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Can any one help me with the Java equivalent of this?
wordCountRDD.saveAsNewAPIHadoopFile(outputFile,classOf[Text],classOf[IntWritable],classOf[TextOutputFormat[Text,IntWritable]])
I tried below : but it give me error at TextOutputFormat<>(Text,IntWritable) ..
wordCountRDD.saveAsNewAPIHadoopFile(
output,
Text.class,
IntWritable.class,
TextOutputFormat<>(Text,IntWritable)
context.hadoopConfiguration());
Here:
TextOutputFormat<>(Text,IntWritable)
You have to pass the class instead:
TextOutputFormat.class
But note: the java type system doesn't allow you to express something like. TextOutputFormat<Text,IntWritable>.class! See here for why that is.
From that point of view, TextOutputFormat.class seems to be your only option.
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C:\Users>javaC C:\Main.java
C:\Main.java:1: error: error while writing Main: C:\Main.class
public class Main {
^
1 error
The error indicates that javac cannot create the compilation output C:\Main.class.
By default, a normal user does not have write access to the root of the C: drive. Create your class elsewhere (not directly in C:\), but for example in C:\development.
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This Code works fine in java 7.
Iteration in java 8 is successful but I am stacked while if else decision making.
I have one list in which i have integer as well as double value. How can i parse this and set to in model class?
AverageRatingModel avgRatingModel = new AverageRatingModel();
for(Property p:propertylist){
if(p.getName().equals("averagevote")){
avgRatingModel.setAvgRating(Double.parseDouble(p.getValue()));
}
if(p.getName().equals("nbvotes")){
avgRatingModel.setNoOfVotes(Integer.parseInt(p.getValue()));
}
}
You can use two streams but it would be horrible. It would must better to have a data structure which is designed for Properties.
properties.ifPresentDouble("averagevote", avgRatingModel::setAvgRating);
properties.ifPresentInt("nbvotes", avgRatingModel::setNoOfVotes);
You code will be much cleaner if you have useful data structure for your properteis.
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For example, I have my main method as well as the method returnOdds(original), that returns the integer array "odd"
How would I print the elements of this array in the main method? With a for loop?
A for loop would work. If you don't care about the format, though, a simpler solution might be to use Arrays.toString, which will convert in the form "[elem1, elem2, ..., elemn]".
"With a for loop?"
answer : "yes"
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My sqlserver table has a column designed as a BIT datatype. It has values 1 and 0s
Then in my Java code, I do
result = new ArrayList
result.add( (Boolean)(rs.getBoolean("columnName")));
Then when I read the value from the list - it shows as Long.
According to everything I find, it says hat a BIT datatype is supposed to map to boolean.
Why does it come as Long?
What can be done to fix this?
You can call getBoolean directly and let it take care of all the casting/coverting:
result.add(rs.getBoolean("columnName"));
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String[] arraylist = {"0","0","0","0","0","0","0"};
but now I want to replace inside the array above to 1, to make it like this
String[] arraylist = {"0","0","0","1","0","0","0"};
Once try follow if you know position you want to change
arraylist[3]="1";
Hope this will helps you.