This question already has answers here:
How do I split a string in Java?
(39 answers)
Closed 3 years ago.
So, I am trying to split a string but I don't just want to split it by single character strings, but rather by entire strings.
So if my String is ["hello buddy my name is buddy"], my delimiter would be "buddy".
I want it to split into: ["hello", "my name is"].
I hope i'm not over complicating it.
public static void main(String[ ] args) {
String test = "hello buddy my name is buddy";
String[] res = test.split("buddy");
for (String s: res) {
System.out.println(s);
}
}
Seems to do what you want, no?
Related
This question already has answers here:
Split string with dot as delimiter
(13 answers)
Closed last month.
Code:
public class StringBuffer_Filtering_data
{
public static void main(String[] args)
{
String [] records={
"1001.ajay.manager.account.45000.male.38",
"1002.aiswrya.clerk.account.25000.female.30",
"1003.varun.manager.sales.50000.male.35",
"1004.amit.manager.account.47000.male.40",
"1005.kareena.executive.sales.15000.female.24",
"1006.deepak.clerk.sales.23000.male.30",
"1007.sunil.accountant.sales.13000.male.29",
"1008.satvik.director.purchase.80000.male.45"
};
StringBuffer sb=new StringBuffer(255);
for(String record:records)
{
String[] fields=record.split(".");
if(fields[2].equals("manager"))
{
System.out.println(record);
}
}
}
}
Expected output:
1001,ajay,manager,account,45000,male,38
1003,varun,manager,sales,50000,male,35
1004,amit,manager,account,47000,male,40
split's argument is a regular expression (regex), not a plain old string. In the context of a regex, . is a special character while means "any character". If you want to split the string by the literal ., you'll need to escape it:
String[] fields=record.split("\\.");
// Here ----------------------^^
This question already has answers here:
How to split a String by space
(17 answers)
Closed 1 year ago.
I have a problem in my Java code:
I want to split a string in parts an undefined amound of parts with different length. I want to split it whenever a space appears in the string.
You can split string easily like this:
class HelloWorld {
public static void main(String[] args) {
String str = "Hey there welcome to java!";
String[] splited = str.trim().split("\\s+");
for (String word : splited)
{
System.out.println(word);
}
}
}
Output:
Hey
there
welcome
to
java!
This question already has answers here:
How do I split a string in Java?
(39 answers)
Closed 5 years ago.
Can someone please tell me how to split this string?
Sample Input
String in = "Erin M Haggens";
Desired Output
String str1 = "Erin";
String str2 = "M";
String str3 = "Haggens";
Use the String.split() method.
The code myStr.split("\\s+") should work for you. Then you can use each element of the returned array as one of your outputted strings.
This question already has answers here:
How to split a string on | (pipe) in Java [duplicate]
(3 answers)
Closed 7 years ago.
I'm wondering why I cannot split a text that contain the | as a separator in String. The splitting works fine when I use commas or the like..
Here is an SSCE
package tests;
public class Tests {
public static void main(String[] args) {
String text1="one|two|three|four|five";
String text2="one,two,three,four,five";
String [] splittedText1 = text1.split("|");
String [] splittedText2 = text2.split(",");
for(String elem : splittedText1) System.out.println("text1="+elem);
for(String elem : splittedText2) System.out.println("text2="+elem);
}
}
Any ideas why it doesn't work with "|" ??
Since split(String regex) takes a regex and | is a meta character, you need to escape it.
String[] splittedText1 = splittedText1.split("\\|");
Or you can simply use Pattern class
A compiled representation of a regular expression.
String[] splittedText1 = splittedText1.split(Pattern.quote("|"));
Because the split pattern is actually a regex. You need to escape |, since it has a special meaning in the context of a regular expression (it marks an alternative):
String [] splittedText1 = text1.split("\\|");
This question already has an answer here:
Java regex : matching a char except when preceded by another char
(1 answer)
Closed 8 years ago.
I got a string in java that I would like to split in parts on following criteria:
the '#' char is a separator
if '#' is escaped via backslash then is should not be considered a separator
i.e.
"abc#xyz#kml\#ijk"
should be split into
"abc", "xyz", "kml\#ijk"
I can do it easily with StringTokenizer and add some logic for the escape char but I would like to get it via one-liner String.split call with the correct regex. So far my "best" attempt is following:
public static void main(String[] args) {
String toSplit = "abc#xyz#kml\\#ijk";
String[] arr = toSplit.split("[^\\\\]#");
System.out.println(Arrays.toString(arr));
}
and the result is:
[ab, xy, kml#ijk]
The last letter of the first two parts is cut out.
Any idea how to avoid that?
Have you looked into lookbehinds?
public static void main(String[] args) {
String toSplit = "abc#xyz#kml\\#ijk";
String[] arr = toSplit.split("(?<!\\\\)#");
System.out.println(Arrays.toString(arr));
}