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PropertiesLauncher command line arguments not working with Spring Boot executable Jar

So I have basic multi-module Spring Boot project. The goal, that I had was to build executable jar and pass additional properties with the help of -Dloader.path=....
For some reason (if I understand purpose of this argument) loader.path is being ignored completely.
My project structure is following:
\-
|--conf
|---default
|--pets-api
|--pets-app (this module contains the Main-Class)
|--pets-domain
|--pets-infrastructure
Since no custom active profile is being passed it uses "default". Jar contains application-default.propeties file, that has single configuration server.servlet.context-path=/v1.
/conf/default location has 2 properties files:
application.properties
random.properties - this is bind to #ConfigurationProperties(prefix = "...") inside application
When I run it normally everything is fine java -jar pets-app-0.0.1-SNAPSHOT.jar. It just uses application-default.properties file and that is it.
Now when I am trying to utilize -Dloader.path argument as in java -Dloader.path=PATH/TO/conf/default -jar pets-app-0.0.1-SNAPSHOT.jar it starts application same as before, as if I am not adding 2 more file to classpath.
What is used:
Java 17
Spring Boot 2.6.12
Gradle
Did anyone come across this as well? Any suggestion on how to resolve it?
PS. If there is need to see the code, I can upload it to GitHub.

Disable spring-context-indexer by profile

I want to enable Spring Context Indexer on a project but I am having issues with Swagger3 (check here and here).
I understand the limitations and would like to enable it, at least, at the DEV profile where we do not need Swagger running.
My goal is to disable indexing on PROD environment. From docs:
you can fallback to a regular classpath arrangement (as though no index was present at all) by setting spring.index.ignore to true, either as a system property or in a spring.properties file at the root of the classpath.
My first approach (without success) was setting an env var (Windows 10) with the following:
SPRING_APPLICATION_JSON={"spring":{"index":{"ignore":true}}}
If I create a spring.properties file and set the value accordingly it works. But I can't figure how to use different properties for each profile, I imagined it was something like the application.properties file but I was wrong.
How can I achieve that?
EDIT:
Just to be clear, this config (spring.index.ignore) will just work if inside a spring.properties file, not an application.properties one. (Just double-checked before this edit)
Actually I have one application-prod.properties and one application-dev.properties.
I don't know the difference between spring.properties and application.properties but the first one doesn't seem to work with multiple profiles as the later.
Edit 2:
Just went through org.springframework.context.index.CandidateComponentsIndexLoader and it uses SpringProperties.getFlag(IGNORE_INDEX) to read the value.
SpringProperties class is clear about the file it uses:
Reads a spring.properties file from the root of the Spring library classpath, and also allows for programmatically setting properties through setProperty. When checking a property, local entries are being checked first, then falling back to JVM-level system properties through a System.getProperty check.
I think I will need to pass a property to Java runner during initialization. Will research a little bit more about it.

you can use different application.properties file as follow:
add the following files to the resource folder:
application.properties
spring.profiles.active=dev #place profile name you want to use
application-dev.properties
#dev properties
...
You can create many application-env.properties you may wish
application-env.properties
#env properties
...

Spring Boot supports profile-specific properties files. You have to name these files with the following format: application-{profile}.properties. You can activate a profile via JVM system parameter: -Dspring.profiles.active=dev. You can read more about this subject here: https://www.baeldung.com/spring-profiles

Multiple profiled properties configuration in Spring-boot 2

I have a spring-boot 2.1.3.RELEASE application with multiple properties files.
In my /src/main/resources I have my-app.properties and profiled my-app-local.properties.
Also, outside the project I have another profiled properties file /config/my-app-local.properties.
The point of this configuration is to have the following properties hierarchy:
/resources/my-app.properties
/resources/my-app-local.properties
/config/my-app-local.properties
So when I try to run the application with the following parameters:
--spring.profiles.active=local --spring.config.name=my-app --spring.config.location=config/my-app.properties
the application fails to start because it can't find any properties files.
However, this configuration and parameters worked perfectly on spring-boot 1.5.19.RELEASE. How can the same be achieved in spring-boot 2?

use spring.config.additional-location doc
When custom config locations are configured by using spring.config.location, they replace the default locations. For example, if spring.config.location is configured with the value classpath:/custom-config/,file:./custom-config/, the search order becomes the following:
file:./custom-config/
classpath:custom-config/
Alternatively, when custom config locations are configured by using spring.config.additional-location, they are used in addition to the default locations. Additional locations are searched before the default locations. For example, if additional locations of classpath:/custom-config/,file:./custom-config/ are configured, the search order becomes the following:
file:./custom-config/
classpath:custom-config/
file:./config/
file:./
classpath:/config/
classpath:/

Spring Boot refuses to pick up application test properties [duplicate]

I have a spring boot application that I can package in a war that I want to deploy to different environments. To automate this deployment it'd be easier to have the configuration file externalized.
Currently everything works fine with a application.properties file in src/main/resources. Then I use ´mvn install´ to build a war deployable to tomcat.
But I would like to use a .yml file that does not need to be present on mvn install but that would be read from during deployment of the war and is in the same or a directory relative to my war.
24. externalized configuration shows where spring boot will look for files and 72.3 Change the location of external properties of an application gives more detail on how to configure this but I just do not understand how to translate this to my code.
My application class looks like this:
package be.ugent.lca;
Updated below
Do I need to add a #PropertySource to this file? How would I refer to a certain relative path?
I feel like it's probably documented in there as most spring boot documentation but I just don't understand how they mean me to do this.
EDIT
Not sure if this should be a separate issue but I think it's still related.
Upon setting the os variable the error of yaml file not found went away. Yet I still get the same error again as when I had no application .properties or .yml file.
Application now looks like this:
#Configuration
**#PropertySource("file:${application_home}/application.yml")**
#ComponentScan({"be.ugent.lca","be.ugent.sherpa.configuration"})
#EnableAutoConfiguration
#EnableSpringDataWebSupport
public class Application extends SpringBootServletInitializer{
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
The application_home OS variable
$ echo $application_home
C:\Masterproef\clones\la15-lca-web\rest-service\target
My application.yml file(part it complains about):
sherpa:
package:
base: be.ugent.lca
Error upon java -jar *.war
All variations upon:
Caused by: java.lang.IllegalArgumentException: Could not resolve placeholder 'sherpa.package.base' in string value "${sherpa.package.base}"
at org.springframework.util.PropertyPlaceholderHelper.parseStringValue(PropertyPlaceholderHelper.java:174)
at org.springframework.util.PropertyPlaceholderHelper.replacePlaceholders(PropertyPlaceholderHelper.java:126)
at org.springframework.core.env.AbstractPropertyResolver.doResolvePlaceholders(AbstractPropertyResolver.java:204)
at org.springframework.core.env.AbstractPropertyResolver.resolveRequiredPlaceholders(AbstractPropertyResolver.java:178)
at org.springframework.context.support.PropertySourcesPlaceholderConfigurer$2.resolveStringValue(PropertySourcesPlaceholderConfigurer.java:172)
at org.springframework.beans.factory.support.AbstractBeanFactory.resolveEmbeddedValue(AbstractBeanFactory.java:808)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:1027)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:1014)
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:545)
... 142 more

Using external properties files
The answer lies in the Spring Boot Docs, I'll try to break it down for you.
First of all, no you should not use #PropertySource when working with Yaml configuration, as mentioned here under the Yaml shortcomings :
YAML files can’t be loaded via the #PropertySource annotation. So in the case that you need to load values that way, you need to use a properties file.
So, how to load propery files? That is explained here Application Property Files
One is loaded for you: application.yml , place it in one of the directories as mentioned in the link above. This is great for your general configuration.
Now for your environment specific configuration (and stuff like passwords) you want to use external property files, how to do that is also explained in that section :
If you don’t like application.properties as the configuration file name you can switch to another by specifying a spring.config.name environment property. You can also refer to an explicit location using the spring.config.location environment property (comma-separated list of directory locations, or file paths).
So you use the spring.config.location environment property.
Imagine you have an external config file: application-external.yml in the conf/ dir under your home directory, just add it like this:
-Dspring.config.location=file:${home}/conf/application-external.yml as a startup parameter of your JVM.
If you have multiple files, just seperate them with a comma. Note that you can easily use external properties like this to overwrite properties, not just add them.
I would advice to test this by getting your application to work with just your internal application.yml file , and then overwrite a (test) property in your external properties file and log the value of it somewhere.
Bind Yaml properties to objects
When working with Yaml properties I usually load them with #ConfigurationProperties, which is great when working with for example lists or a more complex property structure. (Which is why you should use Yaml properties, for straightforward properties you are maybe better of using regular property files). Read this for more information: Type-Safe Configuration properties
Extra: loading these properties in IntelliJ, Maven and JUnit tests
Sometimes you want to load these properties in your maven builds or when performing tests. Or just for local development with your IDE
If you use IntelliJ for development you can easily add this by adding it to your Tomcat Run Configuration : "Run" -> "Edit Configurations" , select your run configuration under "Tomcat Server" , check the Server tab and add it under "VM Options".
To use external configuration files in your Maven build : configure the maven surefire plugin like this in your pom.xml:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<configuration>
<argLine>-Dspring.config.location=file:${home}/conf/application-external.yml</argLine>
</configuration>
</plugin>
When running JUnit tests in IntelliJ:
Run → Edit Configurations
Defaults → JUnit
add VM Options -> -ea -Dspring.config.location=file:${home}/conf/application-external.yml

Yes, you need to use #PropertySource as shown below.
The important point here is that you need to provide the application_home property (or choose any other name) as OS environment variable or System property or you can pass as a command line argument while launching Spring boot. This property tells where the configuration file (.properties or .yaml) is exactly located (example: /usr/local/my_project/ etc..)
#Configuration
#PropertySource("file:${application_home}config.properties")//or specify yaml file
#ComponentScan({"be.ugent.lca","be.ugent.sherpa.configuration"})
#EnableAutoConfiguration
#EnableSpringDataWebSupport
public class Application extends SpringBootServletInitializer{
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}

There is a very simple way to achieve this.
Inside your original application.properties file you can just specify the following line:
spring.config.import=file:Directory_To_The_File/Property_Name.properties
It will automatically sync all the properties from the external property file.
Now lets say that you have a situation where you need to get properties from multiple property files. In that case, you can mention the same line in the external property file which in turn will take the remaining properties from the second property file and so on.
Consider the following example.
application.properties:
spring.config.import=file:Resources/Custom1.properties
Custom1.properties:
server.port=8090
.
.
.
spring.config.import=file:Resources/Custom2.properties

One of the easiest way to use externalized property file using system environment variable is, in application.properties file you can use following syntax:
spring.datasource.url = ${OPENSHIFT_MYSQL_DB_HOST}:${OPENSHIFT_MYSQL_DB_PORT}/"nameofDB"
spring.datasource.username = ${OPENSHIFT_MYSQL_DB_USERNAME}
spring.datasource.password = ${OPENSHIFT_MYSQL_DB_PORT}
Now, declare above used environment variables,
export OPENSHIFT_MYSQL_DB_HOST="jdbc:mysql://localhost"
export OPENSHIFT_MYSQL_DB_PORT="3306"
export OPENSHIFT_MYSQL_DB_USERNAME="root"
export OPENSHIFT_MYSQL_DB_PASSWORD="123asd"
This way you can use different value for same variable in different environments.

Use below code in your boot class:
#PropertySource({"classpath:omnicell-health.properties"})
use below code in your controller:
#Autowired
private Environment env;

Spring Boot, no console logging is available if --spring.config.location is provided while starting

I have a simple web app based on Spring Boot, I want to externalize my configuration using --spring.config.location when I start the app, like this:
java -jar app.jar --spring.config.location=file://home/user/application-dev.properties
When I start the app without --spring.config.location it does print all the logs in console, otherwise there's no output.
There're no logging-related properties neither in 'main' application.properties nor in the external config I'm trying to use.
The same thing happens when I use SPRING_CONFIG_LOCATION env variable instead of passing the argument.