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Replacing text in XWPFParagraph without changing format of the docx file

I am developing font converter app which will convert Unicode font text to Krutidev/Shree Lipi (Marathi/Hindi) font text. In the original docx file there are formatted words (i.e. Color, Font, size of the text, Hyperlinks..etc. ).
I want to keep format of the final docx same as the original docx after converting words from Unicode to another font.
PFA.
Here is my Code
try {
fileInputStream = new FileInputStream("StartDoc.docx");
document = new XWPFDocument(fileInputStream);
XWPFWordExtractor extractor = new XWPFWordExtractor(document);
List<XWPFParagraph> paragraph = document.getParagraphs();
Converter data = new Converter() ;
for(XWPFParagraph p :document.getParagraphs())
{
for(XWPFRun r :p.getRuns())
{
String string2 = r.getText(0);
data.uniToShree(string2);
r.setText(string2,0);
}
}
//Write the Document in file system
FileOutputStream out = new FileOutputStream(new File("Output.docx");
document.write(out);
out.close();
System.out.println("Output.docx written successully");
}
catch (IOException e) {
System.out.println("We had an error while reading the Word Doc");
}

Thank you for ask-an-answer.
I have worked using POI some years ago, but over excel-workbooks, but still I’ll try to help you reach the root cause of your error.
The Java compiler is smart enough to suggest good debugging information in itself!
A good first step to disambiguate the error is to not overwrite the exception message provided to you via the compiler complain.
Try printing the results of e.getLocalizedMessage()or e.getMessage() and see what you get.
Getting the stack trace using printStackTrace method is also useful oftentimes to pinpoint where your error lies!
Share your findings from the above method calls to further help you help debug the issue.
[EDIT 1:]
So it seems, you are able to process the file just right with respect to the font conversion of the data, but you are not able to reconstruct the formatting of the original data in the converted data file.
(thus, "We had an error while reading the Word Doc", is a lie getting printed ;) )
Now, there are 2 elements to a Word document:
Content
Structure or Schema
You are able to convert the data as you are working only on the content of your respective doc files.
In order to be able to retain the formatting of the contents, your solution needs to be aware of the formatting of the doc files as well and take care of that.
MS Word which defined the doc files and their extension (.docx) follows a particular set of schemas that define the rules of formatting. These schemas are defined in Microsoft's XML Namespace packages[1].
You can obtain the XML(HTML) format of the doc-file you want quite easily (see steps in [1] or code in link [2]) and even apply different schemas or possibly your own schema definitions based on the definitions provided by MS's namespaces, either programmatically, for which you need to get versed with XML, XSL and XSLT concepts (w3schools[3] is a good starting point) but this method is no less complex than writing your own version of MS-Word; or using MS-Word's inbuilt tools as shown in [1].
[1]. https://www.microsoftpressstore.com/articles/article.aspx?p=2231769&seqNum=4#:~:text=During%20conversion%2C%20Word%20tags%20the,you%20can%20an%20HTML%20file.
[2]. https://svn.apache.org/repos/asf/poi/trunk/src/scratchpad/testcases/org/apache/poi/hwpf/converter/TestWordToHtmlConverter.java
[3]. https://www.w3schools.com/xml/
My answer provides you with a cursory overview of how to achieve what you want to, but depending on your inclination and time availability, you may want to use your discretion before you decide to head onto one path than the other.
Hope it helps!

Attempting to parse a file (mmp format) from legacy software using Python

I have a piece of Legacy software called Mixmeister that saved off playlist files in an MMP format.
This format appears to contain binary as well as file paths.
I am looking to extract the file paths along with any additional information I can from these files.
I see this has been done using JAVA (I do not know JAVA) here (see aorund ln 56):
https://github.com/liesen/CueMeister/blob/master/src/mixmeister/mmp/MixmeisterPlaylist.java
and Haskell here:
https://github.com/larjo/MixView/blob/master/ListFiles.hs
So far, I have tried reading the file as binary (got stuck); using Regex expressions (messy output with moderate success) and attempting to try some code to read chunks (beyond my skill level).
The code I am using with moderate success for Regex is:
file='C:\\Users\\xxx\\Desktop\\mixmeisterfile.mmp'
with open(file, 'r', encoding="Latin-1") as filehandle:
#with open(file, 'rb') as filehandle:
for text in filehandle:
b = re.search('TRKF(.*)TKLYTRKM', text)
if b:
print(b.group())
Again, this gets me close but is messy (the data is not all intact and surrounded by ascii and binary characters). Basically, my logic is just searching between two strings to attempt to extract the filenames. What I am really trying to do is get closer to something like what the JAVA has in GIT, which is (the code below is sampled from the GIT link):
List<Track> tracks = new ArrayList<Track>();
Marker trks = null;
for (Chunk chunk : trkl.getChunks()) {
TrackHeader header = new TrackHeader();
String file = "";
List<Marker> meta = new LinkedList<Marker>();
if (chunk.canContainSubchunks()) {
for (Chunk chunk2 : ((ChunkContainer) chunk).getChunks()) {
if ("TRKH".equals(chunk2.getIdentifier())) {
header = readTrackHeader(chunk2);
} else if ("TRKF".equals(chunk2.getIdentifier())) {
file = readTrackFile(chunk2);
} else {
if (chunk2.canContainSubchunks()) {
for (Chunk chunk3 : ((ChunkContainer) chunk2).getChunks()) {
if ("TRKM".equals(chunk3.getIdentifier())) {
meta.add(readTrackMarker(chunk3));
} else if ("TRKS".equals(chunk3.getIdentifier())) {
trks = readTrackMarker(chunk3);
}
}
}
}
}
}
Track tr = new Track(header, file, meta);
I am guessing this would either use RIFF or the chunk library in Python if not done using a Regex? Although I read the documentation at https://docs.python.org/2/library/chunk.html, I am not sure that I understand how to go about something like this - mainly I do not understand how to properly read the binary file which has the visible mixed in file paths.

I don't really know what's going on here but I'll try my best and if it doesn't work out then please excuse my stupidity. When I had a project for parsing weather data for a Metar, I realized that my main issue was that I was trying to turn everything into a String type, which wasn't suitable for all the data and so it would just come out as nothing. Your for loop should work just fine. However, when you traverse, have you tried making everything the same type, such as a Character/String type? Perhaps there are certain elements messed up simply because they don't match the type you are going for.

Adding elements to an JSON object in a external JSON file?

(After months of surfing the internet, talking to the school's computing department and try code out, I still don't get how to do it, but I do know more specific about what I trying to do)
Previously I said I want to "Add lines" to a existing JSON file.
What I want to do is simply add an element to an JSON object from a file, then save the file.
However I am still confused about how to do it.
The process I am guessing is to use ajax to load the content of the file (the JSON code in the file) into a variable then add the new element into the object then save the file.
I have seen a lot of code but are all just too confusing and looks like its for webpages. I am trying to edit a file on the computer as a program which I think webpage related code such as xmlhttp requests are irrelevant as the file is in a folder in appdata.
I have been confused and thought Java and Javascript were the same thing, I know now they're not.
What code or functions would I look for and how would it be used in the code?
(Please don't post pseudocode because I have no idea how to write the code for them since I have literally no idea how to code anything other than a html webpage and some php. Other coding language like Java, Javascript and Python I have little knowledge with but not enough to write a program alone.)

I think it would be best to use code that somebody else has already written to manipulate the JSON. There are plenty of libraries for that, and the best would be the officially specified one, JSON-P. What you would do is this:
Go to http://jsonp.java.net/ and download JSON-P. (You will have to examine the page carefully to find the link to "JSON Processing RI jar".) You will need to include this JAR in your class path while you write your program.
Add imports to your program for javax.json.*.
Write this code to do the job (you will have to catch JsonExceptions and IOExceptions):
JsonReader reader = Json.createReader(new FileReader("launcher_profiles.json"));
JsonObject file = reader.readObject();
reader.close();
JsonObject profiles = file.getJsonObject("profiles");
JsonObject newProfile = Json.createObjectBuilder()
.add("name", "New Lines")
.add("gameDir", "New Lines")
.add("lastVersionId", "New Lines")
.add("playerUUID", "")
.build();
JsonObjectBuilder objectBuilder = Json.createObjectBuilder()
.add("New Profile Name", newProfile);
for (java.util.Map.Entry<String, JsonValue> entry : profiles.entrySet())
objectBuilder.add(entry.getKey(), entry.getValue());
JsonObject newProfiles = objectBuilder.build();
// Now, figure out what I have done so far and write the rest of the code yourself! At the end, use this code to write out the new file:
JsonWriter writer = Json.createWriter(new FileWriter("launcher_profiles.json"));
writer.writeObject(newFile);
writer.close();

Format ParseException with JavaCC

I was wondering how could it be possible to format in a human-readable format a ParseException thrown by JavaCC: in fact it includes fields such asbeginLine, beginColumn, endColumn, endLine in the token reference of the exception, but not the reference to the source parsed.
Thanks! :)

The problem is that, by default, JavaCC doesn't retain the raw source data. So unless you keep a reference to the tokens somehow, they're not held in memory. And even if you did hang onto all the regular tokens, you'd need to add special handling for any SKIP tokens that you'd defined - e.g., for discarding whitespace and comments. The reason JavaCC doesn't retain all this stuff is that it would use a lot more memory.
Keeping all the token images is definitely doable... just takes some semi-manual intervention.

I don't know if it is enough, but you can use property currentToken from catched ParseException object:
try {
parser.Start();
}
catch(ParseException e){
System.out.println("Problem with code!");
System.out.println("Unknown symbol >> "
+ e.currentToken.image
+ " << Line:" + e.currentToken.beginLine
+ ", column:" + e.currentToken.beginColumn);
//e.printStackTrace();
}

Just keep the filename before calling the parser. Then when you catch ParseException, reread the file and, using beginLine, skip to the right line. Alternatively, instead of the filename, keep the original source text yourself.
I recently used javacc and did exactly that. Also had to handle include-like files recursively so I had the parser build a stack of included source files. Upon catching ParseException, it was a simple matter to walk the stack so the user could see the context (i.e. line number in the parent) where each file was included.

Reading an XML File using FileInputStream (for Java)?

For my project I have to serialize and deserialize a random tree using Java and XStream. My teacher made the Tree/RandomTree algorithms, so I don't have to worry about that. What I don't know how to do is this: I am using FileInputStream to read/write the xml file that I serialized and deserialized, but when I deserialize, I do not know the method used to read the file. After I read the file I should be able to convert it from XML and then print it out as a string. Here's what I have so far. (I imported everything correctly, just didn't add it to my code segment).
FileInputStream fin;
try
{
// Open an input stream
fin = new FileInputStream ("/Users/Pat/programs/randomtree.xml");
//I don't know what to put below this, to read FileInpuStream object fin
String dexml = (String)xstream.fromXML(fin);
System.out.println(dexml);
// Close our input stream
fin.close();
System.out.println(dexml);
// Close our input stream
fin.close();
}
// Catches any error conditions
catch (IOException e)
{
System.err.println ("Unable to read from file");
System.exit(-1);
}
Edit: I figured it out; I don't think I have to print it as a string, I just needed to make a benchmarking framework to time it and such, but thanks again!

The xstream.fromXML() method will do the reading from the input stream for you. I think the problem is that you are casting the return value from xstream.fromXML(fin) into a String when it should be cast to the type of object you originally serialized (RandomTree I assume). So the code would look like this:
RandomTree tree = (RandomTree)xstream.fromXML(fin);
EDIT: after clarification in comments, the author's goal is to first read into a String so the XML contents can be printed before deserialization. With that goal in mind, I recommend taking a look at the IOUtils library mentioned in this thread

From what I understand from http://x-stream.github.io/tutorial.html (I've never worked with XStream before), you need to define your types first. Casting to String is definitely wrong, you probably want a customized type (depending on what's inside your random XML), then you need to map the XML tags to your members:
e.g.
xstream.alias("person", Person.class);
xstream.alias("phonenumber", PhoneNumber.class);
meaning that it maps the "person" tag inside your XML to your Person class.
To derserialize, you can do:
RandomTree myRandomTree = (RandomTree)xstream.fromXML( xml );
Also, you are closing your stream twice, and you probably want to do it in a finally block :)
edit: Having read your comment above...
Your task involves two steps:
Deserialization
Serialization
In order to serialize your object, you must deserialize it first from your input file.
To output your Object as String, simply do
String xml = xstream.toXML( myRandomTree );