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Convert only time part in android from string to time

I need to convert a time stamp that currently is in string format "08.00" to a valid time in java so I later can compare time. How do I convert this string to time?

Something like this
DateFormat sdf = new SimpleDateFormat("hh:mm");
Date date = sdf.parse(time);

Instead of using the Date and/or SimpleDateFormat classes, perhaps consider LocalTime
String time = "08:00";
LocalTime lt = LocalTime.parse(time);
System.out.println(lt);
Output:
08:00
And can compare to other times easily with LocalTime::isBefore() or LocalTime::isAfter()
Example

Try below code,
String time = "08.00";
try {
DateFormat sdfInput = new SimpleDateFormat("hh.mm");
Date date = sdfInput.parse(time);
DateFormat sdfOutput = new SimpleDateFormat("hh:mm");
Log.e( "Time: ", sdfOutput.format(date));
} catch (Exception e) {
e.printStackTrace();
}
Output -> Time: 08:00

The easiest way to do so is with a SimplDateFormatter:
DateFormat sdf = new SimpleDateFormat("hh:mm")
Then you can call Date date = sdf.parse(*your time string*)
Now you have your time as a valid Date object.

I have timeformat like this hhmmss="151918"
so you can use any format instead of hhmmss according to your current time format like
"hh.mm" or hh:mm:ss etc
and you can call this method form any where you needed.
fun convertTimeFormat(time:String):String{
var formattedTime=""
try {
val inputFormat: DateFormat = SimpleDateFormat("hhmmss")
val timeObj = inputFormat.parse(time)
Log.d("timeObj",""+timeObj)
formattedTime=SimpleDateFormat("hh:mm aa").format(timeObj)
} catch (e: ParseException) {
e.printStackTrace()
}
return formattedTime
}

java.text.ParseException: Unparseable date: "2018-05-23T06:39:37+0000"

I'm trying to create a Date from a String I receive from the server. The String is:
2018-05-23T06:39:37+0000
So the correct format should be:
yyyy-MM-dd'T'HH:mm:ss.SSSZ
Here is my code:
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
try {
Date parsedDate = simpleDateFormat.parse(createdDate);
createdDate = parsedDate.toString();
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);
I don't know if there is any way to do this, because after that I would like to parse again to the next format:
dd/MM/yyyy hh:mm
I've tried to parse the original String using this last format directly but I'm getting the same exception.
Any suggestion?

I see you've solved your own problem with a little help from the comments, however I would suggest you seriously consider LocalDate, as the older Date classes are quite troublesome at times.
In fact, as your incoming value has a TimeZone, you'll need to use ZonedDateTime to parse your input.
String createdDate = "2018-05-23T06:39:37+0000";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ssZ");
ZonedDateTime localDate = ZonedDateTime.parse(createdDate, formatter);
System.out.println(localDate.format(DateTimeFormatter.ofPattern("dd/MM/yyyy HH:mm")));
Output:
23/05/2018 06:39

The given input date String format
2018-05-23T06:39:37+0000
is incorrect so that you are getting ParseException since millisecond(SSS) part is missing from your date format yyyy-MM-dd'T'HH:mm:ss.SSSZ
So please try with
2018-05-23T06:39:37.235-0530
so below code should work
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
try {
Date parsedDate = simpleDateFormat.parse(createdDate);
createdDate = parsedDate.toString();
System.out.println(parsedDate.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);

Ok, the first mistake (as you've pointed) is I didn't have milliseconds on the original String.
After removing "SSS" from the simpleDateFormat it works like a charm. So this is the final code:
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat defaultDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ", Locale.getDefault());
try {
Date parsedDate = defaultDateFormat.parse(createdDate);
SimpleDateFormat finalDateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm", Locale.getDefault());
createdDate = finalDateFormat.format(parsedDate);
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);

Java DateFormat conversion automatically increases hour by 1

I am trying to take date in string and its input format string and converting the date in output format. However after conversion into Date, the java code increases the number of hours by one. I am not able to understand what causes the bug.
My Code:
try {
DateFormat outputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
DateFormat inputFormat = new SimpleDateFormat(format);
Date date = inputFormat.parse(parameterValue);
parameterValue = outputFormat.format(date);
return parameterValue;
} catch (ParseException ex) {
// take action
}
format string: ddMMMyyyy / hh:mm z
Input Date: 07DEC2015 / 10:02 GMT
Output Date: 07/12/2015 11:02:00

outputFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
resolved it.

If you don't want to use timezone, in java 8 you can use LocalDate/LocalTime/LocalDateTime:
LocalDateTime localDateTimeInstance = LocalDateTime.parse(dateToBeConverted, DateTimeFormatter.ofPattern(formatOfDateToBeConverted));
return localDateTimeInstance.format("dd/MM/yyyy hh:mm:ss");
/*
Also check out ZoneDate, ZoneTime (for timezone)
Checkout - LocalDate, LocalTime
*/

Get Date object from String in form 2012-07-26 23:59:59

I have the input string as 2012-07-27 and I want the output as Date but with the same format like 2012-07-27
Code
DateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
try {
Date today = df.parse("20-12-2005 23:59:59");
System.out.println("Today = " + df.format(today));
} catch (ParseException e) {
e.printStackTrace();
}
Output
20-12-2005 23:59:59
But it's string object I want the same output (20-12-2005 23:59:59) as date object not as string object.
How can I get the Date in the form DD-MM-YYYY HH:MM:SS?

Date today is the date object you get for input String. There are nothing like formatted dates in Java. Date is always just date object. You perform all sorts of operations on that date object and when you want to Store (or) display just apply format()
df.format(today) // is just for formatting and display purpose.

There is difference in your format passed to SimpleDateFormat and way you are passing date string. You should Also use HH
DateFormat df = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
try {
Date today = df.parse("20-12-2005 23:59:59");
System.out.println("Today = " + df.format(today));
//To Print Real Today
System.out.println("Real Today = " + df.format(new Date()));
} catch (ParseException e) {
e.printStackTrace();
}

The Date class has many deprecated methods and the only correct way to create it right now is via a long (read doc for details).
You should look into GregorialCalendar where you can pass some constant fields of Calendar as attributes.
If you want to input the date from your String, I would either do a custom parser that creates a calendar or something like this.
Hope I helped :)

Java ParseException while attempting String to Date parsing

I'm having a hard time Parsing/Formatting a Date string received back from a web service. I've attempted multiple approaches, but with no luck.
Sample Date String:
2011-10-05T03:00:00Z
Exception:
W/System.err(10072): java.text.ParseException: Unparseable date: "2011-10-05T05:00:00Z" (at offset 10)
W/System.err(10072): at java.text.DateFormat.parse(DateFormat.java:626)
Sample Code:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:SSSS");
Date date = formatter.parse(info.AiringTime);
I've found that if I remove the "T" between the date and the time and replace it with a space, it will format just fine. Anybody have any suggestions?
--UPDATE--
After looking deeper into the API documentation, I found this:
All response DateTime values are in UTC format. You need to apply the UTC offset to calculate the local time for display.
DateTime is a date-and-time value specified in one of the following formats:
UTC format: YYYY-MM-DDThh:mm:ssZ. For example: 2011-03-15T02:00:00Z.
Local time with an offset: YYYY-MM-DDThh:mm:ss + or - hh:mm (positive or negative offset). For example, for US Pacific time: 2011-03-14T06:00:00 -08:00.
Any suggestions on the UTC format approach?

You could try:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
String dateString = dateString.replace("Z", "GMT+00:00");
Date date = dateFormat.parse(dateString);
The above code should correctly handle the case where a timezone is specified in the date. As Z represents the UTC/GMT timezone it is replaced by GMT so the SimpleDateFormat can interpret it correctly (i would love to know a cleaner way of handling this bit if anyone knows one).

Try,
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");

This pattern should parse the date you provide: "yyyy-MM-dd'T'HH:mm:ss'Z'".
If you want to use SimpleDateFormat and you have a limited number of variations, you can create separate formatters for each pattern and chain them:
Date date = formatter1.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter2.parse(info.AiringTime);
if (date == null)
{
date = formatter3.parse(info.AiringTime);
}
}
}
or put them in a list and iterate until non-null or no more formatters.
If you have too many patterns for this to be practical, you can parse it yourself or try one of these libraries.

This worked for me
SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}

SimpleDateFormat isoDateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss'Z'");
SimpleDateFormat viewFriendlyDateFormat = new SimpleDateFormat("dd/MMM/yyyy hh:mm:ss aaa");
String viewFriendlyDate = "";
try {
Date date = isoDateFormat.parse(timestamp);
viewFriendlyDate = viewFriendlyDateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}