I am trying to draw an arc within another arc at at distance of 10px in Wear OS.
We know that an arc can be drawn using the following:
canvas.drawArc(arcBounds, 0, 90, false, paint);
The above statement will draw an arc from 3pm to 6pm.
I would like to draw another arc at the same startAngle and sweepAngle within the above arc.
Assuming that the total number of arc that need to be drawn is based on the size of a list, how can I achieve the expected output?
Here is what my original arcBounds init method looks like:
private void initArcBounds(int width, int height, int additionalMargin) {
float margin = res.getDimension(R.dimen.timearc_margin) + additionalMargin;
arcBounds.left = margin;
arcBounds.top = margin;
arcBounds.right = width - margin;
arcBounds.bottom = height - margin;
}
for (Event el : eventList) {
canvas.drawArc(arcBounds, start, sweepAngle, false, timeArcPaints);
arcBounds.inset(10,10);
}
To create concentric arcs inward, we just need to "shrink" the bounds by the desired measure on each side. The RectF class has the convenient inset(dx, dy) method which will do just that. It expects those measures in pixels, so we can simply pass 10 for each, with no adjustments needed.
This will modify the RectF's bounds, so to keep those at their initial values in the original, we can create a temporary copy before the draw loop with RectF's copy constructor.
For example, altogether:
RectF temp = new RectF(arcBounds);
for (...) {
canvas.drawArc(temp, 0, 90, false, paint);
temp.inset(10f, 10f);
}
Related
double degPi = degrees * Math.PI / 180;
double a = Math.cos(degPi)*tImgCover.getScaledHeight();
double b = Math.sin(degPi)*tImgCover.getScaledWidth();
double c = -Math.sin(degPi) * tImgCover.getScaledHeight();
double d = Math.cos(degPi)* tImgCover.getScaledWidth();
double e = absX;
double f = absY;
contentByte.addImage(imgae, a, b, c, d, e, f);/*add image*/
How to rotate around the image center by itext?
If we have an Image image and coordinates x, y, we can draw the image without rotation with its lower left corner at the given coordinates like this
contentByte.addImage(image, image.getWidth(), 0, 0, image.getHeight(), x, y);
A bitmap image from the resources has a size of 1x1 with the coordinate origin at its lower left. Thus, this operation stretches the image to its correct size and moves it so its lower left is at the given coordinates.
If we want to draw the same image as if the one drawn above was rotated around its center by an angle rotate, therefore, we can do this by moving the 1x1 image so that the origin is in its center, stretch it to its correct size, rotate it, and then move the origin (which still is at the center of the rotated image) to the center of the unrotated image. These operations are easier to express using AffineTransform instances (from package com.itextpdf.awt.geom) instead number tupels. Thus:
// Draw image as if the previous image was rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Stretch it to its dimensions
AffineTransform B = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform C = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform D = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedImage)
For example drawing both images using
int x = 200;
int y = 300;
float rotate = (float) Math.PI / 3;
results in something like this:
With a Flip
The OP asked in a comment
how to add rotate and flip image？
For this you simply insert a mirroring affine transformation into the sequence of transformations above.
Unfortunately the OP did not mention which he meant a horizontal or a vertical flip. But as changing the rotation angle accordingly transforms one in the other, that isn't really necessary, either.
// Draw image as if the previous image was flipped and rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Flip it horizontally
AffineTransform B = new AffineTransform(-1, 0, 0, 1, 0, 0);
// Stretch it to its dimensions
AffineTransform C = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform D = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform E = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
M.preConcatenate(E);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedFlippedImage)
The result with the same image as above:
With Interpolation
The OP asked in a yet another comment
How anti aliasing ?
The iText Image class knows an Interpolation property. By setting it to true (before adding the image to the document, obviously),
image.setInterpolation(true);
low resolution images are subject to interpolation when drawn.
E.g. using a 2x2 image with differently colored pixels instead of the image of Willi, you get the following results, first without interpolation, then with interpolation:
Confer the AddRotatedImage.java test testAddRotatedInterpolatedImage which adds this image:
Beware: iText Image property Interpolation effectively sets the Interpolate entry in the PDF image dictionary. The PDF specification notes in this context:
NOTE A conforming Reader may choose to not implement this feature of PDF, or may use any specific implementation of interpolation that it wishes.
Thus, on some viewers interpolation may occur differently than in your viewer, maybe even not at all. If you need a specific kind of interpolation on every viewer, upscale the image with the desired amount of interpolation / anti-aliasing before loading it into an iText Image.
public static BufferedImage rotateClockwise90( BufferedImage inputImage ){
int width = inputImage.getWidth();
int height = inputImage.getHeight();
BufferedImage returnImage = new BufferedImage( height, width , inputImage.getType() );
for( int x = 0; x < width; x++ ) {
for( int y = 0; y < height; y++ ) {
returnImage.setRGB( height-y-1, x, inputImage.getRGB( x, y ) );
}
}
return returnImage;
}
Does anyone know whether libGDX has a method for scrolling/shifting an image/texture within itself?
To explain; I would like to be able to scroll the contents (pixels) of an image, either vertically or horizontally within its own region. For example, if an image is shifted 1 pixel to the right, all pixels move 1 to the right and those on the right-most-edge are wrapped to the left-most-edge. The image size does not change, only the positioning of the pixels within it change.
I have mainly been working with the Sprite class, it can do a lot (scale, rotate, etc) but shift/scroll as I need it, isn't there.
Before writting the method myself, I thought I'd ask here...
The following worked for me, this was provided by Kush:
float delta = 0f;
// In the Actors act method
delta += Gdx.graphics.getDeltaTime();
// Horizontal
batch.draw(texture, 0, 0, width, height, 0 + delta * 10, 1, 1 + delta * 10, 0);
// Vertical
batch.draw(texture, 0, 0, width, height, 1, 0 + delta * 10, 0, 1 + delta * 10);
You won't need Sprite for this, draw directly Texture using batch. For wrapping first set
Texture texture = new Texture("example.png");
texture.setWrap(TextureWrap.Repeat, TextureWrap.Repeat);
then draw using uv
batch.draw(texture, x, y, width, height, u, v, u2, v2);
or any other method that suits you in SpriteBatch.
More adventures with Graphics2D!
This time I'm investigating the various paint / colour modes and ways to paint complex borders. The typical method is to fill the Shape or Polygon, and then draw the same Shape over the top (in a different colour). I'm familiar with setting Strokes and so forth to vary border thickness and other bits.
My latest attempt was to use RadialGradientPaint as a way of defining multiple bands of colour, but this doesn't appear to apply to the draw / drawPolygon call (or the extra colours aren't showing up.
The draw call is drawing a thickness 3 empty Polygon, but as a uniformly-blue strip. Below is the gradient / paintComponent code:
g2d.setStroke(new BasicStroke(h.getHexBorderWidth())); // this is set to 3
Point2D center = new Point2D.Float(50, 50);
float radius = 1;
float[] dist = {0.0f, 0.5f, 1.0f};
Color[] colors = {Color.RED, Color.WHITE, Color.BLUE};
// the float value is defined as 0.0 in the constructor
RadialGradientPaint p =
new RadialGradientPaint(center, radius, new Point2D.Float(), dist, colors,
CycleMethod.NO_CYCLE);
g2d.setPaint(p);
if(((BasicHexagon) h).isAnimating()
&& ((BasicHexagon) h).getCurrentTransform() != null) { // just general null checks
g2d.draw(((BasicHexagon) h).getCurrentTransform()); // this is a transformed Shape
} else {
g2d.drawPolygon(h.getBase()); // this is a Polygon
}
Any better ways I'm missing out on, or any way that this isn't being called correctly?
I want to draw some (filled) polygons with libGDX. It shoudn't be filled with a graphic/texture. I have only the vertices of the polygon (closed path) and tried to visualize with meshes but at some point this is not the best solution, I think.
My code for an rectangle is:
private Mesh mesh;
#Override
public void create() {
if (mesh == null) {
mesh = new Mesh(
true, 4, 0,
new VertexAttribute(Usage.Position, 3, "a_position")
);
mesh.setVertices(new float[] {
-0.5f, -0.5f, 0
0.5f, -0.5f, 0,
-0.5f, 0.5f, 0,
0.5f, 0.5f, 0
});
}
}
// ...
#Override
public void render() {
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
mesh.render(GL10.GL_TRIANGLE_STRIP, 0, 4);
}
is there a function or something to draw filled polygons in an easier way?
Since recent updates of LibGDX, #Rus answer is using deprecated functions. However, I give him/her credits for the new updated version below:
PolygonSprite poly;
PolygonSpriteBatch polyBatch = new PolygonSpriteBatch(); // To assign at the beginning
Texture textureSolid;
// Creating the color filling (but textures would work the same way)
Pixmap pix = new Pixmap(1, 1, Pixmap.Format.RGBA8888);
pix.setColor(0xDEADBEFF); // DE is red, AD is green and BE is blue.
pix.fill();
textureSolid = new Texture(pix);
PolygonRegion polyReg = new PolygonRegion(new TextureRegion(textureSolid),
new float[] { // Four vertices
0, 0, // Vertex 0 3--2
100, 0, // Vertex 1 | /|
100, 100, // Vertex 2 |/ |
0, 100 // Vertex 3 0--1
}, new short[] {
0, 1, 2, // Two triangles using vertex indices.
0, 2, 3 // Take care of the counter-clockwise direction.
});
poly = new PolygonSprite(polyReg);
poly.setOrigin(a, b);
polyBatch = new PolygonSpriteBatch();
For good triangulating algorithms if your polygon is not convex, see the almost-linear earclipping algorithm from Toussaint (1991)
Efficient triangulation of simple polygons, Godfried Toussaint, 1991
Here is a libGDX example which draws a 2D concave polygon.
Define class members for PolygonSprite PolygonSpriteBatch
PolygonSprite poly;
PolygonSpriteBatch polyBatch;
Texture textureSolid;
Create instances, 1x1 size texture used with red pixel as workaround. An array of coordinates (x, y) is used for initialization of the polygon.
ctor() {
textureSolid = makeTextureBox(1, 0xFFFF0000, 0, 0);
float a = 100;
float b = 100;
PolygonRegion polyReg = new PolygonRegion(new TextureRegion(textureSolid),
new float[] {
a*0, b*0,
a*0, b*2,
a*3, b*2,
a*3, b*0,
a*2, b*0,
a*2, b*1,
a*1, b*1,
a*1, b*0,
});
poly = new PolygonSprite(polyReg);
poly.setOrigin(a, b);
polyBatch = new PolygonSpriteBatch();
}
Draw and rotate polygon
void draw() {
super.draw();
polyBatch.begin();
poly.draw(polyBatch);
polyBatch.end();
poly.rotate(1.1f);
}
I believe the ShapeRenderer class now has a polygon method for vertex defined polygons:
ShapeRenderer.polygon()
You can use the ShapeRenderer API to draw simple, solid-color shapes with Libgdx.
The code you've given is a reasonable way to draw solid color polygons too. Its much more flexible than ShapeRenderer, but is a good bit more complicated. You'll need to use glColor4f to set the color, or add a Usage.Color attribute to each vertex. See the SubMeshColorTest example for more details on the first approach and the MeshColorTexture example for details on the second approach.
Another option to think about is using sprite textures. If you're only interested in simple solid colors objects, you can use very simple 1x1 textures of a single color and let the system stretch that across the sprite. Much of Libgdx and the underlying hardware are really optimized for rendering textures, so you may find it easier to use even if you're not really taking advantage of the texture contents. (You can even use a 1x1 white texture, and then use a SpriteBatch with setColor and draw()
to draw different color rectangles easily.)
You can also mix and match the various approaches, too.
Use triangulation algorithm and then draw all triangles as GL_TRIANGLE_STRIP
http://www.personal.psu.edu/cxc11/AERSP560/DELAUNEY/13_Two_algorithms_Delauney.pdf
just wanted to share my related solution with you, namely for implementing and drawing a walkZone with scene2d. I basically had to put together the different suggestions of the others' posts:
1) The WalkZone:
import com.badlogic.gdx.graphics.Pixmap;
import com.badlogic.gdx.graphics.Texture;
import com.badlogic.gdx.graphics.g2d.PolygonRegion;
import com.badlogic.gdx.graphics.g2d.TextureRegion;
import com.badlogic.gdx.math.EarClippingTriangulator;
import com.badlogic.gdx.math.Polygon;
import com.mygdx.game.MyGame;
public class WalkZone extends Polygon {
private PolygonRegion polygonRegion = null;
public WalkZone(float[] vertices) {
super(vertices);
if (MyGame.DEBUG) {
Pixmap pix = new Pixmap(1, 1, Pixmap.Format.RGBA8888);
pix.setColor(0x00FF00AA);
pix.fill();
polygonRegion = new PolygonRegion(new TextureRegion(new Texture(pix)),
vertices, new EarClippingTriangulator().computeTriangles(vertices).toArray());
}
}
public PolygonRegion getPolygonRegion() {
return polygonRegion;
}
}
2) The Screen:
you can then add a listener in the desired Stage:
myStage.addListener(new InputListener() {
#Override
public boolean touchDown(InputEvent event, float x, float y, int pointer, int button) {
if (walkZone.contains(x, y)) player.walkTo(x, y);
// or even directly: player.addAction(moveTo ...
return super.touchDown(event, x, y, pointer, button);
}
});
3) The implementation:
The array passed to te WZ constructor is a set of x,y,x,y... points. If you put them counter-clockwise, it works (I didn't check the other way, nor know how it exactly works); for example this generates a 100x100 square:
yourScreen.walkZone = new WalkZone(new int[]{0, 0, 100, 0, 100, 100, 0, 100});
In my project it works like a charm, even with very intricated polygons. Hope it helps!!
Most answers suggest triangulation, which is fine, but you can also do it using the stencil buffer. It handles both convex and concave polygons. This may be a better solution if your polygon changes a lot, since otherwise you'd have to do triangulation every frame. Also, this solution properly handles self intersecting polygons, which EarClippingTriangulator does not.
FloatArray vertices = ... // The polygon x,y pairs.
Color color = ... // The color to draw the polygon.
ShapeRenderer shapes = ...
ImmediateModeRenderer renderer = shapes.getRenderer();
Gdx.gl.glClearStencil(0);
Gdx.gl.glClear(GL20.GL_STENCIL_BUFFER_BIT);
Gdx.gl.glEnable(GL20.GL_STENCIL_TEST);
Gdx.gl.glStencilFunc(GL20.GL_NEVER, 0, 1);
Gdx.gl.glStencilOp(GL20.GL_INVERT, GL20.GL_INVERT, GL20.GL_INVERT);
Gdx.gl.glColorMask(false, false, false, false);
renderer.begin(shapes.getProjectionMatrix(), GL20.GL_TRIANGLE_FAN);
renderer.vertex(vertices.get(0), vertices.get(1), 0);
for (int i = 2, n = vertices.size; i < n; i += 2)
renderer.vertex(vertices.get(i), vertices.get(i + 1), 0);
renderer.end();
Gdx.gl.glColorMask(true, true, true, true);
Gdx.gl.glStencilOp(GL20.GL_ZERO, GL20.GL_ZERO, GL20.GL_ZERO);
Gdx.gl.glStencilFunc(GL20.GL_EQUAL, 1, 1);
Gdx.gl.glEnable(GL20.GL_BLEND);
shapes.setColor(color);
shapes.begin(ShapeType.Filled);
shapes.rect(-9999999, -9999999, 9999999 * 2, 9999999 * 2);
shapes.end();
Gdx.gl.glDisable(GL20.GL_STENCIL_TEST);
To use the stencil buffer, you must specify the number of bits for the stencil buffer when your app starts. For example, here is how to do that using the LWJGL2 backend:
LwjglApplicationConfiguration config = new LwjglApplicationConfiguration();
config.stencil = 8;
new LwjglApplication(new YourApp(), config);
For more information on this technique, try one of these links:
http://commaexcess.com/articles/7/concave-polygon-triangulation-shortcut
http://glprogramming.com/red/chapter14.html#name13
http://what-when-how.com/opengl-programming-guide/drawing-filled-concave-polygons-using-the-stencil-buffer-opengl-programming/
I want it to be at 0 on the y-axis, that is what I mean by flat to the ground.
I am making the floor of my game in android, I am using opengl es 1. I have a square I am using as the floor, so obviously I want it to be flat to the ground. I want the y-axis to be 0, but whenever I set it to this the square isn't on the screen. But if I set all of the y-axis to 0.1 then the square is hovering from the center of the screen to the top right corner, not flat to the ground.
This is the vertices array:
float w = 10;
float h = 10;
float vertices[] ={
0f, 0.1f, 0f,
w, 0.1f, 0f,
0f, 0.1f, -h,
w, 0.1f, -h
};
I am then storing it in the normal float buffer:
ByteBuffer vbb = ByteBuffer.allocateDirect(vertices.length * 4);
vbb.order(ByteOrder.nativeOrder());
mFVertexBuffer = vbb.asFloatBuffer();
mFVertexBuffer.put(vertices);
mFVertexBuffer.position(0);
And then when it comes to drawing it:
gl.glDrawElements( GL10.GL_TRIANGLES,2*3, GL10.GL_UNSIGNED_BYTE, mIndexBuffer);
And this is setting up the frustum, which I don't think should make a difference but...
public void onSurfaceChanged(GL10 gl, int width, int height) {
gl.glViewport(0, 0, width, height);
float aspectRatio;
float zNear =.1f;
float zFar = 1000f;
float fieldOfView = 1f;
float size;
gl.glEnable(GL10.GL_NORMALIZE);
aspectRatio=(float)width/(float)height;
gl.glMatrixMode(GL10.GL_PROJECTION);
size = zNear * (float)(Math.tan((double)(fieldOfView/2.0f)));
gl.glFrustumf(-size, size, -size /aspectRatio,
size /aspectRatio, zNear, zFar);
gl.glMatrixMode(GL10.GL_MODELVIEW);
}
Why is it not flat? and why when the y-axis is 0, does it disappear?
I am tring to achieve this:
Where the white section is the floor.
Your object is "disappearing", because your object has no height.
It's like if you were holding an infinitely thin piece of paper flat in front of your eyes. If the paper is above or below your field of vision, then you can see it, but if you put it exactly parallel to your eyes, you wouldn't be able to see it.
It's not really clear to me what you expect it to look like. How do you want this floor to look, will you be looking at it from above, or from an angle? Do you want it to fill from the center of the screen to the bottom? Maybe a mockup image could really help explain what you're trying to achieve.