiveDate" data-type="number" order="descending"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
========= UPDATE =========
Many thanks to Tomalak for the correct XSL syntax, and to Ian Roberts for pointing out that in order to use namespaces in my XSLT, I need to call "setNamespaceAware(true)" at the very beginning, in my DocumentBuilderFactory.
========= END UPDATE =========
Q: How can I write an XSLT stylesheet that filters out all elements and/or all node trees in the "http://foo.com/abc" namespace?
I have an XML file that looks like this:
SOURCE XML:
<zoo xmlns="http://myurl.com/wsdl/myservice">
<animal>elephant</animal>
<exhibit>
<animal>walrus</animal>
<animal>sea otter</animal>
<trainer xmlns="http://foo.com/abc">Jack</trainer>
</exhibit>
<exhibit xmlns="http://foo.com/abc">
<animal>lion</animal>
<animal>tiger</animal>
</exhibit>
</zoo>
DESIRED RESULT XML:
<zoo xmlns="http://myurl.com/wsdl/myservice">
<animal>elephant</animal>
<exhibit>
<animal>walrus</animal>
<animal>sea otter</animal>
</exhibit>
</zoo>
XSLT (thanks to Tomalak):
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:a="http://foo.com/abc"
exclude-result-prefixes="a"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="a:* | #a:*" />
</xsl:stylesheet>
Thank you in advance!
JAVA PROGRAM THAT SUCCESSFULLY DOES THE XSLT FILTERING BY NAMESPACE:
import java.io.*;
import org.w3c.dom.*; // XML DOM
import javax.xml.parsers.*; // DocumentBuilder, etc
import javax.xml.transform.*; // Transformer, etc
import javax.xml.transform.stream.*; // StreamResult, StreamSource, etc
import javax.xml.transform.dom.DOMSource;
public class Test {
public static void main(String[] args) {
new Test().testZoo();
}
public void testZoo () {
String zooXml = Test.readXmlFile ("zoo.xml");
if (zooXml == null)
return;
try {
// Create a new document builder factory, and make sure it[s namespace-aware
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
DocumentBuilder docBuilder = dbf.newDocumentBuilder ();
// Read XFDD input string into DOM
Document xfddDoc =
docBuilder.parse(new StringBufferInputStream (zooXml));
// Filter out all elements in "http://foo.com/abc" namespace
StreamSource styleSource = new StreamSource (new File ("zoo.xsl"));
Transformer transformer =
TransformerFactory.newInstance().newTransformer (styleSource);
// Convert final DOM back to String
StringWriter buffer = new StringWriter ();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes"); // Remember: we want to insert this XML as a subnode
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.transform(new DOMSource(xfddDoc), new StreamResult (buffer));
String translatedXml = buffer.toString();
}
catch (Exception e) {
System.out.println ("convertTransactionData error: " + e.getMessage());
e.printStackTrace ();
}
}
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:a="http://foo.com/abc"
exclude-result-prefixes="a"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="a:* | #a:*" />
</xsl:stylesheet>
Empty templates match nodes but do not output anything, effectively removing what they match.