This question already has answers here:
Is it possible to decrypt MD5 hashes?
(24 answers)
Closed 3 years ago.
My problem is revert operation encode .
String computedLtpaTokenMd5 = new String(Base64.encodeBase64(MessageDigest.getInstance("MD5").digest(ltpaToken.getBytes())));
how to recover the token ltpaToken by computedLtPaTOkenMD5?
You cannot.
That is the whole point of a cryptographic hash function (which MD5 is, or rather was, you should not use it anymore): It is one-way.
All you can do is check if a given token matches that hashed value (by running the same hash function again and either getting the same output or not).
(You can reverse the Base64 encoding, but not the MD5 hashing)
Related
This question already has answers here:
How to convert byte[] to Byte[] and the other way around?
(9 answers)
Closed 3 years ago.
I want to convert a Byte array into a byte array, but I don't see any way to do so in java without using a loop.
Can someone please tell me a way to make it ?
There is no need for that, because Java has an auto-unboxing system that automatically converts Bytes to bytes. So, you can use them the same way. But if you really have to, you have to use a loop.
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Why is char[] preferred over String for passwords?
(17 answers)
Closed 7 years ago.
I am writing a little web framework and I want to enable SSL encryption with a SSL key which will be supplied by the user.
This might seem overly cautious, but is it common to pass the password for the keystore file as a String passed in the parameters of a method?
This is what I had in mind:
public void enableSSL(String keystorePath, String keystorePassword) {
// ... do things
}
It is always safer to store the password into character array than a string.
Please refer below query:
Why is char[] preferred over String for passwords?
Also refer the below coding guide lines from oracle site:
http://www.oracle.com/technetwork/java/seccodeguide-139067.html#2
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 8 years ago.
I'm trying to do a comparison in Java with 2 strings containing a extended ASCII character.
boolean result = "éasdfasdf".substring(0,1).equals("é");
Can somebody explain why this results false? I think it has something to do with character encoding, but I can't figure out what exactly the problem is here...
Update: ideone.com does successfully run these 2 lines, so the problem is locally in my box. I think I found some more proof of that:
System.out.println("éb".charAt(1) == 'b');
Does also fails... Can it be the problem of 2 different character encodings?
Use
boolean result = "éasdfasdf".substring(0,1).equals("é")
And it will give expected result!The reason is simple - using '==' you compare objects by reference, not by value. So equals() solves this problem
This question already has answers here:
What type of hash does WordPress use?
(11 answers)
Closed 8 years ago.
How can i encrypt password to get the same output like wordpress to compare it later with my db ?
As mentioned here WordPress uses the PasswordHash class from the phpass for generating the password hashes. According to the links, the default implementation used involves the use of a salt, and 8 rounds of MD5 hashing. Exactly how and when the salt is applied, and what goes into the MD5 don't seem to be readily available. However, there seem to be a java port of phpass here.
As I stated in the comments, WordPress uses MD5 to encrypt its passwords. Here's a link to some code about password hashing in PHP, which I think might be what you're looking for:
Password Hashing In PHP
This question already has answers here:
Guessing the encoding of text represented as byte[] in Java
(7 answers)
Closed 8 years ago.
I'm receiving a byte[] of information in an unspecified encoding format. Is there a way to convert it to a String without knowing the character encoding?
The tool of choice is CharsetMatch from ICU: http://userguide.icu-project.org/conversion/detection
It is not an exact science, so there is a confidence score that you have to watch and it will take some experimentation, but will definitely get you where you want to go. Good Luck!