I have an Object array which is a list of argument values a function could take. This could be any complex object.
I am trying to build a json out of the Object array using gson as below:
private JsonArray createArgsJsonArray(Object... argVals) {
JsonArray argsArray = new JsonArray();
Arrays.stream(argVals).forEach(arg -> argsArray.add(gson.toJson(arg)));
return argsArray;
}
This treats all the arg values as String.
It escapes the String args
"args":["\"STRING\"","1251996697","85"]
I prefer the following output:
"args":["STRING",1251996697,85]
Is there a way to achieve this using gson?
I used org.json, I was able to achieve the desired result, but it does not work for complex objects.
EDIT:
I applied the solution provided by #Michał Ziober, but now how do I get back the object.
Gson gson = new Gson();
Object strObj = "'";
JsonObject fnObj = new JsonObject();
JsonObject fnObj2 = new JsonObject();
fnObj.add("response", gson.toJsonTree(strObj));
fnObj2.addProperty("response", gson.toJson(strObj));
System.out.println(gson.fromJson(fnObj.toString(),
Object.class)); --> prints {response='} //Not what I want!
System.out.println(gson.fromJson(fnObj2.toString(),
Object.class)); --> prints {response="\u0027"}
Use toJsonTree method:
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.google.gson.JsonArray;
import java.util.Date;
public class GsonApp {
public static void main(String[] args) {
GsonApp app = new GsonApp();
System.out.println(app.createArgsJsonArray("text", 1, 12.2D));
System.out.println(app.createArgsJsonArray(new Date(), new A(), new String[] {"A", "B"}));
}
private Gson gson = new GsonBuilder().create();
private JsonArray createArgsJsonArray(Object... argVals) {
JsonArray argsArray = new JsonArray();
for (Object arg : argVals) {
argsArray.add(gson.toJsonTree(arg));
}
return argsArray;
}
}
class A {
private int id = 12;
}
Above code prints:
["text",1,12.2]
["Sep 19, 2019 3:25:20 PM",{"id":12},["A","B"]]
If you want to end up with a String, just do:
private String createArgsJsonArray(Object... argVals) {
Gson gson = new Gson();
return gson.toJson(argVals);
}
If you wish to collect it back and alter just do:
Object[] o = new Gson().fromJson(argValsStr, Object[].class);
Try using setPrettyPrinting with DisableHtml escaping.
Gson gson = new GsonBuilder().setPrettyPrinting().disableHtmlEscaping().create();
JsonParser jp = new JsonParser();
JsonElement je = jp.parse(jsonArray.toString());
System.out.println( gson.toJson(je));
Related
I have a JsonObject named "mapping" with the following content:
{
"client": "127.0.0.1",
"servers": [
"8.8.8.8",
"8.8.4.4",
"156.154.70.1",
"156.154.71.1"
]
}
I know I can get the array "servers" with:
mapping.get("servers").getAsJsonArray()
And now I want to parse that JsonArray into a java.util.List...
What is the easiest way to do this?
Definitely the easiest way to do that is using Gson's default parsing function fromJson().
There is an implementation of this function suitable for when you need to deserialize into any ParameterizedType (e.g., any List), which is fromJson(JsonElement json, Type typeOfT).
In your case, you just need to get the Type of a List<String> and then parse the JSON array into that Type, like this:
import java.lang.reflect.Type;
import com.google.gson.reflect.TypeToken;
JsonElement yourJson = mapping.get("servers");
Type listType = new TypeToken<List<String>>() {}.getType();
List<String> yourList = new Gson().fromJson(yourJson, listType);
In your case yourJson is a JsonElement, but it could also be a String, any Reader or a JsonReader.
You may want to take a look at Gson API documentation.
Below code is using com.google.gson.JsonArray.
I have printed the number of element in list as well as the elements in List
import java.util.ArrayList;
import com.google.gson.Gson;
import com.google.gson.JsonArray;
import com.google.gson.JsonObject;
import com.google.gson.JsonParser;
public class Test {
static String str = "{ "+
"\"client\":\"127.0.0.1\"," +
"\"servers\":[" +
" \"8.8.8.8\"," +
" \"8.8.4.4\"," +
" \"156.154.70.1\"," +
" \"156.154.71.1\" " +
" ]" +
"}";
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
JsonParser jsonParser = new JsonParser();
JsonObject jo = (JsonObject)jsonParser.parse(str);
JsonArray jsonArr = jo.getAsJsonArray("servers");
//jsonArr.
Gson googleJson = new Gson();
ArrayList jsonObjList = googleJson.fromJson(jsonArr, ArrayList.class);
System.out.println("List size is : "+jsonObjList.size());
System.out.println("List Elements are : "+jsonObjList.toString());
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
OUTPUT
List size is : 4
List Elements are : [8.8.8.8, 8.8.4.4, 156.154.70.1, 156.154.71.1]
I read solution from official website of Gson at here
And this code for you:
String json = "{"client":"127.0.0.1","servers":["8.8.8.8","8.8.4.4","156.154.70.1","156.154.71.1"]}";
JsonObject jsonObject = new Gson().fromJson(json, JsonObject.class);
JsonArray jsonArray = jsonObject.getAsJsonArray("servers");
String[] arrName = new Gson().fromJson(jsonArray, String[].class);
List<String> lstName = new ArrayList<>();
lstName = Arrays.asList(arrName);
for (String str : lstName) {
System.out.println(str);
}
Result show on monitor:
8.8.8.8
8.8.4.4
156.154.70.1
156.154.71.1
I was able to get the list mapping to work with just using #SerializedName for all fields.. no logic around Type was necessary.
Running the code - in step #4 below - through the debugger, I am able to observe that the List<ContentImage> mGalleryImages object populated with the JSON data
Here's an example:
1. The JSON
{
"name": "Some House",
"gallery": [
{
"description": "Nice 300sqft. den.jpg",
"photo_url": "image/den.jpg"
},
{
"description": "Floor Plan",
"photo_url": "image/floor_plan.jpg"
}
]
}
2. Java class with the List
public class FocusArea {
#SerializedName("name")
private String mName;
#SerializedName("gallery")
private List<ContentImage> mGalleryImages;
}
3. Java class for the List items
public class ContentImage {
#SerializedName("description")
private String mDescription;
#SerializedName("photo_url")
private String mPhotoUrl;
// getters/setters ..
}
4. The Java code that processes the JSON
for (String key : focusAreaKeys) {
JsonElement sectionElement = sectionsJsonObject.get(key);
FocusArea focusArea = gson.fromJson(sectionElement, FocusArea.class);
}
Kotlin Extension
for Kotlin developers you can use this extension
inline fun <reified T> String.convertToListObject(): List<T>? {
val listType: Type = object : TypeToken<List<T?>?>() {}.type
return Gson().fromJson<List<T>>(this, listType)
}
Given you start with mapping.get("servers").getAsJsonArray(), if you have access to Guava Streams, you can do the below one-liner:
List<String> servers = Streams.stream(jsonArray.iterator())
.map(je -> je.getAsString())
.collect(Collectors.toList());
Note StreamSupport won't be able to work on JsonElement type, so it is insufficient.
I have the following JSON Array as a string like this,
String output = "[{\"Symbol\":\"AMZN\",\"Name\":\"Amazon.com Inc\",\"Exchange\":\"NASDAQ\"},{\"Symbol\":\"VXAZN\",\"Name\":\"CBOE Amazon VIX Index\",\"Exchange\":\"Market Data Express\"}]";
I want to parse it and make a string array like this,
array = {"AMZN Amazon.com Inc NASDAQ", "VXAZN CBOE Amazon VIX Index Market Data Express"};
I came up with the following code to parse the string into a JSON Array using the json-simple-1.1.1.jar library,
import org.json.simple.*;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
public class RESTclient {
public static void main(String[] args) {
String output = "[{\"Symbol\":\"AMZN\",\"Name\":\"Amazon.com Inc\",\"Exchange\":\"NASDAQ\"},{\"Symbol\":\"VXAZN\",\"Name\":\"CBOE Amazon VIX Index\",\"Exchange\":\"Market Data Express\"}]";
JSONParser parser = new JSONParser();
JSONArray jsonArray = null;
try {
jsonArray = (JSONArray) parser.parse(output);
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println(jsonArray);
}
}
This gives me the following OUTPUT,
[{"Name":"Amazon.com Inc","Exchange":"NASDAQ","Symbol":"AMZN"},{"Name":"CBOE Amazon VIX Index","Exchange":"Market Data Express","Symbol":"VXAZN"}]
Now after this, is there an elegant way to achieve my desired output?
You have to write extra code.
ArrayList<String> stringArray = new ArrayList<String>();
for (Iterator iterator = jsonArray.iterator(); iterator.hasNext();) {
JSONObject map = (JSONObject)iterator.next();
stringArray.add(map.get("Symbol")+" "+map.get("Name")+" "+map.get("Exchange"));
}
//stringArray is want you want
You can do it with Jackson like,
private ObjectMapper mapper = new ObjectMapper();
String[] outputArray = mapper.readValue(jsonString, String[].class);
I have a JsonObject named "mapping" with the following content:
{
"client": "127.0.0.1",
"servers": [
"8.8.8.8",
"8.8.4.4",
"156.154.70.1",
"156.154.71.1"
]
}
I know I can get the array "servers" with:
mapping.get("servers").getAsJsonArray()
And now I want to parse that JsonArray into a java.util.List...
What is the easiest way to do this?
Definitely the easiest way to do that is using Gson's default parsing function fromJson().
There is an implementation of this function suitable for when you need to deserialize into any ParameterizedType (e.g., any List), which is fromJson(JsonElement json, Type typeOfT).
In your case, you just need to get the Type of a List<String> and then parse the JSON array into that Type, like this:
import java.lang.reflect.Type;
import com.google.gson.reflect.TypeToken;
JsonElement yourJson = mapping.get("servers");
Type listType = new TypeToken<List<String>>() {}.getType();
List<String> yourList = new Gson().fromJson(yourJson, listType);
In your case yourJson is a JsonElement, but it could also be a String, any Reader or a JsonReader.
You may want to take a look at Gson API documentation.
Below code is using com.google.gson.JsonArray.
I have printed the number of element in list as well as the elements in List
import java.util.ArrayList;
import com.google.gson.Gson;
import com.google.gson.JsonArray;
import com.google.gson.JsonObject;
import com.google.gson.JsonParser;
public class Test {
static String str = "{ "+
"\"client\":\"127.0.0.1\"," +
"\"servers\":[" +
" \"8.8.8.8\"," +
" \"8.8.4.4\"," +
" \"156.154.70.1\"," +
" \"156.154.71.1\" " +
" ]" +
"}";
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
JsonParser jsonParser = new JsonParser();
JsonObject jo = (JsonObject)jsonParser.parse(str);
JsonArray jsonArr = jo.getAsJsonArray("servers");
//jsonArr.
Gson googleJson = new Gson();
ArrayList jsonObjList = googleJson.fromJson(jsonArr, ArrayList.class);
System.out.println("List size is : "+jsonObjList.size());
System.out.println("List Elements are : "+jsonObjList.toString());
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
OUTPUT
List size is : 4
List Elements are : [8.8.8.8, 8.8.4.4, 156.154.70.1, 156.154.71.1]
I read solution from official website of Gson at here
And this code for you:
String json = "{"client":"127.0.0.1","servers":["8.8.8.8","8.8.4.4","156.154.70.1","156.154.71.1"]}";
JsonObject jsonObject = new Gson().fromJson(json, JsonObject.class);
JsonArray jsonArray = jsonObject.getAsJsonArray("servers");
String[] arrName = new Gson().fromJson(jsonArray, String[].class);
List<String> lstName = new ArrayList<>();
lstName = Arrays.asList(arrName);
for (String str : lstName) {
System.out.println(str);
}
Result show on monitor:
8.8.8.8
8.8.4.4
156.154.70.1
156.154.71.1
I was able to get the list mapping to work with just using #SerializedName for all fields.. no logic around Type was necessary.
Running the code - in step #4 below - through the debugger, I am able to observe that the List<ContentImage> mGalleryImages object populated with the JSON data
Here's an example:
1. The JSON
{
"name": "Some House",
"gallery": [
{
"description": "Nice 300sqft. den.jpg",
"photo_url": "image/den.jpg"
},
{
"description": "Floor Plan",
"photo_url": "image/floor_plan.jpg"
}
]
}
2. Java class with the List
public class FocusArea {
#SerializedName("name")
private String mName;
#SerializedName("gallery")
private List<ContentImage> mGalleryImages;
}
3. Java class for the List items
public class ContentImage {
#SerializedName("description")
private String mDescription;
#SerializedName("photo_url")
private String mPhotoUrl;
// getters/setters ..
}
4. The Java code that processes the JSON
for (String key : focusAreaKeys) {
JsonElement sectionElement = sectionsJsonObject.get(key);
FocusArea focusArea = gson.fromJson(sectionElement, FocusArea.class);
}
Kotlin Extension
for Kotlin developers you can use this extension
inline fun <reified T> String.convertToListObject(): List<T>? {
val listType: Type = object : TypeToken<List<T?>?>() {}.type
return Gson().fromJson<List<T>>(this, listType)
}
Given you start with mapping.get("servers").getAsJsonArray(), if you have access to Guava Streams, you can do the below one-liner:
List<String> servers = Streams.stream(jsonArray.iterator())
.map(je -> je.getAsString())
.collect(Collectors.toList());
Note StreamSupport won't be able to work on JsonElement type, so it is insufficient.
I want the following json ,where List<form> will have list of form_id,form_name, how can I convert this using jsonobject, I am not getting the proper json output. Please help me with this.
Json:
{
"forms": [
{ "form_id": "1", "form_name": "test1" },
{ "form_id": "2", "form_name": "test2" }
]
}
The above is the json structure that i need it for a list.Where id ,name is a list from form object
public static JSONObject getJsonFromMyFormObject(List<Form> form) {
JSONObject responseDetailsJson = new JSONObject();
JSONArray jsonArray = null;
System.out.println(form.size());
for (int i = 0; i < form.size(); i++) {
JSONObject formDetailsJson = new JSONObject();
formDetailsJson.put("form_id", form.get(i).getId());
formDetailsJson.put("form_name", form.get(i).getName());
jsonArray = new JSONArray();
jsonArray.add(formDetailsJson);
}
responseDetailsJson.put("form", jsonArray);
return responseDetailsJson;
}
Facing issue here not getting output as a list
The code in the original question is close to achieving the described desired result. Just move the JSONArray instance creation outside of the loop.
import java.util.ArrayList;
import java.util.List;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
public class Foo
{
public static JSONObject getJsonFromMyFormObject(List<Form> form)
{
JSONObject responseDetailsJson = new JSONObject();
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < form.size(); i++)
{
JSONObject formDetailsJson = new JSONObject();
formDetailsJson.put("form_id", form.get(i).getId());
formDetailsJson.put("form_name", form.get(i).getName());
jsonArray.add(formDetailsJson);
}
responseDetailsJson.put("forms", jsonArray);
return responseDetailsJson;
}
public static void main(String[] args)
{
List<Form> forms = new ArrayList<Form>();
forms.add(new Form("1", "test1"));
forms.add(new Form("2", "test2"));
JSONObject jsonObject = getJsonFromMyFormObject(forms);
System.out.println(jsonObject);
}
}
class Form
{
String id;
String name;
Form(String i, String n)
{
id = i;
name = n;
}
String getId()
{
return id;
}
String getName()
{
return name;
}
}
Properbly http://www.roseindia.net/tutorials/json/jsonobject-java-example.shtml will help.
According the comment from Tushar, here the extract from the aboved linked website:
Now in this part you will study how to use JSON in Java.
To have functionality of JSON in java you must have JSON-lib. JSON-lib also
requires following "JAR" files:
commons-lang.jar
commons-beanutils.jar
commons-collections.jar
commons-logging.jar
ezmorph.jar
json-lib-2.2.2-jdk15.jar
JSON-lib is a java library for that transforms beans, collections, maps, java arrays and XML to JSON and
then for retransforming them back to beans, collections, maps and
others. In this example we are going to use JSONObject class for
creating an object of JSONObject and then we will print these object
value. For using JSONObject class we have to import following package
"net.sf.json". To add elements in this object we have used put()
method. Here is the full example code of FirstJSONJava.java is as
follows:
FirstJSONJava.java
import net.sf.json.JSONObject;
public class FirstJSONJava
{
public static void main(String args[])
{
JSONObject object=new JSONObject();
object.put("name","Amit Kumar");
object.put("Max.Marks",new Integer(100));
object.put("Min.Marks",new Double(40));
object.put("Scored",new Double(66.67));
object.put("nickname","Amit");
System.out.println(object);
}
}
To run this example you have to follow these few steps as follows:
Download JSON-lib jar and other supporting Jars
Add these jars to your classpath
Create and save FirstJSONJava.java
Compile it and execute it.
I'm using GSON on my Java EE server to provide some json to views.
In some object, I have long text, that can contains anything (like 'What a "great" news!').
I'm supprised that by default GSON doesn't escape the double quote, so it doesn't generate a valid JSON.
Is there a good way of doing this ?
Maybe I'm not understanding your question, but I was able to get GSON to handle Strings with quotes without any settings or changes.
import com.google.gson.Gson;
public class GSONTest {
public String value;
public static void main(String[] args) {
Gson g = new Gson();
GSONTest gt = new GSONTest();
gt.value = "This is a \"test\" of quoted strings";
System.out.println("String: " + gt.value);
System.out.println("JSON: " + g.toJson(gt));
}
}
Output:
String: This is a "test" of quoted strings
JSON: {"value":"This is a \"test\" of quoted strings"}
Maybe I don't understand what you're asking?
Try using setPrettyPrinting with DisableHtml escaping.
import com.google.gson.Gson;
Gson gson = new GsonBuilder().setPrettyPrinting().disableHtmlEscaping().create();
JsonParser jp = new JsonParser();
JsonElement je = jp.parse(jsonArray.toString());
System.out.println( gson.toJson(je));
Here's some sample GSON code:
final JsonObject obj = new JsonObject();
obj.addProperty("foo", "b\"a\"r");
System.out.println(obj.toString());
The Output is:
{"foo":"b\"a\"r"}
(as it should be)
So either you are doing something wrong, or you are using an ancient version of GSON. Perhaps you should show some of your code?
That is what I did to solve that
private final Gson mGson;
{
GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(String.class, new EscapeStringSerializer());
mGson = builder.create();
}
private static class EscapeStringSerializer implements JsonSerializer<String> {
#Override
public JsonElement serialize(String s, Type type, JsonSerializationContext jsonSerializationContext) {
return new JsonPrimitive(escapeJS(s));
}
public static String escapeJS(String string) {
String escapes[][] = new String[][]{
{"\\", "\\\\"},
{"\"", "\\\""},
{"\n", "\\n"},
{"\r", "\\r"},
{"\b", "\\b"},
{"\f", "\\f"},
{"\t", "\\t"}
};
for (String[] esc : escapes) {
string = string.replace(esc[0], esc[1]);
}
return string;
}
}