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Instagram application does not open with Android Intent

This is my code, the thing is I don't want to send images I just want the IG app to open. Yes the app is installed but still it is not getting picked up.
This was working fine till last week. Please help.
Uri uri = Uri.parse("http://instagram.com/");
Intent insta = new Intent(Intent.ACTION_VIEW, uri);
insta.setPackage("com.instagram.android");
if (isIntentAvailable(insta)) {
this.startActivityForResult(insta, REQUEST_CODE_MY_PICK);
} else {
}
private boolean isIntentAvailable(Intent intent) {
final PackageManager packageManager = getPackageManager();
List<ResolveInfo> list = packageManager.queryIntentActivities(intent, PackageManager.MATCH_DEFAULT_ONLY);
return list.size() > 0;
}

Try this
Uri appUri = Uri.parse("https://instagram.com/_u/user_name");
Uri browserUri = Uri.parse("https://instagram.com/user_name");
try{ //first try to open in instagram app
Intent appIntent = getPackageManager().getLaunchIntentForPackage("com.instagram.android");
if(appIntent != null){
appIntent.setAction(Intent.ACTION_VIEW)
appIntent.setData(appUri);
startActivity(appIntent);
}
}catch(Exception e){ //or else open in browser
Intent browserIntent = new Intent(Intent.ACTION_VIEW, browserUri);
startActivity(browserIntent);
}

Try to replace Uri.parse("http://instagram.com/") with Uri.parse("https://instagram.com/"). Also try to remove the isIntentAvailable and just call startActivity(insta) without 'forResult' and lastly remove insta.setPackage line.

resolveActivity works if I don't check if it is null

I wrote this code to open a website in the browser from my app in android studio(google):
String google = "http://www.google.com";
Uri webAddress = Uri.parse(google);
Intent goToGoogle= new Intent(Intent.ACTION_VIEW, webAddress);
if(goToGoogle.resolveActivity(getPackageManager()) != null) {
startActivity(goToGoogle);
}
the app just does what I want it to do when I do not put the if statement, otherwise the button does nothing. Why is that?
thanks

The resolveActivity() method returns the Activity Component that is used to handle the Intent, so, if there is an Activity handling the intent, it will return true
Make sure that an Activity is handling your intent, placing this code into a java class of an Activity.
String google = "http://www.google.com";
Uri webAddress = Uri.parse(google);
Intent goToGoogle= new Intent(Intent.ACTION_VIEW);
goToGoogle.setData(webAdress);
if(goToGoogle.resolveActivity(getPackageManager()) != null) {
startActivity(goToGoogle);
}

How to send the Pre-populated text message to specific (intended) Whats-App user / users? [duplicate]

Since I found some older posts, that tell that whatsapp doesn't support this, I was wondering if something had changed and if there is a way to open a whatsapp 'chat' with a number that I'm sending through an intent?

UPDATE
Please refer to https://faq.whatsapp.com/en/android/26000030/?category=5245251
WhatsApp's Click to Chat feature allows you to begin a chat with
someone without having their phone number saved in your phone's
address book. As long as you know this person’s phone number, you can
create a link that will allow you to start a chat with them.
Use: https://wa.me/15551234567
Don't use: https://wa.me/+001-(555)1234567
Example: https://wa.me/15551234567?text=I'm%20interested%20in%20your%20car%20for%20sale
Original answer
Here is the solution
public void onClickWhatsApp(View view) {
PackageManager pm=getPackageManager();
try {
Intent waIntent = new Intent(Intent.ACTION_SEND);
waIntent.setType("text/plain");
String text = "YOUR TEXT HERE";
PackageInfo info=pm.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
//Check if package exists or not. If not then code
//in catch block will be called
waIntent.setPackage("com.whatsapp");
waIntent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(waIntent, "Share with"));
} catch (NameNotFoundException e) {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT)
.show();
}
}
Also see http://www.whatsapp.com/faq/en/android/28000012

With this code you can open the whatsapp chat with the given number.
void openWhatsappContact(String number) {
Uri uri = Uri.parse("smsto:" + number);
Intent i = new Intent(Intent.ACTION_SENDTO, uri);
i.setPackage("com.whatsapp");
startActivity(Intent.createChooser(i, ""));
}

Simple solution, try this.
String phoneNumberWithCountryCode = "+62820000000";
String message = "Hallo";
startActivity(
new Intent(Intent.ACTION_VIEW,
Uri.parse(
String.format("https://api.whatsapp.com/send?phone=%s&text=%s", phoneNumberWithCountryCode, message)
)
)
);

I found the following solution, first you'll need the whatsapp id:
Matching with reports from some other threads here and in other forums the login name I found was some sort of:
international area code without the 0's or + in the beginning + phone number without the first 0 + #s.whatsapp.net
For example if you live in the Netherlands and having the phone number 0612325032 it would be 31612325023#s.whatsapp.net -> +31 for the Netherlands without the 0's or + and the phone number without the 0.
public void sendWhatsAppMessageTo(String whatsappid) {
Cursor c = getSherlockActivity().getContentResolver().query(ContactsContract.Data.CONTENT_URI,
new String[] { ContactsContract.Contacts.Data._ID }, ContactsContract.Data.DATA1 + "=?",
new String[] { whatsappid }, null);
c.moveToFirst();
Intent whatsapp = new Intent(Intent.ACTION_VIEW, Uri.parse("content://com.android.contacts/data/" + c.getString(0)));
c.close();
if (whatsapp != null) {
startActivity(whatsapp);
} else {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT)
.show();
//download for example after dialog
Uri uri = Uri.parse("market://details?id=com.whatsapp");
Intent goToMarket = new Intent(Intent.ACTION_VIEW, uri);
}
}

This should work whether Whatsapp is installed or not.
boolean isWhatsappInstalled = whatsappInstalledOrNot("com.whatsapp");
if (isWhatsappInstalled) {
Uri uri = Uri.parse("smsto:" + "98*********7")
Intent sendIntent = new Intent(Intent.ACTION_SENDTO, uri);
sendIntent.putExtra(Intent.EXTRA_TEXT, "Hai Good Morning");
sendIntent.setPackage("com.whatsapp");
startActivity(sendIntent);
} else {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT).show();
Uri uri = Uri.parse("market://details?id=com.whatsapp");
Intent goToMarket = new Intent(Intent.ACTION_VIEW, uri);
startActivity(goToMarket);
}
private boolean whatsappInstalledOrNot(String uri) {
PackageManager pm = getPackageManager();
boolean app_installed = false;
try {
pm.getPackageInfo(uri, PackageManager.GET_ACTIVITIES);
app_installed = true;
} catch (PackageManager.NameNotFoundException e) {
app_installed = false;
}
return app_installed;
}

Tested on Marshmallow S5 and it works!
Uri uri = Uri.parse("smsto:" + "phone number with country code");
Intent sendIntent = new Intent(Intent.ACTION_SENDTO, uri);
sendIntent.setPackage("com.whatsapp");
startActivity(sendIntent);
This will open a direct chat with a person, if whatsapp not installed this will throw exception, if phone number not known to whatsapp they will offer to send invite via sms or simple sms message

use this singleline code use to Sending message through WhatsApp
//NOTE : please use with country code first 2digits without plus signed
try {
String mobile = "911234567890";
String msg = "Its Working";
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://api.whatsapp.com/send?phone=" + mobile + "&text=" + msg)));
}catch (Exception e){
//whatsapp app not install
}

Here is the latest way to send a message via Whatsapp, even if the receiver's phone number is not in your Whatsapp chat or phone's Contacts list.
private fun openWhatsApp(number: String) {
try {
packageManager.getPackageInfo("com.whatsapp", PackageManager.GET_ACTIVITIES)
val intent = Intent(
Intent.ACTION_VIEW,
Uri.parse("https://wa.me/$number?text=I'm%20interested%20in%20your%20car%20for%20sale")
)
intent.setPackage("com.whatsapp")
startActivity(intent)
} catch (e: PackageManager.NameNotFoundException) {
Toast.makeText(
this,
"Whatsapp app not installed in your phone",
Toast.LENGTH_SHORT
).show()
e.printStackTrace()
}
}
intent.setPackage("com.whatsapp") will help you to avoid Open With chooser and open Whatsapp directly.
Importent Note: If You are ending in catch statement, even if Whatsapp is installed. Please add queries to manifest.xml as follows:
<queries>
<package android:name="com.whatsapp" />
</queries>
Please see this answer for more details.

To check if WhatsApp is installed in device and initiate "click to chat" in WhatsApp:
Kotlin:
try {
// Check if whatsapp is installed
context?.packageManager?.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA)
val intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://wa.me/$internationalPhoneNumber"))
startActivity(intent)
} catch (e: NameNotFoundException) {
Toast.makeText(context, "WhatsApp not Installed", Toast.LENGTH_SHORT).show()
}
Java:
try {
// Check if whatsapp is installed
getPackageManager().getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
Intent intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://wa.me/" + internationalPhoneNumber));
startActivity(intent);
} catch (NameNotFoundException e) {
Toast.makeText(context, "WhatsApp not Installed", Toast.LENGTH_SHORT).show();
}
getPackageInfo() throws NameNotFoundException if WhatsApp is not installed.
The internationalPhoneNumber variable is used to access the phone number.
Reference:
https://faq.whatsapp.com/general/chats/how-to-use-click-to-chat?category=5245251
https://stackoverflow.com/a/2201999/9636037
https://stackoverflow.com/a/15931345/9636037

The following code is used by Google Now App and will NOT work for any other application.
I'm writing this post because it makes me angry, that WhatsApp does not allow any other developers to send messages directly except for Google.
And I want other freelance-developers to know, that this kind of cooperation is going on, while Google keeps talking about "open for anybody" and WhatsApp says they don't want to provide any access to developers.
Recently WhatsApp has added an Intent specially for Google Now, which should look like following:
Intent intent = new Intent("com.google.android.voicesearch.SEND_MESSAGE_TO_CONTACTS");
intent.setPackage("com.whatsapp");
intent.setComponent(new ComponentName("com.whatsapp", "com.whatsapp.VoiceMessagingActivity"));
intent.putExtra("com.google.android.voicesearch.extra.RECIPIENT_CONTACT_CHAT_ID", number);
intent.putExtra("android.intent.extra.TEXT", text);
intent.putExtra("search_action_token", ?????);
I could also find out that "search_action_token" is a PendingIntent
that contains an IBinder-Object, which is sent back to Google App and checked, if it was created by Google Now.
Otherwise WhatsApp will not accept the message.

Currently, the only official API that you may make a GET request to:
https://api.whatsapp.com/send?phone=919773207706&text=Hello
Anyways, there is a secret API program already being ran by WhatsApp

As the documentation says you can just use an URL like:
https://wa.me/15551234567
Where the last segment is the number in in E164 Format
Uri uri = Uri.parse("https://wa.me/15551234567");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);

This is what worked for me :
Uri uri = Uri.parse("https://api.whatsapp.com/send?phone=" + "<number>" + "&text=" + "Hello WhatsApp!!");
Intent sendIntent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(sendIntent);

This works to me:
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo("com.whatsapp", PackageManager.GET_ACTIVITIES);
Intent intent = new Intent();
intent.setComponent(new ComponentName(packageName,
ri.activityInfo.name));
intent.setType("text/plain");
intent.putExtra(Intent.EXTRA_TEXT, element);
} catch (NameNotFoundException e) {
ToastHelper.MakeShortText("Whatsapp have not been installed.");
}

Use direct URL of whatsapp
String url = "https://api.whatsapp.com/send?phone="+number;
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);

You'll want to use a URL in the following format...
https://api.whatsapp.com/send?text=text
Then you can have it send whatever text you'd like. You also have the option to specify a phone number...
https://api.whatsapp.com/send?text=text&phone=1234
What you CANNOT DO is use the following:
https://wa.me/send?text=text
You will get...
We couldn't find the page you were looking for
wa.me, though, will work if you supply both a phone number and text. But, for the most part, if you're trying to make a sharing link, you really don't want to indicate the phone number, because you want the user to select someone. In that event, if you don't supply the number and use wa.me as URL, all of your sharing links will fail. Please use app.whatsapp.com.

this is much lengthy but surly working.
enjoy your code:)
//method used to show IMs
private void show_custom_chooser(String value) {
List<ResolveInfo> list = null;
final Intent email = new Intent(Intent.ACTION_SEND);
email.setData(Uri.parse("sms:"));
email.putExtra(Intent.EXTRA_TEXT, "" + value);
email.setType("text/plain"); // vnd.android-dir/mms-sms
WindowManager.LayoutParams WMLP = dialogCustomChooser.getWindow()
.getAttributes();
WMLP.gravity = Gravity.CENTER;
dialogCustomChooser.getWindow().setAttributes(WMLP);
dialogCustomChooser.getWindow().setBackgroundDrawable(
new ColorDrawable(android.graphics.Color.TRANSPARENT));
dialogCustomChooser.setCanceledOnTouchOutside(true);
dialogCustomChooser.setContentView(R.layout.about_dialog);
dialogCustomChooser.setCancelable(true);
ListView lvOfIms = (ListView) dialogCustomChooser
.findViewById(R.id.listView1);
PackageManager pm = getPackageManager();
List<ResolveInfo> launchables = pm.queryIntentActivities(email, 0);
// ////////////new
list = new ArrayList<ResolveInfo>();
for (int i = 0; i < launchables.size(); i++) {
String string = launchables.get(i).toString();
Log.d("heh", string);
//check only messangers
if (string.contains("whatsapp")) {
list.add(launchables.get(i));
}
}
Collections.sort(list, new ResolveInfo.DisplayNameComparator(pm));
int size = launchables.size();
adapter = new AppAdapter(pm, list, MainActivity.this);
lvOfIms.setAdapter(adapter);
lvOfIms.setOnItemClickListener(new OnItemClickListener() {
#Override
public void onItemClick(AdapterView<?> arg0, View arg1,
int position, long arg3) {
ResolveInfo launchable = adapter.getItem(position);
ActivityInfo activity = launchable.activityInfo;
ComponentName name = new ComponentName(
activity.applicationInfo.packageName, activity.name);
email.addCategory(Intent.CATEGORY_LAUNCHER);
email.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK
| Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
email.setComponent(name);
startActivity(email);
dialogCustomChooser.dismiss();
}
});
dialogCustomChooser.show();
}

I'm really late here but I believe that nowadays we have shorter and better solutions to send messages through WhatsApp.
You can use the following to call the system picker, then choose which app you will use to share whatever you want.
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "This is my text to send.");
sendIntent.setType("text/plain");
startActivity(sendIntent);
If you are really need to send through WhatsApp all you need to do is the following (You will skip the system picker)
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "This is my text to send.");
sendIntent.setType("text/plain");
// Put this line here
sendIntent.setPackage("com.whatsapp");
//
startActivity(sendIntent);
If you need more information you can find it here: WhatsApp FAQ

private fun sendWhatsappMessage(phoneNumber:String, text:String) {
val url = if (Intent().setPackage("com.whatsapp").resolveActivity(packageManager) != null) {
"whatsapp://send?text=Hello&phone=$phoneNumber"
} else {
"https://api.whatsapp.com/send?phone=$phoneNumber&text=$text"
}
val browserIntent = Intent(Intent.ACTION_VIEW, Uri.parse(url))
startActivity(browserIntent)
}
This is a much easier way to achieve this. This code checks if whatsapp is installed on the device. If it is installed, it bypasses the system picker and goes to the contact on whatsapp and prefields the text in the chat. If not installed it opens whatsapp link on your web browser.

Sending to WhatsApp Number that exist in your contact list.
Notice that we are using ACTION_SEND
Intent whatsappIntent = new Intent(Intent.ACTION_SEND);
whatsappIntent.setType("text/plain");
whatsappIntent.setPackage("com.whatsapp");
whatsappIntent.putExtra(Intent.EXTRA_TEXT, "SMS TEXT, TEXT THAT YOU NEED TO SEND");
try {
startActivityForResult(whatsappIntent, 100);
} catch (Exception e) {
Toast.makeText(YourActivity.this, "App is not installed", Toast.LENGTH_SHORT).show();
}
If Number doesn't exist in contact list. Use WhatsApp API.
String number = number_phone.getText().toString(); // I toke it from Dialog box
number = number.substring(1); // To remove 0 at the begging of number (Optional) but needed in my case
number = "962" + number; // Replace it with your country code
String url = "https://api.whatsapp.com/send?phone=" + number + "&text=" + Uri.parse("Text that you want to send to the current user");
Intent whatsappIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
whatsappIntent.setPackage("com.whatsapp");
whatsappIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try {
context.startActivity(whatsappIntent);
} catch (android.content.ActivityNotFoundException ex) {
Toast.makeText(YourActivity.this, "App is not installed", Toast.LENGTH_SHORT).show();
}

Check this code,
public void share(String subject,String text) {
final Intent intent = new Intent(Intent.ACTION_SEND);
String score=1000;
intent.setType("text/plain");
intent.putExtra(Intent.EXTRA_SUBJECT, score);
intent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(intent, getString(R.string.share)));
}

This works to me:
public static void shareWhatsApp(Activity appActivity, String texto) {
Intent sendIntent = new Intent(Intent.ACTION_SEND);
sendIntent.setType("text/plain");
sendIntent.putExtra(android.content.Intent.EXTRA_TEXT, texto);
PackageManager pm = appActivity.getApplicationContext().getPackageManager();
final List<ResolveInfo> matches = pm.queryIntentActivities(sendIntent, 0);
boolean temWhatsApp = false;
for (final ResolveInfo info : matches) {
if (info.activityInfo.packageName.startsWith("com.whatsapp")) {
final ComponentName name = new ComponentName(info.activityInfo.applicationInfo.packageName, info.activityInfo.name);
sendIntent.addCategory(Intent.CATEGORY_LAUNCHER);
sendIntent.setFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_NEW_TASK);
sendIntent.setComponent(name);
temWhatsApp = true;
break;
}
}
if(temWhatsApp) {
//abre whatsapp
appActivity.startActivity(sendIntent);
} else {
//alerta - você deve ter o whatsapp instalado
Toast.makeText(appActivity, appActivity.getString(R.string.share_whatsapp), Toast.LENGTH_SHORT).show();
}
}

get the contact number whom you want to send the message and create uri for whatsapp, here c is a Cursor returning the selected contact.
Uri.parse("content://com.android.contacts/data/" + c.getString(0)));
i.setType("text/plain");
i.setPackage("com.whatsapp"); // so that only Whatsapp reacts and not the chooser
i.putExtra(Intent.EXTRA_SUBJECT, "Subject");
i.putExtra(Intent.EXTRA_TEXT, "I'm the body.");
startActivity(i);

From the documentation
To create your own link with a pre-filled message that will
automatically appear in the text field of a chat, use
https://wa.me/whatsappphonenumber/?text=urlencodedtext where
whatsappphonenumber is a full phone number in international format and
URL-encodedtext is the URL-encoded pre-filled message.
Example:https://wa.me/15551234567?text=I'm%20interested%20in%20your%20car%20for%20sale
Code example
val phoneNumber = "13492838472"
val text = "Hey, you know... I love StackOverflow :)"
val uri = Uri.parse("https://wa.me/$phoneNumber/?text=$text")
val sendIntent = Intent(Intent.ACTION_VIEW, uri)
startActivity(sendIntent)

This one worked finally for me in Kotlin:
private fun navigateToWhatsApp() {
try {
val url = "https://api.whatsapp.com/send?phone=+91${getString(R.string.contact)}"
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(url)).setPackage("com.whatsapp"))
} catch (e: Exception) {
showToast("Whatsapp app not installed in your device")
}
}

The following API can be used in c++ as shown in my article.
You need to define several constants:
//
#define    GroupAdmin                <YOUR GROUP ADMIN MOBILE PHONE>
#define GroupName                <YOUR GROUP NAME>
#define CLIENT_ID                <YOUR CLIENT ID>
#define CLIENT_SECRET            <YOUR CLIENT SECRET>
#define GROUP_API_SERVER        L"api.whatsmate.net"
#define GROUP_API_PATH          L"/v3/whatsapp/group/text/message/12"
#define IMAGE_SINGLE_API_URL    L"http://api.whatsmate.net/v3/whatsapp/group/image/message/12"
//
Then you connect to the API’s endpoint.
hOpenHandle = InternetOpen(_T("HTTP"), INTERNET_OPEN_TYPE_DIRECT, NULL, NULL, 0);
if (hOpenHandle == NULL)
{
return false;
}
hConnectHandle = InternetConnect(hOpenHandle,
GROUP_API_SERVER,
INTERNET_DEFAULT_HTTP_PORT,
NULL, NULL, INTERNET_SERVICE_HTTP,
0, 1);
if (hConnectHandle == NULL)
{
InternetCloseHandle(hOpenHandle);
return false;
}
Then send both header and body and wait for the result that needs to be “OK”.
Step 1 - open an HTTP request:
const wchar_t *AcceptTypes[] = { _T("application/json"),NULL };
HINTERNET hRequest = HttpOpenRequest(hConnectHandle, _T("POST"), GROUP_API_PATH, NULL, NULL, AcceptTypes, 0, 0);
if (hRequest == NULL)
{
InternetCloseHandle(hConnectHandle);
InternetCloseHandle(hOpenHandle);
return false;
}
Step 2 - send the header:
std::wstring HeaderData;
HeaderData += _T("X-WM-CLIENT-ID: ");
HeaderData += _T(CLIENT_ID);
HeaderData += _T("\r\nX-WM-CLIENT-SECRET: ");
HeaderData += _T(CLIENT_SECRET);
HeaderData += _T("\r\n");
HttpAddRequestHeaders(hRequest, HeaderData.c_str(), HeaderData.size(), NULL);
Step 3 - send the message:
std::wstring WJsonData;
WJsonData += _T("{");
WJsonData += _T("\"group_admin\":\"");
WJsonData += groupAdmin;
WJsonData += _T("\",");
WJsonData += _T("\"group_name\":\"");
WJsonData += groupName;
WJsonData += _T("\",");
WJsonData += _T("\"message\":\"");
WJsonData += message;
WJsonData += _T("\"");
WJsonData += _T("}");
const std::string JsonData(WJsonData.begin(), WJsonData.end());
bResults = HttpSendRequest(hRequest, NULL, 0, (LPVOID)(JsonData.c_str()), JsonData.size());
Now just check the result:
TCHAR StatusText[BUFFER_LENGTH] = { 0 };
DWORD StatusTextLen = BUFFER_LENGTH;
HttpQueryInfo(hRequest, HTTP_QUERY_STATUS_TEXT, &StatusText, &StatusTextLen, NULL);
bResults = (StatusTextLen && wcscmp(StatusText, L"OK")==FALSE);

"New Tag Collected" instead of reading tags of application - NFC android

I have a class, which creates conncection to NFC and two activites. Both of them creates an object of that class so they can connect to NFC.
Earlier it worked somehow but now I've got problem - my application doesn't do anything onNewIntent, even on the first activity. Instead of it, I can see "New tag collected" from build-in app called "Tags" (Nexus S).
What should I do?
class:
public NFCForegroundUtil(Activity activity)
{
super();
this.activity = activity;
mAdapter = NfcAdapter.getDefaultAdapter(activity
.getApplicationContext());
mPendingIntent = PendingIntent.getActivity(activity, 0, new Intent(
activity, activity.getClass())
.addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP), 0);
IntentFilter ndef = new IntentFilter(NfcAdapter.ACTION_TAG_DISCOVERED);
IntentFilter ndef2 = new IntentFilter(NfcAdapter.ACTION_NDEF_DISCOVERED);
IntentFilter ndef3 = new IntentFilter(NfcAdapter.ACTION_TECH_DISCOVERED);
try
{
ndef2.addDataType("*/*");
}
catch (MalformedMimeTypeException e)
{
throw new RuntimeException("fail", e);
}
mFilters = new IntentFilter[] {ndef, ndef2, ndef3 };
mTechLists = new String[][] { new String[] {
// android.nfc.tech.NfcV.class.getName(),
android.nfc.tech.NfcA.class.getName(),
android.nfc.tech.IsoDep.class.getName() } };
mAdapter.enableForegroundDispatch(this, mPendingIntent, mFilters, mTechLists);
}
activity 1:
#Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
nfcForegroundUtil = new NFCForegroundUtil(this);
}
#Override
protected void onNewIntent(Intent intent)
{
super.onNewIntent(intent);
Intent i = new Intent(this, NfcDisplayLabelActivity2.class);
startActivity(i);
}

Go to settings -> Apps -> All -> Tags(in my case) -> disable

I had a similar problem when trying to open my app from an NFC tag. I had registered an intentfilter in my AndroidManifest.xml for the scheme "magicnfc" and yet it opened the Android OS Tags app instead of mine.
I discovered that the NFC intent (TECH_DISCOVERED in my case) had higher priority than a generic scheme-based intent filter. Because the Tags app registered TECH_DISCOVERED, it was getting opened instead of mine.
Luckily, apps can register for NDEF_DISCOVERED (a higher priority filter) and get opened instead of the Tags app.
That made my app open when I tapped the tag.
More info is here:
http://developer.android.com/guide/topics/connectivity/nfc/nfc.html
But I found that I had to override the function onNewIntent, with code like this:
if (NfcAdapter.ACTION_NDEF_DISCOVERED.equals(getIntent().getAction())) {
String uri = intent.getDataString();
Parcelable[] rawMsgs = intent.getParcelableArrayExtra(NfcAdapter.EXTRA_NDEF_MESSAGES);
if (rawMsgs != null) {
msgs = new NdefMessage[rawMsgs.length];
for (int i = 0; i < rawMsgs.length; i++) {
msgs[i] = (NdefMessage) rawMsgs[i];
}
}
}
For me, all I needed was:
String uri = intent.getDataString();
Good luck!

You can listen for all tags activated using the ACTION_TAG_DISCOVERED intent, rather than filtering for a specific one with the following code:
public NFCForegroundUtil(Activity activity)
{
super();
this.activity = activity;
mAdapter = NfcAdapter.getDefaultAdapter(activity
.getApplicationContext());
mPendingIntent = PendingIntent.getActivity(activity, 0, new Intent(
activity, activity.getClass())
.addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP),
0);
// See below
mAdapter.enableForegroundDispatch(this, mPendingIntent, null, null);
}
From the NFCAdapter Documentation :
If you pass null for both the filters and techLists parameters that acts a wild card and will cause the foreground activity to receive all tags via the ACTION_TAG_DISCOVERED intent.

Your problem is when you initialise the intent i onNewIntent
The class should be itself, not the second class.
The right code should be :
#Override
protected void onNewIntent(Intent intent)
{
super.onNewIntent(intent);
Intent i = new Intent(this, NfcDisplayLabelActivity1.class);
startActivity(i);
}

I was seeing "New tag collected" from build-in app called "Tags" because my application didn't work properly.
When it works ok, it has higher priority than "Tags" and phone reads tags from my application. But when it works unproperly and phone collect a tag, "Tags" application is activated and "Tags" application talks to my device.
After repairing code, my app has higher priority and phone reads tags using my application.

Optimal way to create shorcut for other package activity

I'm trying to create programmability a home shortcut for any installed application.
Considering that the only thing I would have available would the application name, let's say for example the Calculator com.android.calculator2 (1.5).
I'm using current code bellow, shortcut is created successfully but activity cannot be launched from shortcut (wrong activity class name I guess) and also sometimes the icon seems to be corrupted.
Also add com.android.launcher.permission.INSTALL_SHORTCUT to manifest.xml.
Is there a optimal way to achieved this?
String appName = "com.android.calculator2";
Context newAppContext = null;
// Get other package context
try {
newAppContext =
context.createPackageContext(appName, Context.CONTEXT_IGNORE_SECURITY);
} catch (NameNotFoundException e) {
e.printStackTrace();
}
// Create shortcut
if(newAppContext != null) {
// Get Application Name
PackageManager pm = context.getPackageManager();
ApplicationInfo ai;
try {
ai = pm.getApplicationInfo(appName, 0);
} catch (final NameNotFoundException e) {
ai = null;
}
// Get application label
String applicationName = (String) (ai != null ? pm.getApplicationLabel(ai) : "(unknown)");
// Shortcut intent
Intent shortcutIntent = new Intent (Intent.ACTION_MAIN);
/** Problem in here **
shortcutIntent.setClassName(newAppContext, newAppContext.getClass().getName());
*********************/
shortcutIntent.addCategory(Intent.CATEGORY_LAUNCHER);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// Create intent
final Intent putShortCutIntent = new Intent();
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent);
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_NAME, applicationName);
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_ICON_RESOURCE,
Intent.ShortcutIconResource.fromContext(newAppContext,
R.drawable.icon));
putShortCutIntent.setAction("com.android.launcher.action.INSTALL_SHORTCUT");
// Broadcast intent
context.sendBroadcast(putShortCutIntent);
}
EDIT:
Managed to achieve this by getting the Intent from PackageManager.getLaunchIntentForPackage(String packageName).
So:
// Intent shortcutIntent = new Intent (Intent.ACTION_MAIN);
// shortcutIntent.setClassName(newAppContext, newAppContext.getClass().getName());
// shortcutIntent.addCategory(Intent.CATEGORY_LAUNCHER);
// shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
Intent shorcutIntent = pm.getLaunchIntentForPackage(appName);

You will get "wrong activity class name", when it cannot find the main activity class in the package. It needs that info so that it can launch the correct Activity in the correct package. So in your example, it should be:
shortcutIntent.setClassName("com.android.calculator2", "ClassName");
I don't know what the "ClassName" should be for the Calculator application(maybe you can check its source code), but it should be something like "com.android.calculator2.MainActivity"
EDIT:
Ok, it seems it is possible to get the "ClassName" dynamically:
PackageManager packageManager = context.getPackageManager();
ResolveInfo info = packageManager.resolveActivity(shortcutIntent, 0);
if(info != null) {
shortcutIntent.setClassName(info.activityInfo.packageName, info.activityInfo.name);
}